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Let $ G $ be a Lie group and $ H $ a connected subgroup of $ G $. If $ N_G(H)/H $ is finite does that imply $ H $ must be closed in $ G $?

Let $ G $ be a Lie group and $ H $ a connected subgroup of $ G $. If $ N_G(H)/H $ is finite does that imply $ H $ must be closed in $ G $? The assumption that $ N_G(H)/H $ is finite cannot be weakened ...
Ian Gershon Teixeira's user avatar
3 votes
0 answers
134 views

When do quotients of $G$-vector bundles exist?

Let's work in the category of smooth (paracompact, Hausdorff) manifolds. Let $M$ be a manifold and $G$ a Lie group acting on $M$. Suppose $E$ is a $G$-vector bundle on $M$ (that is, $G$ acts on $E$ by ...
skwok's user avatar
  • 51
5 votes
0 answers
133 views

Division of fibration by $\Sigma_{n}$ gives Serre fibration

This is related to a question posted on StackExchange: https://math.stackexchange.com/questions/4776877/left-divisor-of-a-fibration-by-compact-lie-group-is-a-fibration. The question there had received ...
Jeremy's user avatar
  • 311
2 votes
1 answer
294 views

Are there always flat connections?

Let $G$ be a simply connected Lie group and $\Gamma$ a cocompact discrete and torsion-free subgroup. Is there a (real or complex) smooth vector bundle $E$ over the manifold $G/\Gamma$, which does not ...
user avatar
3 votes
1 answer
349 views

Existence (or non existence) of principal bundle charts compatible with an $f$-reduction

I asked this question on math stack exchange here, but I wonder if it would be better received here. Let $\pi:P\rightarrow M$ and $\pi':P'\rightarrow M$ be principal $G$ and $H$ bundles respectively, ...
Chris's user avatar
  • 391
4 votes
0 answers
178 views

The homotopy type of the space of symplectic structures

While reading the book Introduction to the $h$-Principle by Y. Eliashberg and N. Mishachev, I noticed that the authors state, at the end of section 9.1.A, that the space of all symplectic structures ...
Akerbeltz's user avatar
  • 516
3 votes
1 answer
337 views

Path lifting property for $\pi:M\rightarrow M/G$ for $G$ compact Lie acting smoothly and freely

Let $M$ be a smooth manifold and let $G$ be a compact Lie group acting smoothly and freely over $M$. Let $\pi:M\rightarrow M/G$ be the canonical projection, and endow $M/G$ with the unique ...
Akerbeltz's user avatar
  • 516
0 votes
0 answers
84 views

The closure of the subgroup generated by a vector field may not be compact

Suppose $X$ is a vector field on a manifold $M$, consider the one parameter group: $$L=\left\{\phi^t_X: t\in\mathbb{R}\right\}$$ where $\phi^t_X$ is the flow of the vector field $X$, which sends $p\in ...
Z. Liu's user avatar
  • 101
10 votes
2 answers
696 views

Homotopy properties of Lie groups

Let $G$ be a real connected Lie group. I am interested in its special homotopy properties, which distinguish it from other smooth manifolds For example $G$ is homotopy equivalent to a smooth compact ...
Arshak Aivazian's user avatar
6 votes
0 answers
341 views

When exponential map is 1-1 from vector fields to diffeomorphisms

Let $M$ be a connected and complete Riemannian manifold of positive dimension, $k$ be a positive integer, and let $\mathfrak{X}^k_c$ be the set of class $C^k$-vector fields on $M$ of compact support. ...
ABIM's user avatar
  • 5,405
7 votes
1 answer
368 views

Does complexified isometry group act transitively on tangent bundle of compact Riemannian manifold?

$\DeclareMathOperator\SL{SL}\DeclareMathOperator\SO{SO}\DeclareMathOperator\SU{SU}\DeclareMathOperator\O{O}\DeclareMathOperator\Iso{Iso}$Let $ g $ be the round metric on the sphere $ S^n $. Since $ S^...
Ian Gershon Teixeira's user avatar
1 vote
1 answer
345 views

Is the manifold of complex points of a quotient of compact groups just the tangent bundle?

In great generality a Lie group mod its maximal compact subgroup is contractible (for example this is true for all connected Lie groups). Whenever this is true then the Lie group $ D $ is ...
Ian Gershon Teixeira's user avatar
3 votes
2 answers
298 views

Transitive action on non-orientable $ M $ lifts to orientable double cover

Suppose that $ M $ is non-orientable with transitive action by a Lie group $ G $. Does that imply that some Lie group $ G' $ acts transitively on the orientable double cover $M'$? This is true for ...
Ian Gershon Teixeira's user avatar
7 votes
1 answer
221 views

Is a quotient of real linear algebraic groups always a Cartesian product of compact and contractible factors?

