Skip to main content

All Questions

Filter by
Sorted by
Tagged with
2 votes
0 answers
121 views

Generalized identity with Stirling numbers of the second kind and falling factorials

It is known that Striling numbers of the second kind satisfy the relation $$ \sum\limits_{k=0}^{n}{n \brace k}(x)_k = x^n. $$ where $(x)_n$ is the falling factorials such that $$ (x)_n = x(x-1)(x-2)\...
Notamathematician's user avatar
0 votes
1 answer
169 views

Partial sums of binomial coefficients and related family of polynomials

Let $a(n)$ be A302117. Here $$ a(n) = 4(n-1)a(n-1) - \frac{1}{3}\prod\limits_{k=0}^{n-1}(2k-3), \\ a(0) = 0. $$ Let $$ T(n,k) = \sum\limits_{i=0}^{k} \binom{n}{i}. $$ Let $P_n(z)$ be the family of ...
Notamathematician's user avatar
3 votes
1 answer
192 views

Density of Pisot polynomials

Recall that a Pisot polynomial $P=x^n+ a_{n-1}x^{n-1}\ldots a_1$ has integer coefficients, a real root $x_1>1$ and all other roots $|x_i|<1$ for $1\leq i \leq n$. One key result is that $\{(...
ericf's user avatar
  • 680
2 votes
0 answers
113 views

Numbers of positive terms in polynomials equal A069999

Let $a(n)$ be A069999 (i.e., number of possible dimensions for commutators of $n \times n$ matrices; it is independent of the field). OEIS states that no generating function is known. Let $P(n,k)$ be ...
Notamathematician's user avatar
0 votes
0 answers
60 views

Algorithm for $q$-Bell numbers

Let $T(n,k)$ be A126347 (i.e., triangle, read by rows, with row polynomials $B(n, q)$). Here $$ B(n, q) = \sum\limits_{k=0}^{n-1}\binom{n-1}{k}B(k, q)q^k, \\ B(0, q) = 1. $$ Start with vector $\nu$ of ...
Notamathematician's user avatar
7 votes
0 answers
208 views

How biased is $(x_i x_j)_{i,j}$, $x_i\in \mathbb{F}_2$?

Let $N = \frac{n (n-1)}{2}$. Let $V$ be the $N$-dimensional vector space over $\mathbb{F}_2$ consisting of tuples $(x_{(i,j)})_{1\leq i <j \leq n}$, $x_{(i,j)}\in \mathbb{F}_2$. Let $S$ be the set ...
H A Helfgott's user avatar
  • 20.2k
3 votes
0 answers
214 views

A family of polynomials related to integer partitions

For a positive integer $n$, let $p(n)$ be the number of partitions of $n$. For $1\le k\le n$, let $p(n,k)$ denote the number of partitions of $n$ having exactly $k$ terms; in other words, $p(n,k)$ is ...
Zhi-Wei Sun's user avatar
  • 15.6k
0 votes
0 answers
121 views

Closed form of coefficients of a finite field polynomial

I want to find a valid polynomial for a finite field $\mathbb{Z}_p[x]_{f(x)}$ with $d=deg(f(x))$. For this definition to hold, it can be deduced that $p$ must be prime and the polynomial $f(x)$ ...
Cardstdani's user avatar
2 votes
1 answer
310 views

Generating function for A300483 (related to Chebyshev polynomial of first kind)

Let $a(n)$ be A300483. Here $$ a(n) = 2\int\limits_{t \geqslant 0}T_n\left(\frac{t+1}{2}\right)\exp(-t)\,dt. $$ where $T_n(x)$ is $n$-th Chebyshev polynomial of first kind. Let $b(n)$ be an integer ...
Notamathematician's user avatar
2 votes
0 answers
71 views

