Skip to main content

Questions tagged [gr.group-theory]

Questions about the branch of algebra that deals with groups.

Filter by
Sorted by
Tagged with
4 votes
1 answer
524 views

What is the outer automorphism group of the Lie group $\text{SL}_2(\mathbb{R})$ as an abstract group?

I hope to ask what the outer automorphism group of the Lie group $\text{SL}_2(\mathbb{R})$ is, just as an abstract group. It seems like Dieudonné's paper On the automorphisms of the classical groups ...
XYSquared's user avatar
  • 175
4 votes
2 answers
504 views

Unique product group which is not right orderable

(1) I am looking for an example of a u.p (unique product) group which is not right orderable (RO). Almost any group I pick up (obviously torsion-free, as u.p. group cannot have nontrivial torsion ...
Bhaskar Vashishth's user avatar
4 votes
0 answers
199 views

Generalization of the fundamental theorem of cyclic groups 2

This post is a sequel of Generalization of the fundamental theorem of cyclic groups Let $G$ be a finite group then the fundamental theorem of cyclic groups can be formulated as follows: Theorem: $G$ ...
Sebastien Palcoux's user avatar
4 votes
3 answers
376 views

Proof that lifts of geodesics are quasi-geodesics (relatively hyperbolic groups)

$\DeclareMathOperator\Cay{Cay}$Suppose $G$ is a relatively hyperbolic group with peripheral subgroups $P_1,P_2,\dots, P_n$, and suppose $\mathcal{S}$ is a finite generating set for $G$. Let $X=\Cay(G,\...
luthien's user avatar
  • 421
4 votes
1 answer
195 views

Finite p-groups and their fibered products

Is every finite $p$-group an epimorphic image of a fibered product of two finite $p$-groups which can be generated by $2$ elements?
Pablo's user avatar
  • 11.3k
4 votes
1 answer
204 views

Totally right preorderable groups

Are there any known non-trivial sufficient conditions, or full characterizations, of a totally right-preorderable group? More precisely: totally right-preorderable: has a non-trivial total right-...
Alexander Pruss's user avatar
4 votes
5 answers
1k views

Groups of order $p(p^2+1)/2$

It seems that when $p>3$ is a prime, then each group of order $p(p^2+1)/2$ is abelian as I checked by Gap for small $p$. Is it true for each $p$? Thanks for your answers
BHZ's user avatar
  • 1,168
4 votes
2 answers
433 views

What is the current status of representation theory of $n$-ary groups in terms of hypermatrices?

An $n$-ary group is a generalization of the usual concept of a group where the binary operation (2-argument operation) is instead an $n$-ary ($n$-argument) operation. More info here on Wikipedia. I ...
Sidharth Ghoshal's user avatar
4 votes
1 answer
515 views

Generating infinite index subgroups of a free group

Let $F$ be nonabelian finitely generated free group, let $H \leq F$ be a finitely generated subgroup of infinite index and let $x,y \in F \setminus H$. Must there be some $a \in F$ such that $[F : \...
Pablo's user avatar
  • 11.3k
4 votes
2 answers
308 views

Another quotient of Hurwitz group

The paper An update on Hurwitz groups by Marston Conder seems to suggest that the Chevalley group $G(2,5)$ of order $5859000000$ is a quotient of $G := \langle a, b \ | \ a^2, b^3, (ab)^7, [a,b]^{10} \...
Thomas's user avatar
  • 2,811
4 votes
1 answer
237 views

Minimal number of generators of satellite knot groups

In light of Knot groups with big number of generators, I was wondering... Question 1 What is the minimal number of generators of the fundamental group of a satellite knot? Another more specific ...
Shijie Gu's user avatar
  • 2,083
4 votes
1 answer
142 views

Can the degree of $k$-nilpotence of a simple simply connected compact Lie group be in $(0,1)$?

Let $G$ be a simple (i.e. every proper normal subgroup is discrete) simply connected compact Lie group. Define the degree of $k$-nilpotence of $G$ to be the Haar measure of the set $$\{(x_1,\dotsc,x_{...
MSMalekan's user avatar
  • 2,118
4 votes
2 answers
388 views

Bound on the index of an abelian subgroup in discrete subgroup of the euclidean group?