Let $ G $ be the real points of a linear algebraic group and $ G' $ a Zariski closed subgroup. Then is $ G/G' $ a Cartesian product $$ (K/K') \times F $$ where $ F $ is contractible? Here $ K,K' $ ...
Ian Gershon Teixeira's user avatar
1 vote
0 answers
138 views

Automorphism group of indefinite orthogonal Lie group $G=O(p,q)$ vs that of a double covering group $\tilde{G}$

Previously I mentioned in Automorphism group of a Lie group $G$ vs that of a double covering group $\tilde{G}$: same or not? that the automorphism group of a Lie group 𝐺 may be the same as that of ...
wonderich's user avatar
  • 10.5k
0 votes
0 answers
88 views

Automorphism group of a Lie group $G$ vs that of a double covering group $\tilde{G}$: same or not? [duplicate]

Previously there are some counterexamples given in Automorphism group of a Lie group $G$ vs that of a covering group $\tilde G$: same or not? such that the automorphism group of a Lie group 𝐺 is not ...
wonderich's user avatar
  • 10.5k
4 votes
1 answer
364 views

When is a smooth field's flow map volume preserving diffeomorphism

Let $V:\mathbb{R}^n\rightarrow \mathbb{R}^n$ be a $C^{\infty}$ vector field. Fix a (single) real number $d$ such that $$ 1\leq d\leq n . $$ Under what conditions is the flow map $\Phi_V$ defined as ...
AndrewH's user avatar
  • 43
4 votes
1 answer
304 views

Atiyah-Bott-Shapiro generalization to $U(n) \to ({Spin(2n) \times U(1)})/{\mathbf{Z}/4}$ for $n=2k+1$

Atiyah, Bott, and Shapiro paper on Clifford Modules around page 10 shows two facts. 1 - There is a lift $U(n) \to Spin^c(2n)$ from $U(n) \to SO(2n)\times U(1)$. Also an embedding (injective group ...
Марина Marina S's user avatar
0 votes
1 answer
254 views

$SU(k)/SO(k)$ as a manifold, for each positive integer $k$ [closed]

The quotient space $SU(k)/SO(k)$ is also a homogeneous space constructed out of the Lie groups (special unitary $SU(k)$ and special orthogonal $SO(k)$). Because the $SO(k)$ may not be a normal ...
Марина Marina S's user avatar
6 votes
0 answers
196 views

Logarithm on formal power series continuous?

Denote $V:=\mathbb{R}^d$ and consider the Cartesian product $V^\infty:=\prod_{k=0}^\infty V^{\otimes k}$ together with its canonical projections $\pi_k : V^\infty\rightarrow V^{\otimes k}, (v_0, v_1, \...
fsp-b's user avatar
  • 463
2 votes
0 answers
406 views

Is $U(n)$ a Kahler manifold?

I am wondering if it is known whether the unitary group $U(n)$ is a Kahler manifold, and, if so, what is a reference for this.
Mo Behzad Kang's user avatar
3 votes
0 answers
83 views

Quotients of a fixed manifold by a fixed Lie group

Let $M$ a connected paracompact differentiable manifold. Let $G$ a connected Lie group. I am interested in the possible "regular" (e.g. smooth) quotients of $M$ by actions of $G$. What ...
jpdm's user avatar
  • 141
4 votes
1 answer
164 views

Explicit example of an equivariant embedding of $U(n)/( U(k) \times U(n-k))$ into a finite dimensional $U(n)$-representation

We know that if $H$ is a closed subgroup of a compact Lie group $G$ one can find a finite dimensional $G$-representation $V$ and an element $v_0 \in V$ such that $\textrm{Stab}(v_0)= H$. This gives a $...
MLV's user avatar
  • 73
6 votes
0 answers
177 views

Equivariant Morse theory for non-compact Lie groups

Let $G$ be a Lie group acting properly on a smooth manifold $M$. The (non-equivariant) definition of a Morse function does not carry over to equivariant functions $M \rightarrow \mathbb{R}$ (where $\...
Lukas's user avatar
  • 198
3 votes
1 answer
370 views

Genericity of equivariant embeddings

I'd like to ask an equivariant version of this question. Let $M$ be a closed manifold equipped with the action of a compact Lie group $G$. By the Mostow-Palais embedding theorem, $M$ can be embedded ...
geometricK's user avatar
  • 1,903
8 votes
1 answer
228 views

