Skip to main content

All Questions

Filter by
Sorted by
Tagged with
65 votes
14 answers
6k views

Notions of convergence not corresponding to topologies

This question concerns the ramifications of the following interesting problem that appeared on Ed Nelson's final exam on Functional Analysis some years ago: Exam question: Is there a metric on the ...
jon's user avatar
  • 801
1 vote
0 answers
141 views

Can a closed null-homotopic curve be filled in by a disc?

Let $U\subseteq\Bbb R^n$ be an open set and $\gamma\subset U$ a closed null-homotopic curve in $U$ (i.e. it can be contracted to a point). Then is there an embedded disc $D\subset U$ with boundary $\...
M. Winter's user avatar
  • 13.6k
1 vote
2 answers
248 views

A few questions about Tychonoff plank

In the Morita's following article (K. Morita. Some properties of M-spaces), constructing an space $X$ and defining an identification on it. My first question is how to prove that $S$ is countably ...
Mehmet Onat's user avatar
  • 1,367
0 votes
0 answers
51 views

Approximating open subset of profinite group by union of cosets of ideal

I am trying to understand the proof of Theorem 1.3 in this paper by poonen. Poonen refers to Lemma 20 in a different paper. He claims that the open subset $U_P \subseteq \hat{\mathcal{O}}_P$ can be ...
jb1403's user avatar
  • 1
4 votes
0 answers
155 views

Two other variants of Arhangel'skii's Problem

This question is a follow up to another question of mine, which turned out to be easy (for background on Arhangel'skii's Problem see Arhangel'skii's problem revisited). Recall that a space is ...
Santi Spadaro's user avatar
14 votes
1 answer
581 views

How “disconnected” can a continuum be?

A continuum is a compact connected metrizable topological space. Given a cardinal $\kappa$, a topological space $X$ is called $\kappa$-connected if it is not possible to write $X$ as the disjoint ...
Alessandro Codenotti's user avatar
8 votes
2 answers
362 views

Is every contractible homogeneous space of a connected Lie group homeomorphic to a Euclidean space?

Problem. Let $G$ be a connected Lie group and $H$ is a closed subgroup of $G$ such that the homogeneous space $G/H$ is contractible. Is $G/H$ homeomorphic to a Euclidean space $\mathbb R^n$ for some $...
Taras Banakh's user avatar
2 votes
1 answer
171 views

Is the collapse of a totally disconnected compact Hausdorff space still totally disconnected?

Let $S$ be a totally disconnected compact Hausdorff space and let $A\subset S$ be a closed subset. Let $S/A$ denote the space we get when collapsing $A$ to a point. Is this space still totally ...
user avatar
0 votes
1 answer
109 views

Extending maps from a discrete set to a Stone-Čech compactification while retaining an injectivity condition

For $S$ a set, let $\beta_{\bf2}(S)$ be a compact, totally disconnected space containing $S$ where $S$ in the subspace topology is discrete and $S$ is a dense subspace, and $\beta_{\bf2}(S)$ has the ...
Tri's user avatar
  • 1,644
3 votes
2 answers
257 views

Cancelable commutative monoids with finite maximal subgroups

Suppose $\mathcal{M} = (M, +, 0)$ is a cancelable commutative monoid. Let $G$ be the maximal subgroup of $M$, i.e. $$G = \{ a \in M \colon (\exists b \in M)\, a + b = 0 \}.$$ For $a, b \in M$ say $a \...
Nate Ackerman's user avatar
18 votes
0 answers
1k views

"Next steps" after TQFT?

(Disclaimer: I'm rather nervous that this isn't appropriate for MathOverflow, but given the contents of my question I don't really know a better place to ask something like this.) Recently, I've been ...
Nicholas James's user avatar
0 votes
0 answers
117 views

Example of a metrizable space that is not an ANR

I have been looking for an example of a metrizable space that is not an absolute neighborhood retract (ANR). Recall that a metrizable space $X$ is called an ANR if there exists an open set $U$ in a ...
Katrina's user avatar
  • 506
7 votes
1 answer
501 views

Non-homeomorphic connected one-dimensional Hausdorff spaces that have continuous bijections between them in both sides

I need to construct an example of two non-homeomorphic connected one-dimensional Hausdorff spaces that have continuous bijections between them in both sides. Spaces should have induced ("good&...
jkjfgk's user avatar
  • 73
9 votes
1 answer
734 views

Does the category of locally compact Hausdorff spaces with proper maps have products?

nlab presents a proof that the category of locally compact Hausdorff spaces does not admit infinite products in general. In particular it shows that there is no infinite product of $\mathbb{R}$, since ...
Oddly Asymmetric's user avatar
4 votes
1 answer
182 views

Given $f$ from the cylinder $C$ to the interval constant on one boundary, is there a $r:C\to C$ constant on a boundary with $f\circ r = f$?