Property of a family of simple polynomials related to the A329369

Let $a(n)$ be A329369 (i.e., number of permutations of $\{1,2,\dotsc,m\}$ with excedance set constructed by taking $m-i$ ($0 < i < m$) if $b(i-1) = 1$ where $b(k)b(k-1)\cdots b(1)b(0)$ ($0 \...
Notamathematician's user avatar
2 votes
1 answer
372 views

On properties of sums involving the floor function

During my research on properties of fractional part and integer part functions, I was led to consider the function of two variables $f(n,k)=\frac{2^{k}+1}{2^{ n}+1}\left\lfloor \frac{2^{n}+1}{2^{k}+1}\...
 Babar's user avatar
  • 611
3 votes
0 answers
240 views

On thickness of binary polynomials

OEIS A169945 introduces the concept of thickness of a polynomial as the magnitude of the largest coefficient in the expansion of the square of the polynomial. Considering the $2^{n+1}$ polynomials $p(...
Sayan Dutta's user avatar
17 votes
1 answer
687 views

Multiply an integer polynomial with another integer polynomial to get a "big" coefficient

I have copied this question from StackExchange, in the hope that some experts here can provide some relevant insight. Thanks to Greg Martin for improving the question. Given $f(x) = a_0 + a_1 x + a_2 ...
ghc1997's user avatar
  • 823
4 votes
0 answers
263 views

Cosine Modulo $p$?

Consider the integers modulo a prime $p$. I'm looking for a nice polynomial function that acts as a sort of "cosine" on the integers modulo $p$. Specifically, I'm looking for solutions to ...
mtheorylord's user avatar
1 vote
0 answers
69 views

Simplification of computing $f(n,z)$

Let $$ s(n,z)=\sum\limits_{j=0}^{n}L(n,j,z) $$ where $$ L(n,j,z)=\sum\limits_{p=0}^{n-j-1}f(p,z)L(n-j-1,p,z), \\ L(n,n,z)=1 $$ Now let $s(n,z)$ be an arbitrary function such that $s(0, z)=1$. It means ...
Notamathematician's user avatar
1 vote
0 answers
180 views

Applications of hyperbolic polynomials?

The recently posted MO-Q "Positivity of the coefficients of Taylor series associated to the Riemann hypothesis" (see also this MO-Q) has re-kindled my interest in hyperbolic polynomials--...
Tom Copeland's user avatar
  • 10.5k
3 votes
2 answers
459 views

Short sequence beats long sequence

I have encountered some comparison between two binomial sums. It was amusing how the one with "fewer" summands exceeds (in value) than the other which consists of many more terms. In fact, ...
T. Amdeberhan's user avatar
3 votes
1 answer
210 views

Powers of $2$ up to $2^{m-1}$ from a polynomial of degree $m-1$

Let $T(n,k)$ be a triangle of coefficients such that $T(n,k)\geqslant0$ for $n>0$, $0<k\leqslant n$, $0$ otherwise. Also $$T(2n+1,1)=\frac{1}{2n+1}, T(2n,1)=0$$ $$T(n,k)=\frac{1}{n}(T(n-1,k-1)+(...
Notamathematician's user avatar
5 votes
1 answer
358 views

The number of polynomials on a finite group, II

This question is follow up of this MO-post. First let us recall the necessary definitions. A function $f:X\to X$ on a group $X$ is called a polynomial if there exists $n\in\mathbb N$ and elements $a_0,...
Taras Banakh's user avatar
  • 41.9k
3 votes
1 answer
194 views

Checking presence of a specific term in product polynomial

I have a multivariate polynomial $P$ which is a product of $M$ low degree polynomials $p_i$ $$P(x_1, x_2, \dotsc, x_n) = \prod_{i=1}^M p_i(x_1, x_2, \dotsc, x_n)$$ where the maximum degree of each $...
Math-fort's user avatar
  • 103
3 votes
0 answers
144 views

