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When $\lambda$-commutativity implies commutativity?

Let $\mathcal{B}(F)$ the algebra of all bounded linear operators on an infinite-dimensional complex Hilbert $F$. Let $T,S\in\mathcal{B}(F)$. The pair $(T,S)$ is said to $\lambda$-commute if there ...
Schüler's user avatar
  • 724
1 vote
1 answer
98 views

If $\text{Im}(S^*M)\subseteq \text{Im}(M)$, is $\text{Im}(SM)\subseteq \text{Im}(M)$?

Let $F$ be a complex Hilbert space and $\mathcal{B}(F)$ the algebra of all bounded linear operators defined on $F$. Assume that $M\in \mathcal{B}(F)^+$ (i.e. $\langle Mx\;, \;x\rangle\geq 0$ for all ...
Schüler's user avatar
  • 724
4 votes
0 answers
120 views

Reductive Operator Problem

In the 1972 paper ''An equivalent Formulation of the Invariant Subspace Conjecture'' Dyer, Pedersen, and Porcelli announce the following result: The Invariant Subspace Problem has a positive ...
Adi Tcaciuc's user avatar
3 votes
1 answer
187 views

Algebraic tensor product of C*-algebras extends via ideals? Application to restriction theorem?

Is the following assertion and the proof below correct, or am I missing something very important? Moreover, would the corollaries be correct then? Besides, I would also appreciate a lot any comment, ...
C-star-W-star's user avatar
0 votes
1 answer
328 views

Find the trace for some elements in group algebra

Let $K=\langle b,c,d\mid b^{2}=c^{2}=d^{2}=bcd=1\rangle $. Now we consider $$D=K*\mathbb Z/2\mathbb Z=\left\{a,b,c,d\mid a^{2}=b^{2}=c^{2}=d^{2}=bcd=1\right\}$$ where $*$ is the free product. Then we ...
Jack's user avatar
  • 407
2 votes
0 answers
164 views

An operator valued Egoroff's theorem

The following statements suggests $B(H)$-valued Egoroff's theorem when $H$ is a separable Hilbert space. Probably it will be hold even if a von Neumann algebra $M$ whose predual is separable is ...
ABB's user avatar
  • 4,058
9 votes
0 answers
230 views

Using Property (T) to approximate invertible matrices

In the wikipedia article for Kazhdan's Property (T), there's an intriguing application: Similarly, groups with property (T) can be used to construct finite sets of invertible matrices which can ...
Eric Reckwerdt's user avatar
7 votes
2 answers
485 views

The von Neumann algebra generated by a non-closable operator

Let $H$ be a separable Hilbert space and let $M$ be a densely defined operator $\mathcal{D}(M) \subset H \to H$. It is closable iff its adjoint $M^{\star}$ is densely defined, and then its closure $\...
Sebastien Palcoux's user avatar
8 votes
1 answer
302 views

Does every integer map generate a von Neumann algebra of type I?

Consider a map $m: \mathbb{N} \to \mathbb{N}$ (we call it an integer map). Let $E_r$ be the set $m^{-1}(\{r\})$. Let $H$ be the Hilbert space $\ell^2(\mathbb{N})$ and consider the densely defined ...
Sebastien Palcoux's user avatar
2 votes
1 answer
341 views

Closed two-sided ideals in $C(X,M_n)$

As is known (see Kadison-Ringrose, 3.4.1) each closed ideal $I$ in the $C^*$-algebra $C(X)$ of continuous functions on a compact space $X$ has the form $$ I=\{f\in C(X): \ \forall x\in S\quad f(x)=0 \}...
Sergei Akbarov's user avatar
10 votes
0 answers
201 views

Masas in SAW*-algebras

I asked this question three years ago at MSe but it has no response; let me try here. Pedersen distilled the following class of C*-algebras which he termed SAW*-algebras (Journal of Operator Theory, ...
Tomasz Kania's user avatar
  • 11.3k
1 vote
0 answers
179 views

Positive square roots of inverse operators on different Sobolev spaces

Let $D$ be a self-adjoint (in the $H^0$-inner product) first-order differential operator on a manifold $M$, where $H^i$ stands for the $i$-th Sobolev space on $M$. Then $D$ extends to a bounded ...
geometricK's user avatar
  • 1,903
1 vote
0 answers
233 views

Bochner integrals with values in a Hilbert $A$-module

I'm wondering whether there exists a generalisation of Bochner integration with values in a Hilbert $A$-module $M$, where $A$ is a general $C^*$-algebra rather than $\mathbb{C}$ (and whether there are ...
geometricK's user avatar
  • 1,903
2 votes
1 answer
172 views

Why $\mathcal{B}_1(F)$ is not a subalgebra of $\mathcal{B}(F)$?

