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For topological torus action, there is a subcircle whose fixed point is the same as the torus

Let $T=\mathbb{S}^{1}\times \mathbb{S}^{1}\times \cdots \times \mathbb{S}^{1} $ ($n$ times) be an $n$-dimensional torus acting on any topological space $X$. The group $G$ is said to act on a space $X$ ...
Mehmet Onat's user avatar
  • 1,367
4 votes
1 answer
469 views

How to calculate $\mathrm{TP}(\mathbb{F}_p[t])$?

$\DeclareMathOperator\TP{TP}$I am trying to learn about topological periodic cyclic homology following the notes: https://www.uni-muenster.de/IVV5WS/WebHop/user/nikolaus/Papers/Lectures.pdf https://...
onefishtwofish's user avatar
5 votes
0 answers
374 views

Comparing notions related to $(\infty,2)$-categories

I am trying to understand two related notions: $(\infty,2)$-category as in Definition 5.5.1.3, Kerodon weak $\infty$-bicategory as in Definition 4.1.1 in "$(\infty,2)$-Categories and the ...
Balaji Subramoniam's user avatar
1 vote
0 answers
154 views

Poincaré-Hopf Theorem for domains with a point of vanishing curvature

Consider $\Omega \subset \mathbb{R}^2$ a convex planar domain having positive curvature on the boundary except for a point $p \in \partial \Omega$ where the curvature vanishes. I would like to know ...
DrHAL's user avatar
  • 111
2 votes
2 answers
302 views

When is $\smash{\check{H}}^{q}(X,A;R)\cong H_{c}^{q}(X-A;R)$ for a pair $(X,A)$?

I'm trying to understand the proof of Corollary 1.3 part b. in a paper by Bestvina and Mess titled 'The Boundary of negatively curved groups'. I do not understand why $\smash{\check{H}}^{q}(X,A;R)\...
Harsh Patil's user avatar
1 vote
0 answers
168 views

Does the symmetric algebra functor preserve inclusions?

Theorem: For any compact abelian group $G$, the homogeneous component $% H^{2}\left( B_{G};% %TCIMACRO{\U{2124} }% %BeginExpansion \mathbb{Z} %EndExpansion \right) $ of degree $2$ is naturally ...
Mehmet Onat's user avatar
  • 1,367
1 vote
0 answers
133 views

A question about fixed point set of the compact group actions

Let $G$ be an infinite compact Lie group acting on a compact space $X$. Denote $F=F(G,X)=\{x\in X$ : $gx=x$ for all $g\in G\}$. Show that if $H^*(B_{G_x};\mathbb{Q})=0$ for all $x \notin F$ and $T^1$ ...
Mehmet Onat's user avatar
  • 1,367
3 votes
1 answer
150 views

Homogeneous regular (= polynomial component) maps with odd degree and their being global homeomorphisms in dimensions higher than one?

Let $F:\mathbb{R}^m \to\mathbb{R}^m, F:=(F_1\dots F_m)$ be a regular map, i.e. with components $F_i$ that are polynomials. Assume further that each $F_i$ is an odd degree (say $d$) homogenous ...
Learning math's user avatar
3 votes
1 answer
243 views

Applications of Thom's first isotopy lemma

Thom's first isotopy lemma says that given a smooth map $f:M\to P$ between smooth manifolds, and a closed Whitney stratified subset $S$ of $M$, such that $f|_S:S\to P$ is proper and $f|_X:X\to P$ is a ...
RKS's user avatar
  • 585
8 votes
1 answer
470 views

Non-triviality of Whitehead products in wedges of CW-complexes

Suppose $X$ and $Y$ are finite, simply connected, based CW-complexes and $m,n\geq 2$. If $a\in \pi_m(X)$ and $b\in \pi_n(Y)$, then one can regard these as elements of the homotopy groups of $X\vee Y$. ...
J.K.T.'s user avatar
  • 517
15 votes
1 answer
787 views

If homotopy groups of spaces are identical, then stable ones are also identical?

