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3 votes
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169 views

Cellular structure of $F_4$

Is there the cellular structure of the Exceptional Lie group $F_4$? Is there a reference to it? Thanks
Sajjad Mohammadi's user avatar
3 votes
0 answers
134 views

When do quotients of $G$-vector bundles exist?

Let's work in the category of smooth (paracompact, Hausdorff) manifolds. Let $M$ be a manifold and $G$ a Lie group acting on $M$. Suppose $E$ is a $G$-vector bundle on $M$ (that is, $G$ acts on $E$ by ...
skwok's user avatar
  • 51
4 votes
1 answer
523 views

Is automorphism on a compact group necessarily homeomorphism? How about N-dimensional torus? [closed]

Is automorphism on a compact group necessarily homeomorphism? I don't think so,but I think it is possible on the N-dimensional torus.
user530909's user avatar
7 votes
0 answers
237 views

Relation beween Chern-Simons and WZW levels, and transgression

3d Chern-Simons gauge theories based on a Lie group $G$ are classified by an element $k_{CS}\in H^4(BG,\mathbb{Z})$, its level. Via the CS/WZW correspondence the theory is related with a 2d non-linear ...
Andrea Antinucci's user avatar
12 votes
1 answer
379 views

Approximate classifying space by boundaryless manifolds?

As pointed out by Achim Krause, any finite CW complex is homotopy equivalent to a manifold with boundary (by embedding into $\mathbb R^n$ and thickening), and so every finite type CW complex can be ...
0207's user avatar
  • 123
5 votes
0 answers
110 views

Are there exotic examples of a Lie group up to coherent isotopy?

This question is based on attempting to construct the (homotopy type) of Lie groups using Cobordism Hypothesis style abstract nonsense. There is an $\infty$-groupoid of smooth, framed manifolds where ...
Charles Wang's user avatar
6 votes
0 answers
121 views

Explicit representatives for Borel cohomology classes of a compact Lie group?

I'm looking for explicit representatives of $H^3_{Borel}(G, R/Z)$, i.e. a measurable function $G^3\to R/Z$ representing a generator of the cohomology group. (Here $G$ is a compact (perhaps simple) ...
Kevin Walker's user avatar
  • 12.8k
4 votes
0 answers
249 views

Homotopy group of maps into S^3 using its Lie group multiplication to define the group operation

The Bruschlinsky group of maps of a space X into S1 up to homotopy, using the multiplication on S1, is well-known to equal the first cohomology group of X (at least assuming X is a reasonably nice ...
Daniel Asimov's user avatar
7 votes
0 answers
194 views

Are the spaces BG for compact connected groups G ind-projective or ind-Kähler?

Let $G$ be a compact connected group, or maybe better its complexification. By thinking about the simplicial Borel space, or using $n$-acyclic $G$-spaces for higher and higher $n$, it's "easy&...
Ben Webster's user avatar
  • 44.7k
1 vote
1 answer
153 views

For topological torus action, there is a subcircle whose fixed point is the same as the torus

Let $T=\mathbb{S}^{1}\times \mathbb{S}^{1}\times \cdots \times \mathbb{S}^{1} $ ($n$ times) be an $n$-dimensional torus acting on any topological space $X$. The group $G$ is said to act on a space $X$ ...
Mehmet Onat's user avatar
  • 1,367
1 vote
0 answers
133 views

A question about fixed point set of the compact group actions

Let $G$ be an infinite compact Lie group acting on a compact space $X$. Denote $F=F(G,X)=\{x\in X$ : $gx=x$ for all $g\in G\}$. Show that if $H^*(B_{G_x};\mathbb{Q})=0$ for all $x \notin F$ and $T^1$ ...
Mehmet Onat's user avatar
  • 1,367
6 votes
1 answer
429 views

Does $\pi_1(H)=0\Rightarrow \pi_3(G/H)=0$ for a simple and simply connected Lie group $G$?

$\DeclareMathOperator\SU{SU}$Let $G$ be a simple and simply-connected Lie group and $H\neq 1$ be a simple and simply connected subgroup, is it true that $\pi_3(G/H)=0$? If not, what is a counter-...
Davi Costa's user avatar
1 vote
1 answer
192 views

Lie group framing and framed bordism

What is the definition of Lie group framing, in simple terms? Is the Lie group framing of spheres a particular type of Lie group framing? (How special is the Lie group framing of spheres differed ...
zeta's user avatar
  • 447
5 votes
1 answer
328 views

Is the inclusion of the maximal torus in a simply connected compact Lie group null-homotopic?

