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Is "Escherian metamorphosis" always possible?

$\DeclareMathOperator\int{int}\DeclareMathOperator\diam{diam}\DeclareMathOperator\area{area}\DeclareMathOperator\cl{cl}\DeclareMathOperator\ran{ran}\DeclareMathOperator\dom{dom}$This is a tweaked ...
Noah Schweber's user avatar
16 votes
0 answers
325 views

Rational equivalence of smooth closed manifolds

All spaces below will be assumed simply connected. A continuous map is a rational equivalence if it induces an isomorphism of the rational homology groups. Two spaces are rationally equivalent if they ...
algori's user avatar
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16 votes
0 answers
734 views

What is the current status of the question of whether or not the mapping class group has Kazhdan's Property (T)?

$\DeclareMathOperator\Mod{Mod}$Let $\Mod(S)$ be the mapping class group of a closed oriented surface $S$ of genus at least $3$. My question is easy to state: is it currently known whether or not $\...
Thomas's user avatar
  • 161
16 votes
0 answers
369 views

Transcendence of sum of reciprocals of factorials

For $A \subseteq \mathbb{N}$, define $\displaystyle x_A = \sum_{n \in A} \frac{1}{n!}$. It is easy to see that for every infinite $A$, $x_A$ is irrational. Question: Is there an infinite $A \subseteq \...
Sam's user avatar
  • 161
16 votes
0 answers
558 views

Identity involving Schur polynomials, binomial coefficients and contents of partition

Let $C_{\lambda,\mu}$ be the coefficients defined as $$ s_\lambda\left(\frac{x_1}{1-x_1},...,\frac{x_N}{1-x_N}\right)=\sum_{\mu\supset \lambda}C_{\lambda\mu}s_\mu(x_1,...,x_N),$$ where $s$ are the ...
Marcel's user avatar
  • 2,552
16 votes
0 answers
288 views

Fibrations whose total spaces are more highly connected than their fibers

The (generalized) Hopf fibrations $S^1 \to S^3 \to S^2$, $S^3 \to S^7 \to S^4$ and $S^7 \to S^{15} \to S^8$ have the property that their total spaces are more highly connected than their fibers. Are ...
Jens Reinhold's user avatar
16 votes
0 answers
222 views

Reference request: Milnor rank of spheres

Milnor defines the rank of a smooth manifold $M$ as the maximum cardinality of a linearly independent set of vector fields on $M$ whose elements are pair wise commuting. In other words, the rank of $M$...
Douglas Finamore's user avatar
16 votes
0 answers
875 views

"Geometric" proof of Kunneth formula

The usual proof of the Kunneth formula (say for either the homology or cohomology of manifolds) is essentially pure homological algebra. I was wondering if there was a more geometric proof, i.e., one ...
Matt Larson's user avatar
  • 1,046
16 votes
0 answers
437 views

Can non-reduced fibers appear over a subset of codimension $\geq 2$?

I already asked this on math.stackexchange.com, but didn't receive an answer. Suppose $f: X \to Y$ is a (possibly proper) morphism of complex manifolds (resp. smooth varieties) such that all fibers of ...
red_trumpet's user avatar
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16 votes
0 answers
755 views

Is there a "natural" proof of the equality $4^2=2^4$?

This question, or rather any answer that it might receive, would probably belong to the realm of Awfully sophisticated proof for simple facts. Still, I claim that I have quite serious motivation for ...
მამუკა ჯიბლაძე's user avatar
16 votes
0 answers
475 views

Progess on a Problem/Conjecture of Sullivan?

In Sullivan's postscript to his MIT notes https://www.maths.ed.ac.uk/~v1ranick/surgery/gtop.pdf he describes some problems and conjectures, where Problem 4 is: "Analyze the action of Gal($\...
Tian An's user avatar
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16 votes
0 answers
274 views

Why should an abelian variety with few places of bad reduction and a lot of endomorphisms not have many points?

