Questions tagged [linear-orders]
The linear-orders tag has no usage guidance.
70 questions
3
votes
1
answer
103
views
Topology on set of "real lower bounds"
Specific question: Is there a name for the "topology of real lower bounds"? This is the order topology for the ordering $\supseteq$ on the set
$$
\mathbb{LB} = \bigl\{ [t, \infty) \mid t \...
5
votes
0
answers
107
views
Structure of well-ordered commutative monoids
Let $(M,+)$ be a commutative monoid. Let $<$ be a well-ordering on $M$, where
$\forall a\in M,\ 0\leq a$
$\forall a,b,c\in M,\ a<b\Rightarrow a+c<b+c$
The first condition means $M$ will be ...
0
votes
1
answer
210
views
Permutations which respect a partial order
I have been studying the following situation, and I have a claim I believe to be true, but am unsure on how to approach it. I would appreciate any references I could look into where others have ...
1
vote
1
answer
54
views
Reference for tree of bad sequences of WPO
I'm looking for a reference to give in Wikipedia for the following result: Let $X$ be a WPO. Let $T_X$ be the tree of bad sequnces of $X$, and let $o(X)$ be the ordinal height of the root of $T_X$. ...
4
votes
1
answer
182
views
Find an order-embedding of $S_3\times{\bf2}\times{\bf2}$ into ${\mathbb Z}^4$
A function $f:P\to Q$ from a poset $(P,\le_P)$ to a poset $(Q,\le_Q)$ is an order-embedding if, for all $p,p'\in P$, $p\le_P p'$ if and only if $f(p)\le_Q f(p')$.
We partially order the Cartesian ...
6
votes
0
answers
151
views
Which monomials are "leadable"?
Question: Let $k$ be a field, let $f \in k[t_1,\ldots,t_N]$ be a nonzero polynomial. Which monomials
$m_a = t_1^{a_1} \cdots t_N^{a_n}$ appearing in $f$ are leadable in the sense that they are the ...
3
votes
0
answers
72
views
What are all the order types of maximal chains of $\Delta^0_2$ sets?
A set of natural numbers is $\Delta^0_2$ if it’s computable from the halting set. Consider the quasi-order/pre-order of all $\Delta_0^2$ sets ordered by $m$-reduction, or equivalently consider the ...
2
votes
0
answers
91
views
Ordered vector space that can be embedded into its bidual
We say that an ordered vector space $(V, \ge)$ (over $\mathbb{R}$) is "bidual embeddable" (I made up this name, not sure whether this concept already exists) if for every $x \in V$, if $x$ ...
-3
votes
1
answer
101
views
Order-embeddability of ${\frak b}$ and ${\frak d}$ in $\mathbb{R}$ [duplicate]
The starting point of this question is the observation that in ${\sf (ZFC)}$, all ordinals $\alpha < \omega_1$ can be order-embedded in $\mathbb{R}$.
Let $\omega^\omega$ denote the set of all ...
2
votes
0
answers
63
views
Countable highly order-transitive subgroups of $\mathrm{Aut}(\mathbb{Q},\leq)$
Consider $A := \mathrm{Aut}(\mathbb{Q},\leq)$, the group of order-automorphisms of $(\mathbb{Q},\leq)$. Call a subgroup $U$ highly order-transitive if for any two finite ordered sequences $s_1$ and $...
2
votes
0
answers
98
views
Closed images of linearly ordered spaces
Is there a description of the class of continuous closed images of linearly ordered spaces?
5
votes
0
answers
204
views
Given a totally ordered system of Banach spaces, can we we always change the norms to get isometric embeddings?
Given a real vector space $V$ which is the union of a totally ordered family of vector subspaces $V=\bigcup_{i\in I} V_i$. By that I mean that we assume that $(I,\leq)$ is a totally ordered set and ...
10
votes
0
answers
381
views
Can one define in ZFC a directed system of embeddings on the class of all linear orders realizing the surreal line as the direct limit?
Consider the surreal line $\langle\newcommand\No{\text{No}}\No,\leq\rangle$, in its order structure only. This is a proper class linear order, which is universal for all set-sized linear orders, as ...
4
votes
1
answer
174
views
Classifying the endofunctors of the category $\Delta$ of finite linear orders
Is there a theory of endofunctors of the category $\Delta$ of finite linear orders ?
Can they be classified ? Is there a reference on this ?
Can one classify endofunctors $T:\Delta\to\Delta$ which ...
1
vote
0
answers
195
views
A variant of Buchholz's ordinal notation
Buchholz here introduced an ordinal notation, consisting of a set $\mathcal{T}$, a linear order $\prec$ on $\mathcal{T}$ and some $\mathcal{OT} \subset \mathcal{T}$ such that $(\mathcal{OT}, \prec)$ ...
4
votes
0
answers
207
views
Is there a ${\bf 0'}$-computable linear order with "all intervals wild"?
Say that a linear order $L$ is a thicket iff $L$ is infinite, and for all elements $a,b,c_1,...,c_n\in L$ with $a<_Lb$ and $[a,b]_L$ infinite the following are equivalent:
$\{a,b\}\subseteq \...
