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31 votes
1 answer
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Can the fundamental group of any manifold be realized as the fund grp of a finite space?

Recently, I was asked to calculate the fundamental group of the space $X= \{a,b,c,d\}$ with open sets generated by $\{ a, c, abc, acd \}$. Turns out, $\pi_1(X)\cong \mathbb Z$ and in fact, $X$ is the ...
Abhishek Parab's user avatar
31 votes
3 answers
3k views

Are the higher homotopy groups of the Hawaiian earring trivial?

The fundamental group of the Hawaiian earring is very complicated, but since it's "1-dimensional" one might guess that the higher homotopy groups vanish. Do they? Since the Hawaiian earring does not ...
Noah Snyder's user avatar
  • 28.1k
31 votes
4 answers
4k views

Fibrations and Cofibrations of spectra are "the same"

My question refers to a folklore statement that I have now seen a couple of times, but never really precise. One avatar is: "For spectra every cofibration is equivalent to a fibration" (e.g. in the ...
Simon Markett's user avatar
31 votes
6 answers
5k views

Book recommendation for cobordism theory

I am planning to organize a seminar on cobordism theory and I'm looking for a reference. Such a reference is preferably a book, but I'm open to other ideas. The audience is familiar with ...
Thomas Rot's user avatar
  • 7,583
31 votes
4 answers
8k views

What is 'formal' ?

The key step in Kontsevich's proof of deformation quantization of Poisson manifolds is the so-called formality theorem where 'a formal complex' means that it admits a certain condition. I wonder why ...
Xiao Xinli's user avatar
31 votes
3 answers
2k views

Is the counit of geometric realization a Serre fibration?

Recall that a Serre fibration between topological spaces is a map which has the homotopy lifting property (HLP) for all CW complexes (equivalently for all disks $D^k$). The Serre fibrations are the ...
Chris Schommer-Pries's user avatar
31 votes
2 answers
2k views

Why is the motivic category defined over the site of smooth schemes only?

Fix a base scheme $S$. Stable and unstable motivic categories over $S$ are defined as certain categories of higher stacks on the Nisnevich site $Sm_S$ of smooth schemes over $S$. Why smooth? As a ...
Tim Campion's user avatar
  • 63.9k
31 votes
3 answers
3k views

Why aren't there more classifying spaces in number theory?

Much of modern algebraic number theory can be phrased in the framework of group cohomology. (Okay, this is a bit of a stretch -- much of the part of algebraic number theory that I'm interested in...)....
Cam McLeman's user avatar
  • 8,467
31 votes
2 answers
3k views

A natural construction of real numbers?

Summary Someone claims $\mathbb{R}$ can be constructed as the following intriguing quotient, which is related to Gromov's bounded cohomology. I want to find out if it is true. $$\frac{\bigl\{f:\mathbb{...
Student's user avatar
  • 5,230
31 votes
3 answers
4k views

Algebras over the little disks operad

Hello, The so-called "recognition principle" of Boardman-Vogt and May leaves me unsatisfied. My problem is the following: The "recognition principle" says that every "group-like" algebra over the ...
Oblomov's user avatar
  • 2,521
31 votes
2 answers
1k views

Is Lie group cohomology determined by restriction to finite subgroups?

Consider the restriction of the group cohomology $H^*(BG,\mathbb{Z})$, where $G$ is a compact Lie group and $BG$ is its classifying space, to finite subgroups $F \le G$. If we consider the product of ...
overcaffeinated's user avatar
31 votes
1 answer
3k views

What was the error in the proof of Roos' theorem?

Background: In 1961, Roos (who, sadly, apparently passed away just last month) purported to prove [1] that in an abelian category with exact countable products (AB4${}^\ast_\omega$), limits of inverse ...
Tim Campion's user avatar
  • 63.9k
31 votes
1 answer
4k views

For which varieties is the natural map from the Chow ring to integral cohomology an isomorphism?

