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Questions tagged [modules]

For questions on modules over rings.

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Semiperfect modules are $D1$

Let $M_R$ be a module. We say that $M$ is lifting or has $D1$ if for every submodule $N \subset M$ there is a decomposition $M=A \oplus B$ such that $A \subset N$ and $N \cap B \ll M$ (that is, $N \...
Hussein Eid's user avatar
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Right maximal ideals in skew-Laurent rings over division Rings

Let $R$ be a Noetherian domain, and let $D$ denote its division ring. Define $S = D_q[x_1^{\pm 1}, x_2^{\pm 1}]$ as an iterated skew-Laurent polynomial ring with the relation $x_1 x_2 = q x_2 x_1$. Is ...
Sky's user avatar
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Finitely generated module over a skew Laurent polynomial ring $\mathbb{K}[x_1^{\pm 1},x_2^{\pm1}]$

Let $A := \mathbb{K}_{\Lambda}[x_1^{\pm 1}, x_2^{\pm 1}, x_3^{\pm 1}, x_4^{\pm 1}]$, $B := \mathbb{K}_{\Lambda'}[x_1^{\pm 1}, x_2^{\pm 1}, x_3^{\pm 1}]$, and $C := \mathbb{K}_{\Lambda''}[x_1^{\pm 1}, ...
Sky's user avatar
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2 votes
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Does a matrix ring over a ring satisfy the Koethe conjecture if the coefficient ring itself satisfies the Koethe conjecture?

I just want to know whether the following statement is true or false. If $R$ is a ring satisfying the Koethe conjecture, then the matrix ring over $R$ also satisfies the Koethe conjecture. Or is it ...
Eunnaya First's user avatar
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43 views

Endomorphism algebra of equivariant maps of isotypic module

Let $A$ be a simple Artinian $K$-algebra with a minimal left ideal $M$. Here, $M$ can be viewed as a simple left $A$ module, and, by Schur's lemma, $D=\text{End}_A(M)$ is a $K$-algebra. By Wedderburn-...
khashayar's user avatar
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2 votes
2 answers
189 views

A semisimple ring is left square-full iff it is right square-full

Let $R$ be a ring with unity and $M$ any right $R$-module. A submodule $X$ of $M$ is called square-root in $M$ if $X \oplus X$ embeds in $M$ (i.e., there exists a monomorphism $X \oplus X \to M$). ...
Hussein Eid's user avatar
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58 views

When is a bimodule that is projective as a right and as a left module also projective as a bimodule

Are there practical criteria for determining when a bimodule that is projective as a right and as a left module is projective as a bimodule? Some illustrative examples of what goes wrong and what goes ...
Gheorghe Bucătaru's user avatar
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59 views

Bimodule endomorphisms of a bimodule over a noncommutative ring

Let $R$ be a noncommutative ring and $M$ an $R$-$R$-bimodule that is projective as left $R$-module. We know that the bimodule of left $R$-module endomorphisms ${}_REnd(M)$ is isomorphic to the tensor ...
Gheorghe Bucătaru's user avatar
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Dimension of hom spaces between indecomposable modules

Undergraduate-Level Background Let $A$ be an Artin algebra over an algebraically closed field $k$, and let $C = Rep(A)$ denotes the category of $k$-linear, $k$-finite dimensional representations of $A$...
Student's user avatar
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1 answer
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If a bimodule is "generated" by single elements, must the elements be conjugate?

Let $A$ and $B$ be Artin $k$-algebras for a commutative artinian ring $k$ (e.g. $A$ and $B$ are finite dimensional $k$-algebras for a field $k$). Let $M$ be an $A$-$B$-bimodule of finite length over $...
kevkev1695's user avatar
3 votes
1 answer
339 views

If the Hom-space of finite length modules is generated by single elements, must the elements be conjugate?

