Skip to main content

Questions tagged [ac.commutative-algebra]

Commutative rings, modules, ideals, homological algebra, computational aspects, invariant theory, connections to algebraic geometry and combinatorics.

Filter by
Sorted by
Tagged with
0 votes
1 answer
137 views

$k(F_i)_{i=1}^{n}=k(G_j)_{j=1}^{m}$ iff there exist $a_i,b_j \in k$ such that $\langle F_i-a_i \rangle_{i=1}^{n} = \langle G_j-b_j \rangle_{j=1}^{m}$

Let $k$ be an algebraically closed field of characteristic zero, for example $k=\mathbb{C}$ and let $F_1,\ldots,F_n,G_1,\ldots,G_m \in \mathbb{C}[x,y]$, $n,m \in \mathbb{N}-\{0\}$. Claim: $\mathbb{C}(...
user237522's user avatar
  • 2,837
1 vote
0 answers
159 views

On certain definition of arithmetical ring

The definition of an arithmetical ring states that A ring $R$ is arithmetical if the ideal lattice is distributive or equivalently $R$ is locally a valuation ring. I was reading a paper where ...
Amit Phogat's user avatar
3 votes
1 answer
329 views

Finite subschemes of projective bundles

$\DeclareMathOperator\Spec{Spec}\DeclareMathOperator\Proj{\mathbf{Proj}}$Let $S$ be a Noetherian scheme and $X$ finite $S$-scheme. The finite morphism $X \to S$ is projective in the sense of the ...
user avatar
10 votes
0 answers
194 views

Singularity category of a hypersurface associated to $M_{11}$

For reasons to do with classifying spaces of finite groups, I have the following algebra. Let $k$ be a field of characteristic two, and let $R = k[x,y,z]/(x^2 y + z^2)$, as a graded $k$-algebra with $|...
Dave Benson's user avatar
  • 16.2k
9 votes
2 answers
790 views

Algebraic power series of finite order

Apologies if the question is too elementary/something well-known. I believe it is a well-known fact that the rational formal power series $F(z)=\frac{P(z)}{Q(z)}$ which have finite order under ...
Sam Hopkins's user avatar
  • 24.2k
13 votes
2 answers
446 views

Tensor product of finite type UFD algebras over an algebraically closed field is again UFD?

Let $K$ be an algebraically closed field, $A$ and $B$ two finite type $K$-algebras which are assumed to be UFD. Is $A \otimes_K B$ again a UFD? This question has been already asked here and here, but ...
Libli's user avatar
  • 7,300
4 votes
1 answer
948 views

Tensor product and homomorphism

Let $A$ be a commutative ring, and $M$ be an $A$-module, and $M^*$ be $\mathrm{Hom}_A(M,A)$. Let $f$ be the map from $M \otimes_A M^*$ to $\mathrm{Hom}_A(M,M)$, such that, for all $x=\sum_i a_i \...
marco2013's user avatar
  • 353
2 votes
1 answer
304 views

Normal forms of ADE singularities

Given a surface $X:f(x,y,z)=0\subset \mathbb{A}^{3}_{\mathbb{C}}$ with only ADE singularities, how does one determine the correct singularity type of $X$ by computing the normal forms? Does a similar ...
H U's user avatar
  • 481
7 votes
2 answers
917 views

Is this exact sequence known?

$\newcommand{\Tors}{{\rm Tors}} \newcommand{\tf}{{\rm\, t.f.}} \newcommand{\Gt}{{\Gamma\!,\,\Tors}} \newcommand{\Gtf}{{\Gamma\!,\tf}} \newcommand{\Q}{{\mathbb Q}} \newcommand{\Z}{{\mathbb Z}} \...
Mikhail Borovoi's user avatar
2 votes
1 answer
191 views

Cohen-Macaulay fiber products

Let $R$ be a regular local ring, $X$ and $Y$ smooth $R$-schemes, $T\to Y$ a regular closed immersion over $R$ with $T$ smooth over $R$, and $f: X\to Y$ an $R$-morphism. Is the fiber product scheme $...
user avatar
4 votes
1 answer
328 views

Example of a certain type of Cohen-Macaulay ring

Let $k$ be a perfect field. I am looking for a $k$-algebra $R$ with the following properties. $R$ is of finite type over $k$ and is a domain; for all ${\mathfrak p}\in{\rm Spec}(R)$, the local ring $...
Damian Rössler's user avatar
10 votes
1 answer
561 views

Can you constructively prove a univariate polynomial algebra over a Jacobson ring is itself Jacobson?

