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14 votes
2 answers
725 views

Are there any non-conjugation "extendible automorphisms" in the category of finite groups?

Let $\mathbf{Grp}$ be the category of groups. Given a subcategory $\mathscr{G}$ of $\mathbf{Grp}$ and $G\in\mathit{Ob}(\mathscr{G})$, a $\mathscr{G}$-extendible map on $G$ will here mean an assignment ...
Noah Schweber's user avatar
14 votes
2 answers
1k views

If every definable class admits a group structure, must global choice hold?

It is a remarkable fact, due to Hajnal and Kertész and explained very well in this MathOverflow answer by user Ashutosh, that the axiom of choice is equivalent to the assertion that every nonempty set ...
Joel David Hamkins's user avatar
13 votes
4 answers
843 views

What is a "general" relation algebra?

I'm trying to understand why (or if) the axioms of relation algebras are "the right ones." For example, we can back up the idea that the group axioms exactly capture the notion of "...
Noah Schweber's user avatar
8 votes
0 answers
148 views

What is this quotient of the free product?

Previously asked at MSE. The construction here can generalize to arbitrary algebras (in the sense of universal algebra) in the same signature with the only needed tweak being the replacement of "...
Noah Schweber's user avatar
3 votes
2 answers
347 views

Are there $2^{\aleph_0}$ pairwise non-isomorphic countable groups containing every finite group?

Let us call a group $(G,\cdot)$ finitarily complete if $G$ is countable, and every finite group is isomorphic to a subgroup of $(G,\cdot)$. Is there a collection of $2^{\aleph_0}$ pairwise non-...
Dominic van der Zypen's user avatar
1 vote
0 answers
162 views

Solution of an equation over free group

Let $F_n$ be a free group on $n$ generators. Let $w \in F_n$ be a word such that there does not exist any solution in $F_n$ for the equation $w.w(t_1, \ldots, t_n) = 1$, where $t_1, \ldots, t_n$ are ...
Shri's user avatar
  • 355
5 votes
1 answer
294 views

Words which are not inverted by any endomorphism

Let $w$ be a word in a free group $F_2$ of two generators $x_1, x_2$ such that there does not exist any endomorphism of free group which takes $w$ to $w^{-1}$. Let $w_1, w_2$ be two words in the same ...
Shri's user avatar
  • 355
4 votes
0 answers
166 views

Is there any good methods for writing down basis for laws of groups?

I am wondering if there is a good method to write down a finite equational basis for a finite group. Especially I am wondering if there is a good method in following situations: We can write a group ...
Todor Antic's user avatar
10 votes
2 answers
581 views

Maximal Abelian subgroups of $S_\omega$

Let $S_\omega$ be the group of permutations (bijections) $\varphi:\omega\to\omega$, together with composition as binary operation. Zorn's Lemma implies that every commutative subgroup of $S_\omega$ is ...
Dominic van der Zypen's user avatar
3 votes
1 answer
153 views

Is having a Frobenius pair first-order expressible in the language of groups?

I am trying to figure out whether or not the following property is first-order expressible in the language of groups. $$\text{$G$ has a subgroup $H$ with which it forms a Frobenius pair $(H,G)$.}$$ My ...
Y. Tamer's user avatar
  • 133
9 votes
0 answers
275 views

Is “simplicity is elementary” still hard? (Felgner’s 1990 theorem on simple groups, and subsequent work)

I came across a reference in this MathOverflow answer to an intriguing result of Ulrich Felgner [1]: among finite non-Abelian groups, the property of being simple is first-order definable. According ...
Peter LeFanu Lumsdaine's user avatar
4 votes
1 answer
125 views

Logical generators of groups and $\mathrm{Aut}$-bases

An element $s$ of a group $G$ is a logical generator of $G$ iff every element of $G$ can be defined in the first order language of groups with $s$ as a parameter. In this case we may call $G$ a ...
Sh.M1972's user avatar
  • 2,233
18 votes
3 answers
547 views