Let $A$ be an Artin $k$-algebra for a commutative artinian ring $k$ (e.g. $A$ is a finite dimensional algebra over a field $k$). Let $X,Y$ be finite length left $A$-modules. If $\text{Hom}_A(X,Y)$ is ...
kevkev1695's user avatar
2 votes
1 answer
210 views

Direct product of direct sum of a flat module

In the book "Rings and Categories of Modules" by Anderson & Fuller, this problem is given: If $V^A$, i.e. the direct product of the module $V$ by the index set $A$, is flat for all sets $...
karparvar's user avatar
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An example a right Noetherian domain which is left uniform but not right uniform

Recall that a module $M_R$ ($R$ is a ring with unity) is called uniform if the intersection of any two nonzero submodules is nonzero. We say that $M_R$ is an SIP-module if the intersection of any two ...
Hussein Eid's user avatar
9 votes
1 answer
315 views

Nonzero module with vanishing derived fibers

What's an example of a nonzero $R$-module with vanishing derived fibers at all points of $\mathrm{Spec}(R)$? This was asked in When does a quasicoherent sheaf vanish? but the answer there only says ...
Andy Jiang's user avatar
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1 answer
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An example of a commutative ring $R$ which has a proper right ideal which is not a right SIP $R$-module

Recall that a module $M_R$ ($R$ is a ring with unity) is called SIP if the intersection of any two summands of $M$ is also a summand. I asked before if there exists a commutative ring which is not an ...
Hussein Eid's user avatar
1 vote
1 answer
87 views

An example of a commutative ring which is not SIP

Recall that a module $M_R$ ($R$ is a unital ring) is called an SIP-module if the intersection of any two summands of $M$ is a summand. The ring $R$ is called (left) right SIP-ring if the module (${}...
Hussein Eid's user avatar
5 votes
0 answers
288 views

Representation functor on modules

Let $k$ be a field and $A$ a unital associative $k$-algebra. The representation functor associates, to each object in non-commutative geometry, a genuine geometric object on the representation variety ...
Qwert Otto's user avatar
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If $R$ is a regular square-free ring, then $R$ is dual-square-free

Let $R$ be a ring with unity. We call $R$ regular if every principal (left) right ideal is a summand (i.e., generated by an idempotent). A module $M$ is called square-free if whenever $A,B$ are ...
Hussein Eid's user avatar
0 votes
1 answer
98 views

A question on clean rings

Recall that a ring $R$ is called clean if every element of $R$ is a sum of a unit of $R$ and an idempotent of $R$. We call a module $M$ clean if its endomorphism ring $End(M)$ is a clean ring. ...
Hussein Eid's user avatar
1 vote
1 answer
75 views

Lemma of Harada and Sai on sums of modules with a "chain" of monomorphisms between them

I am trying to get a contradiction from the following set of hypotheses: Let $R$ be a ring. Let $M$ be a direct sum of non-zero $R$-modules $M_1$, $M_2$, $\dotsc$. For each $i\ge1$, let $f_i:M_i\to M_{...
Tri's user avatar
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2 votes
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101 views

What is the natural module?

Lemma 2.9 of [1]: Let $\operatorname{char}(K) \neq 2 $ and let $G$ be $\operatorname{Spin}(m,K)$, $n=\operatorname{rank} G$, and let $V$ be the natural $m$-dimensional module. Suppose $f\in G$ and $f^...
scsnm's user avatar
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468 views

How fast does the number of "fixed" points grow compared to the size of the ball in the following group?

I have copied this question from Math.StackExchange, in the hope that some experts here can provide some relevant insight. Let $M = \oplus_{i\in \mathbb Z} V^{(i)}$ where each $ V^{(i)} \cong \mathbb ...
ghc1997's user avatar
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3 votes
2 answers
214 views

Characterize rings $R$, such that the countable product $P=R^N$ has the property that every finitely generated submodule of $P$ is free

What are the rings whose countable power has the property that every finitely generated submodule is free?
Rado's user avatar
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2 votes
1 answer
152 views

A commutative ring with unity which does not have relatively pseudo-injective ideals with zero intersection

Let $R$ be a ring with $1$ and $M$ and $N$ be any right $R$-modules. We say that $M$ is pseudo-$N$-injective if every $R$-monomorphism $f:X \to M$ from a submodule $X_R$ of $N_R$ can be extended to $N$...
Hussein Eid's user avatar
2 votes
2 answers
416 views

Tensor product over $\mathbb{Z}$ and p-adic integer ring $\mathbb{Z}_p$

Thanks for your reading. Suppose we have two $\mathbb{Z}_p$-modules $A,B$. Do we always have $A \otimes_{\mathbb{Z}} B \simeq A \otimes_{\mathbb{Z}_p} B$, as abelian groups or $\mathbb{Z}_p$-modules? ...
Rellw's user avatar
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1 vote
0 answers
60 views