My apologies if this question is too naive. Let $X$ be a smooth projective complex variety. There is a natural map $A^{\bullet}(X) \to H^{2\bullet}(X)$ of graded rings from the Chow ring of $X$ to ...
Qiaochu Yuan's user avatar
31 votes
1 answer
2k views

K(r)-localization and monochromatic layers in the chromatic spectral sequence

While preparing some lecture notes, I had a basic point of confusion come up that I haven't been able to settle. The $BP$-Adams spectral sequence (or $p$-local Adams-Novikov spectral sequence) for ...
Eric Peterson's user avatar
31 votes
1 answer
2k views

A modern interpretation of Quillen's computation of the K theory of finite fields

In his beautiful paper On the cohomology and K theory of the general linear group over a finite field, Quillen constructs (if I understand correctly) an isomorphism on connected components of K-theory ...
Dmitry Vaintrob's user avatar
31 votes
1 answer
1k views

What results about the topology of manifolds depend on the dimension mod 3?

There are a lot of interesting results about the topology of manifolds that depend on the dimension of the manifold mod 2, mod 4, or mod 8. The simplest ones involve the cup product $$ \smile \colon ...
John Baez's user avatar
  • 22.3k
31 votes
0 answers
866 views

The central insight in the proof of the existence of a class of Kervaire invariant one in dimension 126

I understand from a helpful earlier MO question that the techniques leading to the celebrated resolution of the Kervaire invariant one problem in the other candidate dimensions yield no insight on ...
jdc's user avatar
  • 2,995
31 votes
0 answers
2k views

When is a compact topological 4-manifold a CW complex?

Freedman's $E_8$-manifold is nontriangulable, as proved on page (xvi) of the Akbulut-McCarthy 1990 Princeton Mathematical Notes "Casson's invariant for oriented homology 3-spheres". Kirby showed that ...
Andrew Ranicki's user avatar
30 votes
6 answers
3k views

Poincare duality and the $A_\infty$ structure on cohomology

If $X$ is a topological space then the rational cohomology of $X$ carries a canonical $A_\infty$ structure (in fact $C_\infty$) with differential $m_1: H^\ast(X) \to H^{\ast+1}(X)$ vanishing and ...
Jeffrey Giansiracusa's user avatar
30 votes
5 answers
4k views

The role of ANR in modern topology

Absolute neighborhood retracts (ANRs) are topological spaces $X$ which, whenever $i\colon X\to Y$ is an embedding into a normal topological space $Y$, there exists a neighborhood $U$ of $i(X)$ in $Y$ ...
30 votes
3 answers
3k views

Why is homology not (co)representable?

This is in the same vein as my previous question on the representability of the cohomology ring. Why are the homology groups not corepresentable in the homotopy category of spaces?
Dinakar Muthiah's user avatar
30 votes
2 answers
2k views

Does there exist any non-contractible manifold with fixed point property?

Does there exist any non-trivial space (i.e not deformation retract onto a point) in $\mathbb R^n$ such that any continuous map from the space onto itself has a fixed point. I highly suspect that the ...
Anubhav Mukherjee's user avatar
30 votes
5 answers
5k views

What's special about the Simplex category?

I have been wondering lately what makes simplicial sets 'tick'. Edited The category $\Delta$can be viewed as the category of standard $n$-simplices and order preserving simplicial maps. The goal of ...
user avatar
30 votes
4 answers
3k views

Is the space of diffeomorphisms homotopy equivalent to a CW-complex?

Clarification: My question concerns the homotopy type of the space of $C^k$ diffeomorphisms with the compact-open $C^k$ topology, where $0< k \leq\infty$. I have stated my question below with $k=1$ ...
Ricardo Andrade's user avatar
30 votes
2 answers
2k views

Unstable homotopy groups of spheres beyond Toda's range

In 1962 Toda published his book "Composition methods in homotopy groups of spheres", which contains computations of $\pi_{n+k}(S^n)$ for $k\le 19$ and $n\le 20$. The values of these groups are ...
Mark Grant's user avatar
  • 35.9k
30 votes
1 answer
1k views

Are homeomorphic representations isomorphic?