3
votes
1
answer
162
views
A closed subset of a Dedekind-complete order has subspace topology equal to order topology
Here's a fairly easy fact from point-set topology that I'm having trouble finding a reference for. Say $X$ is a total order satisfying the least-upper bound property, and $S$ is a closed subset of it....
6
votes
0
answers
190
views
A representation of a partial order by a slowly changing sequence of linear orders
We study visualizations of attractors, which occur in chaotic dynamic systems, and for a few years trying to prove or refute Conjecture [3]. It has an equivalent formulation in terms of order theory, ...
6
votes
1
answer
237
views
Ordering preference for two zero mean Gaussian outcomes
Let $X\sim \mathcal{N}(0,1)$ be a standard Gaussian random variable. If we let $f_a(x)\triangleq\mathbb{E}[\max\{aX,x\}]$ for $a,x >0$, how to prove that $$f_a(f_b(1))<f_b(f_a(1))~~\text{for }0&...
3
votes
1
answer
176
views
Is there an explicit linear extension for the subsequence partial order?
Consider the set of finite sequences (of bounded length $\leq k$, if necessary) whose elements are taken from some finite alphabet $\Sigma$. We define a partial order on this set so that
$X = (X_1,...,...
9
votes
1
answer
276
views
Is a Banach lattice isomorphic to a Hilbert space in fact a Hilbert lattice?
The title says it all:
Let $E$ be a Banach lattice, which is isomorphic to a Hilbert space (as normed spaces). Is there an equivalent Hilbert norm on $E$, which still makes it a Banach lattice with ...
19
votes
1
answer
1k
views
Suprema of directed sets
Let $(X, \le)$ be a partially ordered set. We call a subset $S \subseteq X$...
... a chain if each two elements in $S$ are comparable with respect to $\le$ (in other words, $S$ is linearly ordered ...
1
vote
0
answers
99
views
About a type of permutations
How many permutations are there on the set $\{1,2, \cdots, n\}$ ($n\geq 3$), such that any three elements are not in increasing or decreasing order? For example, for $n=3$ we have $(1,3,2), (2,1,3), (...
1
vote
0
answers
86
views
Name for partial orders which are total on connected components
In my context, I encounter a lot of partial orders with the distinguished property that the order is total on connected components. Equivalently, they satisfy the condition
$$x \le y,z \enspace \lor \...
14
votes
1
answer
624
views
On certain order-automorphisms of the rationals
Consider the rationals $\mathbb{Q}$ with the usual order $\leq$. Now let $A$ be a subset of $\mathbb{Q}$, such that foreseen with the induced order $\leq$, $(A,\leq)$ is a dense linear order.
...
2
votes
1
answer
211
views
Fundamental theorem of linear orders
Let $(\Omega,\leq)$ be a countable linear order. Suppose that for every finite $m \in \mathbb{N}$, and all subsets $S_1$ and $S_2$ of $\Omega$ of order $m$, there is an order-automorphism of $(\Omega,\...
8
votes
2
answers
578
views
Ordinal notations within non-standard models of arithmetic
It is well-known that the order type of any countable non-standard model of arithmetic $\mathfrak{A}$ is $\omega+(\omega^*+\omega)\eta$. My question is what could be said about the order types of ...
4
votes
1
answer
307
views
Characterization of Archimedean linearly ordered monoids
In this question, it is shown that all Archimedean ordered groups are isomorphic to an ordered subgroup of $\mathbb R$. Additionally, it is shown that if such a group is complete, then it is ...
1
vote
1
answer
213
views
Self-embeddings of uncountable total orders
A nice theorem of Dushnik and Miller (from 1940) states that if $(\Omega,\leq)$ is a countable total order, then either
there is an element $\omega \in \Omega$ such that $(\Omega \setminus \{\omega\}...
8
votes
1
answer
314
views
A strictly decreasing function between uncountable subsets of the reals
By a standard technique of inductive killing everything relevant (in this case decreasing homeomorphisms between uncountable $G_\delta$-subsets of the real line) it is possible to prove the following ...
3
votes
0
answers
46
views
Maximal number of sets, obtained as intersections of semiintervals of $k$ linear orders
Given a finite set $S$ with $n$ elements, and a fixed small $k$ (say $k=3$), how to find $k$ linear orders $\leq_1, \dots, \leq_k$ on $S$, such that the number of feasible subsets of $S$ is ...
3
votes
2
answers
152
views
What is the dimension of a subspace of the product of $n$ linearly ordered compacta
This question is motivated by this problem of Dominic van der Zypen.
Problem. Let $X=\prod_{i=1}^nX_i$ be the Tychonoff product of linearly ordered compact Hausdorff spaces $X_1,\dots,X_n$. Is it ...
15
votes
1
answer
1k
views
Characterizing $\mathbf{R}$ as an ordered group
A standard characterization of $\mathbf{R}$ uses the order and the field structure: any linearly ordered field that is archimedean and complete is isomorphic to $(\mathbf{R}, +, \times, <)$ as an ...
