Skip to main content

All Questions

Filter by
Sorted by
Tagged with
24 votes
1 answer
2k views

When is the product $(1+1)(1+4)…(1+n^2)$ a perfect square?

This is a modification of an unanswered problem on the math StackExchange. When is the product $(1+1)(1+4)…(1+n^2)$ a perfect square? If $(1+1)(1+4)…(1+n^2)=k^2$ then one possibility is $n=3$, $k=...
Ken W. Smith's user avatar
  • 1,021
19 votes
3 answers
2k views

Stronger versions of Wilson's Theorem

Problem Let $c \in \mathbb{N}$ $;$ $\exists$ a prime $p$ for which: $$p^c \mid (p-1)!+1$$ Does $\exists$ $M$ $\in$ $\mathbb{N}$ $;$ $\forall$ $c \geqslant M$ $;$ $\nexists$ $p$ ...
Haran's user avatar
  • 371
19 votes
1 answer
3k views

Sums of primes that are themselves prime

I'm not a math expert so this may be a trivial question; if $p_i$ is the $i$-th prime, let: $$S(n) = \sum_{i=1}^n p_i$$ be the sum of the first $n$ primes and $$P(n) = | \{1 \leq i \leq n \mid S(...
Marzio De Biasi's user avatar
19 votes
2 answers
1k views

Floors of rationals to powers: Infinite number of primes?

Let $r=a/b$ be a rational number in lowest terms, larger than $1$, and not an integer (so $b > 1$). Q. Does the sequence $$ \lfloor r \rfloor, \lfloor r^2 \rfloor, \lfloor r^3 \rfloor, \...
Joseph O'Rourke's user avatar
17 votes
3 answers
2k views

About the prime divisors of values of polynomials

Let $P$ be a polynomial having integer coefficients (and degree $\geq 3$), and let $\mathscr P_P$ be the set of prime numbers dividing some value $P(n)$ with $n \in \mathbb Z$. Is it true that $\...
Konstantinos Gaitanas's user avatar
16 votes
1 answer
1k views

Elementary Proof of Infinitely many primes $\mathfrak{p} \in \mathbb{Z}[i]$ in the sector $\theta < \arg \mathfrak{p} <\phi $

A quick look at the primes in $\mathbb{Z}[i]$ suggests they might be evenly distributed by angle if we zoom out on a coarse enough scale. I would like ask about the much weaker statement forgetting ...
john mangual's user avatar
  • 22.8k
15 votes
6 answers
7k views

Prime factorization of n+1

If $n=\prod_{i=1}^{k} p_i^{e_i}$ is a prime factorization of integer $n$. Is there a quick way to find the prime factorization of $n+1$? Or the only way to do it is recalculating the whole ...
Vor's user avatar
  • 342
12 votes
1 answer
869 views

Analytic lower bounds on the first sign change of pi(x) - li(x)?

There have been many results on the first sign change of $\pi(x)-{\mathrm{li}}(x)$: among others, Lehman, te Riele, Bays & Hudson, Demichael, Chao & Plymen, and most recently Saouter & ...
Charles's user avatar
  • 9,114
12 votes
1 answer
547 views

Seeking references for finding primes infinitely often

I've been pondering this weakened version of the finding primes problem for a while: Is there an algorithm which given $k$ outputs a prime $p > 2^k$ in time $F(\log_2(p))$? This differs from ...
Dan Brumleve's user avatar
  • 2,302
12 votes
3 answers
929 views

Mertens-like sum in arithmetic progressions

I find myself needing a good estimate for $\sum_{p\le x,\, p\equiv a\bmod q} 1/p$, perhaps something like $$ \sum_{p\le x,\, p\equiv a\bmod q} \frac1p = \frac{\log\log x}{\phi(q)} + b(q,a) + O\big(\...
Greg Martin's user avatar
  • 12.8k
12 votes
3 answers
3k views

111...11 base p = 111...11 base q

Feels like I am probably missing something obvious. Are there distinct primes $p,q$ and positive integers $m,n$ such that $$ \sum_{i=0}^{n} p^i = \sum_{j=0}^{m} q^j$$ Guessing the answer is no, but ...
Not Bill's user avatar
  • 129
12 votes
1 answer
1k views

Why do the Maynard-Tao weights work so well?