Let $G$ be a finite group. Let $V_1, V_2$ be two finite-dimensional real representations. Suppose $f: V_1 \to V_2$ is a $G$-equivariant homeomorphism. Can one conclude that $V_1$ and $V_2$ are ...
UVIR's user avatar
  • 803
30 votes
3 answers
3k views

Mumford conjecture: Heuristic reasons? Generalizations? ... Algebraic geometry approaches?

The Mumford conjecture states that for each integer $n$, we have: the map $\mathbb{Q}[x_1,x_2,\dots] \to H^\ast(M_g ; \mathbb{Q})$ sending $x_i$ to the kappa class $\kappa_i$, is an isomorphism in ...
Kevin H. Lin's user avatar
30 votes
1 answer
2k views

Morava K-theories for dummies?

Professor Urs Würgler passed away one year ago, and his wife engraved his tombstone with "the formula he was the most proud of" : $B(n)_*(X)\cong P(n)_*(K(n))\square_{\Sigma_n}K(n)_*(X)$ However ...
Dr. Goulu's user avatar
  • 403
30 votes
1 answer
2k views

Two questions on rational homotopy theory

I'm trying to read Quillen's paper "Rational homotopy theory" and am a little confused about the construction. As I understand, he associates a dg-Lie algebra over $\mathbb{Q}$ to every 1-reduced ...
Akhil Mathew's user avatar
  • 25.6k
30 votes
3 answers
3k views

Examples for non-naturality of universal coefficients theorem

Does anyone have good examples of a space $X$ and a map $f: X \to X$ so that $f_*: H_*(X) \to H_*(X)$ is the identity but (e.g.) $f_*: H_*(X; \mathbb{F}_2) \to H_*(X; \mathbb{F}_2)$ is not the ...
Dylan Thurston's user avatar
30 votes
5 answers
2k views

Is the universal covering of an open subset of $\mathbb{R}^n$ diffeomorphic to an open subset of $\mathbb{R}^n$ ?

Is the universal covering of a connected open subset $U$ of ℝn diffeomorphic to an open subset of ℝn (standard differentiable structure)? If not true in general, is there any condition ...
Fiamma Battaglia - Elisa Prato's user avatar
30 votes
1 answer
3k views

What is, really, the stable homotopy category?

When you try to understand the fuss behind the new good categories of spectra that arose on the 90's, you read things such as the following paragraph written by Peter May (from "The Hare and the ...
Bruno Stonek's user avatar
  • 3,004
30 votes
1 answer
2k views

Identifying the stacks in Devinatz-Hopkins-Smith

I read the Devinatz-Hopkins-Smith proof of the nilpotence conjectures last year, and while I followed along sentence to sentence I don't think I understood much of the motivating reasons for why what ...
Eric Peterson's user avatar
30 votes
1 answer
787 views

Is a filtered colimit of rational spaces again rational?

Let me first explain the statement of the question and then give some indication why the answer might be 'yes'. By a space I mean, say, a simplicial set and by rational I mean rational in the sense of ...
Thomas Nikolaus's user avatar
30 votes
1 answer
2k views

Which of the proofs of the fundamental theorem of algebra can actually produce bounds on where the roots are?

One of the old classic MO questions is a big-list of proofs of the fundamental theorem of algebra. Here is a second big-list question about this big list: Which of the FTA proofs can, even in ...
Qiaochu Yuan's user avatar
30 votes
0 answers
1k views

Todd class as an Euler class

Let $X$ be a relatively nice scheme or topological space. In various physics papers I've come accross, the Todd class $\text{Td}(T_X)$ is viewed as the Euler class of the normal bundle to $X\to LX$. ...
Pulcinella's user avatar
  • 5,701
30 votes
0 answers
2k views

Why do Clifford algebras determine $KO$ (and $K$-)-theory?

In the paper "Clifford modules" by Atiyah-Bott-Shapiro, they construct a family of Clifford algebras $C_k$ over the real numbers, so that $C_k$ is the algebra associated to a negative definite form on ...
Akhil Mathew's user avatar
  • 25.6k
29 votes
10 answers
3k views

Are infinite dimensional constructions needed to prove finite dimensional results?

