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Questions tagged [knot-theory]

Knot theory is dealing with embedding of curves in manifolds of dimension 3. A knot is a single circle embedded in the affine space of dimension 3 as a smooth curve not crossing itself. Many knot invariants are known and can be used to distinguish knots.

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Fundamental group of the complement of a codimension two submanifold

Let $M$ denote an arbitrary closed, connected, n-dimensional manifold for $n\geq 4$. Does there always exist a closed (not necessarily connected!) codimension two submanifold $S \subset M$ such that $\...
ThorbenK's user avatar
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1 vote
0 answers
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Tangle hypothesis and ribbon category

The tangle hypothesis, when specialized to ordinary framed tangles, says that the framed tangles form the free braided category with all duals (i.e. considered as a 3-category, all the 1- and 2-...
Trebor's user avatar
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3 votes
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Hat knot Floer Homology with Z coefficients calculation

I would like to ask for recommended references which carry out the calculation of the hat knot Floer homology of a knot with $\mathbb{Z}$ coefficients, i.e., $\widehat{\operatorname{HFK}}(K;\mathbb{Z})...
horned-sphere's user avatar
1 vote
1 answer
91 views

When is a 2-bridge knot hyperbolic?

It is known that 2-bridge knots in $S^3$ can be classified by the Schubert form. My question is: which 2-bridge knots are hyperbolic? (Do we have a complete classification for hyperbolicity in 2-...
YC Su's user avatar
  • 605
3 votes
2 answers
189 views

Necessary condition for invertible knot concordance from both ends

It is clear that if $K_1$ and $K_2$ are two concordant knots by a concordance that only present ambient isotopic phenomena (no saddles, maxima, or minima) they are invertible concordant from both ends....
jamp's user avatar
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-2 votes
1 answer
141 views

Existence of orientable finite volume complete cusp hyperbolic 3-manifolds $\mathbb{H}^3 / \Gamma$, where $\Gamma$ has no parabolic generators?

Let $K$ be a hyperbolic knot, i.e., $S^3 - K$ is an orientable finite volume cusp hyperbolic 3 manifold. Let $M=S^3 - K$ then $M= \mathbb{H}^3/\Gamma$, where $\Gamma$ (Kleinian group) is discret ...
T ghosh's user avatar
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11 votes
2 answers
515 views

Knots having the same Alexander module which are not S-equivalent

As is discussed in this answer, S-equivalence class can be regarded as the Alexander module plus Blachfield pairing, an isomorphism of some duals of Alexander modules. There are examples of knots ...
Tetsuya Ito's user avatar
3 votes
1 answer
150 views

Slice-ribbon conjecture in other 3-manifolds

There is some notion of what it means for a knot $K\hookrightarrow M$ to be "slice." In particular, we may ask, for example, that there is a topologically embedded disk in $M\times[0,1]$ ...
boink's user avatar
  • 245
8 votes
1 answer
348 views

Finite two-relator groups and quotients of knot groups

Let $G$ be a one-relator group $\langle A \mid R = 1 \rangle$. Then clearly $G$ is finite if and only if it is cyclic of finite order, i.e. can be given by a presentation $\langle a \mid a^n = 1 \...
Carl-Fredrik Nyberg Brodda's user avatar
2 votes
0 answers
141 views

Blackboard framing for embedded surfaces

A framed link is a link $L\subset\mathbb{R}^3$ equiped with the data of a normal vector field, called the framing; an isotopy of a framed link is an ambient isotopy, altering the framing accordingly. ...
Léo S.'s user avatar
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Asymptotic growth of twisted alexander polynomials and hyperbolic volume for infinite families of knots

Let $\{K_n\}_{n=1}^\infty$ be an infinite family of hyperbolic knots with increasing crossing number, and let $\rho_n: \pi_1(S^3 \setminus K_n) \to SL_N(\mathbb{C})$ be a sequence of irreducible ...
Chandler Halderson's user avatar
-3 votes
1 answer
106 views

Knot group of mirror image [closed]

Are the knot group and the knot group of its mirror image isomorphic? And,How about the case of knotted surfaces?
sayonara's user avatar
4 votes
1 answer
84 views

