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Questions tagged [lie-groups]

Lie Groups are Groups that are additionally smooth manifolds such that the multiplication and the inverse maps are smooth.

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how to determine the Weyl group of a diagonalizable subgroup?

Assume that $G$ is a connected compact Lie group (or a connected complex reductive group), and $K$ is a diagonalizable subgroup of $G$. It is known that the Weyl group $W_G(K)$ of $K$, defined as $N_G(...
gang han's user avatar
6 votes
1 answer
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A request for suggestions of advanced topics in representation theory

Please Note: The main points of the question below are in bold in order to minimize the time required to read the question. Let me begin by stating that I understand representation theory is a vast ...
5 votes
1 answer
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Other than SU(3), SO(4), SU(2)xU(1), are there compact semisimple Lie groups which exactly two 3-dimensional representations that are dual to each other?

In my original question, I asked which compact Lie groups $G$ have a certain property. Jim and Dan showed that this property is equivalent to $G$ having exactly two irreducible 3-dimensional ...
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6 votes
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distributions on Lie groups and representations

Let $G$ be a Lie group and $\pi$ a continuous action on $V$, a Fréchet space. This action induces a representation of the space of compactly supported functions, $C_c(G)$, with convolution as product ...
Yul Otani's user avatar
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9 votes
2 answers
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Lattices in $SL(n,\mathbb R)$

If $\Gamma\subseteq SL(n,\mathbb{R})$ is a lattice (i.e. discrete and finite covolume), does $\Gamma$ necessarily contain some $\mathbb{R}$-diagonalizable copy of $\mathbb{Z}^{n-1}$? I know that the ...
ALB's user avatar
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3 votes
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How to find the normalizer of a finite subroup in a Lie group?

If a group $G$ is generated by finitely many subgroups $G_i$ and $H$ a subgroup of $G$, under which conditions can $N_G(K)$, the normalizer of $K$ in $G$, be generated by all the normailizers $N_{G_i}(...
Gang Han's user avatar
8 votes
3 answers
3k views

Homology versus cohomology of Lie groups

A central advantage of cohomology theory over homology -- at least in terms of richness of structure and strength as an invariant -- is the additional ring structure from the cup product. Recall that ...
Vidit Nanda's user avatar
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Is the "Toeplitz algebra" the representation ring of a Hopf algebra related to SU(2)?

More precisely, does there exist a Hopf algebra $H$ whose category of (finite-dimensional, complex) representations is generated under direct sum and tensor product by two one-dimensional ...
Qiaochu Yuan's user avatar
3 votes
1 answer
465 views

How can one find generators of basic differential forms on homogeneous spaces?

Dear all, In short, my problem is that I would like to have a better control of the 1-forms on a homogeneous space. Contrary to the group case, the module of differential form is not trivialisable. ...
Amin's user avatar
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53 votes
5 answers
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Beautiful descriptions of exceptional groups

I'm curious about the beautiful descriptions of exceptional simple complex Lie groups and algebras (and maybe their compact forms). By beautiful I mean: simple (not complicated - it means that we need ...
zroslav's user avatar
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3 votes
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Transformation of the fundamental group of Lie groups under group homomorphisms

Hello! I have encountered the following problem while trying to solve a different one: let G, H be two semisimple Lie groups, and $G\to H$ a Lie group homomorphism. Does anyone know if the question ...
Ana 's user avatar
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Proof for which primes H*G has torsion

In 1960 Borel proved a beautiful result: **Theorem**. Let G be a simple, simply connected Lie group. Suppose that *p* is a prime that does not divide any of the coefficients of the highest root (...
Dylan Wilson's user avatar
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33 votes
8 answers
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"Modern" proof for the Baker-Campbell-Hausdorff formula

Does someone has a reference to a modern proof of the Baker-Campbell-Hausdorff formula? All proofs I have ever seen are related only to matrix Lie groups / Lie algebras and are not at all geometric (...
Mark.Neuhaus's user avatar
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1 vote
1 answer
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Lorentz quotient and orientation

$$ U \; = \; \left( \begin{array}{cc} 0 & 1 \\\ 1 & 0 \end{array} \right) , $$ Given a real oriented vector space $V$ with inner product, form Lorentzian $L = V \oplus U....
Will Jagy's user avatar
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10 votes
4 answers
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Commutativity of the fundamental group of any Lie Group [closed]