Finite presentability and elementary equivalence

Do there exist two elementary equivalent finitely generated groups $G,H$ such that $G$ is finitely presented but $H$ is not finitely presentable? It seems reasonable to think that finite ...
AGenevois's user avatar
  • 8,401
2 votes
1 answer
223 views

Possible symmetry groups of power terms

Previously asked and bountied at MSE: Let $\mathfrak{E}=(\mathbb{N};\mathit{exp})$ be the algebra in the sense of universal algebra consisting of the natural numbers with just exponentiation. To each ...
Noah Schweber's user avatar
9 votes
1 answer
759 views

What classes of groups can arise as "symmetry groups of terms"?

Let $\mathfrak{A}$ be an algebra (in the sense of universal algebra). To each term $t(x_1,...,x_n)$ in the language of $\mathfrak{A}$ in which each variable actually appears we can assign a group $G_\...
Noah Schweber's user avatar
29 votes
2 answers
794 views

Does $\mathrm{SO}(3)$ act faithfully on a countable set?

Let $\mathrm{SO}(3)$ be the group of rotations of $\mathbb{R}^3$ and let $S_\infty$ be the group of all permutations of $\mathbb{N}$. Is $\mathrm{SO}(3)$ isomorphic to a subgroup of $S_\infty$? This ...
Erik Walsberg's user avatar
8 votes
1 answer
896 views

Quantifier elimination for abelian groups

In the Wikipedia article (https://en.wikipedia.org/wiki/Quantifier_elimination#cite_note-4) it is said that every abelian group has quantifier elimination property and a long old paper of W. Szmielew ...
Sh.M1972's user avatar
  • 2,233
4 votes
1 answer
103 views

Computable change in minimum word length of subgroup elements

Let $G$ be an infinite finitely generated group. Fix a finite generating set for $G$. Define $\mathrm{len}_G:G\to\mathbb{Z}_{\geq 0}$ by sending $g$ to the minimum length of a word in the generators ...
user avatar
9 votes
0 answers
108 views

Decidable membership for subgroup generated by three elements in $F_2\times F_2$

Let $F_2$ be the non-abelian free group on two generators. Let $G\subset F_2\times F_2$ be a subgroup generated by three elements. Is there an algorithm deciding if a given element of $F_2\times F_2$ ...
user avatar
5 votes
1 answer
87 views

Equality to a power of a given word undecidable in finitely presented group with decidable word problem

Let $G$ be a group with an explicit finite presentation. Assume $G$ has a decidable word problem. Can there exist an explicit word $w\in G$ such that there is no algorithm deciding if a given word $w'\...
user avatar
6 votes
1 answer
150 views

Empty preimage under homomorphism of finitely presented groups with decidable word problems

Let $f:G\to H$ be a homomorphism of finitely presented groups with decidable word problems. Assume you are given explicit finite presentations for both $G$ and $H$ and you are given the words to which ...
user avatar
12 votes
1 answer
468 views

Is the diagonal of finitely presented groups computable?

Let $f:G\to H$ be a surjective homomorphism of finitely presented groups. If the kernel of $f$ is finitely generated then is $G\times_H G$ is a finitely presented group? Can one compute an explicit ...
user avatar
15 votes
2 answers
916 views

Element being trivial in a finitely presented group independent of ZFC

Is there an explicit finitely presented group $G$ and an element $g\in G$ such that the statement "$g$ is equal to the identity" is independent of ZFC?
user avatar
5 votes
1 answer
146 views

Empty preimage under homomorphism of finitely presented groups independent of ZFC

Is there a homomorphism of finitely presented groups $f:G\to H$ and an element $h\in H$ such that the statement "$f^{-1}(h)$ is empty" is independent of ZFC?
user avatar
2 votes
0 answers
71 views

Empty preimage under homomorphism of finitely presented groups with decidable word problems

Let $G, H$ be finitely presented groups with decidable word problems. Can there be a homomorphism $f:G\to H$ such that there is no algorithm deciding given $w\in H$ whether $f^{-1}(w)$ is empty or not?...
user avatar
7 votes
1 answer
143 views

Is there a pseudofinite group with a quantifier-free instance of the order property?