Finding an overtwisted disk in a contact surgery diagram

I've been reading through Surgery on Contact 3-Manifolds and Stein Surfaces by Ozbagci & Stipsicz and have been stuck on an exercise. Consider the following contact surgery diagram for $(S^3,\xi_{-...
Hrhm's user avatar
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3 votes
1 answer
75 views

A uniform upper bound for the linking number of periodic orbits of algebraic vector fields

Inspired by these two posts on knots orbits of polynomial vector fields on $\mathbb{R}^3$(A polynomial vector field on $\mathbb{R}^3$ which has a knot periodic orbit) and (Are total curvature and the ...
Ali Taghavi's user avatar
4 votes
3 answers
288 views

A polynomial vector field on $\mathbb{R}^3$ which has a knot periodic orbit

Is there a polynomial vector field $$P(x,y,z)\partial_x+Q(x,y,z)\partial_y+R(x,y,z)\partial_z$$ which has a closed orbit $K$ such that $K$ is a non trivial knot?
Ali Taghavi's user avatar
4 votes
1 answer
268 views

Seifert surfaces of fibered knots

Given a fibered knot $K\subseteq S^3$, does every genus-minimizing Seifert surface appear as the fiber of a bundle $S^3\setminus K\to S^1$?
mrburch's user avatar
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0 votes
0 answers
98 views

Does suspension preserve the inequivalence of knots?

Let $S$ be the suspension operator. Let $K1$ and $K_2$ be two knots in $S^3$ which are not equivalent. Does this imply that their suspensions in 4 sphere are not equivalent in the sense ...
Ali Taghavi's user avatar
1 vote
0 answers
54 views

Are total curvature and the unknoting number of closed orbits of algebraic vector fields bounded uniformly by the degree of vector field?

I am interested in this question since 1999 when I heared the definition of a knot and I read the definition of unknoting and the total curvature of a knot. To what extent can closed ...
Ali Taghavi's user avatar
1 vote
1 answer
108 views

Horizontal knots on 3 sphere

Motivation: First I present my motivation for this question but this motivational part is not my main question. I participated in a talk on knot theory. Then I presented the following ...
Ali Taghavi's user avatar
10 votes
2 answers
598 views

Is there a "simplest" way to embed a graph in 3-space?

I consider embeddings of graphs into 3-space with edges embedded as arbitrary curves. In the simplest (non-trivial) case the graph $G$ is a cycle or union of cycles, in which case the embeddings can ...
M. Winter's user avatar
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3 votes
1 answer
161 views

How to properly define a slice knot (or a locally flat disk)?

A knot $K\subset\Bbb S^3=\partial \Bbb D^4$ is said to be (topolopgically) slice if there is a locally flat disk $D\subset\Bbb D^4$ with $\partial D=D\cap \Bbb S^3=K$. As far as I understand, locally ...
M. Winter's user avatar
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2 votes
1 answer
136 views

Is there a Dehn-like presentation of a knot quandle?

The knot group can be presented using either a Wirtinger presentation (with generators corresponding to arcs of the knot diagram) or a Dehn presentation (with generators corresponding to regions of ...
Yury Belousov's user avatar
2 votes
0 answers
44 views

Link invariants on a thickened surface

Let $\Sigma$ be an oriented surface. I want to know about link invariants in $\Sigma\times [0,1]$. I already know the Ozawa polynomial introduced in this paper, but I couldn’t find any other than that....
AW.'s user avatar
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4 votes
1 answer
144 views

link cobordism classes

Just an extremely basic question on link cobordism: It would seem that all (framed) 1-links in $\mathbb{R}^3$ are (framed) cobordant to (framed) unlinks and in fact: to (framed) unknots --- for ...
Urs Schreiber's user avatar
3 votes
0 answers
82 views

Cup-product ($\cup$) vs. cross-product ($\times$) on the space of graph homology

I'm currently reading Nieper-Wißkirchen's Chern numbers and Rozansky-Witten invariants of compact Hyper-Kähler manifolds. He introduces the space of graph homology $\mathcal B$ as the free $K[\circ]$-...
red_trumpet's user avatar
  • 1,286
12 votes
2 answers
307 views