My question might be trivial, but my lack of knowledge of this particular subject has not enabled me to find the answer. What I want to know is the following. Let $I=[0,1]$ and $C=S^1\times I$ be the ...
Mathieu Baillif's user avatar
0 votes
0 answers
303 views

Proof that a first integral is not a constant function

Let $U$ be an (open) set in $\mathbb{R}^n$. And we are given a set of $m$ basis functions $$B=\{\psi_i(x): U \rightarrow \mathbb{R}\mid i=1,\ldots,m \}$$ such that all of them are differentiable and ...
NicAG's user avatar
  • 247
19 votes
2 answers
804 views

Existence of a *really* nice topology on the powerset of a topological space

TL;DR. Given a topological space $X$, is there a natural way to "induce" a topology on $\mathcal{P}(X)$ from the topology of $X$ in such a way that 1) all the basic operations of set theory (...
Emily's user avatar
  • 11.8k
1 vote
1 answer
72 views

Is this notion of being "fully" convex closed under set addition?

While reading through "Linear Operators: General theory" by "Jacob T. Schwartz", reading the corollary to II.10.1 which states that for a compact convex subset $C$ of some ...
P. Quinton's user avatar
4 votes
2 answers
156 views

Does there exist a non-hemicompact regular space for which the 2nd player in the $K$-Rothberger game has a winning Markov strategy?

Assume spaces are regular. A space is $\sigma$-compact if and only if the second player in the Menger game has a winning Markov strategy (relying on only the most recent move of the opponent and the ...
Steven Clontz's user avatar
16 votes
1 answer
481 views

Where can I learn more about the topology on $\mathbb{R}$ induced by the map $\mathbb{R} \to \prod_{a>0} (\mathbb{R}/a\mathbb{Z})$?

Consider the (continuous, injective, abelian group homomorphism) map $\Phi \colon \mathbb{R} \to \prod_{a>0} (\mathbb{R}/a\mathbb{Z})$ (where the target is given the product topology) taking $x\in \...
Gro-Tsen's user avatar
  • 32.5k
3 votes
0 answers
200 views

Contractibility of the pseudo-boundary of the Hilbert cube

Let the separable Hilbert cube $Q=\prod_{i=1}^{+\infty}[0,1]$ embed into the real Hilbert space $H=l^2(\mathbb{Z}^+)$, whose coordinate unit vectors are $\{ e_i \}_{i=1}^{+\infty}$, as the subset $\...
Zerox's user avatar
  • 1,543
5 votes
2 answers
223 views

Continuous functions on $[0,1]^\omega$ and a product lower bound

I have a concrete question about continuous functions on $X = [0,1]^\omega$ (with the product topology). The map $f:X\to [0, 1]$ given by $(x_i)\mapsto \prod x_i$ is well-defined and Borel but not ...
dnkywin's user avatar
  • 53
5 votes
1 answer
288 views

Extreme amenability of topological groups and invariant means

Recently I'm reading the paper Ramsey–Milman phenomenon, Urysohn metric spaces, and extremely amenable groups by Pestov. When it comes to the definition of an extremely amenable topological group, it ...
Muduri's user avatar
  • 225
8 votes
1 answer
181 views

Stone-topological/profinite equivalence for quandles

A quandle $(Q,\triangleleft,\triangleleft^{-1})$ is a set $Q$ with two binary operations $\triangleleft,\triangleleft^{-1}:Q\times Q\to Q$ such that the following hold for all $x,y,z\in Q$: (Q1) ...
Alex Byard's user avatar
76 votes
9 answers
15k views

understanding Steenrod squares

There is a function on $\mathbb{Z}/2\mathbb{Z}$-cohomology called Steenrod squaring: $Sq^i:H^k(X,\mathbb{Z}/2\mathbb{Z}) \to H^{k+i}(X,\mathbb{Z}/2\mathbb{Z})$. (Coefficient group suppressed from ...
Aaron Mazel-Gee's user avatar
3 votes
2 answers
2k views

Can every real function be approximated with a Riemann-integrable one with any precision required?