Let $\mathcal{B}(F)$ the algebra of all bounded linear operators on a complex Hilbert space $F$. Let $M\in \mathcal{B}(F)^+$ (i.e. $M^*=M$ and $\langle Mx\;, \;x\rangle\geq 0$ for all $x\in F$. I ...
Schüler's user avatar
  • 724
3 votes
1 answer
158 views

Showing the following inclusion between two subalgebras of $\mathcal{B}(F)$

Let $\mathcal{B}(F)$ the algebra of all bounded linear operators on a complex Hilbert space $F$. Let $M\in \mathcal{B}(F)^+$ (i.e. $M^*=M$ and $\langle Mx\;, \;x\rangle\geq 0$ for all $x\in F$). I ...
Schüler's user avatar
  • 724
2 votes
1 answer
941 views

Original statement of Naimark's dilation theorem

Naimark's dilation theorem in papers and textbooks is usually stated as: Let $E$ be a regular, positive, $B(\mathcal H)$-valued measure on $X$. Then there exists a Hilbert space $\mathcal K$, a ...
Chris Ramsey's user avatar
  • 3,984
2 votes
1 answer
238 views

Why is index unchanged after applying functional calculus?

Suppose $D$ is the Dirac operator on a closed spin manifold $M$, with spinors $S$. One can take the functional calculus of $D$ with respect to the continuous function $f:\mathbb{R}\rightarrow\mathbb{R}...
geometricK's user avatar
  • 1,903
2 votes
1 answer
411 views

Problem of convergence of the following sequence

Let $E$ be a complex Hilbert space, with inner product $\langle\cdot\;, \;\cdot\rangle$ and the norm $\|\cdot\|$. Let $T\in \mathcal{L}(E)$ be bounded linear operators from $E$ to $E$ and $M\in \...
Schüler's user avatar
  • 724
2 votes
0 answers
205 views

relative amenability of von Neumann algebra

Let $\cal{M}$ be a finite von Neumann algebra and $\cal{N}$ be a von Neumann subalgebra of $\cal{M}$. The von Neumann algebra $\cal{M}$ is is amenable relative to $\cal{N}$ if there exists a norm ...
Albert harold's user avatar
7 votes
0 answers
222 views

Can C*/W*-algebras be realized as (involutive?) monoid/co-monoid objects?

I would like to know how close one can get to realizing the category of C*-algebras as a category of monoid objects. Related (almost, but not quite, duplicate) questions are: "Recovering a monoidal ...
Tom Mainiero's user avatar
1 vote
1 answer
160 views

When will the $G$-invariant measure space be isomophic to the tracial state space of the crossed product $C^\ast$-algebra

Suppose a countable discrete amenable group $G$ acts continuously on a infinite Compact Hausdorff space $X$, i.e. $\alpha:G\curvearrowright X$. Suppose $\alpha$ is minimal. Write $M_G(X)$ for all $G$-...
Targaryen's user avatar
  • 181
4 votes
1 answer
201 views

closure of a separating set of pure states

Let $A$ be a unital C*-algebra, and let $\mathcal R$ be a separating family of irreducible representations of $A$. Each vector state of a representation in $\mathcal R$ is a pure state, and the span ...
Andre Kornell's user avatar
4 votes
1 answer
157 views

Norm of "tensoring" with the identity

Consider a Banach space $E$ and a discrete set $X$. For an operator $T$ on $\ell^2(X)$ I can consider and induced operator $T'$ on the Bochner-Lebesgue space $\ell^2(X;E)$ of $E$-valued square-...
duh's user avatar
  • 165
4 votes
0 answers
263 views

Approximately inner conditional expectations of $II_{1}$ factors

In many contexts it is helpful to think of conditional expectations as averages of unitary conjugates, a standpoint vindicated by many standard techniques in the theory of finite von Neumann algebras. ...
Jon Bannon's user avatar
  • 7,057
1 vote
4 answers
367 views

Classification of $C^*$ algebras whose all non scalar elements have disconnected spectrum

To what extent have all unital $C^*$ algebras $A$ with the following property been classified? Is there a simple $C^*$ algebra with this property? Does $C(K)$ satisfy this property, where $K$ is an ...
Ali Taghavi's user avatar
5 votes
1 answer
203 views

