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Is there a natural topology for subsets of a fixed topological space?

This question is an extension/clarification of the question: Is there a natural topology for sets of topological spaces? The Hausdorff distance assigns a distance to any two subspaces $X, Y$ of a ...
user39598's user avatar
  • 653
13 votes
2 answers
656 views

Is there a natural topology for sets of topological spaces?

The Gromov–Hausdorff metric makes a set of compact metric spaces into a metric space itself. I am wondering what some natural generalizations there are for arbitrary topological spaces. Namely, is ...
user39598's user avatar
  • 653
0 votes
1 answer
65 views

Is there a characterization of monoids that distribute over each other?

Let $(M, e_1, \times_1, e_2, \times_2)$ be an algebraic structure such that $(M, e_1, \times_1)$ and $(M, e_2, \times_2)$ are monoids $x \times_1 (y \times_2 z) = (x \times_1 y) \times_2 (x \times_1 ...
Keith's user avatar
  • 631
1 vote
0 answers
89 views

Measurability of a map involving probability measures

Let $X$ be a metrizable topological space and $\mathscr B_X$ the Borel $\sigma$-algebra on it. Let $\Delta X$ denote the set of probability measures on $(X,\mathscr B_X)$, and let $\mathscr B_{\Delta ...
triple_sec's user avatar
8 votes
0 answers
249 views
+300

Maps with small fibers between manifolds of equal dimension

The following question is an attempt to revise this one into what I intended. Important revisions are shown in bold. Are there any known examples of a compact Riemannian manifold $M$ with (possibly ...
Matthew Kvalheim's user avatar
13 votes
1 answer
859 views

Mistake on article about Bohr compactification?

$\DeclareMathOperator\b{b}\newcommand\B{{\operatorname B}}$I wish to get help understanding the content of two theorems of [Iva] that seem mutually contradictory. First some context. Let $\b(\mathbb{R}...
stgo's user avatar
  • 193
5 votes
1 answer
284 views

Codimension zero embeddings and maps with small fibers

Edit: as explained in my comment on alesia's answer, I mistakenly did not ask below the question I intended (due to my misguided efforts to simplify it). Thus, I revised and reposted my question here. ...
Matthew Kvalheim's user avatar
3 votes
0 answers
52 views

Does there exist a multi-valued "monotone" and "compact" map from a Boolean algebra to the "free" part of $\mathcal{P}(\kappa)$?

This is a follow-up to my previous question, which has a negative answer. Here is the most general version that I'm interested: Does there exist a Boolean algebra $A$, an infinite cardinal $\kappa$, ...
David Gao's user avatar
  • 2,830
12 votes
1 answer
395 views

Is $X\times X$ homeomorphic to $X$ for a space of probability measures?

Let $\mathcal M_1(S)$ be the (compact, metrizable) space of probability Borel measures on the circle $S=\{z\in\mathbb C: |z|=1\}$ with its weak $*$ topology, so $\mu_n\to\mu$ if and only if $$ \int_S ...
Christian Remling's user avatar
7 votes
1 answer
296 views

Lower bound on dimension required to disconnect manifold?

This question seems quite classical, but I don't quite know what subarea of topology it falls into. Suppose that removing the set $S$ disconnects the 2-torus $\mathbb{T}^2 = \mathbb{R}^2\diagup\mathbb{...
Ronnie Pavlov's user avatar
3 votes
1 answer
343 views

Fundamental group of the grid on $\mathbb{R}^\mathbb{N}$

The grid on $\mathbb{R}^2$ is defined by the set of points such that at most one coordinate is not an integer. With this in mind, e endow $\mathbb{R}^\mathbb{N}$ with the product topology, where $\...
Dominic van der Zypen's user avatar
10 votes
1 answer
662 views

Are there any tests for knowing whether a topological space admits a CW structure?

We know that for n $\ge$ 5, a manifold admits a piecewise linear structure if and only if its Kirby-Siebenmann class vanish and Galewski and Stern showed the existence of a similar invariant to test ...
Tyrannosaurus's user avatar
3 votes
1 answer
144 views

Jordan plane curve such that $\frac{d(g(x),g(y))}{d(x,y)}\to0$?