Let $G$ be a simply connected compact Lie group and $T$ its maximal torus with inclusion $i:T \hookrightarrow G$. By simply connectedness of the group $G$ and asphericity of the torus $T$, the induced ...
ms_87h's user avatar
  • 53
5 votes
0 answers
133 views

Division of fibration by $\Sigma_{n}$ gives Serre fibration

This is related to a question posted on StackExchange: https://math.stackexchange.com/questions/4776877/left-divisor-of-a-fibration-by-compact-lie-group-is-a-fibration. The question there had received ...
Jeremy's user avatar
  • 311
4 votes
0 answers
226 views

Is the total space of a $ U_1 $ principal bundle over a compact homogeneous space always itself homogeneous?

Let $ U_1 \to E \to B $ be a $ U_1 $ principal bundle. Suppose that $ B $ is homogenous (admits a transitive action by a Lie group) and compact. Then must it be the case that $ E $, the total space of ...
Ian Gershon Teixeira's user avatar
4 votes
0 answers
425 views

Non-triviality of map $S^{24} \longrightarrow S^{21} \longrightarrow Sp(3)$

Let $\theta$ be the generator of $\pi_{21}(Sp(3))\cong \mathbb{Z}_3$, (localized at 3). How to show the composition $$S^{24}\longrightarrow S^{21}\overset{\theta}\longrightarrow Sp(3)$$ is non-trivial ...
Sajjad Mohammadi's user avatar
4 votes
2 answers
408 views

Classifying space of a non-discrete group and relationship between group homology and topological homology of Lie groups

I have a very soft question which might be very standard in textbooks or literature but I haven't seen it. To a fixed group $G$ we may attach different topologies to make it different topological ...
XYC's user avatar
  • 441
4 votes
0 answers
175 views

Is there any results about the stable (or unstable) cohomology operations on cohomology of Lie groups?

$\DeclareMathOperator\SU{SU}$For the $\mod p$ singular cohomology of classical Lie groups, such as $H^*(\SU(n); \mathbb{Z}/p\mathbb{Z})$, there are well known results about the actions of the stable ...
cyber's user avatar
  • 71
4 votes
1 answer
244 views

Homotopy groups of quotient of SU(n)

Let $X$ be the quotient topological space obtained by identifying the matrices $A$ and $\overline{A}$ in the topological group $\mathrm{SU}(n)$ (here $\overline{A}$ denotes entry-wise complex ...
Quizzical's user avatar
  • 271
3 votes
0 answers
152 views

Equivariant classifying space and manifold models

The classifying space $BS^1$ for $S^1$-bundles can be taken to be the colimit of $\mathbb{CP}^n$ which are smooth manifolds and the inclusions $\mathbb{CP}^n \hookrightarrow \mathbb{CP}^{n+1}$ are ...
UVIR's user avatar
  • 803
4 votes
1 answer
419 views

Faithful locally free circle actions on a torus must be free?

Is it true that every faithful and locally smooth action $S^1 \curvearrowright T^n$ is free? I know such an action must induce an injection $\rho:\pi_1(S^1)\to\pi_1(T^n)$. Another related question is: ...
Chan Ki Fung's user avatar
7 votes
2 answers
539 views

Injectivity of the cohomology map induced by some projection map

Given a (compact) Lie group $G$, persumably disconnected, there exists a short exact sequence $$1\rightarrow G_c\rightarrow G\rightarrow G/G_c\rightarrow 1$$ where $G_c$ is the normal subgroup which ...
Ye Weicheng's user avatar
6 votes
1 answer
555 views

Cobordism cohomology of Lie groups

Are there any results about cobordism cohomology of Lie groups?For example, $\mathrm{MU}^*(\mathrm{SU}(n))$.
wushilp's user avatar
  • 61
4 votes
0 answers
128 views

Real Representation ring of $U(n)$ and the adjoint representation

I have two questions: It is well known that the complex representation ring $R(U(n))=\mathbb{Z}[\lambda_1,\cdots,\lambda_n,\lambda_n^{-1}]$, where $\lambda_1$ is the natural representation of $U(n)$ ...
user avatar
10 votes
0 answers
308 views

Compact Lie groups are rational homotopy equivalent to a product of spheres

According to [1] and [2], it is “well-known” that a compact Lie group $G$ has the same rational homology, and according to [2] is even rational homotopy equivalent, to the product $\mathbb{S}^{2m_1+1} ...
Gro-Tsen's user avatar
  • 32.5k
10 votes
2 answers
696 views