Flat polynomials with factors of big height

Let $p(x)$ be a polynomial of degree $n$ with all coefficients in $\{-1,0,1\}$ (such polynomials are sometimes called flat). I am wondering how big the coefficients of a factor of $p$ can be. Call ...
Wolfgang's user avatar
  • 13.4k
4 votes
0 answers
186 views

A problem in the spirit of P. Borwein's polynomials

A well-known conjecture (now a theorem) of P. Borwein (see Wang and Krattenthaler - An asymptotic approach to Borwein-type sign pattern theorems) states: For all positive integers $n$, the sign ...
T. Amdeberhan's user avatar
1 vote
0 answers
159 views

A follow up on Bergeron's conjecture and a question

We say two polynomials satisfy $P(x)\geq Q(x)$ iff $P(x)-Q(x)$ has non-negative coefficients. Recall $(n)_q!=\prod_{j=1}^n(1-q^j)$ and the Gaussian polynomials $\binom{n}k_q=\frac{(n)_q!}{(k)_q!(n-k)...
T. Amdeberhan's user avatar
4 votes
1 answer
539 views

A (mild?) question on the number of monomials

Let $[n]_q=\frac{1-q^n}{1-q}$ with $[0]_q=0$. Recall the $q$-factorials $[n]_q!=[1]_q[2]_q\cdots[n]_q$ (with $[0]_q!=1$) and the $q$-binomials $$\binom{n}k_q=\frac{[n]_q!}{[k]_q!\,[n-k]_q!}.$$ Now, ...
T. Amdeberhan's user avatar
2 votes
1 answer
213 views

Coefficient of a term in a several variable polynomial multipled with Vandermonde determinant

Let $\Delta_n(x_1, \ldots, x_n)$ denote the Vandermonde determinant $\displaystyle \prod_{1 \leq i < j \leq n}(x_j - x_i)$. Let $c_1, \ldots, c_n$ and $K$ be nonnegative integers satisfying $$c_1 + ...
Rajkumar's user avatar
  • 167
2 votes
1 answer
385 views

Determinants of striped Hankel matrices

This question is related to the matrices described in Deyi Chen's recent MO post (look at some examples there). The main difference: we are asking for a determinant evaluation instead of a permanent, ...
T. Amdeberhan's user avatar
6 votes
1 answer
242 views

$(q,t)$-Fibonacci polynomials: area & bounce statistics

This is related to my earlier (unanswered) MO post. Preserve notations from there. We take advantage of the one-to-one correspondence between the $(s,s+1)$-core partitions and $(s,s+1)$-Dyck paths. ...
T. Amdeberhan's user avatar
3 votes
1 answer
372 views

How many ways can $N$ be written as a sum of terms in the form $2^i3^j$?

Given a positive integer $N$, let $f(N)$ be the number of ways $N$ can be decomposed as a sum of terms of the form $2^i3^j$, where each such term appears at most once in the sum. For example, $f(10) = ...
Gautam's user avatar
  • 1,703
1 vote
0 answers
96 views

Polynomial composition utilizing polynomials in two different finite fields

At every $n\in\mathbb N$ (all polynomials are of degree $O(1)$) is there $g_{3,1}^{(n)},\dots,g_{3,k}^{(n)}\in\mathbb F_3[x_1,\dots,x_n]$ at $k=\mathsf{poly}(n)$ and $g_2^{(n)}\in\mathbb F_2[x_1,\dots,...
Turbo's user avatar
  • 13.9k
1 vote
0 answers
107 views

Palindromicity of $q$-polynomials related to Catalan triangles

The present problem comes from further consideration of my earlier questions, from here and here. Start with the following variants of Catalan triangles $\frac{2k+1}{n+k+1}\binom{2n}{n-k}$. Now, ...
T. Amdeberhan's user avatar
3 votes
0 answers
195 views