Is it true that if pointed spaces $X, Y$ have the same homotopy groups $\pi_n(X) \cong \pi_n(Y)$, then they have the same stable homotopy groups $\pi^S_n(X) \cong \pi ^S_n(Y)$? In particular, is this ...
Arshak Aivazian's user avatar
2 votes
0 answers
164 views

Triviality of map $(\Sigma \theta)^*$

We know that there is a cofibration sequence $$S^{4n+1}\xrightarrow{\theta}\Sigma^{4m-1} Q_{n-m} \rightarrow \Sigma^{4m-1} Q_{n-m+1} \rightarrow S^{4n+2}\xrightarrow{\Sigma\theta}\Sigma^{4m} Q_{n-m}.$$...
Sajjad Mohammadi's user avatar
9 votes
1 answer
673 views

Homotopy groups of finite CW complex finitely generated as Lie algebra

This is probably a well-known question, but I haven't found the answer on MO or MSE. It is well-known that the homotopy groups of a finite CW complex $X$ need not be finitely presented, even as $\...
R. van Dobben de Bruyn's user avatar
10 votes
1 answer
493 views

Structure of second homotopy group of a compact CW complex

I am interested in the second (and higher as well) homotopy groups of compact CW complexes. I know these groups don't need to be finitely generated (e.g. for $S^1 \vee S^2$ they are not), but I'd like ...
SFSH's user avatar
  • 275
0 votes
0 answers
143 views

Cohomology ring of $\mathbb{P}(\mathcal{O}(-1)\oplus \mathcal{O})$

Let $\mathcal{O}(-1)$ be the Hopf bundle over $\mathbb{C}\mathbb{P}^\infty$. Let $\mathcal{O}$ be the trivial rank one bundle. Consider the projectivization of the rank two bundle $\mathcal{O}(-1)\...
asv's user avatar
  • 21.8k
1 vote
0 answers
77 views

Contractible orbit space of action of compact Lie group on Euclidean space

R. Oliver proved that the following in https://www.jstor.org/stable/1970955 Theorem: Any action of a compact Lie group on a Euclidean space has contractible orbit space. My question is that this ...
Mehmet Onat's user avatar
  • 1,367
5 votes
1 answer
472 views

Two spectral sequences arising from a simplicial spectrum

Let $X_\bullet$ be a simplicial spectrum, and let $X = |X_\bullet|$ be the geometric realization. Let's assume each $X_n$ is connective. From this situation, we can form two filtrations on $X$: the ...
Brian Shin's user avatar
7 votes
1 answer
601 views

do all two manifolds admit a three-colorable triangulation?

A triangulation of a two-manifold $M$ is three-colorable if all vertices of the triangulation can be colored red, green, or blue without any two adjacent vertices having the same color. My question: ...
A_Physicist.'s user avatar
7 votes
0 answers
191 views

Complex cobordism and integrable systems

In Jack Morava's paper On the complex cobordism ring as a Fock representation, it was remarked right at the beginning that complex cobordism may play a role in the theory of integrable systems. In ...
user1271629's user avatar
11 votes
0 answers
225 views

The algebras and coalgebras of the homology functor

My question is very simple, but I suspect far from the intuition with which singular homology is introduced. Consider singular homology as a functor $$H_n : {\sf Top}\times{\sf Ab} \to \sf Ab$$ This ...
fosco's user avatar
  • 13.6k
5 votes
0 answers
188 views

Are there known minimal models for the cohomology of semisimple Lie algebras?

My student and I recently found a cute construction of a minimal model for the cohomology of a Lie algebra $\mathfrak{g}$. This is a "minimal model" in the sense that it is a minimal chain-...
user509184's user avatar
  • 1,335
3 votes
0 answers
90 views

When does homology preserve inverse limits of Eilenberg-MacLane spaces?

Let $... \to G_3 \to G_2 \to G_1$ be an inverse system of abelian groups and $G$ the limit of the system. By a theorem of Goerss the integral homology of the Eilenberg-MacLane space $K(G,n)$ for $n &...
willie's user avatar
  • 499
2 votes
1 answer
179 views

On the existence, for $\langle X,R\rangle$ a finite presentation of a group $G$, of an exact sequence of $\mathbb{Z}G$ modules

From this Q&A -- for $\langle X,R\rangle$ a finite presentation of a group $G$, there is an exact sequence of $\mathbb{Z}G$ modules $$0\rightarrow\pi_{2}(Z)\rightarrow \mathbb{Z}G^{\oplus R}\...
Souvik Mandal 's user avatar
4 votes
0 answers
80 views

For a map $x: S^0 \to X$, $J(X,x) \otimes Y = 0$ iff $x \otimes 1_Y$ is nilpotent?