Homotopy properties of Lie groups

Let $G$ be a real connected Lie group. I am interested in its special homotopy properties, which distinguish it from other smooth manifolds For example $G$ is homotopy equivalent to a smooth compact ...
Arshak Aivazian's user avatar
6 votes
1 answer
644 views

Torus bundles and compact solvmanifolds

I asked this question on MSE 9 days ago and it got a very helpful comment from Eric Towers providing the Palais Stewart reference, but no answers. So I'm crossposting it here. Let $$ T^n \to M \to T^m ...
Ian Gershon Teixeira's user avatar
5 votes
0 answers
132 views

geometry and connected sum of aspherical closed manifolds

Let $ G $ be a Lie group with finitely many connected components, $ K $ a maximal compact subgroup, and $ \Gamma $ a torsion free cocompact lattice. Then $$ \Gamma \backslash G/K $$ is an aspherical ...
Ian Gershon Teixeira's user avatar
9 votes
1 answer
444 views

Compact flat orientable 3 manifolds and mapping tori

There are 10 compact flat 3 manifolds up to diffeomorphism, 6 orientable and 4 non orientable. I am looking to better understand how to construct the orientable ones. The six orientable ones are ...
Ian Gershon Teixeira's user avatar
21 votes
1 answer
837 views

What is the homotopy type of the poset of nontrivial decompositions of $\mathbf{R}^n$?

Consider the following partial order. The objects are unordered tuples $\{V_1,\ldots,V_m\}$, where each $V_i \subseteq \mathbf{R}^n$ is a nontrivial linear subspace and $V_1 \oplus \cdots \oplus V_m =...
Inna's user avatar
  • 1,025
2 votes
1 answer
484 views

Mapping torus of orientation reversing isometry of the sphere

$\DeclareMathOperator\SL{SL}\DeclareMathOperator\SO{SO}\DeclareMathOperator\SU{SU}\DeclareMathOperator\O{O}\DeclareMathOperator\Iso{Iso}$ Let $ f_n $ be an orientation reversing isometry of the round ...
Ian Gershon Teixeira's user avatar
3 votes
0 answers
164 views

Equivalent condition for compact group to act transitively

Let $ M $ be a connected manifold. Let $ \pi_1(M) $ be the fundamental group of $ M $. Suppose there exists a compact group $ K $ that acts transitively on $ M $. Then $ \pi_1(M) $ must have a finite ...
Ian Gershon Teixeira's user avatar
11 votes
1 answer
455 views

Asking whether there is a compact Lie group containing affine symplectic group

The affine symplectic group is interesting and important in physics. However, the Lie group is noncompact. In order to have some good properties (Basically, we need some good behavior of Haar measure) ...
En-Jui Kuo's user avatar
3 votes
0 answers
238 views

CW structure on $\mathrm{PU}(3)$/Heisenberg group

$\DeclareMathOperator\SU{SU}\DeclareMathOperator\PU{PU}$Consider the quotient space $\PU(3)/H=\SU(3)/G_{81}$ where $H$ is the Heisenberg group of order 27 $G_{81}$ is the No. 9 group of order 81 (...
wonderich's user avatar
  • 10.5k
4 votes
0 answers
320 views

Finite subgroup of $\mathrm{SO}(4)$ which acts freely on $\mathbb{S}^3$

Let $\Gamma$ be a finite subgroup of $\mathrm{SO}(4)$ acting freely on $\mathbb{S}^3$. It is known that all such $\Gamma$ can be classified. Is there any characterization of $\Gamma$ such that $\Gamma$...
Adterram's user avatar
  • 1,441
1 vote
0 answers
138 views

Automorphism group of indefinite orthogonal Lie group $G=O(p,q)$ vs that of a double covering group $\tilde{G}$

Previously I mentioned in Automorphism group of a Lie group $G$ vs that of a double covering group $\tilde{G}$: same or not? that the automorphism group of a Lie group 𝐺 may be the same as that of ...
wonderich's user avatar
  • 10.5k
0 votes
0 answers
88 views

Automorphism group of a Lie group $G$ vs that of a double covering group $\tilde{G}$: same or not? [duplicate]

Previously there are some counterexamples given in Automorphism group of a Lie group $G$ vs that of a covering group $\tilde G$: same or not? such that the automorphism group of a Lie group 𝐺 is not ...
wonderich's user avatar
  • 10.5k
2 votes
0 answers
165 views

Automorphism group of a Lie group $G$ vs that of a covering group $\tilde G$: same or not?

