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Questions tagged [ac.commutative-algebra]

Commutative rings, modules, ideals, homological algebra, computational aspects, invariant theory, connections to algebraic geometry and combinatorics.

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Finiteness of Krull dimension of commutative Noetherian ring for which maximal length of regular sequence in maximal ideals have a uniform upper bound

$\DeclareMathOperator\grade{grade}$Let $R$ be a commutative Noetherian ring. For an ideal $I$ of $R$, let $\grade(I,R)$ be the maximal length of an $R$-regular sequence in $I$. My question is: If $\...
Snake Eyes's user avatar
9 votes
0 answers
181 views

How should we picture the set of monomial orders (= positive monoid orders on $\mathbb{N}^k$)?

Motivation: So apparently there's some sort of sport competition currently going on where I live, which leads to countries being given an element of $\mathbb{N}^3$ called a “medal count”, and not ...
Gro-Tsen's user avatar
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0 votes
0 answers
176 views

$\mathbb{C}(x,f,g)=\mathbb{C}(x,y)$, with each pair of $\{f,g,x\}$ not generating $\mathbb{C}(x,y)$

Let $f,g \in \mathbb{C}[x,y]$ with total degrees $\deg_{1,1}(f),\deg_{1,1}(g) \geq 1$. Write, $f=a_ny^n+a_{n-1}y^{n-1}+\cdots+a_1y^1+a_0$ and $g=b_my^m+b_{m-1}y^{m-1}+\cdots+b_1y^1+b_0$, for some $n,m ...
user237522's user avatar
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3 votes
1 answer
504 views

Description of prime ideals in $\operatorname{Spec}(\mathbb{Z}[x_1, \dots, x_n])$

Edit: This seems to be wrong, as pointed out by Will Sawin in the comments. The prime ideals of $\mathbb{Z}$ and $\mathbb{Z}[x]$ are well-known. It is also not too hard to compute the underlying set ...
diracdeltafunk's user avatar
23 votes
3 answers
2k views

What are some toy models for the stable homotopy groups of spheres?

The graded ring $\pi_\ast^s$ of stable homotopy groups of spheres is a horrible ring. It is non-Noetherian, and nilpotent torsion outside of degree zero. Question: What are some "toy models" ...
Tim Campion's user avatar
1 vote
1 answer
67 views

An example of a commutative ring $R$ which has a proper right ideal which is not a right SIP $R$-module

Recall that a module $M_R$ ($R$ is a ring with unity) is called SIP if the intersection of any two summands of $M$ is also a summand. I asked before if there exists a commutative ring which is not an ...
Hussein Eid's user avatar
6 votes
1 answer
225 views

Integral preimages of topologically noetherian, affine schemes

Let $A\to B$ be a ring homomorphism, $d\in \mathbb{Z}_{>0}$ and let $C=\bigotimes^d_A B$ the $d$-fold tensor product of $B$ over $A$. Then $\mathfrak{S}_d$, the symmetric group of $d$ elements, ...
Johann Gramzow's user avatar
4 votes
1 answer
187 views

Order of pole of Poincaré series

Let $R = \bigoplus_{n \geq 0} R_n$ be a graded Noetherian ring and $M = \bigoplus_{n \geq 0} M_n$ a finitely generated graded $R$-module. Let $\lambda$ be an additive function on the class of all ...
psl2Z's user avatar
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6 votes
2 answers
219 views

Steinitz isomorphism theorem for non-Dedekind domains

(Cross-posted from https://math.stackexchange.com/questions/4931582/steinitz-isomorphism-theorem-for-non-dedekind-domains) Fix a Dedekind domain $R$ and fractional ideals $I, J$. It's a classical ...
DrBrownBear's user avatar
2 votes
1 answer
112 views

Example of non injective module over Noetherian local ring with trivial vanishing against residue field?

Is there an example of a module $M$ over a commutative Noetherian local ring $(R,\mathfrak m, k)$ such that $\text{Ext}_R^{>0}(k, M)=0$ but $M$ is not an injective $R$-module? I know that for such ...
Alex's user avatar
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26 votes
3 answers
2k views

Why the stable module category?

Let $R$ be a ring (usually assumed to be Frobenius). The stable module category is what you get when you take the category $\mathsf{Mod}_R$ of $R$-modules, and kill the projective modules. (Of course, ...
Tim Campion's user avatar
1 vote
2 answers
838 views

Books one can read for 2nd course in Commutative Algebra ( Self Study)

I am a student who has completed master's but couldn't take admission to a PhD program due to some unfortunate reasons. I have done 1 course in Commutative Algebra where I followed the book " ...
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1 answer
219 views

Finding $\mathbb{C}(u,v)$ such that $\mathbb{C}(u,v,x^p+y^p)=\mathbb{C}(x,y)$, for every prime number $p$

Denote the set of prime numbers by $P$, $P=\{2,3,5,7,\ldots\}$. Let $F \subseteq \mathbb{C}(x,y)$ be a subfield of $\mathbb{C}(x,y)$, and for $w \in \mathbb{C}[x,y]$ denote by $F(w)$ the subfield of $\...
user237522's user avatar
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2 votes
1 answer
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Localization of quasi-excellent rings are quasi-excellent?

