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Non-vanishing of product of zero divisors in quotients modulo $n$

This might be of practical importance and even partial answer will help. Let $n$ be odd squarefree integer with known factorization $n=\prod p_i$ with $N$ prime factors. Later we are not asking about ...
joro's user avatar
  • 25.4k
3 votes
0 answers
130 views

Trace map on Ext group

Let $R$ be a (possibly non-commutative) unital ring and $M$ be a perfect left $R$-module. Then, we have the trace map $$ \operatorname{Tr}\colon \mathrm{Hom}_R(M,M)\to R/[R,R]\,. $$ According to the ...
Qwert Otto's user avatar
3 votes
2 answers
214 views

Characterize rings $R$, such that the countable product $P=R^N$ has the property that every finitely generated submodule of $P$ is free

What are the rings whose countable power has the property that every finitely generated submodule is free?
Rado's user avatar
  • 139
0 votes
1 answer
473 views

A subfield $R \subseteq \mathbb{C}(x,y)$ with 'many' generators $w$, $R(w)=\mathbb{C}(x,y)$

Let $R \subseteq \mathbb{C}(x,y)$ and assume that $R=\mathbb{C}(u,v)$, where $u,v \in \mathbb{C}[x,y]$ are algebraically independent over $\mathbb{C}$. Here $\mathbb{N}$ includes $0$. Assume that $R$ ...
user237522's user avatar
  • 2,837
0 votes
1 answer
379 views

Finitely generated and finitely presented [closed]

For a group, it seems fairly clear that finitely presented implies finitely generated. But what about the converse? Is there a finitely generated group that is not finitely presented. (Let's say ...
no upstairs's user avatar
1 vote
0 answers
107 views

A certain subfield of $\mathbb{C}(x,y)$

Let $A=\mathbb{C}(x+y,xy)$, the subfield of symmetric polynomials with respect to the involution $\alpha: (x,y) \mapsto (y,x)$. Denote $G_A=\{w \in \mathbb{C}(x,y) \ | \ \mathbb{C}(x+y,xy,w)=A(w)=\...
user237522's user avatar
  • 2,837
5 votes
1 answer
344 views

Surjection onto endomorphisms of multiplicative group of a field

Let $k$ be an algebraically closed field of characteristic $p > 0$. Denote by $k^\times$ the multiplicative group of $k$. There is a ring homomorphism given by restriction to $k^\times$ $$ \mathbb{...
Nicholas's user avatar
2 votes
2 answers
416 views

Tensor product over $\mathbb{Z}$ and p-adic integer ring $\mathbb{Z}_p$

Thanks for your reading. Suppose we have two $\mathbb{Z}_p$-modules $A,B$. Do we always have $A \otimes_{\mathbb{Z}} B \simeq A \otimes_{\mathbb{Z}_p} B$, as abelian groups or $\mathbb{Z}_p$-modules? ...
Rellw's user avatar
  • 319
5 votes
0 answers
140 views

Gelfand-Kirillov dimension and tensor products

$\DeclareMathOperator\GK{GK}$Let $k$ be the base field. The Gelfand-Kirillov dimension was introduced by Gelfand and Kirillov in their seminal paper on the Gelfand-Kirillov conjecture. A very famous ...
jg1896's user avatar
  • 3,318
3 votes
1 answer
188 views

Is there a uniform family of polynomials $f_p(x) =x^2 + a(p)x + b(p)$ such that $f_p(x)\in \mathbb{Z}[x]$ is irreducible and irreducible mod $p$?

Let $p\in\mathbb{Z}$ be a positive prime number. Is there a "uniform" family of polynomials $f_p(x) =x^2 + a(p)x + b(p)$ of degree two such that $f_p(x)\in \mathbb{Z}[x]$ is both irreducible ...
LSt's user avatar
  • 237
0 votes
0 answers
61 views

The theory of Groebner bases in Jordan case

There are many papers regarding spreading the theory of Groebner-Shirshov bases from Lie algebras to other nonassociative algebras. Also, it has been studied for associative algebras with operators ...
user118746's user avatar
5 votes
1 answer
197 views

Examples of cyclic A-infinity algebra

I am wondering about (references to) examples of cyclic A-infinity algebras- especially including explicit descriptions of the structure maps and pairing. Thanks a lot!
Jak's user avatar
  • 51
2 votes
0 answers
187 views

How to construct an explicit isomorphism of the split Quaternion Algebra $(a,b)_F$ over the field $F$ to $\mathrm{Mat}_2(F)$