In the paper "Points of Order 13 on Elliptic Curves" by Mazur-Tate, they say in the introduction: It seemed ... that if such an abelian variety $J$, which has bad reduction at only one ...
Asvin's user avatar
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16 votes
0 answers
400 views

Quadratic non-residues in elliptic divisibility sequences

Let $E: y^2 = x^3 + ax + b$ be an elliptic curve over $\mathbb{Q}$ with $a,b \in \mathbb{Z}$. Recall that any rational point $P = (x,y)$ can be written uniquely as $P = (u/d^2, v/d^3)$ with $u,v,d \in ...
Daniel Loughran's user avatar
16 votes
0 answers
787 views

Numbers of the form $x^2(x-1) + y^2(y-1) + z^2(z-1)$ with $x,y,z\in\mathbb Z$

Roger Heath-Brown conjectured that any integer $k\not\equiv\pm4\pmod9$ can be expressed as $x^3+y^3+z^3$ with $x,y,z\in\mathbb Z$ in infinitely many different ways. Also it is well-known that some ...
Alkan's user avatar
  • 701
16 votes
1 answer
688 views

Approximating zero sets of real polynomials with "less complicated" polynomials

Let $K \subset \mathbb{R}^n$ be a compact subset, and let $P(x_1,\dots,x_n)$ be a real multivariable polynomial of degree $d$, whose vanishing set we denote by $Z_P$. Is it plausible to approximate $...
SMS's user avatar
  • 1,407
16 votes
0 answers
574 views

Are $0, 1, 4, 7, 8$ the only dimensions in which a bivector-valued cross product exists?

It is a well-known mathematical curiosity that ordinary (vector-valued) cross products over $\mathbb{R}$ exist only in dimensions $0, 1, 3$ and $7$ (this fact is related to Hurwitz's theorem that real ...
pregunton's user avatar
  • 1,206
16 votes
0 answers
631 views

The Octahedral Axiom in group theory

$\require{AMScd}$Here are two results about groups: (The third isomorphism theorem) Suppose that I have $A \triangleleft B \triangleleft C$ and $A \triangleleft C$. Then $C/B \cong (C/A)/(B/A)$. ...
David E Speyer's user avatar
16 votes
0 answers
213 views

Characterization of geometric morphisms without referring explicitly to the left adjoint?

Recall that a functor $f_\ast : \mathcal E \to \mathcal F$ between toposes is called a geometric morphism if it has a left exact left adjoint $f^\ast$. Is there an intrinsic characterization of such ...
Tim Campion's user avatar
16 votes
0 answers
780 views

Shimura varieties and connected components

Let $G$ be a connected reductive algebraic group over $\mathbf{Q}$. I've seen two slightly different definitions in the literature of the Shimura variety of level $U$, for $U \subseteq G(\mathbf{A}_{\...
David Loeffler's user avatar
16 votes
0 answers
372 views

On projectively countable sets in the Hilbert cube

A subset $A$ of a topological space $X$ is called projectively countable if for any continuous map $f:X\to\mathbb R$ the image $f(A)$ is countable. It is easy to see that each projectively countable ...
Taras Banakh's user avatar
16 votes
0 answers
556 views

Reference request for Grothendieck's work on "Integration with values in a topological group"

Disclaimer. This question was already asked in Mathematics Stack Exchange (see the link here). I wanted the question to be migrated here but I was told by a moderator that a question that old is ...
user avatar
16 votes
0 answers
646 views

Consistency strength of $j:L_δ→L_δ$ for some δ

What is the consistency strength of existence of a nontrivial elementary embedding $j:L_δ→L_δ$ for some ordinal $δ$? The consistency strength is strictly between totally ineffable and $ω$-Erdős ...
Dmytro Taranovsky's user avatar
16 votes
0 answers
489 views

An inequality for matrix norms

Working on a problem in combinatorics I come up with the following inequality on matrix norms, which I checked it also numerically: Let $A=(a_{ij})$ be a real symmetric $n\times n$ matrix with ...
Mostafa - Free Palestine's user avatar
16 votes
0 answers
952 views

Continuous cohomology of a profinite group is not a delta functor

Let $G$ be a profinite group, then there is a general notion of continuous cohomology groups $H^n_{\text{cont}}(G, M)$ for any topological $G$-module $M$ (I require topological $G$-modules to be ...
gdb's user avatar
  • 2,923
16 votes
0 answers
255 views

Generalization of Newton's identities to Schur functions

In some recent work, I've stumbled across the following identity for $\lambda \vdash n$: $$ n s_\lambda = \sum_{k=1}^n p_k \sum_{\mu \nearrow_k \lambda} (-1)^{\mathrm{ht}(\lambda/\mu)} s_\mu. $$ Here, ...
Zach H's user avatar
  • 1,989
16 votes
0 answers
345 views

What property do small primes have that prevent the existence of a Tarski monster?