Let $X$ be a spectrum, and let $x : S^0 \to X$ be a map. Let the stable James construction $J(X,x)$ denote the free $E_1$ ring on the $E_0$-ring $(X,x)$. It is computed as the colimit of the $\Delta^{...
Tim Campion's user avatar
8 votes
0 answers
151 views

The James and Morse filtrations of homotopy groups

Denote by $JX$ the James construction on a path connected, well-pointed space $X$. This space is filtered by subspaces $X=J_1X\subseteq\dots\subseteq J_nX\subseteq\dots\subseteq JX$ and is the domain ...
Tyrone's user avatar
  • 5,596
2 votes
1 answer
236 views

Homotopy classes of homeomorphism vs. Homotopy classes of a biholomorphism

This is a more detailed question about my first question Representation theory and topology of Teichmüller space, I asked there how to understand: $$T_{g}\hookrightarrow Hom(\pi_{1}({S}),PSL_{2}(\...
Kenny S's user avatar
  • 77
4 votes
1 answer
251 views

On the initiality of the inclusion from the simplex category to the paracycle category

Thm B.3 of Nikolaus and Scholze shows that the natural inclusion $\Delta \to \Lambda_\infty$, from the simplex category to the paracycle category, is an initial functor, i.e. satisfies the hypotheses ...
Tim Campion's user avatar
2 votes
0 answers
199 views

Proposition 4.3.8 Qing Liu about flat morphisms of schemes

I have a problem with a detail of Qing Liu's proof of Proposition 4.3.8 (pag. 137 of "Algebraic Geometry and Arithmetic Curves"). The statement is: Let $Y$ be a scheme having only a finite ...
BernyPiffaro's user avatar
6 votes
1 answer
285 views

Is this $\mathbb C$-fibration over compact Riemann surface trivial?

I have a question about a complex manifold $M$ and a holomorphic submersion $p : M \to S$ to a compact complex curve satisfying the following conditions: $p^{-1}(x)$ is biholomorphic to $\mathbb{C}$ ...
Chicken feed's user avatar
3 votes
0 answers
189 views

Geometric realization of crossed square

Given a crossed square of groups, you can "totalize" it and get a 2 crossed module in the sense of Conduché "Modules croisés généralisés de longueur 2", then you can apply his ...
clovis chabertier's user avatar
2 votes
1 answer
391 views

Hypercover and hyper descent

I am trying to understand the descent condition using hypercovers. The condition says that a hyper cover of a scheme $X$ is a simplicial set $Y_{\bullet}$ that satisfies the condition $Y_n\rightarrow ...
Hello's user avatar
  • 23
0 votes
1 answer
376 views

Relation between trivial tangent bundle $\Leftrightarrow$ certain characteristic classes of tangent bundle vanish [closed]

We know that framing structure means the trivialization of tangent bundle of manifold $M$. string structure means the trivialization of Stiefel-Whitney class $w_1$, $w_2$ and half of the first ...
zeta's user avatar
  • 447
2 votes
0 answers
179 views

Differentials in the Atiyah-Hirzebruch spectral sequence for a bounded generalized cohomology theory

$\newcommand{\res}{\mathrm{res}}$Let $X$ be a connected finite CW complex, and let $E$ be a bounded spectrum. For simplicity, let me assume that it has homotopy groups concentrated in degrees 0,1,2. ...
JeCl's user avatar
  • 1,001
0 votes
0 answers
69 views

Number of connective orbit types of torus actions

Suppose that topological group $G$ acting on topological space $X$. If the set $\left\{ \left[ G_{x}\right] :x\in X\right\} $ is finite, where $\left[ G_{x}\right] $ denotes the conjugacy class of the ...
Mehmet Onat's user avatar
  • 1,367
4 votes
1 answer
210 views

A question about Gysin exact sequence for cohomology of the orbit space

There is a claim in the following thesis regarding the exact sequence of Gysin. Shouldn't the spherical bundle $\mathbb{S}^1 \rightarrow X \rightarrow X/\mathbb{S}^1$ be orientable for the Gysin exact ...
Mehmet Onat's user avatar
  • 1,367
6 votes
1 answer
429 views

Does $\pi_1(H)=0\Rightarrow \pi_3(G/H)=0$ for a simple and simply connected Lie group $G$?