Property P and R for general 3-manifolds

Let $Y$ be a closed oriented $3$-manifold and $K$ be a knot in $Y$. We say $K$ is the unknot if $K$ is contained in a local $3$-ball in $Y$ and is unknotted therein. Generalized Property R: If a Dehn ...
Qiuyu Ren's user avatar
  • 557
4 votes
1 answer
148 views

Seifert invariants for Brieskorn manifolds $\Sigma(p,q,r)$

I've been studying Brieskorn manifolds $\Sigma(p,q,r)$ for $p,q,r\geq 2$. I know they are defined as the intersection of the complex surface $z_1^p+z_2^q+z_3^r=0$ as a subset of $\mathbb{C}^3$ and $S^...
user13121312's user avatar
3 votes
1 answer
268 views

If the complement of a knot $K$ fibers over the circle is $K$ necessarily fibered?

Let $K \subseteq S^3$ be a knot in the $3$-sphere and assume there exists a smooth map $p \colon S^3\setminus K \to S^1$ which is a fiber bundle. For every point $\require{enclose} \enclose{...
Patrick Perras's user avatar
2 votes
1 answer
261 views

Numerical computation of the second Vassiliev invariant, and the permutation $(1 3 4 2)$

$\DeclareMathOperator\SLL{SLL}$For a smooth embedding $\gamma(t):\mathbb{S}^1\rightarrow\mathbb{R}^3$, the Vassilev invariant of degree 2, which I will denote as $\nu_2(\gamma)$, may be computed ...
guest's user avatar
  • 149
6 votes
1 answer
151 views

Are isomorphisms of fundamental quandles canonical?

Given an (oriented) knot projection, we can create a quandle by assigning each curve segment a generator, and a relation $a \triangleright b = c$ for each intersection. If two projections are related ...
Trebor's user avatar
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2 votes
0 answers
179 views

Power series expansions and limits of knot invariants

This question is moved from math stackexchange which I posted several days ago without an answer. Background(ignore this paragraph if you know finite type invariants well): Recall that a finite type ...
Eric Ley's user avatar
  • 141
5 votes
1 answer
380 views

existence of triangulations of manifolds

Let $M$ be a smooth manifold. Let $K$ be a simplicial complex. Let ${\rm sd}(K)$ be the sub-division of $K$. Suppose there exists a simplicial sub-complex $K_1$ of ${\rm sd}(K)$ such that $K_1$ ...
Shiquan Ren's user avatar
17 votes
2 answers
553 views

$3$-manifold that is a surgery on a knot

By the Lickorish-Wallace theorem, every oriented closed $3$-manifold can be obtained by a surgery on a link in $S^3$. In the statement of this result, links are required: not every such manifold can ...
mathmo's user avatar
  • 331
0 votes
0 answers
102 views

Borromean rings on $\Bbb{RP}^2$ and octonions

If I draw a trefoil knot on a projective plane and draw a circle around it touching the three outer parts of the curve. I can view this as a division of the projective plane in 8 triangles, viewed as ...
Maarten Havinga's user avatar
6 votes
1 answer
311 views

Loop manipulation subgroup of the braid group

Recently, I came across a subgroup of the braid group $B_{2n}$ that I'm calling the "loop manipulation" group $H_n$. The idea is that we treat pairs of adjacent strands in the braid group as ...
pgadey's user avatar
  • 647
5 votes
1 answer
210 views

Is there a nontrivial ribbon knot concordance from a knot to itself?