For an odd prime $p$, a Tarski monster group is an infinite group $G$ such that every proper, non-trivial subgroup $H < G$ is a cyclic group of order $p$. It is known that for every prime $p > ...
Stanley Yao Xiao's user avatar
16 votes
0 answers
411 views

Simple disproof of Danzer — Grünbaum conjecture

I asked this question on the MSE, but I did not get an answer. I hope that one of the experienced participants will check the correctness of the proof or the truth of the statement (and, perhaps, will ...
grizzly's user avatar
  • 269
16 votes
0 answers
784 views

What would be the simplest analog of Langlands in algebraic topology?

It is oversimplified, I know, but just as a superficial analogy, one may think of the fact that abelianization of the fundamental group is the first homology group, as some remote relative of class ...
მამუკა ჯიბლაძე's user avatar
16 votes
0 answers
589 views

The number 1680 and Lagrange's four-square theorem

The number $1680$ has the factorization $2^4\times3\times5\times7$. Rather to my surprise, I found that this number has certain mysterious connection with Lagrange's four-square theorem. QUESTION: ...
Zhi-Wei Sun's user avatar
  • 15.6k
16 votes
0 answers
315 views

A question on surfaces in $\mathbb{P}^4$

On surfaces in $\mathbb P^4$,Ellingsrud and Peskine has proved that There exists an integer $d_0$ such that for any integer $d>d_0$,any smooth surface of degree $d$ in $\mathbb P^4$ is of ...
Jiabin Du's user avatar
  • 271
16 votes
0 answers
616 views

Isoperimetric inequality and geometric measure theory

The following version of the isoperimetric inequality can be easily deduced from the Brunn-Minkowski inequality: Theorem. If $K\subset\mathbb{R}^n$ is compact, then $$ |K|^{\frac{n-1}{n}}\leq n^{-1}...
Piotr Hajlasz's user avatar
16 votes
0 answers
255 views

Abelian varieties (over $\mathbb{Q}$) with large Mordell-Weil rank

Let $A$ be an abelian variety defined over $\mathbb{Q}$ of dimension $g \geq 1$. We shall denote by $A(\mathbb{Q})$ the Mordell-Weil group of rational points in $A$, and denote by $r = r_A$ the rank ...
Stanley Yao Xiao's user avatar
16 votes
0 answers
424 views

Do TQFTs give a complete set of invariants of manifolds?

An $n$-dimensional TQFT is a representation of the category $n$Cob of $n$-dimensional cobordisms. TQFTs are important sources of invariants of manifolds, and such invariants are highly computable by ...
Henry's user avatar
  • 1,430
16 votes
0 answers
438 views

Relationship between the twistor spaces due to Penrose and Salamon

In Penrose's construction of the twistor space of Minkowski spacetime $\mathbb R^{1,3}$, we first complexify $\mathbb R^{1,3}$ to $\mathbb C^4$ and then think of points in it as matrices acting on $\...
Arpan Saha's user avatar
16 votes
0 answers
532 views

Are there smooth and proper schemes over $\mathbb Z$ whose cohomology is not of Tate type

Is there an example of smooth and proper scheme $X \to \mathrm{Spec}(\mathbb Z)$, and an integer $i$ such that $H^i(X, \mathbb Q)$ is not a Hodge structure of Tate type? Alternatively: such that $H^...
user114562's user avatar
16 votes
0 answers
2k views

Kodaira-Spencer maps and deformation theory

This post concerns the following question: Can we black-box the analysis of PDE's which arises in the construction of Kuranishi families for complex analytic structures? The deformation theory of ...
Andy Sanders's user avatar
  • 3,020
16 votes
0 answers
603 views

K-theory and homology of groups

It is known that for any ring $R$, $$K_{1}(R)=H_{1}(GL_{\infty}(R), \mathbb{Z})$$ $$ K_{2}(R)= H_{2}(E_{\infty}(R),\mathbb{Z})$$ $$ K_{3}(R)= H_{3}(St_{\infty}(R),\mathbb{Z})$$ where $GL_{\infty}= ...
Ofra's user avatar
  • 1,613
16 votes
0 answers
247 views

Gap two Sierpinski set?