Write $g$ as the inverse of $f$. Is there a continuous injective $f:S^1\to C\subset\mathbb{R}^2$ such that $$ \displaystyle\sup_{d(x,y)<r}\dfrac{d(g(x),g(y))}{d(x,y)}\to0 $$ as $r\to0$? If you like,...
Chris Sanders's user avatar
9 votes
1 answer
295 views

Connected open sets in the topology generated by the collection of connected open sets

Let $(X,\mathcal{T})$ be a connected topological space. Let $\mathcal{T}'$ be the topology on $X$ that is generated by the collection of connected open sets in $(X,\mathcal{T})$. That is, the ...
Calvin Wooyoung Chin's user avatar
2 votes
0 answers
157 views

About the 7.3.5. Corollary of the book "Measure Theory" by V.I. Bogachev

According to the 7.3.5. Corollary of the book "Measure Theory" by V.I. Bogachev we have the following result: Let $(X,\tau)$ be a completely regular space and let $\Gamma$ be a family of ...
rfloc's user avatar
  • 647
14 votes
1 answer
500 views

Is there an 'unnatural' topological construction of an algebraically closed field of positive characteristic?

It's well known that while there is a natural topological construction of a nearly algebraically closed field of characteristic $0$, algebraically closed fields of positive characteristic seemingly ...
James E Hanson's user avatar
2 votes
1 answer
120 views

"Bad" valid edge contractions

In this paper, an edge contraction of a simplicial complex $\Gamma$ is defined as the operation of removing the neighborhood $N_e\Gamma$ of the edge $e=\{0,1\}$ and identifying $N_0\partial N_e\Gamma$ ...
Leo's user avatar
  • 21
8 votes
1 answer
437 views

Function $\phi$ such that $f(\phi(x,y)) = f(x) + f(y)$

I have a continuous function $f:\mathbb{R}^n\to\mathbb{R}$, and I am looking for a continuous (or at least measurable) function $\phi:\mathbb{R}^{2n}\to\mathbb{R}^n$ such that $f(\phi(x,y))=f(x)+f(y)$....
gmvh's user avatar
  • 3,065
3 votes
1 answer
132 views

Is the interval topology on ${\cal P}(\omega)/(\text{fin})$ connected?

If $(P,\leq)$ is a poset and $x\in X$, we let $\downarrow x = \{p\in P: p \leq x\}$, and $\uparrow x$ is defined dually. The collection $$\Big\{P\setminus (\downarrow x): x\in P\Big\} \cup \Big\{P\...
Dominic van der Zypen's user avatar
3 votes
2 answers
343 views

Cohomology version of Moore space

I asked this question on MSE a few days back but could not get any helpful response. So I am rewriting the post. It is known to me that given a simply connected finite dimensional (which is also level-...
piper1967's user avatar
  • 1,177
5 votes
1 answer
96 views

Preimage of a sublocale by a morphism of locales: description by nucleus?

For completeness of MathOverflow, and to avoid any possible misunderstanding, let me recall the following terminology and facts, which should be standard (experts skip the following 2–3 paragraphs ...
Gro-Tsen's user avatar
  • 32.5k
11 votes
0 answers
427 views

Is there a theory of completions of semirings similar to $I$-adic completions of rings?

Let $L = \text{Con } (\mathbb{N}, 0, +) \setminus \Delta$ be the lattice of monoid congruences on the naturals, excluding the trivial congruence. As it happens, every $\theta \in L$ is the meet of ...
Keith's user avatar
  • 631
3 votes
1 answer
90 views

Even covers and collectionwise normal spaces

We call $X$ strongly collectionwise normal if the set $\mathcal{U}_\Delta$ of all neighbourhoods of the diagonal $\Delta_X$ of $X\times X$ is a uniformity. This is equivalent to the property that for ...
Jakobian's user avatar
  • 1,211
3 votes
3 answers
255 views

Continuum-distanced complete, ultrametric space

Our professor asked us to find a complete metric space where the intersection of nested closed balls can be empty. The following space is such an example, and I would like to learn more on it (since ...
aleph2's user avatar
  • 637
0 votes
1 answer
99 views

A question about G-Hewitt spaces

In the paper linked below, S. A. Antonyan gives the following proposition without proof (in fact all results are given without proof). I need a proof of this theorem. If anyone has information on this ...
Mehmet Onat's user avatar
  • 1,367
3 votes
1 answer
249 views

Relation between $\mathbb{R}$ and the metric space of bounded functions $f:\mathbb{N}\to\mathbb{N}$

