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Questions tagged [lie-groups]

Lie Groups are Groups that are additionally smooth manifolds such that the multiplication and the inverse maps are smooth.

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A question from the paper "Hyperbolic rigidity of higher rank lattices" by Thomas Haettel

In the paper "Hyperbolic rigidity of higher rank lattices" by Thomas Haettel, the author has made the following statement in the proof of Corollary D in page no. 18 ( https://arxiv.org/pdf/...
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Equivariant classifying space and manifold models

The classifying space $BS^1$ for $S^1$-bundles can be taken to be the colimit of $\mathbb{CP}^n$ which are smooth manifolds and the inclusions $\mathbb{CP}^n \hookrightarrow \mathbb{CP}^{n+1}$ are ...
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Topological vector spaces in direct sum

A year ago, I asked this question here at Mathematics Stackexchange, but no one there managed to answer it. So I am elevating it to MathOverflow. This question had emerged as an offshoot of a bigger ...
Michael_1812's user avatar
4 votes
1 answer
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The Hausdorff codimension of singular matrices vs. the Hausdorff codimension of points with divergent trajectories

Let $G:=SL(m+n,\mathbb R)$ and $\Gamma :=SL(m+n,\mathbb Z)$ and $X:=G/\Gamma$. (1) Let $M$ denote the set of all $m \times n$ matrices with real entries. A matrix $A \in M$ is called $\textit{singular}...
No One's user avatar
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2 votes
2 answers
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Particular reduced expression of the longest element of Weyl group

Let $I$ be the Dynkin diagram vertex set and $K$ be a proper nonempty subset of it. Let $w_0^K$ be the longest word of the Dynkin subdiagram $K$, which might be a disjoint union of connected Dynkin ...
F.H.A's user avatar
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7 votes
1 answer
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When a free action gives rise to a $G$-principal bundle

When a free action gives rise to a $G$-principal bundle Let a (topological) group $G$ act freely on a (topological) space $X$. Assume that $G \backslash X$ is Hausdorff. (equivalently the image of ...
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6 votes
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Finite simple groups and $ \operatorname{SU}_n $

A follow-up question to Alternating subgroups of $\mathrm{SU}_n $. $\DeclareMathOperator\PU{PU}\DeclareMathOperator\PSU{PSU}\DeclareMathOperator\PSL{PSL}$Let $ \PU_m $ be the projective unitary group, ...
Ian Gershon Teixeira's user avatar
6 votes
1 answer
357 views

How to distinguish conjugacy classes in SO(2n) efficiently?

In a compact connected Lie group $G$, each element is conjugate to an element of a maximal torus $T$. For a classical group, one can pick a basis of the tautological representation such that $T$ is ...
Andrei Smolensky's user avatar
2 votes
1 answer
357 views

Tensor product of fundamental representations

Let $\mathfrak{g}$ be a simple complex Lie algebra. Let $V_1,\cdots, V_n$ be the fundamental representations (the irreducible ones with fundamental weights $\omega_1,\cdots,\omega_n$). Take a $k$-...
Jun Yang's user avatar
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Non-recurrent points of $F(a,b)=(b,ba)$ in a compact metric group $G$

Consider a compact metric group $G$ [A compact topological group $G$ where the topology is generated by an invariant metric]. I am particularly interested in the case where $G$ is the $n$-dimensional ...
Saúl Pilatowsky-Cameo's user avatar
2 votes
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Representation determined by traces

A discrete, faithful representation of a surface group $G:\pi_1(S_g) \to PSL_2(\mathbb{R})$ is determined, up to conjugacy by $PGL_2(\mathbb R)$, among such representations by the squares of traces of ...
RegularGraph's user avatar
5 votes
1 answer
252 views

Does a compact Lie group action on a family of compact manifolds have diffeomorphic fixed point submanifolds?

Let $\pi: M\to B$ be a fiber bundle of smooth manifolds with $B$ connected and each fiber of $\pi$ is a compact manifold. Let $G$ be a compact Lie group acting smoothly on $M$ such that $\pi(g\cdot m)=...
Zhaoting Wei's user avatar
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Finite subgroups of $\operatorname{U}(2)$

Famously, the finite subgroups of $\operatorname{SU}(2)$ admit an ADE classification. Question. Is there a similar result for finite subgroups of $\operatorname{U}(2)$? Are they classified? If this ...
Federico Carta's user avatar
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1 answer
248 views

What is the Molien series of the SO(2)-invariant ring on the plane (sometimes written C[X]^{SO(2)} )?