I asked the following question on math.SE a couple of days ago. Dietrich Burde gave an answer for the case that the subgroup is not only discrete but also acts cocompactly. What about the general ...
eins6180's user avatar
  • 1,312
4 votes
1 answer
246 views

How do "Kummer closures" of fields look?

Let $F$ be a field and $A$ a finite abelian group. You can ask: does the regular representation $F[A]$ of $A$ split as a direct sum of 1-dimensional representations? This is equivalent to the ...
Theo Johnson-Freyd's user avatar
4 votes
0 answers
238 views

Non-abelian representations and their induced abelian representations

$\DeclareMathOperator\Aut{Aut}\DeclareMathOperator\Out{Out}\newcommand\ab{^{\text{ab}}}$Let $G$ and $H$ be a groups and assume that $H$ is non-abelian. Then we have a morphism $$\Out(H)\rightarrow \...
curious math guy's user avatar
4 votes
1 answer
458 views

Does there exist an order in a number field of deg>1 with a map to F_p for all p?

This question is motivated by a computational issue. Suppose $R$ is a product of orders in numberfields such that there is no ring homomorphism $R \to \mathbb Z$, then can one write an algorithm that ...
Maarten Derickx's user avatar
4 votes
1 answer
238 views

No lifts in an exact sequence of profinite groups?

In pg. 24 of his book on Galois cohomology, Serre gives the following exercise: "Give an example of an extension $1 \to P \to E \to G \to 1$ of profinite groups with the following properties: (i) $...
user avatar
4 votes
0 answers
159 views

Can the numbers of elements of distinct prime orders of a finite simple group coincide? [duplicate]

Does there exist a finite simple group $G$ and distinct prime numbers $p$ and $q$ dividing the order of $G$ such that the numbers of elements of $G$ of order $p$ and $q$ are the same? Remark 1: It ...
Stefan Kohl's user avatar
  • 19.6k
4 votes
1 answer
918 views

Heisenberg group in characteristic two

I have seen two constructions called the Heisenberg group. If $k$ is a field of characteristic not equal to $2$ and $V$ is a $2n$-dimensional vector space over $k$ with symplectic form $\omega : V \...
Justin Campbell's user avatar
4 votes
1 answer
348 views

Is there a topologizable group admitting only Raikov-complete group topologies?

Definition. A group $G$ is called complete (resp. non-topologizable) if each Hausdorff group topology on $G$ is Raikov-complete (resp. discrete). It is clear that each non-topologizable group is ...
Taras Banakh's user avatar
  • 41.9k
4 votes
1 answer
218 views

Inverse limits of perfect groups

Is every group isomorphic to an inverse limit (that is, projective limit) of perfect groups? I guess, the answer is no. In that case: Is there a characterization of the groups that are isomorphic to ...
Hannes Thiel's user avatar
  • 3,497
4 votes
0 answers
458 views

Mackey theory application - semidirect product abelian-by-finite

In order to advance my research I'm supposed to understand this fact: Let $A$ be an abelian group and $S$ a finite group acting on $A$. This defines the semi-direct product $A\rtimes S$: Let $\chi$ ...
Arnon Hod's user avatar
4 votes
1 answer
625 views

Is there an algorithm for computing Schur multiplier?

Suppose we are given group $G=\langle a_1,\ldots,a_n \mid R_1=1,\ldots R_m=1 \rangle$. Is there an algorithm which computes a finite presentation for the Schur multiplier, i.e. second homology group $...
Al Tal's user avatar
  • 1,281
4 votes
2 answers
356 views

Defining parity on the set of all bijections of ${\mathbb{N}}$

Let $\phi:{\mathbb{N}}\rightarrow {\mathbb{N}}$ be a bijection. Can we extend the notion of parity (of a finite permutation) to $\phi$ ? In other words, Can we define a group homomorphism $\Lambda $...
Dozeri's user avatar
  • 53
4 votes
0 answers
210 views

Profinite closure of characteristic subgroup

Let $F$ be a free group of finite rank, and $K\subset F$ a finite index characteristic subgroup. Let $\hat{F}$ be the profinite completion of $F$ (i.e. a free profinite group of same rank), and $\bar{...
ChanaG's user avatar
  • 161
4 votes
1 answer
383 views

Finite dimensional compact abelian group that is not a product of connected and a totally disconnected