Recall the Jacobson radical of a commutative ring $\mathrm J(A)=\lbrace a\in A\mid \forall b\in A:1-ba\in A^\times\rbrace$. The Jacobson radical of a quotient by an ideal $I\vartriangleleft A$ is ...
Arrow's user avatar
  • 10.5k
5 votes
3 answers
510 views

Absolute integral closure of local UFD

Let $R$ be a Nagata Noetherian local UFD, and $K$ be its fraction field. I wonder if its absolute integral closure $R^+$, which is the integral closure of $R$ in $K^\text{sep}$, is flat over $R$. Let $...
pop1's user avatar
  • 81
1 vote
1 answer
146 views

Pure-dimensional intersection of smooth varieties

Let $X\subset \mathbb{P}^n$ be a complex smooth projective variety of degree $d$ and dimension $m$, such that $X$ is not contained in any projective subspace of $\mathbb{P}^n$. Let $P\subset \mathbb{P}...
Jooh's user avatar
  • 389
2 votes
0 answers
211 views

Is a variety always contained in a hypersurface of smaller or equal degree?

(a) Let $V\subset \mathbb{A}^n$ be an affine variety (not necessarily irreducible). Write $\deg(V)$ for the sum of the degrees of its irreducible components. Must there be a hypersurface $W\subset \...
H A Helfgott's user avatar
  • 20.2k
2 votes
1 answer
318 views

Property of a commutative ring that is determined by the prime ideals of the ring

Robert Gilmer, in his paper "Commutative rings in which each prime ideal is principal", says: Some well known theorems indicate that certain ideal-theoretic structure properties of a ...
user 1's user avatar
  • 1,355
5 votes
0 answers
126 views

Koszul algebras among finite dimensional commutative algebras

Given a local commutative artinian algebra $A$ of the form $K[x_1,...,x_n]/I$ with quadratic ideal $I$ and $K$ a field. Question 1: Is there a computer algebra system that can check whether such an ...
Mare's user avatar
  • 26.5k
37 votes
1 answer
1k views

If $A$, $B$ are abelian groups such that $\mathrm{Hom}(A, G) \cong \mathrm{Hom}(B, G)$ for all abelian groups $G$, must $A$ and $B$ be isomorphic?

$\DeclareMathOperator\Hom{Hom}$The question is in the title. If the isomorphism $\Hom(A, G) \cong \Hom(B, G)$ is natural in $G$ then this is just the Yoneda Lemma. If $A$ and $B$ are finitely ...
Carlos Esparza's user avatar
4 votes
1 answer
370 views

Determining when quotient of a polynomial ring is a Gorenstein ring

I would like to be able to look at the ring $R=\mathbb{Z}[x_1,x_2,\ldots,x_n]/\mathcal{I},$ where $\mathcal{I}$ is generated by a finite number of monomials and say whether $R$ is a Gorenstein ring. ...
Haldot's user avatar
  • 214
1 vote
0 answers
150 views

Invariant polynomials under a non-standard group action

There is a whole theory of finding the invariant polynomials for matrix groups $\Gamma$ acting on the polynomial ring $\mathbb{C}[x_1,\ldots,x_n]$. I would be interested in finding invariant ...
Jan-Willem van Ittersum's user avatar
2 votes
1 answer
290 views

Flat scheme-theoretic closure

Suppose $R$ is a discrete valuation ring with fraction field $K$. Let $X\subset \mathbf{P}^n_{C_K}$ be a closed subscheme, flat over $C_K$, a smooth projective curve over $K$. Let $C_R$ be a flat ...
user avatar
2 votes
1 answer
308 views

A question about mapping cone and resolutions

I am studying this papper https://projecteuclid.org/journals/illinois-journal-of-mathematics/volume-44/issue-3/Betti-numbers-of-almost-complete-intersections/10.1215/ijm/1256060413.full By Daniel ...
Mathp's user avatar
  • 33
12 votes
1 answer
656 views

Does every map from a noetherian ring to a valuation ring factor through a DVR?

Let R be a noetherian ring and V a valuation ring with maximal ideal $\mathfrak{m}_V$. Does every morphism of rings $\varphi: R \rightarrow V$ factor through a discrete valuation ring? One may ...
BnPrs's user avatar
  • 195
12 votes
1 answer
417 views

Are algebras of smooth functions formally smooth?