Is it true or false that the Inner (Inn), Outer (Out) and Total (Aut) Automorphism of a Lie group $G$ is the same as the covering group of the Lie group, say $\tilde G$ (regardless of how many types ...
wonderich's user avatar
  • 10.5k
5 votes
0 answers
199 views

Outer and inner automorphism of $\mathrm{Pin}$ groups

$\DeclareMathOperator\Inn{Inn}\DeclareMathOperator\Aut{Aut}\DeclareMathOperator\Out{Out}\DeclareMathOperator\Pin{Pin}\DeclareMathOperator\Spin{Spin}\DeclareMathOperator\SO{SO}\DeclareMathOperator\PSO{...
Марина Marina S's user avatar
6 votes
0 answers
159 views

Cohomology of $\mathrm{BPSO}(2d)$ with $Z_2$ coefficients

$\DeclareMathOperator\BPSO{BPSO}\DeclareMathOperator\PSO{PSO}\DeclareMathOperator\SO{SO}\DeclareMathOperator\BSO{BSO}$The projective group is $\PSO(2d)=\SO(2d)/Z_2$. $\BPSO(2d)$ is the classifying ...
user34104's user avatar
  • 487
4 votes
1 answer
304 views

Atiyah-Bott-Shapiro generalization to $U(n) \to ({Spin(2n) \times U(1)})/{\mathbf{Z}/4}$ for $n=2k+1$

Atiyah, Bott, and Shapiro paper on Clifford Modules around page 10 shows two facts. 1 - There is a lift $U(n) \to Spin^c(2n)$ from $U(n) \to SO(2n)\times U(1)$. Also an embedding (injective group ...
Марина Marina S's user avatar
14 votes
1 answer
340 views

On the homological dimension of a Borel construction

Let $M$ b a closed connected smooth manifold with fundamental group $\Gamma$. Suppose $G$ is a simply-connected Lie group that acts smoothly on $M$. Then the Borel construction $$M//G = M \times_G EG$$...
Jens Reinhold's user avatar
4 votes
0 answers
181 views

Specify the embedding of special unitary group in a Spin group via their representation map

How do we specify the embedding of a Lie group $G_1$ as a subgroup into a larger Lie group $G_2$, with $G_1 \subset G_2$ that agree with a constraint on the mapping between their representations? By ...
wonderich's user avatar
  • 10.5k
5 votes
0 answers
135 views

Specify the embedding of Lie groups (via the representation map) precisely as the embedding of two differentiable manifolds

How do we specify the embedding of a Lie group $G_1$ as a subgroup into a larger Lie group $G_2$, with $G_1 \subset G_2$ that agree with a constraint on the mapping between their representations? By ...
wonderich's user avatar
  • 10.5k
8 votes
1 answer
256 views

The "canonical fibration" for the Lie group $G_2$

$\DeclareMathOperator\SO{SO}$At the very begining of Akbulut and Kalafat - Algebraic topology of $G_2$ manifolds, the authors stated that there is a "canonical fibration" for $G_2$ of the ...
Xing Gu's user avatar
  • 935
1 vote
1 answer
156 views

Necessary and sufficient conditions for the Lie group embedding $G \supset J$ can be lifted to $G$'s covering space [closed]

Suppose the Lie group $G$ contains the Lie group $J$ as a subgroup, so $$ G \supset J. $$ If $G$ has a nontrivial first homotopy group $\pi_1(G) \neq 0$. If $G$ has a universal cover $\widetilde{G}$, ...
Марина Marina S's user avatar
0 votes
1 answer
254 views

$SU(k)/SO(k)$ as a manifold, for each positive integer $k$ [closed]

The quotient space $SU(k)/SO(k)$ is also a homogeneous space constructed out of the Lie groups (special unitary $SU(k)$ and special orthogonal $SO(k)$). Because the $SO(k)$ may not be a normal ...
Марина Marina S's user avatar
9 votes
1 answer
398 views

Homotopically equivalent compact Lie groups are diffeomorphic

I have the following conjecture: Two homotopically equivalent compact Lie groups will be diffeomorphic. It may be necessary to restrict ourselves to only semisimple Lie groups. For simply connected ...
Vladimir Gorbatsevich's user avatar
5 votes
1 answer
372 views

$\pi_{2n-1}(\operatorname{SO}(2n))$ element represents the tangent bundle $TS^{2n}$, not torsion and indivisible for $n>1$?

Question: Is the element $\alpha$ in $\pi_{2n-1}(\operatorname{SO}(2n))$ representing the tangent bundle $TS^{2n}$ of the sphere $S^{2n}$ indivisible and not torsion? My understanding so far — An $\...
wonderich's user avatar
  • 10.5k

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