Congruence for the polynomials $(t+1)^n$

An interesting polynomial congruence is given by $$A_n(t^m)\equiv \left(\frac{1+t+\cdots+t^{m-1}}m\right)^{n+1}A_n(t) \qquad \mod (t-1)^{n+1}, \tag1$$ where $A_n(t)$ are the Eulerian polynomials with ...
T. Amdeberhan's user avatar
11 votes
1 answer
332 views

Counting monomials in product polynomials: Part II

Encouraged by the responses to my earlier MO question, here is a follow up and upgraded quest. Let $e\geq2$ be an integer. Define the polynomials $$P_{n,e}(x)=\prod_{i=1}^{n-1}\left(1+x^{e^{i-1}}+x^{e^...
T. Amdeberhan's user avatar
9 votes
2 answers
538 views

Counting monomials in product polynomials: Part I

This question is motivated by recent work of R P Stanley, Theorems and conjectures on some rational generating functions. Consider the polynomials $$P_n(x)=\prod_{i=1}^{n-1}(1+x^{3^{i-1}}+x^{3^i}).$$ ...
T. Amdeberhan's user avatar
9 votes
1 answer
1k views

"Laurent phenomenon"?

Define the recurrence \begin{align*} n(2n+x-3)u_n(x) &=2(2n+x-2)(4n^2+4nx-8n-3x+3)u_{n-1}(x) \\ &-4(n+x-2)(2n-3)(2n+2x-3)(2n+x-1)u_{n-2}(x) \end{align*} with initial conditions $u_0(x)=0$ and $...
T. Amdeberhan's user avatar
1 vote
1 answer
241 views

Integral zeros of a multivariate polynomial

Consider the multivariate polynomial $$f(x_1,\ldots,x_m)=mk\sum_{i=1}^mx_i^2-mk(k-1)\sum_{i=1}^mx_i-\left(\sum_{i=1}^mx_i\right)^2,$$ for integers $m,k\ge2$. We are looking for integral zeros of $f$ ...
Ebrahim's user avatar
  • 33
3 votes
0 answers
243 views

Interlacing sequences by polynomials?

Given $t=2^\ell$ where $\ell\in\mathbb N_{>0}$ and $M\in\mathbb Z$ and two sets of integers $\{a_1,\dots,a_t\}$ and $\{b_1,\dots,b_t\}$ with $0<a_1\leq \dots\leq a_t<M$ and $0<b_1\leq \...
Turbo's user avatar
  • 13.9k
17 votes
2 answers
1k views

$P(x)=P(y)$ has infinitely many integer solutions

Determine all polynomials $P(x)$ with integer coefficients such that $P(x)=P(y)$ has infinitely many integer solutions in integer $x$ and $y$ with $x \neq y$. Choose $P(x)=a_n(x-k)^{2n}+a_{n-1}(x-k)^{...
apple's user avatar
  • 501
17 votes
1 answer
502 views

Irreducibility of root-height generating polynomial

The height $ht(\alpha)$ of a positive root $\alpha$ in a (finite, crystallographic) root system $\Phi$ is $\sum_{i=1}^n c_i$ where $\alpha = \sum_{i=1}^n c_i \alpha_i$ is its decomposition as a sum of ...
Christian Gaetz's user avatar
2 votes
1 answer
192 views

A Vandermonde-type system

For a prime $p$ and $a_1,\dotsc,a_n\in\mathbb F_p^\times$, consider the system of equations $$ \begin{cases} \begin{align} a_1 + \dotsb + a_n &= 0 \\ a_1x_1 + \dotsb + a_nx_n &...
Seva's user avatar
  • 23k
4 votes
1 answer
139 views

Polynomial expansions via prime-base digits

Fix a prime number $p$. If $n$ is a positive integer, then denote $$\text{$\omega_{p,k}(n):=\#$ of $k$'s in the $p$-ary expansion of $n$}$$ and the total sum of all its $p$-ary digits by $$\Omega_p(...
T. Amdeberhan's user avatar
1 vote
1 answer
552 views