Let SO(2) be the group of rotations in the plane. What is the Molien series (sometimes called the Hilbert-Poincare series) of the SO(2)-invariant ring of polynomials? N.B. The main goal being to ...
Victoria's user avatar
4 votes
1 answer
132 views

Equivalence between the existence of a nonempty open set of elliptic elements and a compact Cartan subgroup

In Goldman's book on Complex Hyperbolic Geometry, on page 203, it is stated that for a real semisimple Lie group $G$, the following are equivalent: $G$ contains a nonempty open subset of elliptic ...
Arnaud Maret's user avatar
1 vote
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K-finiteness of unitary representations of Poincaré-like groups?

$\DeclareMathOperator\SO{SO}\DeclareMathOperator\ISO{ISO}$I'd like to know if there are any papers that study the following problems: Determine when decomposing the unitary irreps of $\ISO(d,1)$ into ...
Lacia's user avatar
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0 answers
217 views

Almost conjugate subgroups of compact simple Lie groups

$\DeclareMathOperator\SU{SU}\DeclareMathOperator\Sp{Sp}\DeclareMathOperator\SO{SO}$Let $G$ be a compact connected Lie group. Definition: Two finite subgroups $H_1,H_2$ of $G$ are said to be almost ...
emiliocba's user avatar
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7 votes
1 answer
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On fixed point sets of actions of compact Lie groups

Let a compact Lie group $G$ act smoothly on a compact smooth manifold $M$. For any compact subgroup $H\subset G$ denote by $E^H$ the image in $M/G$ of the fixed point set of $H$ in $M$. Is it true ...
asv's user avatar
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1 vote
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Centralizer of an element in a matrix Lie group whose Jordan form is given

$\DeclareMathOperator\GL{GL}\DeclareMathOperator\SO{SO}\DeclareMathOperator\Sp{Sp}\DeclareMathOperator\ad{ad}\DeclareMathOperator\Ad{Ad}$Let $G\subset \GL_n(\mathbb{C})$ be a complex matrix Lie group, ...
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0 answers
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Questions on the differential of the Lie logarithm

Let $G$ be a Lie group. Recall the Lie logarithm is well-defined about a neighborhood $U \subset G$ of the identity: $\log:U\to \mathfrak{g}$. I am dealing with a research problem that concerns the ...
Spencer Kraisler's user avatar
2 votes
1 answer
285 views

Question about maximal compact subgroups of Lie groups

Let $G$ be a compact (connected) semisimple Lie group. Let $G_\mathbb{C}$ be the complexification of $G$. Is $G$ a maximal compact subgroup of $G_\mathbb{C}$?
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Splitting of the conformal group into $PSL(2,\mathbb{R})$ and other factorizations

In 1+1 dimensions of Minkowski spacetime, the conformal group can be split into two copies of $PSL(2,\mathbb{R})$ acting on null lines. I'm curious to know if a similar split exists for the conformal ...
Gabriel Palau's user avatar
2 votes
2 answers
519 views

How to use that the Hessian is negative definite in this proof

Let $X$ be a Riemannian compact manifold on which acts a compact Lie group $H^+$. Let $f^+ : X \rightarrow \mathbb{R} $ be a smooth function on $X$. Consider a Lie subgroup $U$ of $H^+$ and suppose ...
Mira's user avatar
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2 votes
0 answers
143 views

Non-uniform lattices and parabolic subgroups in Lie groups

Let $G$ be a semisimple connected Lie group and let $\Lambda < G$ be a non-uniform irreducible lattice. How does it follows that there exists a minimal parabolic subgroup $P$ of $G$ such that the ...
Constantin K's user avatar
9 votes
6 answers
3k views

Motivation for construction of associated fiber bundle from a principal bundle

Given a principal $G$ bundle $P(M,G)$ and a manifold $F$ with an action of $G$ on it from left, we construct a fiber bundle over $M$ with fiber $F$ and call this the associated fiber bundle for $P(M,G)...
Praphulla Koushik's user avatar
4 votes
1 answer
240 views