How do we formally prove that the fundamental group of any Lie group is always commutative?
user14210's user avatar
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Finite dimensional homogeneous spaces of $Diff(S^1)$

This question is a refined version of Representations of infinite dimensional Lie algebras as vector fields on manifolds I'm interested in the finite dimensional homogeneous spaces of $Diff(S^1)$. ...
H. Arponen's user avatar
5 votes
1 answer
404 views

determining symplecticity (if that's a word)

Suppose you have a matrix $M$ in $SL(n, \mathbb{Z}).$ Question: is there a necessary and sufficient condition for $M$ to be conjugate to $N \in Sp(n, \mathbb{Z}).$ It is clearly necessary that the ...
Igor Rivin's user avatar
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2 votes
2 answers
757 views

Abstract Commensurator Group of $\mathbb{Z}^n$ $Comm(\mathbb{Z}^n)\cong GL(n,\mathbb{Q})$?

Hello! In a paper I read that $\mathrm{Comm}(\mathbb{Z}^n)\cong \mathrm{GL}(n,\mathbb{Q})$. Why is that true? How can I find an isomorphism of this groups? I know that $\mathrm{Aut}(\mathbb{Z}^n)\...
Peter's user avatar
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3 votes
1 answer
256 views

Topologic or geometric mean of the structure constants of a semi simple lie algebra

Let $G$ be a semi simple Lie group (or real reductive), $\mathfrak{g}$ its lie algebra and $B$ its killing form. We can defined the 3-form $k$ by $$k(X,Y,Z)=B([X,Y],Z).$$ with $X,Y,Z\in \mathfrak{g}$. ...
shu's user avatar
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3 votes
2 answers
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How to deal with the singular reduction of the Hamiltonian n body problem?

I would like to consider the reduced Hamiltonian $n$ body problem, but am struggling with the angular momentum reduction seeing as the $SO(3)$ action is not free and the reduction is singular. ...
Dayal C Strub's user avatar
7 votes
1 answer
2k views

Can one understand the Kelvin transform conceptually?

Let $U = \mathbf{R}^n - \{ 0 \}$, $n > 2$ and consider for a function $f \in C^2(U)$ the Kelvin transform $$f^\star(x) = r^{2-n} f\left(\frac{x}{r^2}\right),$$ where $r = \lvert x \rvert$. One ...
orbifold's user avatar
8 votes
0 answers
388 views

Reference Request - Spaces of Smooth Vectors

I was recently looking for examples of non-nuclear spaces of smooth vectors of representations of Lie groups. I'll recall the basic definitions. Let $\pi$ be a unitary irreducible representation of a ...
shamovic's user avatar
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1 vote
1 answer
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Proper morphisms: Lie groups vs. group schemes

A Lie group can (often) be recovered as the $\mathbb{R}$-points of a group scheme. I am wondering if this parallelism carries over to proper actions. In particular, let $G$ be a Lie group acting on a ...
Earthliŋ's user avatar
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14 votes
1 answer
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Lie groups vs. algebraic groups and deformations

I am interested in deformations of (discrete subgroups of) Lie groups. But, as I understand it, deformation theory, as a theory, prefers to speak schemes. At least the classical Lie groups can be ...
Earthliŋ's user avatar
  • 1,211
1 vote
1 answer
173 views

Representing elements of U(N) or SO(N) by elementary rotations exp(i phi_n sigma_n)

Given a (orthogonal) basis $(\sigma_n)_{n=1,\dots,K}$ of the algebra $u(N)$, we can represent any element $U$ of the corresponding group $U(N)$ in the form $U=e^{i\sum_{n=1}^K\varphi_n\sigma_n}$. Is ...
Robert Barns's user avatar
5 votes
3 answers
1k views

Matrices generating non-discrete subgroups of SL(2,R)