$\DeclareMathOperator\Mat{Mat}$How to construct an explicit isomorphism of the split quaternion algebra $(a,b)_F$ over the field $F$ to $\Mat_2(F)$? As it is known that the algebra of quaternions is ...
Samuil Lee's user avatar
2 votes
0 answers
33 views

R be a semiprime ring, not right singular, and with finitely uniform dimension to the right

if R is a semiprime ring, not right singular, and with finitely uniform dimension to the right. how can I Show that if I is a non-zero right ideal of R, then there exists an element y ∈ I such that I ∩...
sara's user avatar
  • 21
3 votes
0 answers
106 views

Formulas for the line joining two points in the projective plane over a division algebra

Let $K$ be a[n associative] division algebra (= skew field). By the “projective plane” $\mathbb{P}^2(K)$ over $K$ I mean, as usual, the set of triples $(x,y,z)$ of elements of $K$, not all zero, up ...
Gro-Tsen's user avatar
  • 32.4k
0 votes
0 answers
81 views

Can every $\ast$-algebra be represented in this space of matrices?

Let $k$ be a field with characteristic $0$. For every set $X$, let $\mathcal{B}(X)$ be the set of (possibly infinite) matrices $T = (T_{x,y})_{x,y \in X}$ with coefficients in $k$ such that in each ...
Luiz Felipe Garcia's user avatar
3 votes
0 answers
100 views

Pairing on a Koszul dual pair

Let $A$ be a graded quadratic algebra over a field $k$, and suppose that it admits the Koszul dual $A^!$. I want to know if there is a natural pairing $A\otimes A^!\to k$ or something similar to this. ...
Qwert Otto's user avatar
1 vote
0 answers
37 views

Bounding the length of an R-module of matrices

Loosely related to this: Bounding the length in a module of evaluated skew polynomials Let $C$ be an $\mathbb{F}_q$-vector subspace of $m \times n$ matrices over $\mathbb{F}_q$. Assume WLOG that $m \...
JBuck's user avatar
  • 223
5 votes
2 answers
199 views

Determining the multiplication via addition and some unary operation

It is known that the addition operation in a skew-field $F$ (more generally, in a quasifield) is uniquely determined by the multiplication operation and the unary involutive operation $1_{-}:F\to F$, ...
Taras Banakh's user avatar
  • 41.8k
2 votes
1 answer
124 views

Proof of dynamic programming calculation of Levenshtein distance

Let s1 and s2 are 2 arbitrary strings with lengths l1 and ...
St.Antario's user avatar
2 votes
1 answer
149 views

Non-holonomic modules for $\mathcal{D}(X)$, where $X$ is an affine open subspace of the affine space

Let $k$ be any algebraically closed field of zero characteristic. Let $A_n$ be the n rank Weyl algebra, and $M$ a finitely generated module. We have that $GK(M)$ is always a positive integer and (...
jg1896's user avatar
  • 3,318
0 votes
0 answers
85 views

A naive looking question about Gelfand-Kirillov dimension

Let $A$ and $B$ two affine algebras, $A$ a subalgebra of $B$. If we have a left $A$-module $M$ we can extend the scalars: $B \otimes_A M$. I will denote the resulting $B$-module by $N$ How are $\...
jg1896's user avatar
  • 3,318
-1 votes
1 answer
209 views

Every abelian group can be embedded into a ring [closed]

Let $(G,0,+)$ be an abelian group. Does there always exist a ring with unity $(R,0,1,+,\cdot)$ and an injective homomorphism of groups $ \psi:(G,0,+)\rightarrow (R,0,+)$? Is this hard to prove, or are ...
Ândson josé's user avatar
1 vote
0 answers
118 views

Cyclic homology with coefficients in a bimodule

I've recently been trying to understand Hochschild and cyclic co/homology better, and I've noticed that while it's common to define the Hochschild homology $\mathrm{HH}_{\bullet}(A;M)$ of an $R$-...
Emily's user avatar
  • 11.8k
6 votes
1 answer
273 views

Let $f$, $g$ be two complex polynomials satisfying $f(x-1,y)g(x,y)=f(x,y)g(x-1,y-1)$, what we can say about $f$ and $g$?

Let $f$, $g$ be two non-zero polynomials in $\Bbb C[x,y]$ satisfying the identity $$ f(x-1,y)g(x,y)=f(x,y)g(x-1,y-1). $$ What we can say about $f$ and $g$? In particular, if $f$, $g$ are two non-zero ...
priyanshu chakraborty's user avatar
1 vote
0 answers
77 views

$M^2=0$ defines a Koszul algebra ? What if $M$ is Manin's endomorphism's of Koszul $A$ ? (Here $M^2=\sum_k M_{ik}M_{kj}$ - resembles $d^2=0$).)