Let $M$ be a manifold. Then is the ring of smooth functions $C^\infty(M,\mathbb{R})$ formally smooth over $\mathbb{R}$? If it helps, feel free to assume that $M$ is compact. (This is not a joke ...
Tobias Fritz's user avatar
  • 6,406
1 vote
0 answers
87 views

Projective dimension and certain subideals

My question is related to this one. I thought mine could be very elementary but I'm not sure how to look into it. Let $J$ be an ideal of $R=k[\mathbf{x}]$ where $\mathbf{x}=\{x_1,\dots,x_n\}$. Let $\{...
LeviathanTheEsper's user avatar
8 votes
1 answer
339 views

On actions of finite groups on adic spaces

Let $K$ be an algebraically closed complete non-archimedean field and consider the unit ball $\mathbb{B}^{1}_{K}=Sp(K\langle t\rangle)$. We have an action of $\mathbb{Z}/2\mathbb{Z}$ on $\mathbb{B}^{1}...
FPV's user avatar
  • 541
2 votes
0 answers
256 views

Multivariable Weierstrass preparation theorem

The Weierstrass preparation theorem for formal power series says the following: Let $f(T) \in \mathbf{Z}_p [[ T ]]$ be a formal power series. Then we can write $f(T) = p^{\mu} \cdot u(T) \cdot g(T)$, ...
Adithya Chakravarthy's user avatar
11 votes
1 answer
915 views

Triviality of vector bundles on affine open subsets of affine space

Let $k$ be a field. By the Quillen-Suslin theorem, all vector bundles on $\mathbb{A}^n_k$ are trivial for all $n \geq 0$. If $U \subset \mathbb{A}^n_k$ is an affine open subset, then vector bundles ...
naf's user avatar
  • 10.5k
6 votes
2 answers
345 views

Are finite projective modules over $R[t]$ free when $R$ is DVR?

Let $R$ be a discrete valuation ring (DVR) and let $M$ be a projective module of finite type over the polynomial ring $R[t]$. Is $M$ free over $R[t]$? As far as I understand, this should be a ...
Stabilo's user avatar
  • 1,479
2 votes
0 answers
76 views

What are the epis, monos, and extensions in the Freyd Envelope of a triangulated category?

Let $\mathcal T$ be a triangulated category (or homotopy category of a stable $\infty$-category). Recall that the Freyd envelope of $\mathcal T$ is an abelian category $\mathcal A$ which is ...
Tim Campion's user avatar
1 vote
0 answers
125 views

Confusion regarding change of variable and irreducibility

Let $\mathbb{K}$ be an algebraically closed field of characteristics zero. Let $X$ be an irreducible affine variety, with a rational action of a linearly reductive algebraic group $G$. Also, assume ...
It'sMe's user avatar
  • 839
1 vote
1 answer
96 views

On "minimal presentation" of local rings essentially of finite type over a field

Let $k$ be a field of characteristic $0$. Let $(R,\mathfrak m)$ be a local ring essentially of finite type over $k$ (https://stacks.math.columbia.edu/tag/07DR). Then, $R$ is the homomorphic image of ...
strat's user avatar
  • 361
3 votes
1 answer
284 views

Is this functor $\mathcal{F}: \text{Sch}/\mathbb{Q}\longrightarrow \text{Sets}$ a sheaf?

Consider the functor $\mathcal{F}: \text{Sch}/\mathbb{Q}\longrightarrow \text{Sets}$, defined by sending a scheme $X$ with coordinate ring $\mathcal{O}(X)$ to the set of orbits $B(\mathcal{O}(X))\...
kindasorta's user avatar
  • 2,907
0 votes
0 answers
53 views

A question on bounding the size of the polynomial

Suppose we are given the following n polynomials in $\bar{\mathbb{F}}_2[x_1,...,x_n]$: $f_1 = x_1 + x_n^2$ $f_2 = x_2 + x_1^2$ $\cdot$ $\cdot$ $f_{n-3} = x_{n-3} + x_{n-4}^2$ $f_{n-2} = x_{n-2} + x_{n-...
Rishabh Kothary's user avatar
54 votes
8 answers
58k views

Modern algebraic geometry vs. classical algebraic geometry

Can anyone offer advice on roughly how much commutative algebra, homological algebra etc. one needs to know to do research in (or to learn) modern algebraic geometry. Would you need to be familiar ...
6 votes
0 answers
151 views

Which monomials are "leadable"?

Question: Let $k$ be a field, let $f \in k[t_1,\ldots,t_N]$ be a nonzero polynomial. Which monomials $m_a = t_1^{a_1} \cdots t_N^{a_n}$ appearing in $f$ are leadable in the sense that they are the ...
Pete L. Clark's user avatar
53 votes
9 answers
13k views

Is there a preferable convention for defining the wedge product?

There are different conventions for defininig the wedge product $\wedge$. In Kobayashi-Nomizu, there is $\alpha\wedge\beta:=Alt(\alpha\otimes\beta)$, in Spivak, we find $\alpha\wedge\beta:=\frac{(k+l)...
agt's user avatar
  • 4,306
3 votes
1 answer
382 views

What is the name for algebras generated by elements, all of whose cubes vanish?