Recall that a group $G$ is pseudofinite if every first-order sentence $\varphi$ (in the language of groups) satisfied in $G$ is also satisfied in some finite group. Also recall that an instance of the ...
James E Hanson's user avatar
6 votes
0 answers
294 views

Independence results on pure algebra

I think that the most celebrated result in this direction is Shelah's famous work on Whitehead's Problem: Is every abelian group $A$ such that $Ext^1(A, \mathbb{Z})=0$ free? This is known to be ...
jg1896's user avatar
  • 3,318
11 votes
0 answers
564 views

Isomorphic free groups have bijective generating sets

Let $F(X)$ be the free group on a set $X$. Classically, we can prove the statement: $F(X) \cong F(Y)$ if and only if $|X|=|Y|$. The proofs (that I have seen) consist of turning the group ...
Ali Caglayan's user avatar
  • 1,185
12 votes
2 answers
583 views

Do there exist acyclic simple groups of arbitrarily large cardinality?

Recall that a group $G$ is acyclic if its group homology vanishes: $H_\ast(G; \mathbb Z) = 0$. Equivalently, $G$ is acyclic iff the space $BG$ is acyclic, i.e. $\tilde H_\ast(BG;\mathbb Z) = 0$. In ...
Tim Campion's user avatar
  • 63.9k
5 votes
0 answers
170 views

How much choice is required for a countably-infinite index subgroup of the real additive group?

The existence of such subgroups implies the existence of a non-measurable set; simply intersect each of the cosets with $[0,1]$. The results will all have equal outer measure, but their union will be ...
Keith Millar's user avatar
  • 1,252
8 votes
2 answers
585 views

Is the equational theory of groups axiomatized by the associative law?

Consider the class of groups in the signature {*}. Is the equational theory of that class axiomatized by the associative law? I asked this on math stack exchange but I didn't receive a satisfactory ...
user107952's user avatar
  • 2,013
6 votes
2 answers
186 views

What can the approximation of a group by some class be used for?

Recall the following concept due to Malcev and Gromov. Let $C$ be some class of groups. A group $G$ is said to be approximable by the class $C$ if for every finite symmetric subset $F\subset G$ ...
Leo's user avatar
  • 163
17 votes
2 answers
2k views

Why are model theorists so fond of definable groups?

My PhD was on so called "pure" model theory, and my advisor was not very much interested in applications of model theory to algebra. Now I feel the need to fill in the gap, and I'd like to educate ...
huurd's user avatar
  • 1,031
0 votes
0 answers
147 views

Groups implementable by finite field

I'm interested in finding all groups for which the group operation (and inverse map) may be implemented using finite field arithmetic. I've done some searching and have come across "algebraic groups",...
user135066's user avatar
7 votes
1 answer
601 views

Action of infinite symmetric groups on iterated power sets

Let $X$ be an infinite set, and $k \ge 1$ be a natural number. We work without the axiom of choice. Let $G_0$ be the full symmetric group on $X$, and let $G_1$ be the full symmetric group on ${\cal ...
Thomas Forster's user avatar
10 votes
0 answers
438 views

On the Number of Parallel Automorphism Lines

Given a group $G$, one can define the transfinite line of iterative automorphisms of $G$ to be the following chain of the groups where $G_{\alpha+1}=Aut(G_{\alpha})$ for each ordinal $\alpha$ and the ...
Morteza Azad's user avatar
35 votes
7 answers
4k views

Paradoxical Mathematical Objects Pending for Construction [duplicate]

The possible properties and applications of some mathematical objects have been described far before their rigorous mathematical definition. Some of them even had a seemingly paradoxical description ...
33 votes
1 answer
1k views

Is this conjecture strictly weaker than P=NP?