Consider a matrix $M$ which elements $M_{ij}$ are generators of some algebra $K$, impose new relations: $M^2=0$ and get a new algebra $K_{2}$. Question 1: Is it true that $K_2$ is Koszul algebra when ...
Alexander Chervov's user avatar
1 vote
0 answers
60 views

Bounding the length in a module of evaluated skew polynomials

Let $R$ be a finite principal ideal ring, $S$ a Galois extension of $R$ of degree $m$ (so in particular $S$ is a free $R$-module of rank $m$, and we have an $R$-module isomorphism $S^n \cong \...
JBuck's user avatar
  • 223
1 vote
0 answers
162 views

Integral points on "complex exponential surface" in $\mathbb{C}^3$

I encountered the following object in $\mathbb{C}^3$ defined for $m\in\mathbb{N}$ by $$A_m:=\lbrace (z_1,z_2,z_3)\in\mathbb{C}^3|(2^{2z_3}m-1)2^{2z_1+z_2+1}+3^{z_2-1}(2^{2z_1}-2^2-3^{z_3+1}m)=0\rbrace$...
Jens Fischer's user avatar
11 votes
0 answers
436 views

A rather strange algebra

Let $k$ be an algebraic closed field of zero characteristic and $X$ an affine smooth variety, with $A=\mathcal{O}(X)$ the algebra of regular functions and $\mathcal{V}$ the Lie algebra of vector ...
jg1896's user avatar
  • 3,318
1 vote
0 answers
189 views

The existence of solutions to linear systems of equations over the integer ring $\mathbb{Z}$

There are already detailed results on the solutions of linear equations over fields, but I'd like to inquire about any good conclusions regarding the solutions of linear equations over the integer ...
lunch zheng's user avatar
3 votes
0 answers
40 views

Filtering a pre-Koszul algebra to get a homogeneous associated graded algebra

In Priddy's paper "Koszul resolutions", on p. 42 he defines an algebra $A$ to be pre-Koszul if it can be written as a quotient of a free algebra $F = F\langle x_i \rangle$ with generators $\{...
John Palmieri's user avatar
0 votes
0 answers
34 views

Support of a function acting on an algebra?

Quick: for a measurable function $f$ its support on Euclidean space is clearly just the subset where $f$ does not vanish. Now, let’s have $f$ acting on an finite Lie algebra, f.e. $\mathfrak{gl}$ as $...
relativeentropy's user avatar
0 votes
0 answers
71 views

When is a submodule trivial?

I am a beginner concerning module theory, but I need it for my PhD. Sorry for obvious questions therefore. Given a left $C(G)$-module $(V, \tilde{\rho})$ where $C(G)$ denotes the group algebra over a ...
relativeentropy's user avatar
0 votes
0 answers
46 views

submodules in a direct sum of semisimple modules without common simple factors

Let $A$ be an associative (unital) algebra. Let $M_1,\cdots, M_r$ be pairwise non-isomorphic simple $A$-modules and let $V=\bigoplus^r_{i=1}V_i$, where $$ V_i=M_{i,1}\oplus \cdots\oplus M_{i,n_i}\...
Yong Hu's user avatar
  • 620
0 votes
0 answers
64 views

Proof of a folkloric result about PI-algebras [duplicate]

I am not not an specialist in PI-algebras, but I can say I have a rather good understanding on the subject. It is, of course, interesting to discover if an algebra $A$ is a PI-algebra. But it is also ...
jg1896's user avatar
  • 3,318
5 votes
2 answers
397 views

Ring with vanishing $K_0$

Suppose we have a ring $R$ such that the Grothendieck group $K_{0}(R)=0$. Question 1: Does it follow that there exists two positive natural numbers $n\neq m$ such that $R^{m}$ is isomorphic to $ R^{n}$...
cellular's user avatar
  • 855
0 votes
0 answers
106 views

Is there a counterpart to "a group acting on a space" to "a ring acting on a space", especially if the space is a (Lie) algebra?

I have read something that comes close to this is a module, but as I have understood, a module requires my space to be an abelian group, which would not be the case for a Lie algebra. So, if I have ...
relativeentropy's user avatar
0 votes
0 answers
124 views

Do unitary adjoint representations on $\mathfrak{sl}$ form a ring?