If $R$ is a quasi-excellent ring, then is $R_{\mathfrak p}$ also quasi-excellent for every prime ideal $\mathfrak p$ of $R$ ? I think Matsumura's commutative ring theory book says that localization of ...
Alex's user avatar
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3 votes
2 answers
246 views

Explicit description of transfer for $K_1$

Let $R$ be a commutative regular ring and let $s \in R$ be an element such that $R / s$ is also regular. Then we have a long exact localization sequence $$ \ldots \rightarrow K_i(R/s) \rightarrow K_i(...
Daniel Schäppi's user avatar
3 votes
0 answers
190 views

How can I prove this stronger version of Fedder's Criterion?

I was reading Fedder's original paper which proved what is now known as "Fedder's criterion". I noticed that the abstract stated something which is a priori stronger than what is proved in ...
Anon's user avatar
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0 votes
1 answer
474 views

A subfield $R \subseteq \mathbb{C}(x,y)$ with 'many' generators $w$, $R(w)=\mathbb{C}(x,y)$

Let $R \subseteq \mathbb{C}(x,y)$ and assume that $R=\mathbb{C}(u,v)$, where $u,v \in \mathbb{C}[x,y]$ are algebraically independent over $\mathbb{C}$. Here $\mathbb{N}$ includes $0$. Assume that $R$ ...
user237522's user avatar
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1 vote
1 answer
149 views

$F=\mathbb{C}(u,v)$ satisfying: For every $a,b \in \mathbb{C}[y],c,d \in \mathbb{C}[x]$: $\mathbb{C}(x,y)=F(ax+b)=F(cy+d)$

Let $u,v \in \mathbb{C}[x,y]$, where $u$ and $v$ are algebraically independent over $\mathbb{C}$ and $F=\mathbb{C}(u,v)$. Of course, $d:=[\mathbb{C}(x,y):F] < \infty$. Denote the following ...
user237522's user avatar
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1 vote
1 answer
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On analytic transcendence degree and Krull dimension for homomorphic images of power series rings

Let $k$ be a field of characteristic zero and $I$ be a radical ideal of $k[[x_1,\ldots, x_n]]$. Let $P$ be a minimal prime ideal of the reduced ring $R:=k[[x_1,\ldots, x_n]]/I$. Then, $R_P$ is a field ...
Alex's user avatar
  • 480
2 votes
0 answers
213 views

Open problems in differential algebra and affine algebraic geometry

I am currently doing a PhD in differential algebra and affine algebraic geometry at the University of Buenos Aires. I've been struggling to find a list of interesting and big open problems in these ...
44 votes
4 answers
3k views

Do rings of smooth functions differ from rings of continuous functions?

Let $M$, $N$ be connected nondiscrete compact smooth manifolds. Can the ring of continuous functions on $M$ be isomorphic to the ring of smooth functions on $N$?
Arshak Aivazian's user avatar
1 vote
1 answer
287 views

Unpacking the plethystic substitution $h_n[n\mathbf{z}]$ in a paper by Aval, Bergeron and Garsia

I'm not familiar with the formalism of plethysm, so I need some help in unpacking the plethystic substitution $h_n[n\mathbf{z}]$ found in eqns. 5.6 and 5.9 of "Combinatorics of labelled ...
Tom Copeland's user avatar
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5 votes
2 answers
280 views

Freeness of a quotient module over a regular local ring

Let $R$ be a regular local ring with maximal ideal $m$. Let $t\in m\setminus m^2$. Let $N$ be a submodule of a finitely generated free $R$-module $M$ satisfying $$ tM \subseteq N \subseteq M.$$ ...
Yang's user avatar
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1 vote
1 answer
88 views

Transcendence degree and Krull dimension for homomorphic images of power series rings

Let $k$ be a field of characteristic zero and $I$ be a radical ideal of $k[[x_1,\ldots, x_n]]$. Let $P$ be a minimal prime ideal of the reduced ring $R:=k[[x_1,\ldots, x_n]]/I$. Then, $R_P$ is a field ...
Alex's user avatar
  • 480
3 votes
1 answer
260 views