Coefficients $U_m(n,k)$ in the identity $n^{2m+1}=\sum\limits_{0\leq k \leq m}(-1)^{m-k}U_m(n,k)\cdot n^k$

Review the main result of mathoverflow.net/questions/297900, that is the identity \begin{equation}\label{f1} n^{2m+1}=\sum\limits_{1\leq k \leq n}\sum\limits_{j\geq0}A_{m,j}k^j(n-k)^j, \end{equation} ...
Petro Kolosov's user avatar
11 votes
0 answers
450 views

A congruence involving roots of unity

Let $f(x) \in \mathbb{Z}[x]$ and suppose $f(\omega^j) \in \mathbb{Z}$ for all $j= 1, \dots, n$ where $\omega = e^{2 \pi i/n}$ is a primitive $n^{\text{th}}$ root of unity. Computational evidence ...
user94267's user avatar
  • 305
8 votes
2 answers
565 views

integral transform of Fibonacci polynomials is integral

The Fibonacci polynomials are defined recursively by $F_0(x)=0, F_1(x)=1$ and $F_n(x)=xF_{n-1}(x)+F_{n-2}(x)$, for $n\geq2$. While computing certain integrals, I observe the following (numerically) ...
T. Amdeberhan's user avatar
7 votes
3 answers
735 views

Expanding in Fibonacci powers

Let $F_n$ denote the all-familiar Fibonacci numbers, with $F_0=0, F_1=1, F_2=1$, etc. There is a plethora of properties for these numbers involving their sums, products, convolutions and so on. Here, ...
T. Amdeberhan's user avatar
9 votes
1 answer
285 views

Multivariate quasipolynomials and where to find them

This question is inspired from thinking about David Speyer's question about complex variable Ehrhart theory. In one variable, Ehrhart theory has been vastly generalized. For example it has been ...
Gjergji Zaimi's user avatar
3 votes
3 answers
233 views

sequencial shift on families =flipped powers. How?

Consider the following family of functions $$f_n(w):=\sum_{k=0}^{\infty}\frac{(-1)^{k-1}}{k!}(k+n)^{k-1}w^k.$$ QUESTION 1. Does the following hold? $$f_n(w)=-\frac1{n(f_{-1}(w))^n}.$$ Deeper ...
T. Amdeberhan's user avatar
5 votes
1 answer
211 views

degree of a polynomial over set-partitions

Denote $(x)_t = x(x-1)(x-2)\cdots(x-t+1)$ and fix some $t_1,\dots,t_n\in\mathbb{N}$. Now consider the polynomials $$f_n(x)=\sum_{\pi\in L[n]}(-1)^{\vert\pi\vert-1}(\vert\pi\vert-1)!\prod_{A\in\pi}(x)_{...
T. Amdeberhan's user avatar
7 votes
1 answer
232 views

counting monomials and integrality

For $n\in\mathbb{Z}^{+}$, consider the polynomials $$P_n(x)=\prod_{k=0}^{n-1}(x^n-x^k).$$ QUESTION. Is it possible to find a closed formula for the number of monomials in $P_n(x)$, after expansion? ...
T. Amdeberhan's user avatar
16 votes
2 answers
1k views

are these polynomials or rationals functions?

Let $x$ be a variable. Define the following family of sequences (reminiscent of Lucas polynomials) according to the rule: $P_0(x):=0, P_1(x):=1$ and for $n\geq2$ by $$P_n(x)=xP_{n-1}(x)-P_{n-2}(x).$$ ...
T. Amdeberhan's user avatar
9 votes
2 answers
546 views

Can you tie up these Laurent sequences?

Fix an integer $k\geq3$. Define the two families of sequences $\{x_n\}$ and $\{y_n\}$ according to the rules: $$x_n=\frac{x_{n-1}^2+x_{n-2}^2+\cdots+x_{n-k+1}^2}{x_{n-k}} \qquad n\geq k$$ and $$y_n=\...
T. Amdeberhan's user avatar