Infinite dimensional constructions, such as spaces of diffeomorphisms, spectra, spaces of paths, and spaces of connections, appear all over topology. I rather like them, because they sometimes help me ...
Daniel Moskovich's user avatar
29 votes
5 answers
13k views

(Co)homology of the Eilenberg-MacLane spaces K(G,n)

Let $(G, n)$ be a pair such that $n$ is a natural number, $G$ is a finite group which is abelian if $n \geq 1$. It is well-known that $\pi_n(K(G,n)) = G$ and $\pi_i (K(G,n)) = 0$ if $i \neq n$. Also ...
Akela's user avatar
  • 3,699
29 votes
3 answers
3k views

The homotopy category is not complete nor cocomplete

I understand that the homotopy category of (pointed) topological spaces and continuous maps is not complete. Nor is it cocomplete. In particular it neither has all pullbacks nor all pushouts. What ...
Tyrone's user avatar
  • 5,596
29 votes
3 answers
5k views

finite generated group realized as fundamental group of manifolds

This is discussed in the standard textbooks on algebraic topology. Pick a presentation of the group $G = \langle g_1,g_2,...,g_n|r_1,r_2,...r_m \rangle$ where $g_i$ are generators and $r_j$ are ...
sara's user avatar
  • 291
29 votes
7 answers
4k views

Why does the group act on the right on the principal bundle?

In many textbooks, in fact all textbooks I've seen, the fiberwise group action on the principal bundle is on the right. It seems to me that left actions and right actions are essentially the same. ...
Hwang's user avatar
  • 1,398
29 votes
4 answers
5k views

Quillen's motivation of higher algebraic K-theory

Almost the same question was already asked on MO Motivation for algebraic K-theory? However, to my taste, the answers there consider the subject from a more modern point of view. When I open a book ...
asv's user avatar
  • 21.8k
29 votes
4 answers
4k views

Model structure on Simplicial Sets without using topological spaces

The category of simplicial sets has a standard model structure, where the weak equivalences are those maps whose geometric realization is a weak homotopy equivalence, the cofibrations are ...
J Williams's user avatar
  • 1,292
29 votes
4 answers
3k views

origin of spectral sequences in algebraic topology

I have the following somewhat vague question. I am not sure if it is appropriate for this forum, please feel free to close (or migrate to stackexchange). I have been "brought up" as an algebraic ...
Tom Bachmann's user avatar
  • 1,961
29 votes
6 answers
4k views

Concrete example of $\infty$-categories

I've seen many different notions of $\infty$-categories: actually I've seen the operadic-globular ones of Batanin and Leinster, and the opetopic, and eventually I'll see the simplicial ones too. ...
Giorgio Mossa's user avatar
29 votes
5 answers
2k views

Homotopy groups of spheres in a $(\infty, 1)$-topos

Let $H$ be an $(\infty,1)$-topos (seen as a generalization of the homotopy category of spaces). You can define the suspension of an object $X$ as the (homotopy) pushout of $*\leftarrow X \to *$, ...
Guillaume Brunerie's user avatar
29 votes
2 answers
2k views

A simple proof that parallelizable oriented closed manifolds are oriented boundaries?

So let $M$ be a smooth closed orientable real manifold such that $M$ is parallelizable, i.e., the tangent space $TM$ of $M$ is trivial. From the triviality of $TM$ we get that the Stiefel-Whitney and ...
Hugo Chapdelaine's user avatar
29 votes
4 answers
3k views

Conceptual proof of classification of surfaces?

Every compact surface is diffeomorphic to $S^2$, $\underbrace{T^2\#\ldots \#T^2}_n$, or $\underbrace{RP^2\#\ldots \#RP^2}_n$ for some $n\ge 1$. Is there a conceptual proof of this classification ...
André Henriques's user avatar
29 votes
1 answer
897 views

Is there an explicit description of a cobordism between $\mathbb{CP}^n$ and $\mathbb{RP}^n\times\mathbb{RP}^n$?

With a little bit of work, one can show that $\mathbb{CP}^n$ and $\mathbb{RP}^n\times\mathbb{RP}^n$ have the same Stiefel-Whitney numbers, so by a theorem of Thom, they are (unorientedly) cobordant. ...
Michael Albanese's user avatar

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