4
votes
1
answer
154
views
Kruskal's tree theorem and $\Pi_1$ sentences of linear orderings with finitely many constants
In their paper "Theories with recursive models" [1] Lerman and Schmerl used a version of Kruskal's tree theorem about finite n-augmented trees.
An n-augmented tree is a tree T together with $n$ unary ...
2
votes
1
answer
302
views
Name for this algebraic structure?
I've found myself looking at a structure $\mathbb{M}$ whose important properties are:
$\mathbb{M}$ is a discretely ordered additive monoid.
$\mathbb{M}$ has a least element, and this least element is ...
9
votes
3
answers
599
views
Associative mean
Can there be a function $m(a,b)$ that is both associative and a mean, i.e.,
$\min (a,b) \leq m(a,b) \leq \max (a,b)$? The obvious solutions are $m(a,b) = \max(a,b)$ or $\min(a,b)$, but are there ...
6
votes
1
answer
505
views
Upward Löwenheim–Skolem theorem for well-ordered models with/without measurable cardinals
Consider a complete first order theory $T$ whose language contains a binary predicate $\leq$. Assume that $T$ has an uncountable model that is well-ordered by $\leq$ so that this question isn't stupid ...
5
votes
1
answer
140
views
Is there literature on finite geometries with ordered lines?
A difference between finite geometries and (e.g.) Euclidean space is that "lines" in finite geometries are unordered subsets of the universe, while "lines" in Euclidean space are ordered subsets of ...
4
votes
2
answers
220
views
locally incomparable dense linear orderings extending $\langle \mathbb{R}, < \rangle$
This follows up on Incomparable dense linear orderings extending $\langle \mathbb{R},< \rangle$
and hopefully sparks more discussion.
Where $a<b$, say that the four “types” of nonempty bounded ...
7
votes
1
answer
278
views
Incomparable dense linear orderings extending $\langle \mathbb{R},< \rangle$
Where $a<b$, say that the four “types” of non-empty bounded intervals are:
$(a,b)$, $[a,b]$, $(a,b]$, and $[a,b)$.
Let $\langle X,< \rangle$ and $\langle Y,< \rangle$ be dense linear ...
4
votes
1
answer
210
views
An algebraically generated set of linear orders
Notation: Let $L_1,L_2,...$ be linearly ordered sets.
$L_{i}^{-1}$ denotes the reverse linear order of $L_{i}$,
$L_1+L_2$ denotes the sum of linear orders, i.e. the disjoint union $L_1\cup L_2$ with ...
11
votes
0
answers
438
views
Example of $\aleph_1$-categorical linear order
Is it possible to have an $L_{\omega_1,\omega}$-sentence $\phi$ in a vocabulary that includes $<$ that satisfies the following?
$<$ is a linear order on a definable subset;
$\phi$ is $\aleph_1$-...
2
votes
1
answer
117
views
The pseudo-metric and linear orders
Is there a necessary and sufficient condition for a linearly ordered topological space to be pseudo-metrizable? (by a pseudo-metric, I mean a map $X\times X\rightarrow\mathbb{R}$ in which all the ...
3
votes
1
answer
181
views
Least ordinal not embedded in a total order
If $(E,<)$ is a linear order, let $s(E,<)$ denote the least ordinal which doesn't embed in $(E,<)$.
I am trying to prove the following:
If $(M,+,.,0,1)$ is a model of open induction, (or ...
18
votes
0
answers
895
views
Is the universality of the surreal number line a weak global choice principle?
I'd like to consider the principle asserting that the surreal
number line is universal for all class linear orders, or in other
words, that every linear order (including proper-class-sized)
linear ...
1
vote
0
answers
83
views
reconstructing a linear order corrupted by noise
Suppose we have a partial order (efficiently computable), $\leq$, on $\mathbb{R}^n$, a set $S \subset \mathbb{R}^n$, and let $\rho$ be the standard Euclidean metric. We want to find a set $S^\prime = ...
4
votes
2
answers
519
views
Maximal cones and lexicographic orderings
Let $V$ be a real vector space. It is well known that, given a totally ordered basis of $V$ (say $(b_i)_{i\in I}$ where $I,<$ is totally ordered), $V$ is totally ordered by the lexicographic ...
19
votes
0
answers
775
views
A Linear Order from AP Calculus
In teaching my calculus students about limits and function domination, we ran into the class of functions
$$\Theta=\{x^\alpha (\ln{x})^\beta\}_{(\alpha,\beta)\in\mathbb{R}^2}$$
Suppose we say that $...
3
votes
4
answers
932
views
Is there a compact connected Hausdorff space in which every non-empty $G_\delta$ set has non-empty interior?
Q1.
Is there a compact connected Hausdorff space (with at least two points) in which every non-empty $G_\delta$ set has non-empty interior? (Without the requirement for connectedness, every finite $...
1
vote
0
answers
210
views
Existence of $\lambda$-transitive linear orders for $\lambda \geq \aleph_0$
A linear order $(L, <)$ is $\lambda$-transitive iff any order-preserving bijection between sets of size $\lambda$ can be extended to an order automorphism of $L$.
For $\lambda < \aleph_0$, $2$-...