$\DeclareMathOperator\SU{SU}$Let $G$ be a simple and simply-connected Lie group and $H\neq 1$ be a simple and simply connected subgroup, is it true that $\pi_3(G/H)=0$? If not, what is a counter-...
Davi Costa's user avatar
1 vote
0 answers
53 views

A question about acyclic fixed point set of torus action on acyclic space

Oliver claims in the article (A proof of the Conner conjecture) that any action of a torus on a paracompact $ %TCIMACRO{\U{2124} }% %BeginExpansion \mathbb{Z} %EndExpansion $-acyclic space of finite ...
Mehmet Onat's user avatar
  • 1,367
6 votes
0 answers
271 views

Reference to a definition of a graph homology

Let $G$ be a graph, and define $C_k$ to be the free abelian group on the homomorphisms from graphs $H$ such that $K_k$ is a minor of $H$ without needing to do any vertex deletions, only edge ...
Sean Longbrake's user avatar
5 votes
2 answers
474 views

The classifying space of any topological group is paracompact and locally contractible

I read somewhere that the classifying space $B_{G}$ for any topological group $G$ is paracompact and locally contractible. How can I prove this or can you give me a reference? Another question that I ...
Mehmet Onat's user avatar
  • 1,367
6 votes
2 answers
403 views

"canonical" framing of 3-manifolds

In Witten's 1989 QFT and Jones polynomial paper, he said Although the tangent bundle of a three manifold can be trivialized, there is no canonical way to do this. So if I understand correctly, ...
zeta's user avatar
  • 447
1 vote
0 answers
151 views

Witten's QFT Jones polynomial work on Atiyah Patodi Singer theorem and $\hat A$ genus over Chern character

In Witten's 1989 QFT and Jones polynomial paper, he wrote in eq.2.22 that Atiyah Patodi Singer theorem says that the combination: $$ \frac{1}{2} \eta_{grav} + \frac{1}{12}\frac{I(g)}{2 \pi} $$ is a ...
zeta's user avatar
  • 447
3 votes
1 answer
203 views

Simple closed curves in a simply connected domain

Let $U$ be a bounded simply connected domain in the plane. Let $K$ be the boundary (or frontier) of $U$. For every $\varepsilon>0$ is there a simple closed curve $S\subset U$ such that the ...
D.S. Lipham's user avatar
  • 3,317
4 votes
1 answer
273 views

Two $E_\infty$ structures on infinite matrices

Let $O$ be the infinite orthogonal group. By taking a colimit of the diagram of topological groups $O(1) \to O(2) \to O(3) \to \ldots$, we know $O$ has a continuous group operation given by matrix ...
guest313131's user avatar
3 votes
0 answers
227 views

Classifying spaces beyond CW complexes

We know that for a reasonable topological group $G$ (say a compact Lie group) admits a classifying space for $G$-bundles within the category of countable CW complexes. That means, there is a space $BG$...
UVIR's user avatar
  • 803
1 vote
1 answer
611 views

The Krull dimension of the tensor product of rings

The Krull dimension of a ring $R$ is defined as the length of the longest chain of prime ideals in it. Let $R_i$, for $i\in\mathbb{N}$ denote a sequence of commutative Noetherian rings of Krull ...
rr314's user avatar
  • 35
6 votes
1 answer
255 views

Does a complex-oriented $E_1$ ring spectrum (not assumed to have graded-commutative homotopy groups) receive a map from $MU$?

It's well-known that complex cobordism $MU^\ast$ is universal among complex-oriented associative, graded-commutative cohomology theories $E$. This means that if $E$ is a multiplicative cohomology ...
Tim Campion's user avatar
4 votes
0 answers
174 views

Do the nearby cycle and Beilinson's vanishing cycle functors commute?

Let $X$ be a complex algebraic variety with a pair of regular functions $f_1,f_2$. To these functions we can associate various functors: the nearby cycles functor $\Psi_{f_i}$, the vanishing cycles ...
Sergey Guminov's user avatar
4 votes
0 answers
116 views

Finding inverses of certain elements in the set of normal invariants of a smooth manifold

Let, $V$ denote the Stiefel manifold of 2-frames $V_{10,2}$ . Consider the the map $S_\text{diff} (V) \xrightarrow{\eta} N_\text{diff} (V) $ in the surgery exact sequence of a smooth manifold. . ...
Sagnik Biswas's user avatar
3 votes
2 answers
425 views

A question on the manifold $ \{n\otimes n-m\otimes m:n,m\in S^2,(n,m)=0\} $

Consider a manifold $ N $ defined as follows $$ N=\{n\otimes n-m\otimes m:n,m\in S^2,\quad(n,m)=0\}\subset M^{3\times 3}, $$ where $ S^2 $ denotes the two dimensional sphere, $ (\cdot,\cdot) $ ...
Luis Yanka Annalisc's user avatar
23 votes
3 answers
2k views

What are some toy models for the stable homotopy groups of spheres?

The graded ring $\pi_\ast^s$ of stable homotopy groups of spheres is a horrible ring. It is non-Noetherian, and nilpotent torsion outside of degree zero. Question: What are some "toy models" ...
Tim Campion's user avatar

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