I am looking for an intuitive reason for why the Maynard-Tao weights work well to capture many primes of the form $n+h_1, \ldots , n+h_k$, where $(h_1, \ldots , h_k)$ is any admissible $k$-tuple. For ...
George Shakan's user avatar
12 votes
1 answer
1k views

Prime Power Gaps

In 2000, Baker, Harman and Pintz proved that there is always a prime in the interval $(n-n^{0.525}, n)$. There are also conditional results implying smaller intervals. Nevertheless, I could not find ...
Ami Paz's user avatar
  • 385
11 votes
1 answer
2k views

Distribution of the number of prime factors

Count the number of prime factors of a number $n$ to include multiplicity, so that $$n=24=2^3 \cdot 3 = 2 \cdot 2 \cdot 2 \cdot 3$$ has $4$ prime factors, and $$n = 6500 = 2^2 \cdot 5^3 \cdot 13 = 2 \...
Joseph O'Rourke's user avatar
11 votes
2 answers
1k views

Update for 2015: least prime of form nq+1, with q prime?

I have received a complaint about my 2011 answer least prime in a arithmetic progression which, indeed, gives conflicting reports about this: given a prime $q,$ what can we say about an upper ...
Will Jagy's user avatar
  • 25.7k
11 votes
1 answer
700 views

Squarefree numbers $n$ such that $432n+1$ is also squarefree

This is a second attempt (see Primes $p$ such that $432 p +1$ is prime) Is the set of squarefree numbers $n$ such that $n(432 n+1)$ is also squarefree known to be infinite? Fact: the number of such ...
user21's user avatar
  • 123
11 votes
1 answer
1k views

The Bombieri Vinogradov Theorem restricted to moduli divisible by $k$

The Bombieri-Vinogradov Theorem states that given $A>0$, there exists $B>0$ such that for $Q=\sqrt{x}\left(\log x\right)^{-B},$ we have $$\sum_{q\leq Q}\max_{y\leq x}\max_{\begin{array}{c} a\...
Eric Naslund's user avatar
  • 11.4k
10 votes
1 answer
694 views

Set of prime numbers $q$ such that $\sum\limits_{p\leq\sqrt{q}}p=\pi(q)$, where $p$ are prime numbers

The question is: does the set of prime numbers $q$ such that $\sum\limits_{p\leq\sqrt{q}}p=\pi(q)$, where $p$ are prime numbers, contain infinitely many elements? You can find the first elements here (...
Juan Moreno's user avatar
10 votes
1 answer
708 views

Primes dividing $2^a+2^b-1$

From Fermat's little theorem we know that every odd prime $p$ divides $2^a-1$ with $a=p-1$. Is it possible to prove that there are infinitely many primes not dividing $2^a+2^b-1$? (With $2^a,2^...
Konstantinos Gaitanas's user avatar
10 votes
1 answer
469 views

Asymptotic behavior of a certain sum of ratios of consecutives primes

I am looking for the asymptotic growth of the following sum $$\sum_{k=1}^{n}\frac{p_{k+1}+p_k}{p_{k+1}-p_k}$$ where $p_k$ stands for the prime of index $k$. Manual computations show, for small values ...
Augusto Santi's user avatar
9 votes
1 answer
527 views

Infinitely many primes coming from Euclid's proof

When teaching Euclid's classic proof of the infinitude of primes today, the following question appeared to me. Let $p_1,p_2,p_3,\ldots$ be the prime numbers, listed in increasing order. Set $$k_n = ...
Miriam's user avatar
  • 91
8 votes
1 answer
1k views

Number field analogue of the Goldbach Conjecture

Is there a generalization of Goldbachs conjecture for prime ideals in number fields?
Kikiriku's user avatar
7 votes
1 answer
531 views

Primes arising from permutations

Recently, Paul Bradley proved in arXiv:1809.01012 that for any positive integer $n$ there is a permutation $\pi_n$ of $\{1,\ldots,n\}$ such that $k+\pi_n(k)$ is prime for every $k=1,\ldots,n$ (cf. ...
Zhi-Wei Sun's user avatar
  • 15.6k
7 votes
2 answers
679 views

What is wrong with this deterministic algorithm efficiently generating large primes?

According to PolyMath (Strong) conjecture. There exists deterministic algorithm which, when given an integer k, is guaranteed to find a prime of at least k digits in length of time polynomial in k. ...
joro's user avatar
  • 25.4k
7 votes
1 answer
1k views

Heuristic for Montgomery's conjecture

This is my third question on this site regarding Montgomery's conjecture -- and I apologize if this is too much -- but I am still not understanding well why this conjecture is believed to be true. ...
Joël's user avatar
  • 26k
7 votes
1 answer
1k views

What would be the consequences of $\displaystyle{\lim\inf_{n\to\infty}p_{n+k}-p_{n}\sim k\log k}$?