Is there some proof that Riemann-integrable functions are dense in the space of all real functions? In a sense that for every real function $f$ and number $\varepsilon>0$, there is Riemann-...
user479568's user avatar
2 votes
0 answers
123 views

Homotopy type of a 3-manifold produced via Dehn surgery?

My apologizes if this is a fairly elementary question, I am still a novice when it comes to 3-manifold topology. I am wondering the following: by Kirby calculus, we know that two links (say in $S^{3}$ ...
Elliot's user avatar
  • 295
2 votes
1 answer
155 views

Variation of concept of a Lusin space

Citing from Wikipedia, A Hausdorff topological space is a Lusin space if some stronger topology makes it into a Polish space. Is there a (previously studied) analogous concept of a Hausdorff (...
iolo's user avatar
  • 651
3 votes
1 answer
157 views

Embedding of half open half closed $n$-set in $n$-space

Let $n\geq 2$. Set $\Sigma= \{x\in \mathbb{R}^n: 1\leq |x|<2\}$. Assume $h:\Sigma \rightarrow \mathbb{R}^n$ is continuous and injective. Question: Must $h$ also be an embedding? Some thoughts: $h|...
monoidaltransform's user avatar
7 votes
1 answer
183 views

Is lambda calculus polymorphism a type of generalized monad?

Let $\mathbf{C}$ be a Cartesian closed category. Then simply typed lambda calculus in $\mathbf{C}$ in one type variable can be interpreted as a category $\mathbf{STLC}_{\mathbf C}$ where the objects ...
Johan Thiborg-Ericson's user avatar
10 votes
1 answer
460 views

An incomplete characterisation of the Euclidean line?

We say that a metric space $(X, d)$ is a Banakh space if for every $\rho \in \mathbb{R}_{> 0}$ and every $x \in X$, there are $a,b \in X$ such that $\{y \in X \, \vert \, d(x, y) = \rho\} = \{a, b\}...
Luc Guyot's user avatar
  • 7,893
1 vote
1 answer
119 views

Extremally disconnected rigid infinite Hausdorff compacta(?)

Question: does there exist an extremally disconnected infinite Hausdorff compact space $\ X\ $ such that the only homeomorphism $\ h: X\to X\ $ is the identity homeomorphism $\ h=\mathbb I_X:\ X\to X\...
Wlod AA's user avatar
  • 4,786
0 votes
0 answers
161 views

Gluing faces of n-cube

Assuming $C_n$ be the $n$-cube, the intersection of $C_n$ with a supporting hyperplane $H(P, v)$ is called a face or more precisely a $d$-face if the dimension is $d$. Let $f_0$ and $f_1$ be faces ...
mahu's user avatar
  • 53
6 votes
1 answer
393 views

Algebra generated by transformation matrices

Let $T_n$ be the full transformation monoid of an $n$-set $N_n$ with elements 1,...,n consisting of all functions $f: N_n \rightarrow N_n$. We can associate to each function $f$ a matrix $M_f$ in the ...
Mare's user avatar
  • 26.5k
2 votes
0 answers
103 views

Unordered configuration space with non-distinct points

Consider a topological space $X$, a natural number $n>0$ and the quotient topological space $Q_n(X)$ of $X^n$ by the equivalence relation : $x\sim y$ if and only if there is a permutation $\sigma$ ...
Phil-W's user avatar
  • 1,035
6 votes
0 answers
182 views

Conditions for metrisability

If a normal, first countable space is the union of countably many open metrisable subspaces, must that space be metrisable? Partial answers, which I proved in the 1980's, include: (0) The answer is ...
Mike Reed's user avatar
5 votes
0 answers
131 views

Is the opposite of the category of $\kappa$-Lindelöf Hausdorff spaces locally presentable?