Let $\newcommand{\N}{\mathbb{N}}\newcommand{\B}{\mathbf{B}}\B(\N)$ be the collection of all bounded functions $f:\N\to\N$. (A function $f:\N\to\N$ is bounded if there is $M\in\N$ such that $f(k) < ...
Dominic van der Zypen's user avatar
1 vote
2 answers
202 views

Spaces $X$ with every compactification $0$-dimensional with $\beta X\setminus X$ not locally compact

Previously, in this post I've shown the following characterization of spaces with only zero-dimensional compactifications: Theorem. Let $X$ be strongly zero-dimensional and $\beta X\setminus X$ ...
Jakobian's user avatar
  • 1,211
1 vote
0 answers
41 views

Why does the Kieboom characterization of shape is restricted only to paracompact spaces?

Borsuk founded shape theory as an extension of homotopy theory, appropriate for spaces with bad local properties. Borsuks definition was applied only to compact metric spaces. Later, this was ...
Emo's user avatar
  • 111
2 votes
1 answer
131 views

Strong ultralimits?

I was going through the book Ultrafilters Throughout Mathematics and I came across the notion of ultralimits, defined below. Ultralimit. Let $(X,\tau)$ be a topological space, $(x_i)_{i\in I}$ be a ...
Ray's user avatar
  • 23
11 votes
2 answers
314 views

Spaces with every compactification $0$-dimensional which aren't locally compact

Recently I've proven the following theorem Theorem. Let $X$ be a zero-dimensional locally compact Hausdorff space. Then the following are equivalent: Every compactification of $X$ is zero-dimensional....
Jakobian's user avatar
  • 1,211
7 votes
2 answers
383 views

Connectivity of fibers under fibration replacement

Assume all the spaces mentioned below are simply connected CW complexes. Let $ f: X \to Y $ be a continuous surjctive map between CW complexes, where $ f $ is not necessarily a fibration. Assume that ...
piper1967's user avatar
  • 1,177
9 votes
1 answer
425 views

Delta-generated spaces vs CW complexes

$\newcommand\Top{\mathrm{Top}}\newcommand\CW{\mathrm{CW}}\newcommand\Deltagenerated{\text{$\Delta$-generated}}\newcommand\Spaces{\mathrm{Spaces}}\newcommand\DeltaSpaces{\text{$\Delta$-Spaces}}$I am ...
user39598's user avatar
  • 653
3 votes
1 answer
136 views

For $\mathbb R^n \times Q \cong \mathbb R^m \times Q $ must $n = m$? ($Q$ is the Hilbert cube)

There are several theorems describing the topology on hyperspaces of convex subsets of $\mathbb R^n$ under the Hausdorff metric. For example Antonyan and Jonard-Pérez prove the space of compact convex ...
Daron's user avatar
  • 1,955
1 vote
2 answers
127 views

Homeomorphism and boundary of a complementary component

Let $X\subset \mathbb R^2$ be compact and connected. My question is whether homeomorphisms of $X$ preserve boundaries of complementary components. More precisely, let $h:X\to X$ be a homeomorphism. ...
D.S. Lipham's user avatar
  • 3,317
30 votes
2 answers
2k views

Is every connected subgroup of a Euclidean space closed?

The question listed above (in the context of the complex numbers, but it is a reasonable question to ask in any dimension) was asked by a student in my complex analysis class, and I did not have an ...
Terry Tao's user avatar
  • 114k
8 votes
1 answer
198 views

Topological property of the space of probability measures

Suppose that $\mathbb{P}$ is the metric space of Borel probability measures on the interval $[0,1]$ equipped with the topology of $w^*$ convergence. Consider also $\mathbb{P}_{ac}, \mathbb{P}_{s}$ the ...
an_ordinary_mathematician's user avatar
0 votes
0 answers
43 views

Equivalent conditions for $z$-embeddability

I am looking for where this specific theorem of Blair is originally located: Theorem. Let $S\subseteq X$, the following are equivalent: $S$ is $z$-embedded If $A, B\subseteq S$ are disjoint zero-...
Jakobian's user avatar
  • 1,211
2 votes
0 answers
92 views

Geometric interpretation of flags and the role of the rook monoid and Kazhdan–Lusztig theory in $M_n(\mathbb{C})$

Let $G = GL_n(\mathbb{C})$, $B$ be its Borel subgroup, and $P$ a parabolic subgroup. The space $G/B$ corresponds to complete flags in $ \mathbb{C}^n$, and $G/P$ corresponds to partial flags. The ...
Learner's user avatar
  • 141
7 votes
2 answers
297 views

Compactly generated and paracompact $\Rightarrow$ Hausdorff?