The question is in the title: what would be the number theoretic consequences if we managed to establish the conjectured asymptotic equality $\displaystyle{\lim\inf_{n\to\infty}p_{n+k}-p_{n}\sim k\log ...
Sylvain JULIEN's user avatar
6 votes
2 answers
804 views

Must Mersenne numbers be divisible by arbitrary large primes with exponent one?

Let $M_n$ denote the Mersenne numbers $M_n=2^n-1$. As $n$ varies, must $M_n$ be divisible by arbitrary large prime $p$ with exponent one, i.e. $p \mid M_n, p^2 \nmid M_n$? In other words, must the ...
joro's user avatar
  • 25.4k
6 votes
5 answers
530 views

Arbitrarily long composite anti-diagonals?

Plot points $(a,b) \in \mathbb{N}^2$ if gcd$(a,b) \neq 1$. Call such points composite points. Call a sequence of points $(a+i,b-i), i=0,\ldots,k$ a composite anti-diagonal if all are composite points. ...
Joseph O'Rourke's user avatar
5 votes
1 answer
960 views

There at least 4 divisors of $n-1$ which do not divide $\phi(n)$ if $n$ is a composite of the form $6k+1$

If $n$ is composite then $\phi(n) < n-1$ (Euler's totient function) hence there must be one or more divisors of $n-1$ which do not divide $\phi(n)$. For lack of a better terminology, let us call ...
Nilotpal Kanti Sinha's user avatar
5 votes
1 answer
434 views

consecutive prime gaps and explicit bound

I am aware of the theorem that $p_{n+1}- p_n \leq n^{0.525}$ which is true for all sufficiently large numbers due to Baker, but if i want to make the implicit "for all sufficiently large numbers" ...
user avatar
4 votes
0 answers
238 views

On the values of $\prod_{k=1}^{(p-1)/2}(e^{2\pi i/12}-e^{2\pi i k^2/p})$ for primes $p>3$

In a recent preprint, I investigated $$S_p(x):=\prod_{k=1}^{(p-1)/2}(x-e^{2\pi ik^2/p}),$$ where $p$ is an odd prime and $x$ is a root of unity. Motivated by Question 337879 and Question 338325, ...
Zhi-Wei Sun's user avatar
  • 15.6k
3 votes
0 answers
1k views

Effective upper bound on large prime gaps; or, what is the first prime after a googolplex?

Question What is the best known effective upper bound on the prime gap following x? Motivation Suppose you needed to show a good bound for the gap between a fixed large constant, say $G=10^{10^{100}...
Charles's user avatar
  • 9,114
2 votes
1 answer
379 views

Representation of 2 in sum of powers of positive-negative digits with some base

Define:A set $\mathcal{C}(t)$, a positive integer $n$ is in the $\mathcal{C}(t)$ if $x^t \pmod{n}$ describes a bijection from the set $\{0,1,...,n-1\}$ to itself. Example table: \begin{array}{|c|c|} \...
Pruthviraj's user avatar
2 votes
1 answer
928 views

Is there a formula that can predict the primes in the sequence of ratios of consecutive superior highly composite numbers? : $2, 3, 2, 5, 2, 3, 7,...$

This is the sequence of prime numbers which are the elementary building blocks for the superior highly composite numbers: $2, 3, 2, 5, 2, 3, 7, 2, 11, 13, 2, 3, 5, 17, 19, 2, 23, ...$ The $n^{th}$ ...
user50746's user avatar
  • 341
2 votes
0 answers
422 views

Sequences with high densities of primes: how to boost them to get even more and larger primes

I propose a methodology to help find large prime numbers with a much higher probability than picking up random numbers and testing them for primality. This would help speed up prime number generators ...
Vincent Granville's user avatar
1 vote
1 answer
327 views

Symmetry in Hardy-Littlewood k-tuple conjecture

Assuming Hardy-Littlewood $k$-tuple conjecture, do the "dual" prime constellations $(0,h_1, h_2,\cdots, h_i,\cdots, h_{k-1}=d)$ and $(0, h_{k-1}-h_{k-2}, h_{k-1}-h_{k-3},\cdots,h'_i=h_{k-1}-...
Sylvain JULIEN's user avatar
1 vote
0 answers
174 views

A series of conjectures on $\sum_{x=0}^{(p-1)/2}(\frac{x^5+cx^3+dx}p)$ (I)

Let $p$ be an odd prime. Here I introduce the sum $$S_p(c,d):=\sum_{x=0}^{(p-1)/2}\left(\frac{x^5+cx^3+dx}p\right)$$ with $c,d\in\mathbb Z$, where $(\frac{\cdot}p)$ is the Legendre symbol. I have a ...
Zhi-Wei Sun's user avatar
  • 15.6k
0 votes
1 answer
669 views