Jorgensen's inequality $\mid \left(Tr\left(A\right)\right)^2-4\mid+\mid Tr\left[A,B\right]-2\mid\ge 1$ gives a necessary condition for two matrices A,B to generate a discrete subgroup of SL(2,R). Are ...
ThiKu's user avatar
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1 vote
1 answer
279 views

Heights in reductive groups

Let $G$ be a reductive group over a local non-archimedean field $F$, and let $B$ a Borel subgroup. For my purposes, the case $G = GL_2(\mathbb{Q}_p)$ will be sufficient with $B$ upper triangular ...
Marc Palm's user avatar
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2 votes
1 answer
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density of conjugate of arithmetic subgroup

$K=Q(\sqrt{d} ) , d<0 $, $\Gamma $ an arithmetic subgroup of $G=SU(2,1)(K)$ . Is $\cup_{g\in G}(g^{-1}\Gamma g)$ dense in G for the complex topology?
TOM's user avatar
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2 votes
1 answer
297 views

equations over (some) lie groups

To be concrete, let $G=SL(n, \mathbb{C}),$ $\phi$ an automorphism of $G.$ Is there a characterization of those $x$ for which there exists a $y$ such that $x = y \phi(y)?$ In the special case, the ...
Igor Rivin's user avatar
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4 votes
2 answers
499 views

density in SU(2,1)

Let $K=Q(\sqrt{-3})$ , is $SU(2,1)(K)$ dense in $SU(2,1)(C)$ for the complex topology?
TOM's user avatar
  • 709
8 votes
6 answers
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connected compact semisimple lie group finite fundamental group

I was told that the fundamental group of a connected, compact, semisimple Lie group is finite, with the outline of a possible way to prove this fact. Is there any source however that fleshes this out ...
Amathena's user avatar
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5 votes
2 answers
275 views

partial order on conjugate classes of subgroups

G is a group. For a subgroup H of G, note $[H]$ the class of subgroups which are conjugate to H. Define the binary relation: $[H] \leq [K]$ iff $H_0 \subset K_0$ for some $H_0 \in [H]$ and $...
Linxiao's user avatar
  • 51
3 votes
1 answer
330 views

Examples in the vein of smooth manifold + group = Lie group [closed]

I am currently writing a thesis and got to thinking about the bigger picture of mathematics in the following sense. Both manifolds and groups have highly developed theories in their own rights. When ...
Gaussian Eliminator's user avatar
6 votes
3 answers
466 views

Representation of double cover of $U(n)$ on eigenspaces of harmonic oscillator

Consider the metaplectic representation of $Mp(n)$ on $L^2(\mathbb R^n)$. We can view $U(n)$ as a subgroup of $Sp(n)$ and so inside $Mp(n)$ is a double cover $\tilde U(n)$ of $U(n)$. The restriction ...
Eric O. Korman's user avatar
1 vote
1 answer
299 views

Intertwining Integral defined on a Weyl group?

Why does the intertwining integral such as the one defined in A. W. Knapp's paper "Intertwining operators for semisimple groups" depend only on an element w of a Weyl group? http://www.jstor.org/...
Joe Tarmet's user avatar
2 votes
1 answer
364 views

Is $R(su_{4})\cong R(so_{6})$?

This is one of small the unsettled questions I had in my senior project. I want to prove for type $D$ we have $R(T)$ is a free module over $R(G)$ by finding a basis. I think we should have,$R(G)\cong ...
Kerry's user avatar
  • 799
4 votes
2 answers
578 views

Proper compact connected subgroup of $Spin(n)$

What are the proper compact connected subgroups of $Spin(n)$ of maximal rank where $Spin(n)$ is the spin group, that is, the universal cover of the special orthogonal group $SO(n)$? In fact, I am ...
berl13's user avatar
  • 471
2 votes
2 answers
421 views

Different Lie group structures on a vector space with the same Lie algebra structure

This is an eccentric question: recall that a smooth Lie group structure on $\mathbb R^n$ is uniquely identified by a triple $(\mu,\iota,e)$ where $\mu:\mathbb R^n\times\mathbb R^n\to\mathbb R^n$ is ...
Eruard Munsch's user avatar
7 votes
1 answer
426 views

Lie algebra "generated" by matrix-valued curve?