Bounding the length in a module of evaluated skew polynomials

Let $R$ be a finite principal ideal ring, $S$ a Galois extension of $R$ of degree $m$ (so in particular $S$ is a free $R$-module of rank $m$, and we have an $R$-module isomorphism $S^n \cong \...
JBuck's user avatar
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1 vote
0 answers
67 views

How to find the annihilator of a module/how to determine the torsion module

Given a left $R$-module $M$. Given a subset of $S\subset M$. What are related theorems concerning the annihilator of $S\subset M$ that can be used in practice? $S$ is known. In my case, $R$ is ...
relativeentropy's user avatar
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71 views

When is a submodule trivial?

I am a beginner concerning module theory, but I need it for my PhD. Sorry for obvious questions therefore. Given a left $C(G)$-module $(V, \tilde{\rho})$ where $C(G)$ denotes the group algebra over a ...
relativeentropy's user avatar
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46 views

submodules in a direct sum of semisimple modules without common simple factors

Let $A$ be an associative (unital) algebra. Let $M_1,\cdots, M_r$ be pairwise non-isomorphic simple $A$-modules and let $V=\bigoplus^r_{i=1}V_i$, where $$ V_i=M_{i,1}\oplus \cdots\oplus M_{i,n_i}\...
Yong Hu's user avatar
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6 votes
3 answers
434 views

What is known about finite dimensional modules over the nilCoxeter algebra?

Recall that the nilCoxeter algebra $\mathcal{N}_W$ for a Coxeter group $W$ is given by the $\mathbf{k}$-basis $x_w$ for each $w\in W$ and multiplication $x_ux_v=x_{uv}$ if $\ell(uv)=\ell(u)+\ell(v)$ ...
Christoph Mark's user avatar
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0 answers
35 views

Endomorphism of torsion points of Drinfeld modules

Reposting from mathstackexchange. A Drinfeld module is defined to be an $\mathbb F_q$-algebra morphism $\phi: \mathbb F_q[T] \rightarrow K\{\tau\}$, where $K=\mathbb F_{q^m}$ is a finite field and $K\{...
Reyx_0's user avatar
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6 votes
1 answer
310 views

Factoring through projective modules is an equivalence relation

$\DeclareMathOperator\Hom{Hom}\DeclareMathOperator\PHom{PHom}$I'm reading about stable module categories, and I have a question about the definition of the maps. Let $R$ be a ring, and take (left) ...
StuckInTheFridge's user avatar
3 votes
1 answer
223 views

Monoidal structure on presheaves

I am confused about the following monoidal structure, which gives a symmetric monoidal structure on R-modules (that I think is not Cartesian), even if R is not commutative. Let $C$ be a small category....
user39598's user avatar
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3 votes
0 answers
107 views

Auslander-Reiten sequences where irreducible morphisms are all epi/mono

Let's work in the setting of modules over an Artin algebra $A$, or a finite-dimensional $k$-algebra $A$, or if you like, modules over a connected quiver $Q$ without oriented cycles. Let $M$ be such a ...
Marty's user avatar
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1 vote
0 answers
78 views

Is the matrix ring $\mathbb{M}_n(R)$, $n\geq 2$, over a serial ring $R$ again serial?

Let $R$ be a ring with $1$. A right $R$-module $M$ is called uniserial if its submodules form a chain, i.e., for any two submodules $A,B\subseteq M$ either $A\subseteq B$ or $B\subseteq A$. The module ...
Hussein Eid's user avatar
2 votes
2 answers
139 views

Infinite radical ideal cubed equals zero for tame hereditary Artin algebras

Let $A$ be a tame hereditary Artin algbera and mod$A$ the category of finitely generated (left) $A$-modules. Further, let rad$_A$ be the radical ideal of mod$A$, which is the smallest ideal containing ...
kevkev1695's user avatar
2 votes
1 answer
88 views

Generating sets for a module and scalar extension

Let $k$ be an algebraically closed field and $K/k$ a (transcendental) field extension. Let $A$ be a finite dimensional $k$-algebra, and $M$ an $A$-module. Suppose that the $K \otimes_k A$-module $K \...
bm3253's user avatar
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4 votes
1 answer
198 views

Does hereditary and connected imply that the underlying ring $k$ of a $k$-algebra is a field?