My three computability questions are related to the following group theory question (first asked by Bridson in 1996): For which real $\alpha\ge 2$ the function $n^\alpha$ is equivalent to the Dehn ...
user avatar
10 votes
1 answer
1k views

The Tall Tale of Terminating Transfinite Towers

The transfinite tower of iterative automorphisms of a group $G$ is simply definied to be the following chain of the groups where $G_{\alpha+1}=Aut(G_{\alpha})$ for each ordinal $\alpha$ and the direct ...
Morteza Azad's user avatar
39 votes
4 answers
4k views

The symmetric group theory of natural numbers

Sometimes it is not easy to formulate a correct question. Here is a better version of this question (I still do not know if it is optimal, but it is better than the previous one). We say that a set $...
user avatar
5 votes
1 answer
511 views

Translating first order statements about symmetric groups into the language of numbers and back

A question I was asked recently lead me to the following question. For every closed first order formula $\theta$ in the group signature consider the set $N_\theta$ of natural numbers $n$ such that the ...
user avatar
4 votes
3 answers
279 views

Closed free subgroups of the automorphism group of the countable atomless boolean algebra

Let $\mathcal{B}$ be the (unique up to isomorphism) countable atomless boolean algebra, and $\mathrm{Aut}(\mathcal{B})$ its automorphism group, with pointwise convergence topology. My question: Does $...
Iian Smythe's user avatar
  • 3,115
7 votes
0 answers
177 views

Countable elementary sub-structure of the automorphism group of the binary rooted tree

Let $G$ be the automorphism group of the binary rooted tree. The downward Löwenheim-Skolem theorem states that G has a countable elementary sub-structure. My question is whether such sub-structure ...
Mustafa Gokhan Benli's user avatar
2 votes
1 answer
190 views

Logic article on first-order invariants of abelian groups

I remember reading an article published in the 1970s by a Polish mathematician describing the first-order invariants of a torsion-free abelian group. I do not recollect the author's name, the title of ...
Phill Schultz's user avatar
6 votes
2 answers
461 views

Automorphism of the transfinite rooted binary tree

I was studying combinatorical group theory recently, and I came across the infinite regular rooted binary tree and its automorphism group $Aut(T^{(2)})$with the Grigorchuk subgroup. Let me now ...
FusRoDah's user avatar
  • 3,738
10 votes
1 answer
382 views

Wiener's axiomatization of the group law based on division

Gian-Carlo Rota wrote that [*]: Wiener axiomatized the group law by taking $xy^{-1}$ as the basic operation, and his axiomatization is quite different from any of the other axiom systems for groups....
Noam Zeilberger's user avatar
9 votes
1 answer
276 views

First order formulas for finite groups and invariant theory

Let $G$ be a finite group, and let $K$ be a field of characteristic zero. Let $\phi(x_1,\ldots,x_n)$ be a first order formula in the language of group theory (so $\phi$ can be for example something of ...
Ehud Meir's user avatar
  • 5,039
9 votes
1 answer
339 views

Finite and infinite 4-regular vertex-transitive graphs with identical $R$-balls

Consider the set of all 4-regular connected vertex-transitive graphs. By compactness, for every integer $R \ge 0$, there is an integer $N_R$, so that for every 4-regular vertex-transitive graph of ...
alef's user avatar
  • 91
15 votes
2 answers
972 views

Elementary subgroups of surface groups

From Sela's proof of Tarski's conjecture we know that the surface groups (i.e. fundamental group of a closed surface of genus $\geq 2$) and free (non-abelian) groups have the same first order theory. ...
Cusp's user avatar
  • 1,713
6 votes
2 answers
706 views

Non-trivial problems about the trivial group

Is there any non-trivial problem (maybe open problem) about the trivial group? I asked already a question about the Laws characterizing the trivial group. There is a description of such laws. As ...
Sh.M1972's user avatar
  • 2,233