Given a ring $R$ with identity $1$, we can define the exterior algebra of order $k$ over $R$ to be the algebra over $R$, generated by elements $x_1, \dots, x_k$ satisfying $x_i^2 = 0$ for each index $...
Naysh's user avatar
  • 557
2 votes
0 answers
112 views

Understanding normalization algorithms

Let $R$ be a commutative and reduced ring, finitely presented over $\mathbb Z$. Let $\overline R$ be the integral closure of $R$ in its total ring of fractions. In https://arxiv.org/abs/alg-geom/...
Thibault Poiret's user avatar
6 votes
2 answers
226 views

For which fields $k$ with $k^\times$ not $p$-divisible, does there exist finite $l/k$ such that $l^\times$ is $p$-divisible?

Is there a prime $p$ and a field $k$, not real closed, with $k^\times$ not $p$-divisible, such that there exists a finite extension $l/k$ such that $l^\times$ is $p$-divisible? This question came up ...
Boaz Moerman's user avatar
0 votes
0 answers
213 views

Taking polynomial inverses over a field?

Let $f \in F_p[x] / q(x)$. I know for a fact that the inverse of $f$, $g$ exists in the field. Taking the regular inverse is easy, but I'm looking for the compositional inverse. I'm looking for ...
mtheorylord's user avatar
19 votes
1 answer
2k views

Examples of solid abelian groups

I am reading through Clausen's and Scholze's Lectures on condensed mathematics. I am struggling to understand the concept of solid abelian groups so I am looking for some examples. Is the underlying ...
Konstantin's user avatar
1 vote
1 answer
692 views

Under what conditions is an open subscheme of an affine scheme affine and what ring corresponds to it?

It is well known that an open subscheme of an affine scheme is not necessarily an affine one. But what are (if possible the most general) sufficient conditions for its affinity? And is it known how, ...
Arshak Aivazian's user avatar
8 votes
6 answers
2k views

How many solutions are there to the equation $x^2 + 3y^2 \equiv 1 \pmod{p}$?

Let $p$ be a prime. How many solutions $(x, y)$ are there to the equation $x^2 + 3y^2 \equiv 1 \pmod{p}$? Here $x, y \in \{0, 1, \ldots p-1\}$. This paper (https://arxiv.org/abs/1404.4214) seems like ...
Gautam's user avatar
  • 1,703
5 votes
1 answer
289 views

Cataland: Facets and partition polynomials of cluster complexes

Figure 25 on pg. 101 of "Cataland: Why the Fuss?" by Christian Stump, Hugh Thomas, and Nathan Williams depicts cluster complexes (CCs) associated with generalized $(m)$-Narayana / ...
Tom Copeland's user avatar
  • 10.5k
12 votes
1 answer
576 views

Factoring a polynomial into linear factors by ring extension

The following sounds so natural, I'm surprised I have never asked it before: Question 1. Let $R$ be a commutative ring. Let $P \in R\left[X\right]$ be a polynomial. Can we find a commutative ring $S$ ...
darij grinberg's user avatar
2 votes
0 answers
169 views

The dimension of the representation ring

Let $G$ be a compact Lie group. I am trying to characterize the algebraic properties of the representation ring $R(G)$ of $G$. In the case of the $n$-torus, the representation ring $R(T)$ is ...
Markuss Schmuckler's user avatar
5 votes
0 answers
181 views

The precise relationship between (moduli space of) finite-dimensional commutative local $\kappa$-algebras and number theory?

In [BP08] Poonen constructs and studies $\mathfrak{B}_n$, the moduli space of all based $n$-dimensional commutative associative unital $\kappa$-algebras, where $\kappa$ is an algebraically closed ...
M.G.'s user avatar
  • 7,127
5 votes
0 answers
138 views

Rings over which free modules of a certain rank are reflexive (satisfy Specker's theorem)

Following this question about the case of $\mathbb{Z}_{(p)}$, I've got to ask what is known more generally about rings and dimensions for which Specker's theorem holds. Let me make the following ...
Gro-Tsen's user avatar
  • 32.5k
3 votes
0 answers
249 views

Grothendieck schemes and the Sheffer differential op calculus (Rota, Roman, et al. finite operator calculus)

In "Left differential operators on non-commutative algebras" on p. 4, Michiel Hazewinkel displays "precisely the right definition of differential operator" as $$D\; X^n = F(\tfrac{...
Tom Copeland's user avatar
  • 10.5k

1
8 9
10
11 12
110