All rings are assumed to be associative and have a 1. Let $k$ be a commutative artininan ring and $R$ a finitely generated $k$-algebra. Is it true that if $R$ is connected and hereditary, then $k$ is ...
kevkev1695's user avatar
3 votes
2 answers
401 views

$R$-Module objects in cartesian closed categories

I am looking for a reference for the following statement. Theorem. Let $C$ be a regular, well-powered, countably complete cartesian closed category, $R$ be a (commutative) ring object in $C$, $R\...
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1 vote
0 answers
97 views

Algorithms to decompose a graded module over $R[x]$, where $R$ is a PID

There is a certain class of objects, which can be thought of either as modules over a ring $R[x]$ or as functors. A few equivalent definitions are given below. The question is what computer algorithms ...
GHPR's user avatar
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4 votes
0 answers
127 views

Length of dual module

It is well known that, given a commutative ring $R$ and an $R$-module $M$, the dual module $M^\vee = \operatorname{Hom}_R(M, R)$ does not always satisfy $M^\vee \cong M \ (1)$, and not even $M^{\vee \...
JBuck's user avatar
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5 votes
0 answers
87 views

Tensor product of modules in model vs. infinity categories

Let $C$ be a combinatorial symmetric monoidal model category and let $A$ be a associative algebra object in $C$, that is cofibrant as an object in $C$. In Higher Algebra 4.3.3.17, Lurie proves an ...
Jakob's user avatar
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111 views

Totally isotropic space for bilinear pairing over ring

A duplicate of this: Consider the following well-known inequality: Let $b$ be a non-degenerate symmetric bilinear pairing over a (finite-dimensional) $\mathbb F$-vector space $V$ and $W$ a totally ...
JBuck's user avatar
  • 223
4 votes
1 answer
160 views

Symmetric tensor of highest weight modules for $\mathrm{SU}(2)$

Let $V_i$ be the $(i+1)$-dimensional representation of the special unitary group $\mathrm{SU}(2)$ with the highest weight $i$. Is there any uniform way to compute the irreducible decomposition for the ...
Hebe's user avatar
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1 vote
0 answers
242 views

Is the span of all nilpotent ideals also a nilpotent ideal?

Given a non-zero Lie algebra $\mathcal{L}$ over $\mathbb{C}$, we define $\mathcal{L}^2 = \big[\mathcal{L}, \mathcal{L} \big] = \big\{ [x, y]: x, y\in \mathcal{L} \big\}$, and for any $k\in\mathbb{N}$ ...
Sanae Kochiya's user avatar
3 votes
1 answer
153 views

A question about freeness of a certain class of abelian groups

Lets call an abelian group $G$, to be semi-free (or SF) if every nonzero subgroup of $G$ is isomorphic to $\mathbb{Z}\times H$ for some abelian group $H$. Is every semi-free group, a free group? If ...
Mostafa - Free Palestine's user avatar
2 votes
1 answer
95 views

Two nonsingular non-isomorphic modules with isomorphic injective hulls

Let $R$ be a ring with unity. Are there two nonsingular non-isomorphic right $R$-modules with isomorphic injective hulls?!.
Hussein Eid's user avatar
1 vote
1 answer
84 views

Simple-direct-injective modules

A right $R$-module $M$ is called a simple-direct-injective module if it satisfies any of the following equivalent conditions: For any simple submodules $A,B$ of $M$ with $A \cong B \subseteq^{\oplus} ...
Hussein Eid's user avatar
1 vote
0 answers
167 views

When do limits of $R$-modules commute with direct sum?

Let $R$ be a commutative ring. Is there any good special case in which I can say that a limit of $R$-modules commutes with direct sum? This is of course true for finite direct sums. Are there other ...
Vik78's user avatar
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0 votes
1 answer
96 views

An example of module which is square-free, CS, NOT C3, and NOT nonsingular

Let $M$ be a right $R$-module ($R$ has unity). Recall that $M$ is called square-free if $M$ does not contain two nonzero isomorphic submodules with zero intersection. $M$ is called CS if every ...
Hussein Eid's user avatar

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