Multiplier norm vs cb norm

Let $f:G\to \mathbb{C}$ be a finitely supported functions and let $m_f$ denote the associated multiplier on $C^*_r(G)$, the reduced group $C^*$-algebra: $$m_f(\alpha)(g)=f(g)\alpha(g)$$ for every $\...
duh's user avatar
  • 165
2 votes
2 answers
260 views

Bounded operators leaving dense subspace invariant

Let $A$ be a C$^*$-algebra. A pre-Hilbert $A$-module $H$ is a right $A$ module with a $A$-valued inner product (which is linear in the second variable and conjugate linear in the first variable) such ...
heller's user avatar
  • 481
10 votes
0 answers
325 views

Are ideals in separable C*-algebras complemented subspaces?

Let $A$ be a separable C*-algebra and $J\subseteq A$ a closed two-sided ideal. Does this make $J$ into a complemented subspace of $A$? In other words, does the quotient map $A\to A/J$ have a ...
Tobias Fritz's user avatar
  • 6,406
2 votes
1 answer
447 views

Why do Douglas-Muhly-Pearcy consider the following operator a co-isometry?

I been reading Nagy and Foias' book "Harmonic analysis of operators on Hilbert space". They prove the existence of a isometric (also unitary) dilation. However Douglas-Muhly-Pearcy in http://...
user123124's user avatar
7 votes
0 answers
1k views

Books on von Neumann algebras

I am interested in non-commutative $L^p$ spaces. I have a very basic background on von Neumann algebras. But all the papers appearing now a days really requires very deep knowledge of von Neumann ...
Mathbuff's user avatar
  • 455
5 votes
2 answers
216 views

On the coincidence (or non-coincidence) of two norms defined on the quotient of a given Hilbert $ C^{\ast} $-module by a certain linear subspace

Let $ A $ be a $ C^{\ast} $-algebra, $ I $ a closed two-sided ideal of $ A $, and $ \mathcal{E} $ a Hilbert $ A $-module. Let $$ \mathcal{E}_{I} \stackrel{\text{df}}{=} \{ x \in \mathcal{E} \mid \...
Transcendental's user avatar
3 votes
1 answer
229 views

Symmetric diagonalizable operators and self-adjointness

Given a densely defined symmetric operator $L$ on a Hilbert space $H$, which is also assumed to be diagonalizable, will there always exist a unique extension of $L$ to a self-adjoint operator?
Milan Bernolak's user avatar
1 vote
0 answers
110 views

Are almost positive functionals close to positive functionals?

This is a bit of an open-ended question... Let $S$ be an operator algebra (or an operator system) and consider a functional $\nu:M\to \mathbb{C}$ that satisfies $$\vert \nu(a)\vert \ge -\varepsilon \...
Lambda's user avatar
  • 19
1 vote
1 answer
332 views

Every norm-continuous group of $C^*$-algebra automorphisms weakly inner?

Please, help out of the mind trap. In this prominent paper Kadison and Ringrose prove among other things the following Corollary 8. Each norm-continuous representation of a connected topological ...
Bedovlat's user avatar
  • 1,959
3 votes
1 answer
460 views

Norm inequality for convolution operators on groups

Let $G$ be a discrete, finitely generated group. Let $f\in \mathbb{C} G$ be given. Consider $g\in G\setminus \operatorname{supp} f$ and let $\delta_g$ denote the Dirac delta at $g$. Is it true ...
user10439561's user avatar
3 votes
0 answers
269 views

Finite dimensional representation of tensor product

Let $A$ and $B$ be $C^*$ algebras, and let $\pi:A \odot B \to B(H)$ be a $*$-representation of the algebraic tensor product on a finite dimensional Hilbert space $H$. Let $x \in A \odot B$. Since $H$ ...
burtonpeterj's user avatar
  • 1,769
8 votes
2 answers
759 views

If the diagonal of a positive operator is compact, is the operator itself compact?