Paradox in additive combinatorics

Let $S$ be an infinite set of positive integers. Let us define the following quantities: $N_S(z)$ is the number of elements of $S$, less or equal to $z$ $r_S(z)$ if the number of positive integer ...
Vincent Granville's user avatar
-3 votes
2 answers
606 views

The number of totatives to the nth primorial, in an interval shorter than the nth primorial

(The notation of this question will be improved over the next few days, sorry for the lack of clarity at the moment.) Can, and if so when can, we determine the amount of natural numbers which are ...
Brad Graham's user avatar
65 votes
6 answers
14k views

What is the simplest proof that the density of primes goes to zero?

By density of primes, I mean the proportion of integers between $1$ and $x$ which are prime. The prime number theorem says that this is asymptotically $1/\log(x)$. I want something much weaker, namely ...
Kim's user avatar
  • 4,164
53 votes
5 answers
4k views

Distribution of square roots mod 1

I was wondering about the distribution of $\sqrt{p}$ mod $1$ this morning, as one does while brushing one's teeth. I remembered the paper of Elkies and McMullen (Duke Math. J. 123 (2004), no. 1, 95–...
Marty's user avatar
  • 13.3k
49 votes
4 answers
4k views

Strange (or stupid) arithmetic derivation

Let us consider the following operation on positive integers: $$n=\prod_{i=1}^{k}p_i^{\alpha_i} \qquad f(n):= \prod_{i=1}^{k}\alpha_ip_i^{\alpha_i-1}$$ (Is it true that if we apply this operation to ...
Daniel Soltész's user avatar
48 votes
4 answers
3k views

Twin primes conjecture and extrapolation method

Let $(p_1, p_2)$ be a twin prime pair, where we include $(2, 3)$. If $p_1 \equiv 1$ mod $4$ then we let $t_{(p_1, p_2)} := p_1 ^ 2 / p_2 ^ 2$ otherwise, we let $t_{(p_1, p_2)} := p_2 ^ 2 / p_1 ^ 2$. ...
Dimitris Valianatos's user avatar
37 votes
3 answers
1k views

Is there a $c > 1$ such that for all $n \ge 1$ the largest integer $\le c^n$ is prime?

Does there exist a real number $c > 1$ such that for every natural number $n > 0$, the number $\lfloor c^n \rfloor$ is prime? I doubt such a number $c$ is known to exist, since the best similar ...
John Baez's user avatar
  • 22.3k
36 votes
8 answers
32k views

What are the connections between pi and prime numbers?

I watched a video that said the probability for Gaussian integers to be relatively prime is an expression in $\pi$, and I also know about $\zeta(2) = \pi^2/6$ but I am wondering what are more ...
36 votes
2 answers
7k views

Why do primes dislike dividing the sum of all the preceding primes?

I was investigating primes with the property that the sum of the first $n$ primes is divisible by $p_n$. It turns out that these primes are extremely extremely rare. For primes less than $10^9$, I ...
Nilotpal Kanti Sinha's user avatar
34 votes
1 answer
843 views

Can we write each positive rational number as $\frac1{p_1-1}+\ldots+\frac1{p_k-1}$ with $p_1,\ldots,p_k$ distinct primes?

It is well-known that any positive rational number can be written as the sum of finitely many distinct unit fractions. This is easy since $$\frac1n=\frac1{n+1}+\frac1{n(n+1)}\quad\text{for all}\ n=1,2,...
Zhi-Wei Sun's user avatar
  • 15.6k
32 votes
3 answers
8k views

Ideas in the elementary proof of the prime number theorem (Selberg / Erdős)

I'm reading the elementary proof of prime number theorem (Selberg / Erdős, around 1949). One key step is to prove that, with $\vartheta(x) = \sum_{p\leq x} \log p$, $$(1) \qquad\qquad \vartheta(x) \...
Basj's user avatar
  • 587
32 votes
2 answers
2k views

A Collatz-like problem on prime numbers

Consider the function $f$ on the prime numbers defined by $$ f(p):= \text{ the greatest prime factor of } 2p+1.$$ The iteration of $f$ from any prime $p<10^8$ converges to the cycle $$(3,7,5,11,23,...
Sebastien Palcoux's user avatar
29 votes
4 answers
3k views

Is there an 11-term arithmetic progression of primes beginning with 11?

i.e. does there exist an integer $C > 0$ such that $11, 11 + C, ..., 11 + 10C$ are all prime?
Kim's user avatar
  • 4,164

1
2
3 4 5
7