Let $A(t)$ be a $n\times n$-matrix-valued continuous (plus possibly other niceness conditions; see below) curve, with the matrix entries being complex in general. If I am not mistaken, $A(t)$ ...
AlexArvanitakis's user avatar
4 votes
1 answer
907 views

Is there a generalization of Schur - Weyl duality and plethysm for direct product of special unitary groups?

Consider the semisimple compact group $K=SU(N_1)\times SU(N_2) \times \ldots \times SU(N_S)$ acting naturally on $\mathcal{H}=\mathcal{H}_1 \otimes \mathcal{H}_2 \otimes \ldots \otimes \mathcal{H}_S$, ...
Michał Oszmaniec's user avatar
2 votes
1 answer
572 views

Free affine actions of Borel subgroups

Call an upper triangular $m\times m$ matrix $A$ admissible if the lowest non-zero entry of $A-I$ lies in the last column, and is strictly lower than any other non-zero entry of $A-I$. I'll also regard ...
shane.orourke's user avatar
2 votes
1 answer
241 views

Orbit of the identity matrix under Lie group algebra actions

I would like an explicit description of $\mathbb{R} SO(n) I_n$, i.e., the image of the identity under the action of the group algebra of $SO(n)$ by left multiplication. Equivalently, what is an ...
John Jiang's user avatar
  • 4,466
15 votes
5 answers
3k views

When are all centralizers in a Lie group connected?

Let $G$ be a compact connected Lie group acting on itself by conjugation, $$ G\times G\to G,\qquad (\sigma,h)\mapsto \sigma h \sigma^{-1}.$$ The fixed point set of a closed subgroup $H\le G$ equals ...
Mark Grant's user avatar
  • 35.9k
2 votes
1 answer
232 views

An innocent looking subgroup of $U(n)$

Consider the Lie subalgebra of $\mathfrak{u}(n)$ given by $L = \{A \in \mathfrak{u}(n): \sum_{j=1}^n A_{ij} = 0 \text{ for all } i \in [n]\}$. What is its dimension? What does the corresponding Lie ...
John Jiang's user avatar
  • 4,466
0 votes
1 answer
325 views

identify a curious subgroup in $U(n)$

Consider the following element $A$ in $U(n)$: $$ \begin{pmatrix} 1/2(1+z) & 1/2(1-z) & \\\\ 1/2(1-z) & 1/2(1+z) & \\\\ & &I_{n-2} \end{pmatrix},$$ where $|z| = 1$. Now ...
2 votes
3 answers
549 views

Non-continuous representations of $\operatorname{SL}_2(\mathbf{R})$

How does one construct a non-continuous representation $\rho:\operatorname{SL}_2(\mathbf{R})\rightarrow G$ for some connected (finite dimensional) Lie group $G$?
Hugo Chapdelaine's user avatar
3 votes
1 answer
295 views

Abel transform is an * isomorphism for SL(2, R)

Assume we conisder $G= SL(2, R)$, $K=SO(2)$ and $N$ the strict upper triangular matrices in $G$, $A$ diagonal matrices, and the Borel supgroup $B=NA$, $W$ Weyl group. Then we have an isomorphism of $*...
Marc Palm's user avatar
  • 11.2k
2 votes
1 answer
176 views

Chains in $K\backslash G/B$ lying over a closed $K$-orbit

Let $G$ be a complex connected reductive Lie group, $\theta$ an involution, and $K = G^\theta$ the fixed-point subgroup. Then $K$ has finitely many orbits on $G/B$, one of which is open and (quite ...
Allen Knutson's user avatar
4 votes
2 answers
3k views

Non-linear Lie group [duplicate]

Possible Duplicate: Complex Lie group without faithful real representations? We know that for a matrix (linear) Lie group $G$, we define it to be a closed subgroup of $GL(n,\mathbb{C})$. But Lie ...
Darkmoon's user avatar
6 votes
3 answers
482 views

Linear subspaces in cones over orthogonal groups

Consider the orthogonal group $G=O(n)$ as a subset of the vector space of $n\times n$ real matrices. Let $C=C(G)$ denote the Euclidean cone over $G$, i.e., the space of matrices of the form $tA, A\in ...
Misha's user avatar
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