In A Concise Course in Algebraic Topology by May, a proposition is stated that any open cover of a paracompact space has a numerable refinement, where the space is assumed to be compactly generated ...
LuckyJollyMoments's user avatar
9 votes
1 answer
625 views

The reals: a topological lattice in more than the obvious way?

Define a topological lattice as a (not necessarily bounded) lattice in $\textbf{Top}$, i.e. meet and join are continuous maps $X^2 \rightarrow X$. There are two obvious topological lattice structures ...
Keith's user avatar
  • 631
2 votes
1 answer
103 views

LCH spaces $X$ such that if $Y$ is a perfect image of $X$, then $Y$ is zero-dimensional

I am looking for locally compact Hausdorff spaces $X$ with the following property: If $f:X\to Y$ is a perfect map onto locally compact Hausdorff space $Y$, then $Y$ is zero-dimensional. One can see ...
Jakobian's user avatar
  • 1,211
7 votes
1 answer
339 views

Is $C(X, \{0,1\})$ locally compact?

Let $X$ be a locally compact Hausdorff space. Let $C(X, \{0,1\})$ be the space of continuous functions $X \to \{0,1\}$ with the compact-open topology, that is, the topology generated by the following ...
Luiz Felipe Garcia's user avatar
0 votes
1 answer
98 views

Is every subgroup closed in this complete, nondiscrete topological group?

Another question on Mathoverflow (here: Complete topological groups in which all subgroups are closed) asks if there exists a complete, nondiscrete topological group $G$ such that all subgroups of $G$...
Nick Belane's user avatar
0 votes
0 answers
42 views

Topologizing quasi orders with regards to products

This morning I was asked by a colleague for the "right" way to construct a topology on a quasi-order (aka preorder, a reflexive and transitive relation) such that the topology on a product ...
Steven Clontz's user avatar
4 votes
1 answer
239 views

True or false? Every left or right cancellative, duo semigroup is cancellative

A semigroup $S$ is duo if $aS = Sa$ for all $a \in S$, where $aS := \{ax: x \in S\}$ and similarly for $Sa$; for instance, every commutative semigroup is duo, and so is every group. On the other hand, ...
Salvo Tringali's user avatar
8 votes
2 answers
596 views

If a semigroup embeds into a group, then is it a subdirect product of groups?

The title has it all: Q. If a semigroup $S$ embeds into a group, then is $S$ (isomorphic to) a subdirect product of groups? If yes, then $S$ is a subdirect product of subdirectly irreducible groups,...
Salvo Tringali's user avatar
2 votes
2 answers
154 views

Closure of $C([0,1]^2)$ via weak*-topology [closed]

Let $C([0,1]^2)$ denote the set of continuous functions on $[0,1]^2$. Let $L^1([0,1]^2)$ be the set of all Lebesgue integrable functions on $[0,1]^2$. The dual space of $C([0,1]^2)$, denoted by $C^*([...
tom jerry's user avatar
  • 349
4 votes
0 answers
47 views

Are W-spaces with countable pseudocharacter first countable?

Cross-post of a question originally asked by Almanzoris on Mathematics Stack Exchange. A topological space $X$ is called W-space if P1 has a winning strategy at each point $x \in X$ for the following ...
Steven Clontz's user avatar
0 votes
1 answer
79 views

Dimension of a manifold derived from a dense $G_{\delta}$ subspace

Let $X,Y$ be (compact connected) topological manifolds of dimensions $n,m$, respectively. Assume that a dense $G_{\delta}$ subspace $A$ of $X$ is homeomorphic to a dense $G_{\delta}$ subspace $B$ of $...
William of Baskerville's user avatar
7 votes
2 answers
488 views

Is every cancellative semigroup a subdirect product of subdirectly irreducible cancellative semigroups?

By a classical result of Birkhoff (that is, Theorem 2 in [G. Birkhoff, Subdirect unions in universal algebra, Bull. AMS, 1944]) and the trivial fact that the class of semigroups is closed under the ...
Salvo Tringali's user avatar

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