Isomorphisms of Pin groups

My goal is to identify the $Pin$ group $$ 1 \to Spin(n) \to Pin^{\pm}(n) \to \mathbb{Z}_2 \to 1 $$ such that $Pin^{\pm}(n)$ are isomorphisms to other more familiar groups. My trick is that to look at ...
wonderich's user avatar
  • 10.5k
9 votes
1 answer
750 views

Learning from unsuccessful attempts at the Poincaré conjecture

This is reposted from MSE, but perhaps it is more appropriate to post it here. Let me know if I'm wrong. Among the many unsuccessful attempts at solving the Poincaré conjecture, I'm wondering if there ...
Paul Cusson's user avatar
  • 1,763
3 votes
0 answers
153 views

Diffeomorphisms fixing origin and boundary

Let $D^n$ be a disc in $\mathbb{R}^n$. Is there a known characterization of all the diffeomorphisms of $D^n$ fixing the origin and boundary of $D^n$?
ABIM's user avatar
  • 5,405
3 votes
1 answer
347 views

On functional equation $f\circ \exp=\exp \circ Df$ on a Riemannian manifold or a Lie Group

Let $M$ be a Riemannian manifold or a Lie group whose corresponding exp map (in corresponding context) is denoted by "exp" which is a map $\exp:TM\to M$ We search for the set $\mathcal{H}...
Ali Taghavi's user avatar
2 votes
0 answers
98 views

Compact $G$-ENR's and Euler characteristic computed with Alexander-Spanier cohomology with compact support

Let $(Z,A)$ a compact ENR pair, then $$\chi(Z)=\chi_c(Z-A)+\chi(A)$$ where $\chi_c$ is the Euler characteristic taken in Alexander-Spanier cohomology with compact support (ENR means euclidean ...
Victor TC's user avatar
  • 795
3 votes
1 answer
263 views

Homogeneous manifold deformation retracts onto compact submanifold

Let $G$ be a connected Lie group. Then by a theorem of Cartan there is a diffeomorphism $$ G \cong K \times \mathbb{R}^n $$ where $K$ is a maximal compact subgroup of $G$. Now, let $M$ be a ...
Ian Gershon Teixeira's user avatar
7 votes
1 answer
490 views

Classification of fibrations $\Bbb S^k\longrightarrow\Bbb S^d\longrightarrow B$

Does there exist a complete classification of all fiber bundles $\Bbb S^k\longrightarrow\Bbb S^d\longrightarrow B$, that is, fibrations of $\smash{\Bbb S^d}$ with each fiber homeomorphic to $\smash{\...
M. Winter's user avatar
  • 13.6k
1 vote
0 answers
137 views

When can a spatial Manifold be deformed into another spatial manifold?

I'm reading a paper by Gaiotto, Kapustin, Seiberg, and Willett, titled "Generalised Global Symmetries" (MSN). In section 3.1, paragraph 4 they write something to the order of: If we have a $M^d$ ...
pyroscepter's user avatar
0 votes
0 answers
198 views

Re asking:On the proof by Chu-Kobayashi that transformation groups are Lie groups

I have similar questions asOn the proof by Chu-Kobayashi that transformation groups are Lie groups and even more, how can $Y\in\mathfrak{g}^{*}$ generate 1-parameter global transformation group of $M$ ...
Bey Alexander's user avatar
2 votes
1 answer
143 views

Lie transformation group and the transformation of smooth structure from normal connected subgroup

I'm self-working on two theorems on Lie transformation group from the book Kobayashi transformation group in differential geometry, one is the following Theorem Let $\mathfrak{S}$ the group of ...
Bey Alexander's user avatar
2 votes
1 answer
208 views

Construction of $G$-invariant map between manifolds

Let $M,N$ be two closed differential manifolds and let $G$ be a compact Lie group. Assume that $G$ acts on both manifolds $M,N$ nicely (i.e. free and proper so that $M/G$ and $N/G$ have the structure ...
Stan's user avatar
  • 21
3 votes
0 answers
64 views

Metrically homogeneous spaces as inverse limits

Let $(X,d)$ be a locally compact, separable, connected and $\sigma$-compact metric space such that the group of isometries $G$ acts transitively on $X$. The question is the following: Is $X$ ...
user44172's user avatar
  • 541
15 votes
1 answer
612 views

Is the subgroup $\mathrm{Diff}(M,S)$ of $\mathrm{Diff}(M)$ a Lie subgroup?