Is it consistent to have a set of reals $X$ of size $\aleph_3$ such that for every $Y \subseteq X$, $Y$ has measure zero iff $|Y| \leq \aleph_1$?
Ashutosh's user avatar
  • 9,641
16 votes
0 answers
644 views

Dijkgraaf-Witten topological invariant

We know that given a finite group $G$ and its group 4-cohomology class $w \in H^4[G;U(1)]$, we can obtain a DW topological invariant $Z_{G,w}(M^4)$ as the partition function of the DW theory on a ...
Xiao-Gang Wen's user avatar
16 votes
0 answers
591 views

Are there any examples of hyperbolic curves over finite fields such that the action of frobenius on its prime-to-$p$ fundamental group is known?

Let $X$ smooth curve over a finite field $\mathbb{F}_q$ of type $(g,n)$ - that is, $X$ is an open subscheme of its genus $g$ compactification obtained by removing $n$ points. Any such curve ...
Will Chen's user avatar
  • 10.7k
16 votes
0 answers
382 views

Representation categories and homology

Let $G$ be a finite group. Let $\mathcal{C}=Rep-G$ be the rigid $\mathbb{C}$-linear symmetric monoidal category of finite dimensional complex representations of $G$. Can we recover some homological ...
Ehud Meir's user avatar
  • 5,039
16 votes
0 answers
717 views

Decidable open problems

Are there any significant open problems in mathematics which are clearly decidable (in that it is easy to write a clearly corresponding program which will eventually output either Yes or No (or ...
Sridhar Ramesh's user avatar
16 votes
0 answers
1k views

Connected sum is well-defined for surfaces, proof?

EDIT: So my question is distinct from the question asked here because I am asking an easier question. Why should we have to invoke something as powerful as the "Annulus Theorem" to show that the ...
user380206's user avatar
16 votes
0 answers
363 views

Combinatorial characterization of intersecting intervals in the plane

Consider $n$ points $A=\{A_1,\dotsc,A_n\}$, and another set of points, $B=\{B_1,\dotsc,B_n\}$ in the plane. We can assume they are all disjoint. For each permutation $\pi$, consider the collection of ...
Per Alexandersson's user avatar
16 votes
0 answers
396 views

Division of a square and value of a disk

[Full disclosure] I asked this question on math.stackexchange with little success : https://math.stackexchange.com/questions/1866295/division-of-a-square-and-value-of-a-disk I cam across this problem ...
user33624's user avatar
  • 477
16 votes
0 answers
988 views

A Combinatorial Game: the Snake and the Hunter

The Snake and the Hunter is a game for two players who play in two rounds interchanging the roles of snake and hunter. The game is played in a rectangular grid of points, say $6 \times 6$. In both ...
Bernardo Recamán Santos's user avatar
16 votes
1 answer
743 views

Inequalities for marginals of distribution on hyperplane

Let $H = \{ (a,b,c) \in \mathbb{Z}_{\geq 0}^3 : a+b+c=n \}$. If we have a probability distribution on $H$, we can take its marginals onto the $a$, $b$ and $c$ variables and obtain three probability ...
David E Speyer's user avatar
16 votes
0 answers
439 views

Survey of known results on equivariant transversality

Most basic differential topology theorems carry over to the equivariant case with mild modifications; see for instance Wasserman's paper. One thing that fails (more or less obviously) is equivariant ...
mme's user avatar
  • 9,580
16 votes
0 answers
366 views

Specific cases of the tangle hypothesis in terms of "classical" n-categories

As is well known, the tangle hypothesis of Baez and Dolan proposes that, for suitable definitions, the $n$-category of framed $n$-tangles in $n+k$ dimensions is the free $k$-tuply monoidal $n$-...
Dominic Else's user avatar
16 votes
0 answers
531 views

Aligned roots of irreducible polynomials

It is well known from this famous question that the roots of a random polynomial tend to be close to the unit circle. So I was wondering in a somewhat converse sense: for an irreducible polynomial, is ...
Wolfgang's user avatar
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