It was conjectured by Gordon and recently proved by Agol that ribbon concordance defined a partial order on the semi group of knots. I know that this question is close related to the slice ribbon ...
Judy_xyh's user avatar
2 votes
3 answers
679 views

Solving the unknotting problem by pulling both ends of the string

It is an open question as to whether there is a polynomial time algorithm for recognizing the unknot. Consider the following procedure for doing so on an actual physical string: Suppose there is a ...
Craig Feinstein's user avatar
5 votes
1 answer
189 views

Heegaard splitting of figure-8 knot complement

It is well-known that the figure-8 knot complement in $S^3$ can be described as a circle fibration of a once-punctured torus. Is there also a description of the figure-8 knot as a Heegaard splitting ...
Oblonski's user avatar
  • 133
6 votes
1 answer
148 views

Knotted concordances of slice links

Are there any examples of a link $L$ such that: $L$ is (strongly) slice, meaning that there exists a properly embedded collection $C$ of $n=|L|$ disjoint annuli in $S^3\times [0,1]$ such that $C\cap ...
Alessio Di Prisa's user avatar
2 votes
0 answers
138 views

Mutants or not?

Two 4-tangles (drawn unneccesarily complicated to show how they are related - both are 6-tangles capped off with the same cap): (alternate version with ends at the same point) If I could turn over ...
Hauke Reddmann's user avatar
6 votes
2 answers
394 views

Slice knots in 3-manifolds

Is there a nonslice knot $K\subset S^3$ that is slice in some closed oriented $3$-manifold $Y$? Here, when we say $K$ is slice in $Y$, it means that when regarded as a local knot in $Y\times\{1\}$, $K$...
Qiuyu Ren's user avatar
  • 557
3 votes
1 answer
239 views

Rational 4-tangles vs rational knots

The closure of a rational $4$-tangle is a rational knot. But is the converse true? We could tangle up even the unknot to a hopeless mess before cutting it up, and we could cut it were it "hurts ...
Hauke Reddmann's user avatar
4 votes
0 answers
164 views

Coloured Jones polynomial at 4th root of unity and Arf invariant

Looking at the link invariants of $\operatorname{SU}(2)$ Chern-Simons theory, if we take the coloured Jones polynomial of a knot K, say $J_N^K$ at fundamental representation $N=2$, then we get the ...
hopftype's user avatar
2 votes
0 answers
112 views

A cell complex constructed from singular knots

Let $\mathcal K_n$ be the set of all $n$-singular knots up to isotopy,i.e. an immersion of $S^1$ into $\mathbb R^3$ with $n$ transverse double points that is an embedding when restricted to the ...
Eric Ley's user avatar
  • 141
4 votes
0 answers
112 views

Coloured Jones polynomial of the mirror image of a multicomponent link

This question has been reposted from MathStackExchange It is well understood that the usual Jones polynomial of a knot or link can be related to the Jones polynomial of the mirror image of the knot/...
hopftype's user avatar
6 votes
1 answer
444 views

Relations between relations in the positive braid monoid

The positive braid monoid on $n$ strands is the monoid with generators $s_1$, $s_2$, ..., $s_{n-1}$ and relations $$s_i s_{i+1} s_i = s_{i+1} s_i s_{i+1} \qquad s_i s_j = s_j s_i \text{for}\ |i-j| \...
David E Speyer's user avatar
1 vote
1 answer
125 views

History of knot enumeration tables

There is much arbitraryness in the Rolfsen (and later) tables. Of course anyone would name $7_1$ to be the first knot with $n=7$ crossings, but already my own "natural" ordering attempt (...
Hauke Reddmann's user avatar
1 vote
0 answers
78 views

Reshetikhin-Turaev invariants from extended 3d TQFTs

Attached to any object $V\in \mathcal{C}$ of a ribbon category $\mathcal{C}$, Reshetikhin and Turaev have defined knot invariants $$\tau_V(K)\ \in\ \text{End}_{\mathcal{C}}(1_{\mathcal{C}})$$ for ...
Pulcinella's user avatar
  • 5,701
2 votes
2 answers
226 views

Inverse of a smooth concordance of smooth knots

We say that a smooth concordance of smooth knots C' is inverse to C if the concatenation C•C' is smoothly isotopic to the trivial cylinder. I wonder if there are any known ways of inverting smooth ...
Alex Nho's user avatar
18 votes
1 answer
900 views

ID needed for one mathematician in group photo

The photo below was taken at MSRI in 1984 and MSRI has asked me to try to find out (on behalf of Lou Kauffman, Sofia Lambropoulou and Martha Jones) the identity of the mathematician farthest left, in ...
Silvio Levy's user avatar

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