Let $H$ be a separable Hilbert space with a fixed orthonormal basis $\{e_n\}_n$. For a bounded operator $T$ on $H$, the diagonal of $T$ is the unique operator $D_T$ on $H$ which is diagonal with ...
Ruy's user avatar
  • 2,263
5 votes
1 answer
267 views

Induced group action of the left regular representation strongly continuous

Let $G$ be a compact group and let $\lambda: G \rightarrow \mathcal{U}(L^2(G))$ be the left regular representation, i.e. $\lambda_sf(t)=f(s^{-1}t)$. Why is the induced group action $\overline{\lambda}...
Meike's user avatar
  • 51
1 vote
1 answer
190 views

Bounded operators on the Stinespring representation space

Let $A$ be a $C^*$-algebra and let $\phi:A\to B(H)$ be a completely positive map. The Stinespring representation theorem constructs a representation of $A$ on a Hilbert space $K$, which is constructed ...
user10439561's user avatar
3 votes
1 answer
261 views

CBAP for the full group $C^*$-algebra

Let $G$ be a weakly amenable group, in the sense that it has a net of finitely supported functions $\varphi:G\to \mathbb{C}$ which converge point wise to 1 and their cb norm is bounded uniformly by ...
user10439561's user avatar
3 votes
0 answers
57 views

Integration of Weyl operators multiplied by quasifree state over a symplectic space

I am reading the book "An invitation to the Algebra of Canonical Commutation Relations" by Denes Petz. It is freely available for download here. In Chapter 9, he defines the Lebesgue measure on a ...
Tiju Cherian John's user avatar
3 votes
1 answer
157 views

Self adjoint operators in Kasparov-Modules

In Blackadars book in 17.4.2 it says that for each element $x \in KK(A,B)$ there is a Kasparov module $(E,\pi ,T)$ such that $T=T^*$. Now, the argument for that is that if $(E,\pi, T)$ is any Kasparov-...
Zolf1991's user avatar
1 vote
1 answer
441 views

Extensions of completely positive maps

It is known that for a completely bounded map $\psi:A\to B(H)$ there exist completely positive maps $\phi_1,\phi_2:A\to B(H)$ such that $$\Vert \phi_i\Vert_{cb}=\Vert \psi\Vert_{cb},$$ and the map $\...
user10439561's user avatar
3 votes
0 answers
129 views

Equivariant $K$-homology with $G$-compact support

Let $G$ be a discrete countable group and let $A$ be $\sigma$-unital $G$-$C^*$-Algebra. For a proper locally compact Hausdorff $G$-space $X$ the equivariant $K$-homology with $G$ compact support and ...
Jack123's user avatar
  • 31
2 votes
0 answers
450 views

Separable $\sigma$-unital sub-$C^*$-Algebras

Let $A$ be a $\mathbb{Z}_2$-graded $C^*$-Algebra. Then we can take the direct limit $$ colim_{A_\sigma} KK_*(\mathbb{C}, A_\sigma) $$ over all $\sigma$-unital graded $C^*$-sub-algebras $A_\sigma \...
user104470's user avatar
1 vote
2 answers
386 views

About the quotient norm in the Calkin algebra

Recall that the Calkin algebra, is the quotient $B(H)/B_0(H)$, where $H$ is a Hilbert space and $B(H)$ and $B_0(H)$ are the algebra of bounded and compact operators on $H$. Let $H$ be separable and $...
MSMalekan's user avatar
  • 2,118
2 votes
1 answer
291 views

Homotopy equivalence of Kasparov's $KK$-Theory

The homotopy relation of Kasparov-Cycles is definied in Blackadar's book in 17.2.2. It is an equivalence relation. However, I really don't see a good argument for transitivity and can't find any ...
Ritz's user avatar
  • 29
0 votes
1 answer
155 views

Completely positive map defined by the trace

Let $A=C^*_r(G)$ be the reduced group $C^*$-algebra of a finitely generated group. Consider the map $M_2(A)\to M_2(A)$, $$\left[\begin{array}{ll}a&b\\c&d \end{array}\right]\mapsto \left[\begin{...
user104362's user avatar
8 votes
2 answers
812 views

Weak*-norm continuous operators on von Neumann algebras

Let $M$ be a von Neumann algebra with predual $M_*$, and let $T\colon M\to M$ be a bounded, linear map. Let us say that $T$ is (sequentially) weak*-norm continuous if for every net (sequence) $(a_j)_j$...
Hannes Thiel's user avatar
  • 3,497
3 votes
0 answers
148 views

Full free product of $B(\mathcal H_i)$

It struck me that I know nothing about the full (universal) free product of the $B(\mathcal H_i)$ amalgamated over $\mathbb C$ for Hilbert spaces $\mathcal H_i$ with identified unit vector $\xi_i$. So ...
Chris Ramsey's user avatar
  • 3,984

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