Denote by $\mathrm{Diff}(M)$ the Lie group of smooth diffeomorphisms on a compact smooth manifold. Its Lie algebra can be viewed as the Lie algebra $\mathfrak X(M)$ of vector fields on $M$. Now, given ...
Hang's user avatar
  • 2,789
3 votes
1 answer
347 views

Homotopy type of $SO(4)/SO(2)$

A classical result states that the quotient $SO(4)/SO(3)$ is homotopy equivalent to $S^3$. In fact, this can be stated in more general terms since $SO(n+1)/SO(n)$ has the homotopy type of $S^n$. What ...
X1921's user avatar
  • 325
12 votes
0 answers
142 views

Intrepreting Spin(3) as a certain configuration space

Let $\mathcal{C}$ denote the space of great circles in $\mathbb{S}^2\subset \mathbb{R}^3$. It's pretty easy to see that any element $\mathcal{C}$ can be identified uniquely with the axial line (in $\...
RBega2's user avatar
  • 2,478
3 votes
0 answers
82 views

Is there a transitive Lie group action on the space of matrices with rank bigger than $k$?

$\newcommand{\GL}{\operatorname{GL}}$ Let $H_{>k}$ be the space of real $d \times d$ matrices of rank bigger than $k$, for some fixed $k$. $H_{>k}$ is an open connected submanifold of $ \mathbb{...
Asaf Shachar's user avatar
  • 6,741
7 votes
0 answers
1k views

Quotient by a non-free action of a Lie group and manifolds with corners

The quotient manifold theorem says that If $G$ is a Lie group acting freely and properly on a smooth manifold $M$ then $M/G$ has a (unique) smooth structure such that the projection $\pi:M\to M/G$...
Overflowian's user avatar
  • 2,533
2 votes
1 answer
123 views

Hamiltonian Group action with infinitely many stabiliser types

What is an example of a connected symplectic manifold $(M,\omega)$, with a Hamiltonian action of $G = U(1) =S^{1}$ with infinitely many stabiliser types? Infinitely many stabiliser types means that ...
Nick L's user avatar
  • 6,995
10 votes
1 answer
732 views

What's the sufficient or necessary conditions for a manifold to have Lie group structure?

For example, given a Lie group, its fundamental group must be Abelian. So $\Sigma_g$ ($g>1$) can't have Lie group structure. We also know for $S^n$ only $n=0,1,3$ can have Lie group structures. ...
fff123123's user avatar
  • 249
5 votes
1 answer
149 views

Manifold bounded by Sp(2) realisable inside End(H^2)?

The Lie group $Sp(2) = \{A\in GL(2,\mathbb{H})\mid A^\dagger A = I \}$ has a variety of nice geometric aspects. One of which is that it is the boundary of the disk bundle $D(V)$ of the rank-1 ...
David Roberts's user avatar
  • 35.5k
5 votes
1 answer
339 views

Boundary of the image of a compact manifold in the complex plane

The Question Consider the trace of an $n \times n$ unitary matrix with determinant 1 \begin{align} f: SU(n) &\rightarrow \mathbb{C}\\ U \mapsto \text{tr}\, U &= \sum\limits_{i=1}^{n-1} z_i + \...
Jonathan Rayner's user avatar
2 votes
1 answer
833 views

Which Lie algebras are realised as vector fields on a group?

Fix a Lie group $G$. The vector fields on $G$ form an (infinite-dimensional) Lie algebra with the commutator of vector fields as Lie bracket. What (finite-dimensional) Lie algebras can I realise as ...
Mark B's user avatar
  • 503
2 votes
0 answers
71 views

Connected topological/Lie group $H$ and $Q$, inflate $Q$-cocycle to coboundary in $H$

I am interested in finding mathematical examples and criteria of inflating $Q$-cocycle to coboundary in $H$, under the requirement: (1) Both $H$ and $Q$ are connected topological groups or Lie groups (...
annie marie cœur's user avatar
5 votes
0 answers
477 views

What is the dimension of $M/G$ if it is a manifold and $G$ acts freely and smoothly?

Let $G$ be a Lie group acting smoothly and freely on a smooth manifold $M$. Suppose that the quotient space $M/G$ is a topological manifold. Do we have $$\dim(M/G)=\dim M-\dim G?$$ Notes: This ...
SHP's user avatar
  • 779
2 votes
1 answer
120 views

$E \times_H \mathbb{R}^n$ is isomorphic to the total space of the tautological bundle $\gamma^n$ over $G_n(\mathbb{R}^{n+k})$?

Let $H$ be the subgroup of $\text{GL}(n + k, \mathbb{R})$ consisting of matrices whose lower $n \times k$ block is empty; i.e. consisting of matrices of the form$$\begin{pmatrix} A & * \\ 0 & ...
user74301's user avatar