Let $G$ be a compact abelian group. A compact abelian group is said to have dimension $n$ if $\dim_\mathbb{Q} \mathbb{Q}\otimes \hat G = n$. Equivalently one can show that this holds if $G$ is ...
TopGroups's user avatar
4 votes
1 answer
221 views

On groups without word growth $\succeq\exp(n^{1/2})$

I just asked today the following question: On groups with finite pro-$p$ completion for all primes $p$. However, I can actually simplified what I am interested in, but as it is somewhat a more general ...
Yiftach Barnea's user avatar
4 votes
2 answers
448 views

Does $\text{Sym}(\omega)$ have $2^{\aleph_0}$ pairwise non-isomorphic subgroups?

Let $\text{Sym}(\omega)$ denote the set of all bijections $f:\omega\to\omega$ together with composition as group operation. Does $\text{Sym}(\omega)$ have $2^{\aleph_0}$ pairwise non-isomorphic ...
Dominic van der Zypen's user avatar
4 votes
0 answers
640 views

Closed subgroups of a connected Lie group

Is it true that for any closed subgroup $H$ of a connected Lie group $G$, the group of connected components $\pi_0(H)$ is finite or countable? (inspired by the comment of nfdc23 to this question ).
Mikhail Borovoi's user avatar
4 votes
0 answers
226 views

Possible dimensions for triples of unitary irreducible representations whose tensor product contains the identity

For which triples $\{A,B,C\}$ of positive integers does there exist a (finite or compact) group $G$ with unitary irreducible representations of dimensions $A$,$B$, and $ C$ whose tensor product ...
Mark's user avatar
  • 163
4 votes
0 answers
732 views

Properties of Higman's group

The infinite group of Higman which has no finite quotient is given by the presentation (with 4 generators and 4 relations): $$ G = \langle a_i, i \in \mathbb{Z}/4\mathbb{Z} \mid a_ia_{i+1 \,(\text{mod ...
ARG's user avatar
  • 4,432
4 votes
1 answer
344 views

Extensions of compact Lie groups

Let $G$, $H$ be two compact Lie groups (possibly disconnected). Two short exact sequences of compact Lie groups $$ 0\rightarrow G\rightarrow M_1 \rightarrow H\rightarrow 0, $$ $$ 0\rightarrow G\...
rori's user avatar
  • 231
4 votes
0 answers
593 views

Galois classes of L-functions

Around one month ago, I posted on math.stackexchange a draft I wrote in which I define the notion of Galois class of L-functions: see https://math.stackexchange.com/questions/280876/definition-of-a-...
Sylvain JULIEN's user avatar
4 votes
1 answer
518 views

Finite groups with the same character table *including* class types, and square-free order

There are non-isomorphic finite groups with the same (complex) character table, as $D_4$ and $Q_8$. $$\scriptsize\begin{array}{c|c} \text{class}&1&2A&2B&2C&4 \newline \text{...
Sebastien Palcoux's user avatar
4 votes
3 answers
717 views

Finite, abelian, yet "fugitive" orthogonal subgroups

Update July 29, 2013. I have still not found a good textbook for this topic, if you point one to me I will be grateful :) I have accepted BS's answer anyway, since their explanation was useful to me ...
Juan Bermejo Vega's user avatar
4 votes
2 answers
704 views

Behaviour of cohomology groups under extension of scalars

Let $\hat{R}\to R$ be a homomorphism of commutative unital rings and let $\hat{M}$ be an $\hat{R}G$-module for a group $G$. Does the $R$-module isomorphism $$H^n(G,\hat{M}\otimes R)\cong H^n(G,\hat{M}...
alt.b7's user avatar
  • 51
4 votes
1 answer
373 views

Classification of finite abelian hypergroups and table algebras

Update: Originally, I formulated this question for finite abelian hypergroups, but in a discussion with Geoff Robinson below I realized that the abelian hypergroups defined below are equivalent to ...
Juan Bermejo Vega's user avatar
4 votes
1 answer
158 views

Counting "deflected" permutations: Part I

Let $\mathfrak{S}_n$ denote the group of permutations on $\{1,2,\dots,n\}$. Now, introduce the sets $$\mathcal{A}_n^{(k)}:=\{\pi\in\mathfrak{S}_n: -1\leq \pi(j)-j\leq k,\,\forall j\}.$$ I would like ...
T. Amdeberhan's user avatar
4 votes
2 answers
393 views

Is $(G\rtimes H,H)$ a Gelfand pair iff $G$ is abelian?

