MathOverflow
Vincent Granville's user avatar
Vincent Granville's user avatar
Vincent Granville's user avatar
Vincent Granville
  • Member for 4 years, 4 months
  • Last seen this week
Profile Activity
Stats
3,036
reputation
32k
reached
15
answers
77
questions
Communities
View all
About

Mathematician and machine learning professional. Visit my website MLtechniques.com.

Badges
View all badges
This user doesn’t have any gold badges yet.
7
silver badges
19
bronze badges
Top tags
View all tags
4
Score
48
Posts
52
Posts %
3
Score
23
Posts
25
Posts %
3
Score
13
Posts
14
Posts %
2
Score
24
Posts
26
Posts %
2
Score
19
Posts
21
Posts %
1
Score
28
Posts
30
Posts %
Top posts
View all questions and answers
All Questions Answers
Score Newest
question
23
More mysteries about the zeros of the Riemann zeta function
Dec 24, 2020
question
14
Normal numbers, Liouville function, and the Riemann Hypothesis
May 2, 2021
question
12
Strange behavior of $x_{n+1}=x_n +\lambda \sin x_n$
Jan 30, 2021
question
9
From holes in the image of peculiar functions to new perspective on the Riemann Hypothesis
Jun 25, 2022
question
9
Erroneous Wolfram result for $\sum_{k=1}^\infty (k^3 + a^3)^{-1}$, looking for correct formula
Sep 4, 2020
question
8
Does $x_0=1/3$ lead to periodicity in the logistic map $x_{k+1}=4x_k(1-x_k)$?
Feb 27
question
8
Solving functional equation $f(xy)=f(x+y)$ and Diophantine equations
Mar 23, 2022
question
6
Is this a Brownian motion?
Jan 29, 2022
question
6
Generalized prime number theorem and Riemann Hypothesis for non-number math objects
Jun 6, 2021
question
6
Algebraic and rational parts of a real number
Feb 4, 2021
Top Meta posts
2
0
5
How to find out why a post was deleted
Top network posts
View all network posts
46
Limit associated with a recursion
22
Derivative and calculus over sets such as the rational numbers
20
Simple recurrences converging to $\log 2, \pi, e, \sqrt{2}$ and so on
18
A simple irrational number with the same first 11,667,755 digits as $\frac{2}{3}$
17
Potentially new approach to factoring big numbers

Your privacy

By clicking “Accept all cookies”, you agree Stack Exchange can store cookies on your device and disclose information in accordance with our Cookie Policy.