Bounded generation of group by unipotent radicals of opposite parabolic subgroups

Let $G$ be an almost $k$-simple group that is also simply connected (so that $G(k)^{+}=G(k)$). For opposite parabolic subgroups $P$ and $P^{-}$, it is known that $G(k)^{+}$ is generated by the ...
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Exterior square of $\operatorname{Sp}(4,\mathbb{C})$ is isomorphic to $\operatorname{SO}(5,\mathbb{C})$

I am studying exceptional isomorphisms recently, which arise due to the coincidence in Dynkin diagram. I saw two forms of expressing the exceptional isomorphisms, one is isomorphisms between the spin ...
mhahthhh's user avatar
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2 votes
1 answer
325 views

Orbit space of $\mathrm{SO}(3)$ irreducible representations

$\DeclareMathOperator\SO{SO}$Consider the $7$-dimensional $\mathbb R^7$ real irreducible orthogonal representation of $\SO(3)$. I am seeking a description of the orbit space (when the action is ...
miniii's user avatar
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1 answer
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What are some interesting examples of quotients by Lie group actions?

I’ve been going through Lee’s Introduction to Differential Geometry. It’s a great book but I feel it lacks examples and concrete applications of the ideas presented. I want to work out a list of ...
11 votes
3 answers
587 views

Is every $A \in \mathrm{SL}_n(\mathbb C)$ a product of four unipotent matrices?

Is every matrix $A \in \mathrm{SL}_n(\mathbb C)$ a product of four unipotent matrices? I have verified that this is true if $n = 2$, and I believe I have came across this result before. However, I ...
S. Pek's user avatar
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1 answer
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Sub-coroot lattices

[This is a sequel to the previous question sub-coroot systems, that has been answered! :-) ] Let $T$ be a maximal torus of a compact Lie group $K$, and let $\Lambda \subset {\mathfrak t}$ be the ...
bernardorim's user avatar
13 votes
1 answer
398 views

Mathematical explanation of orbital shell sizes: why is it sufficient to consider single-electron wave functions?

Motivation The question "Is there a good mathematical explanation for why orbital lengths in the periodic table are perfect squares doubled?" asks for an explanation of the sequence 2, 8, 8, ...
Dan Romik's user avatar
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6 votes
2 answers
380 views

Rank one adjoint operators on a Lie algebra

Let $\mathfrak{g}$ be a (finite dimensional) semi-simple Lie algebra over a field $k$ and let $x \in \mathfrak{g}$. By definition, we have the equivalence: $$ \mathrm{rk}(\mathrm{ad}_x) = 0 \iff x = 0,...
Libli's user avatar
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14 votes
1 answer
360 views

Description of the generalized grassmannians and flag varieties (parabolic quotients) associated to the exceptional groups

If $G$ is a classical semisimple algebraic/Lie group over an algebraically closed field (maybe just say $\mathbb{C}$), viꝫ. $\mathit{SL}_n$, $\mathit{SO}_n$, $\mathit{Sp}_n$ (isogenies irrelevant here)...
Gro-Tsen's user avatar
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17 votes
4 answers
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Reference request: Grassmannian and Plucker coordinates in type B, C, D

Grassmannian $Gr(k,n)$ is the set of $k$-dimensional subspace of an $n$-dimensional vector space. What are the Grassmannian in types B, C, D? What are the analog of Plucker coordinates and Plucker ...
Jianrong Li's user avatar
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2 votes
0 answers
105 views

Embeddings of symplectic group into the orthogonal group

Let $\mathfrak{sp}$ denote the complex symplectic Lie algebra and $\mathfrak{so}$ the complex orthogonal one. Do we have an embedding $$ \mathfrak{sp}_{2n-2} \hookrightarrow \mathfrak{so}_{2n}? $$ In ...
Dr. Evil's user avatar
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4 votes
2 answers
670 views

Conjugacy classes in the automorphism group of a simple Lie algebra

A lower bound of the number of conjugacy classes in the automorphism group of a simple Lie algebra $\mathfrak{s}$, of finite dimension over an arbitrary field $\mathbb{F}$, can be the size of the ...
Youness EL KHARRAF's user avatar
0 votes
1 answer
194 views

Sum of weights of an irreducible representation of $U(N)$

Let $R$ be a finite-dimensional irreducible representation of $U(N)$, with the set of weights $W_R$. Each element of $W_R$ is a vector of length $N$ with integer entries. Firstly, I would like to know ...
Blind Miner's user avatar
4 votes
0 answers
120 views

Why are all "non-swinging" representations self-dual?