I am not too deep into abstract algebra, but I need it badly for my PhD. Therefore, I would be happy for some help here! I try to give some sense into: Let $\mathrm{Ad}_{g*}M= U^\dagger M U$ be a ...
relativeentropy's user avatar
3 votes
1 answer
472 views

Tips for how I can proceed with my Lie theoretical problem?

$\DeclareMathOperator\SL{SL}$I am looking at a map from a Lie group into a Lie algebra $\phi$: $$\phi: \SL(n)\rightarrow \mathfrak{sl}_n$$ $$ P \rightarrow U_1^\dagger P U_1 + U_2^\dagger P U_2.$$ $P$ ...
relativeentropy's user avatar
1 vote
1 answer
363 views

Proj construction and nilpotent homogenous elements in graded ring

Let $A= \bigoplus_{n \ge 0} A_n$ be a commutative Noetherian graded ring and $f \in A_d$ a nonzero homogeneous element of degree $d>0$. The natural ring map $q:A \to A/(f)$ induces a well defined ...
user267839's user avatar
  • 5,998
0 votes
0 answers
33 views

determinantal ideal of sum of Galois conjugate matrices

Given $n$ matrices $A_i \in \mathbb{Z}^{m\times m}$. I am interested in the ideal $I_d(A)$ generated by the $d\times d$-minors of $A = \sum_{i=1}^n x_iA_i \in \mathbb{Z}[x_1, \dots , x_n]$. The matrix ...
MatthysJ's user avatar
3 votes
1 answer
426 views

Is Malcev completion an embedding?

The Malcev completion of an abstract group $G$ over a field $k$ of characteristic zero is defined by $$\hat G = \mathbb{G}(\widehat{k[G]}) ,$$ the group-like part of the completed (by the augmentation ...
Qwert Otto's user avatar
0 votes
0 answers
103 views

Matrix of the minimal projective presentation of a $\tau$-rigid module

Let $A$ be a finite dimensional algebra over an algebraically closed field $\mathbb{K}$ of characteristics zero. Suppose $A$ is given by the bound quiver $(Q,I)$. We will use $P_l$ to denote the ...
It'sMe's user avatar
  • 839
0 votes
1 answer
54 views

Orthogonality in Hilbert algebras and congruence

Consider a finite-dimensional Hilbert space $V$ (say, over $\mathbb{C}$) and a finite-dimensional Hilbert algebra $A$ (i.e., Hilbert space with a compatible associative unitary algebra structure). ...
gm01's user avatar
  • 327
4 votes
0 answers
118 views

Adjoining new factors for primes in UFDs

It is well-known that if we pass from a UFD to a new ring where we have factored one of the primes, it does not need to stay a UFD. The classic example is passing from $\mathbb{Z}$ to $\mathbb{Z}[\...
Pace Nielsen's user avatar
  • 18.7k
2 votes
1 answer
158 views

How to decompose a given polynomial by ideal generators

Given a finite set of polynomials $f_1, f_2,..., f_n$ of variables $x_1,...,x_m$, generating the ideal $I$, suppose that we have one more polynomial $g\in I$. What is the algorythm for decomposing $g$ ...
Dmitri Scheglov's user avatar
6 votes
3 answers
434 views

What is known about finite dimensional modules over the nilCoxeter algebra?

Recall that the nilCoxeter algebra $\mathcal{N}_W$ for a Coxeter group $W$ is given by the $\mathbf{k}$-basis $x_w$ for each $w\in W$ and multiplication $x_ux_v=x_{uv}$ if $\ell(uv)=\ell(u)+\ell(v)$ ...
Christoph Mark's user avatar
1 vote
1 answer
115 views

Equivalent definition of Spin group in terms of automorphisms

Let $\mathrm{Cl}(\mathbb{R}^n)$ denote the (real) Clifford algebra on $\mathbb{R}^n$ with respect to the Euclidean inner product. Let $\mathrm{Cl}^0({\mathbb{R}^n})$ denote the even part of $\mathrm{...
geometricK's user avatar
  • 1,903
2 votes
0 answers
135 views

Tensor product of finite extensions of $\mathbb{Q}_p$

Consider the tensor product of finite extensions of a field $F$ of characteristic zero. (I am interested in the case $F=\mathbb{Q}_p$.) $(1)$ If $M$ is a finite Galois extension of $F$ with Galois ...
ZZP's user avatar
  • 622
1 vote
0 answers
148 views

Vanishing (infinite) tensor products

Since the advent of free probabilities and QFT, infinite tensor products of $R$-associative algebras with units has become more familiar to the working mathematician. Starting from the (permuting) ...
Duchamp Gérard H. E.'s user avatar

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