Gelfand duality tells us that the category of compact Hausdorff spaces (with continuous maps as morphisms) is contravariantly equivalent to the category of commutative, unital $C^\ast$-algebras (with $...
Tim Campion's user avatar
5 votes
2 answers
202 views

Polish space isometric to its hyperspace

For a Polish space $(X,d)$ its hyperspace $(K(X),d_H)$ is also a Polish space. (Here $K(X)$ denotes the set of all nonempty compact subsets of $X$, and the Hausdorff metric $d_H$ is defined by $d_H(K,...
chj's user avatar
  • 157
2 votes
0 answers
92 views

Explicit CW-complex replacement of the space of reparametrization maps

Let $P$ be the space of nondecreasing surjective maps from $[0,1]$ to itself equipped with the compact-open topology: $P$ is contractible. There exists a trivial fibration $P^{cof} \to P$ from a CW-...
Philippe Gaucher's user avatar
21 votes
7 answers
1k views

Reference for topological graph theory (research / problem-oriented)

I would be interested in recommendations for topological graph theory texts. I think Gross and Yellen has a great chapter on topological graph theory, and I find Mohar and Thomassen's Graphs on ...
12 votes
1 answer
635 views

Ultrafilter subtraction and "zero"

This is related to a couple recent MO/MSE questions of mine, namely 1,2. Belatedly, I've tweaked this post to remove an overly-ambitious secondary question; see the edit history if interested. Let $\...
Noah Schweber's user avatar
107 votes
9 answers
36k views

solving $f(f(x))=g(x)$

This question is of course inspired by the question How to solve f(f(x))=cosx and Joel David Hamkins' answer, which somehow gives a formal trick for solving equations of the form $f(f(x))=g(x)$ on a ...
Kevin Buzzard's user avatar
6 votes
2 answers
830 views

Do all homogeneous spaces have homogeneous compactifications?

Let $X$ be a separable metric space which is homogeneous, i.e. for every two points $x,y\in X$ there is a homeomorphism $h$ of $X$ onto itself such that $h(x)=y$. A compactification of $X$ is a ...
D.S. Lipham's user avatar
  • 3,317
3 votes
1 answer
228 views

Computing the Heyting operation on the frame of nuclei

(The following definitions are meant to be standard and are reproduced for completeness of the question.) A frame is a partially ordered set in which every finite subset has a greatest lower bound (“...
Gro-Tsen's user avatar
  • 32.5k
19 votes
3 answers
1k views

Is there a Cantor set $C$ in $\mathbb{R}^{2}$ so the graph of every continuous function $[0,1]\rightarrow [0,1]$ intersects $C$?

Consider the Cantor ternary set on the real line with the usual topology and define a Cantor set to be any topological space $C$ homeomorphic to the Cantor ternary set. The idea is to construct a ...
Victor's user avatar
  • 2,136
1 vote
1 answer
732 views

Notations for open and closed sets

I am wondering why a standard notation for open sets is $G$ and that for closed sets is $F$. I mean, $F$ precedes $G$ in the alphabet, whereas open sets are usually introduced before closed ones.
Iosif Pinelis's user avatar
105 votes
5 answers
16k views

Independent evidence for the classification of topological 4-manifolds?

Is there any evidence for the classification of topological 4-manifolds, aside from Freedman's 1982 paper "The topology of four-dimensional manifolds", Journal of Differential Geometry 17(3) 357–453? ...
Brendan Guilfoyle's user avatar
4 votes
1 answer
169 views

Stone–Čech compactification and an ultrafilter of regular closed sets

$\DeclareMathOperator\cl{cl}\DeclareMathOperator\int{int}$A subset $A$ of a topological space $X$ is called regular closed if $A=\cl _{X}\int_{X}A$. The family of all regular closed sets of a ...
Mehmet Onat's user avatar
  • 1,367
7 votes
3 answers
356 views

Hausdorff quasi-Polish spaces

A topological space is said to be quasi-Polish if it is second-countable and completely quasi-metrizable (see for an introduction de Brecht's article: de Brecht, Matthew, Quasi-Polish spaces, Ann. ...
Lorenzo's user avatar
  • 2,286
7 votes
1 answer
262 views

Can you remove a zero dimensional subspace from a cube and obtain a planar space?

The question, which came up in a conversation with my advisor Ola Kwiatkowska, is pretty much in the title: Let $Z\subseteq[0,1]^3$ be zero-dimensional. Is it possible for $[0,1]^3\setminus Z$ to be ...
Alessandro Codenotti's user avatar

1
7 8
9
10 11
104