Cancellation in polynomial composition

Let $k$ be a field. Suppose $P,Q,R\in k[x]$ satisfy $P\circ Q=P\circ R$. What can we conclude about $Q$ and $R$? It may not be the case that $Q=R$; for example, if $P=x^2$, any polynomials $Q,R$ with $...
user50139's user avatar
  • 545
4 votes
2 answers
227 views

Maximal subgroups of finite abelian $2$-groups

Suppose $G$ is a finite abelian $2$-group, and $S$ is a subset of $G$, $\langle S\rangle=G$,$S^{-1}=S$,$e\notin S$. How to determine whether there exists a maximal subgroup $M$ of $G$, such that $S$ ...
lunch zheng's user avatar
1 vote
1 answer
52 views

Exceptional Lenz-Barlotti classes IVa.3 and IVb.3

On this web-site, devoted to the Lenz-Barlotti classification of projective planes, it is written that the class IVa.3 (and its dual IVb.3) is somewhat exceptional, because it contains exactly one ...
Taras Banakh's user avatar
1 vote
0 answers
104 views

Is a normal domain a filtered colimit of Noetherian normal domains?

As described in the title, is any normal domain a filtered colimit of Noetherian normal domains? It will be great if one can show this, even with additional conditions, or if one can provide a ...
GTA's user avatar
  • 1,024
2 votes
1 answer
152 views

A commutative ring with unity which does not have relatively pseudo-injective ideals with zero intersection

Let $R$ be a ring with $1$ and $M$ and $N$ be any right $R$-modules. We say that $M$ is pseudo-$N$-injective if every $R$-monomorphism $f:X \to M$ from a submodule $X_R$ of $N_R$ can be extended to $N$...
Hussein Eid's user avatar
7 votes
3 answers
988 views

A polynomial identity for $\displaystyle \sum_{k=0} ^m (-1)^ka^{m-k}b^k$

I asked this question on MSE here. I was solving this problem: Show that if $\gcd(a, b) = 1$ and $p$ is an odd prime, then $\displaystyle \gcd\left(a+b, \frac{a^p+b^p}{a+b}\right)=1$ or $p$. This ...
pie's user avatar
  • 541
2 votes
0 answers
171 views

Principle of degeneration as precursor of Zariski's connectedness theorem (geometric intuition)

I have following question about so-called "principle of degeneration" in algebraic geometry (which in modern terms is an immediate consequence of Zariski's main theorem and goes in it's ...
user267839's user avatar
  • 6,038
5 votes
2 answers
754 views

A version of Hilbert's Nullstellensatz for real zeros

$\newcommand\R{\Bbb R}$Let $Q(x_1,\dots,x_n)\in\R[x_1,\dots,x_n]$ be an irreducible polynomial such that the dimension of the set $Z:=\{(x_1,\dots,x_n)\in\R^n\colon Q(x_1,\dots,x_n)=0\}$ (defined, say,...
Iosif Pinelis's user avatar
4 votes
1 answer
267 views

A particular morphism being zero in the singularity category

Let $R$ be a commutative Noetherian ring and $D^b(R)$ be the bounded derived category of finitely generated $R$-modules. Let $D_{sg}(R)$ be the singularity category, which is the Verdier localization $...
strat's user avatar
  • 361
5 votes
2 answers
199 views

Determining the multiplication via addition and some unary operation

It is known that the addition operation in a skew-field $F$ (more generally, in a quasifield) is uniquely determined by the multiplication operation and the unary involutive operation $1_{-}:F\to F$, ...
Taras Banakh's user avatar
1 vote
1 answer
136 views

Artinian Gorenstein subrings with same socle degree

I am looking for examples of Artinian Gorenstein subalgebras with the same socle degrees. More precisely, let $A$ be an Artinian Gorenstein $k$-algebra (with $k$ algebraically closed of characteristic ...
Chen's user avatar
  • 1,593
2 votes
0 answers
182 views

Integers as polynomials in infinite variables

This question is more of a request for reference or ideas than else. Forgive (or correct) if there are imprecisions or blatant mistakes. The main idea is that the unique factorization theorem for $\...
CryptoZiddy's user avatar
1 vote
0 answers
181 views

Examples of semirings where the additive neutral element is not absorbing for multiplication

In the case of a non unital ring, the additive 0 must be absorbing for the multiplication because we have a⋅0 = a⋅(a − a) = a⋅a − a⋅a = 0 and similarly on the other side. In the case of a unital ...
Gérard Lang's user avatar
  • 2,655
5 votes
1 answer
349 views

Commutator subgroup of $\mathrm{GL}_n(R)$ when $R$ is a PID with unity

Hua and Reiner in their paper titled "Automorphisms of the unimodular group" have established what will be the commutator subgroup of $\mathrm{GL}_n(\mathbb{Z})$, $\forall n\geq 0$. I have ...
Guest's user avatar
  • 51
6 votes
0 answers
632 views

Generating functions in countable commutative monoids

Let $f: \mathbb{N}_0 \rightarrow \mathbb{C}$ be a function. The power series of $f$ can be viewed as the function $\mathscr{P}_f : q \mapsto \sum_{n \in \mathbb{N}_0}^{} f(n)q^n$ where $q \in \mathbb{...
Tian Vlašić's user avatar
2 votes
0 answers
275 views

Can the completion of a local domain which is not a field be a field?