Let $\mathfrak{g}$ be a semisimple (say complex) Lie algebra, and $V$ an irreducible finite-dimensional representation of $\mathfrak{g}$. Denote by $w_0$ the longest element of the Weyl group, i.e. ...
Ilia Smilga's user avatar
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15 votes
2 answers
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Why are coroots needed for the classification of reductive groups?

As we know reductive groups up to isomorphism corresponds to root data up to isomorphism. My question is why in the definition of root data do we need the coroots? Let's break it down to two questions:...
Andrew NC's user avatar
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12 votes
3 answers
950 views

Smooth map homotopic to Lie group homomorphism

Let $G$ and $H$ be connected Lie groups. A Lie group homomorphism $\rho:G\to H$ is a smooth map of manifolds which is also a group homomorphism. Question: Can we find a smooth (or real-analytic) map $...
Hang's user avatar
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7 votes
1 answer
387 views

Torsion-free Cartan connections

Let $M$ a differentiable manifold and $H\subset G$ a Lie group with a closed subgroup such that $G/H$ is connected. A $H\subset G$-Cartan connection on $M$ can be defined by A principal $G$-bundle on ...
jpdm's user avatar
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4 votes
0 answers
134 views

Finite subgroups of $\mathrm{SL}_2(\mathbb{O})$

What are the finite subgroups (subloops that are groups) of $\mathrm{SL}_2(\mathbb{O})$? In particular, are there any not contained in a $\mathrm{SL}_2(\mathbb{H})$?
Daniel Sebald's user avatar
2 votes
1 answer
120 views

Ree groups and Moufang octagons

Consider a Ree group of type $^2\mathrm{F}_4$, defined over the field $k$. Tits showed that every Moufang generalized octagon arises as a natural geometric module on which a Ree group of this type ...
THC's user avatar
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22 votes
6 answers
2k views

About the definition of E8, and Rosenfeld's "Geometry of Lie groups"

I've been searching the literature for a direct definition of the group $E_8$ (over a general field, but even a definition of just one incarnation would be great). I knew (from talking to people) that ...
Pierre's user avatar
  • 2,287
31 votes
2 answers
1k views

Is Lie group cohomology determined by restriction to finite subgroups?

Consider the restriction of the group cohomology $H^*(BG,\mathbb{Z})$, where $G$ is a compact Lie group and $BG$ is its classifying space, to finite subgroups $F \le G$. If we consider the product of ...
overcaffeinated's user avatar
19 votes
1 answer
1k views

A result on Lie group actions on 15-dimensional spheres?

In this interview by Eric Weinstein to Roger Penrose, Timestamp 1:24:05., what result is the host talking about? Transcription of the relevant part: "If you have two sets of symmetries, known as ...
Qfwfq's user avatar
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7 votes
2 answers
440 views

Quadratic forms on $\mathbb{R}^{16}$ coming from octonions

$\DeclareMathOperator\RRe{Re}\DeclareMathOperator\Spin{Spin}\DeclareMathOperator\Sym{Sym}$Let $\mathcal{H}_2(\mathbb{O})$ denote the (10-dimensional) real vector space of octonionic Hermitian matrices ...
asv's user avatar
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3 votes
2 answers
649 views

Representations of $\mathrm{SO}_n$ versus representations of $\mathrm{Spin}_n$ [duplicate]

$\DeclareMathOperator\SO{SO}\DeclareMathOperator\Spin{Spin}$Since $\Spin_n$ is a compact simply connected simple Lie group, its irreducible representations are equivalent to the irreducible ...
Martim Pereir's user avatar
7 votes
2 answers
775 views

Why is the generalized flag variety a “variety”?

In several places (for example, Chriss & Ginzburg’s book “Representation Theory and Complex Geometry”), the author says that the set $X$ of Borel subalgebras of a semi-simple Lie algebra $\...
yzchen's user avatar
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