Let $G$ be a finite group and $K \subset G$ a subgroup. Then $(G,K)$ is a Gelfand pair if the double coset Hecke algebra $\mathbb{C}(K \backslash G / K)$ is commutative. Let $H$ be a subgroup of $...
Sebastien Palcoux's user avatar
4 votes
1 answer
242 views

Which 3-manifolds have positive rank gradient?

For which $3$-manifolds $M$ is the fundamental group $\pi_1(M)$ finitely generated and has positive rank gradient? Recall that the rank gradient of a finitely generated group $G$ is defined to be $$...
Pablo's user avatar
  • 11.3k
4 votes
0 answers
248 views

Generalization of a theorem of Øystein Ore in group theory: the infinite case

This post is the infinite version of this one, and is motivated by an exchange with Carmela Musella and Maria De Falco. We are interested in relative versions of the following Ore's theorem and ...
Sebastien Palcoux's user avatar
4 votes
2 answers
448 views

Number of torsion-free abelian groups

Let $\mathfrak{c}$ be the cardinality of the continuum. How much Choice, if any, is needed to prove that there are $2^{\mathfrak{c}}$ distinct (mutually nonisomorphic) torsion-free abelian groups of ...
Bruce Blackadar's user avatar
4 votes
1 answer
416 views

Fricke involution on GL(3)

Define $\Gamma_0(N)=\{\begin{pmatrix} a&b&c\\ d&e&f\\ g&h&i \end{pmatrix} \in SL(3,\mathbb{Z})|g\equiv h\equiv 0(\mod N)\}$ be the $N$-level congruence subgroup on GL(3). ...
7-adic's user avatar
  • 3,804
3 votes
0 answers
217 views

References on a certain generalization of Dedekind groups

Recall that a group is called a Dedekind group if all of its subgroups are normal. Also recall that a weaker property of a subgroup than normality is that of being a TI-subgroup: a subgroup $H$ of a ...
Stefan Kohl's user avatar
  • 19.6k
3 votes
1 answer
214 views

What is the growth of the rank of a power of a finite simple group?

Which asymptotic bounds (upper and lower) are known for $s_n$ - the minimal number of generators of $S^n$ where $S$ is a nonabelian finite simple group?
Pablo's user avatar
  • 11.3k
3 votes
0 answers
233 views

A bridge between the algebraic / differential geometry of $\frak{sl}_2(\mathbb{C})$ and the Sheffer-Appell calculus and combinatorics

In "Four examples of Beilinson-Bernstein localization", Anna Romanov introduces the basis $m_k = \frac{(-1)^k}{k!} \partial^k \delta $ on p. 9, where $\partial$ is a partial derivative and $\...
Tom Copeland's user avatar
  • 10.5k
3 votes
4 answers
1k views

Automorphisms of the Selberg class

Hello, assuming Selberg's orthonormality conjecture, let's consider bijective maps $f$ from Selberg's class $\mathcal{S}$ to itself such as: 1) $f$ maps a primitive function of $\mathcal{S}$ to a ...
Sylvain JULIEN's user avatar
3 votes
1 answer
2k views

Automorphisms of quotient groups

I have a general question about automorphism groups. Sorry in advance if I'm talking about well known facts, but I didn't find much in the literature. Let $G$ be a group and let $N$ be a ...
Martino Garonzi's user avatar
3 votes
1 answer
384 views

Using the Lehmer quintic to solve $11$-degree equations and higher?

(This is a natural continuation of a previous post.) I. Quintic method Given the Lehmer quintic, $$x^5 + n^2x^4 - (2n^3 + 6n^2 + 10n + 10)x^3 + (n^4 + 5n^3 + 11n^2 + 15n + 5)x^2 + (n^3 + 4n^2 + 10n + ...
Tito Piezas III's user avatar
3 votes
1 answer
740 views

Bases of free groups

Let $F$ be a free group on a finite set $X$. Let $A \subseteq X$ be a subset of $X$ contained in some $H \leq F$, a subgroup of finite index in $F$. Must there be a basis (free generating set) for $H$ ...
Pablo's user avatar
  • 11.3k