I would like to prove/disprove the following claim: Let $A$ be an equicharacteristic local domain, and denote by $\widehat{A}$ its completion with respect to its maximal ideal. If $\widehat{A}$ is ...
Don's user avatar
  • 293
2 votes
0 answers
93 views

Minimal injective resolution and change of rings

Let $R$ be a commutative Noetherian ring. For an $R$-module $M$, let $0\to E^0_R(M)\to E^1_R(M)\to \ldots $ denote the minimal injective resolution of $M$. I have two questions: (1) If $I$ is an ...
Alex's user avatar
  • 480
6 votes
1 answer
571 views

Original proof of Hilbert irreducibility theorem

Does there exist a modern exposition of Hilbert's original (1892) proof of the Hilbert irreducibility theorem? Of course, I can (and will) read Hilbert's original article, but I would feel more ...
Yuri Bilu's user avatar
  • 1,294
3 votes
0 answers
33 views

Algorithm to determine closedness of orbits?

Consider a reductive group $G$ acting on an affine variety $X$. It is known that for every $x\in X$, we have $G.x\subseteq\overline{G.x}$ is open dense. Then $\partial({G.x})\subseteq X$ is a closed ...
Yikun Qiao's user avatar
2 votes
1 answer
181 views

Is the derived support $\{x\in X\:|\: \mathsf{L}x^* M\neq 0\}$ closed?

Let $X$ be a scheme and consider an object $M$ of its derived category $\mathsf{D}_\text{qc}(X)$, defined as the full subcategory of $\mathsf{D}(\textsf{Mod}(\mathcal{O}_X))$ consisting of the ...
Gabriel's user avatar
  • 771
1 vote
1 answer
156 views

Convergence of a product in $\mathbb Q_2[[X]]$

I thought it would be very easy to prove, but in fact, I did not manage to prove or disprove this fact: the sequence of polynomials $$\left(\prod_{j=0}^k\big(1-2^{2^j}X\big)\right)_{k\in\mathbb N}$$ ...
joaopa's user avatar
  • 3,998
1 vote
0 answers
59 views

If $E \subseteq F=k(x_1,\ldots,x_r)$, satisfies $E(x_1^{i_1},\ldots,x_r^{i_r})=F$, for every $(i_1,\ldots,i_r) \neq (0,\ldots,0)$, then $[F:E] \leq 2$

For $r \geq 2$, let $A_r=\mathbb{C}[x_1,\ldots,x_r]$, $F_r=\mathbb{C}(x_1,\ldots,x_r)$ the field of fractions of $A_r$, and $E_r \subseteq F_r$ an arbitrary subfield of $F_r$ with $[F_r:E_r] < \...
user237522's user avatar
  • 2,837
6 votes
1 answer
272 views

Ideals of functions whose zero locus is a submanifold

Let $M$ be a smooth $m$ dimensional manifold. Suppose that $f_1,\dots,f_k\in C^\infty(M)$ are smooth functions such that the zero locus $$N:=Z_f=\lbrace p\in M:\ f_i(p)=0,\ \forall i=1,2,\dots,k\...
Bence Racskó's user avatar
3 votes
0 answers
111 views

When is a ring complete with respect to its nilradical?

Let $R$ be a commutative ring and let $I$ be its nilradical. When is $R$ complete with respect to $I$? For example, if $I$ is finitely generated, there exists $N$ such that $I^N = 0$ and thus $R$ is ...
Joshua Mundinger's user avatar
5 votes
1 answer
248 views

On the bounded derived category of sheaves with coherent cohomology

Let $(X,\mathcal{O}_X)$ be a locally ringed space such that $\mathcal{O}_X$ is locally notherian, and let $\operatorname{Coh}(\mathcal{O}_X)$ be the category of coherent $\mathcal{O}_X$-modules. The ...
FPV's user avatar
  • 541
1 vote
1 answer
366 views

Proj construction and nilpotent homogenous elements in graded ring

Let $A= \bigoplus_{n \ge 0} A_n$ be a commutative Noetherian graded ring and $f \in A_d$ a nonzero homogeneous element of degree $d>0$. The natural ring map $q:A \to A/(f)$ induces a well defined ...
user267839's user avatar
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