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Questions tagged [ac.commutative-algebra]

Commutative rings, modules, ideals, homological algebra, computational aspects, invariant theory, connections to algebraic geometry and combinatorics.

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Discovery of Hilbert polynomial

Presumably it was Hilbert who discovered Hilbert polynomials - where did they first appear? The basic theorem is that for a finitely generated graded module $M = \bigoplus_k M_k$ over the ring of ...
pinaki's user avatar
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2 votes
1 answer
121 views

Projective dimension and subrings

$\DeclareMathOperator\pd{pd}$Suppose that $R$ is a commutative ring and $R'$ is a subring of $R$ such that $R$ is a free $R'$-module of finite rank. Assume that both $R$ and $R'$ are regular local ...
Ahmed Matar's user avatar
10 votes
1 answer
853 views

Is it a valuation ring?

It is known that a one-dimensional Noetherian local ring is a discrete valuation ring if it is integrally closed. Then, even if it is not Noetherian, would a one-dimensional local ring become a ...
George's user avatar
  • 328
5 votes
0 answers
107 views

Generalized Puiseux series for diagonal reflections of the curves $y = \frac{x}{(1-ax)(1-bx)^m}$

Reflection of the curve $y = f_m(x) = \frac{x}{(1-ax)(1-bx)^m}$ through the diagonal line $y=x$ in the $xy$-plane can be regarded as local compositional inversion of the curve $y=f_m(x)$. ($x,y,a,b$ ...
Tom Copeland's user avatar
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1 vote
0 answers
87 views

Factorial surfaces and smoothness

It is well-known that normal curves are smooth. Moreover, a UFD of Krull dimension one is regular. Is there any higher-dimensional analog? For example, given a normal projective surface $S$ over $\...
Jooh's user avatar
  • 389
12 votes
2 answers
776 views

Hilbert polynomials of graded algebras evaluated at negative numbers

Let $k$ be a field and let $R$ be a commutative (standard) graded $k$-algebra, that is, $R=\bigoplus_{n=0}^\infty R_n$ with $R_0=k$ (and $R=k[R_1]$). The Hilbert function $h_R:\mathbb{N}\rightarrow \...
walkar's user avatar
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3 votes
1 answer
153 views

A question about freeness of a certain class of abelian groups

Lets call an abelian group $G$, to be semi-free (or SF) if every nonzero subgroup of $G$ is isomorphic to $\mathbb{Z}\times H$ for some abelian group $H$. Is every semi-free group, a free group? If ...
Mostafa - Free Palestine's user avatar
8 votes
1 answer
191 views

Do graded-commutative rings satisfy the strong rank condition?

Let $R$ be a ring. Recall that $R$ is said to satisfy the strong rank condition if, whenever $R^m \to R^n$ is a monomorphism of right $R$-modules (with $m,n \in \mathbb N$), we have $m \leq n$. It is ...
Tim Campion's user avatar
2 votes
1 answer
134 views

An etale cover of a semiperfect ring

Assume that $R$ is a semiperfect ring in characteristic $p$, i.e the frobenius is surjective on $R$. I think one can prove that an etale cover of $R$ should again be semiperfect by considering the ...
ALi1373's user avatar
  • 95
2 votes
1 answer
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height of sum of prime ideals

Suppose $R$ is a Cohen-Macaulay local ring and $P,Q$ are prime ideals in $R$. Let the height of $P$ and $Q$ be $m$ and $n$ respectively. Then is it true that the height of $P+Q$ is at most $m+n$?
dongrugose's user avatar
2 votes
2 answers
422 views

A proof of $\dim(R)+1 \leq \dim(R[T]) \leq 2 \dim(R)+1$ with the Coquand-Lombardi characterization of Krull dimension

Question. Can we use the Coquand-Lombardi characterization$^1$ of Krull dimension to prove the well-known inequalities$^2$ $$\dim(R)+1 \leq \dim(R[T]) \leq 2 \cdot \dim(R)+1,$$ where $R$ is any ...
Martin Brandenburg's user avatar
1 vote
0 answers
52 views

Symmetric 0-dimensional schemes with generic Hilbert function and Grassmannians

I've came across this problem while thinking about some properties of fat schemes. Let me give you an explicit (motivating) example: We have $S=\mathbb{C}[x,y,z]$, the coordinate ring of $\mathbb{P}^2$...
gigi's user avatar
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2 votes
1 answer
169 views

Is $\mathrm{Hom}_R(M,R)\neq \mathfrak m \mathrm{Hom}_R(M,R)$ if $M \neq \mathfrak m M$ and $\mathrm{Hom}_R(M,R)\neq 0$?

Let $(R,\mathfrak m)$ be a commutative Noetherian local ring and $M$ be an $R$-module such that $M \neq \mathfrak m M$ and $\mathrm{Hom}_R(M,R)\neq 0$. Then, is it true that $\mathrm{Hom}_R(M,R)\neq \...
Snake Eyes's user avatar
3 votes
1 answer
148 views

Formal étaleness along Henselian thickenings

Assume that $f:X\to Y$ is an étale map between smooth varieties and $(S,I)$ is a Henselian pair. Let $\alpha\in X(S/I)$. Can we say that the lifts of $\alpha$ to $X(S)$ are in bijection with the lifts ...
ALi1373's user avatar
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2 votes
1 answer
146 views

Why is this map a split monomorphism?

I have a question regarding a lemma in the proof of Hopkins-Neeman Correspondence. It is the beginning part of Lemma 1.2 in the The Chromatic Tower for D(R) Let $Y$ be an object of the derived ...
Subham Jaiswal's user avatar
4 votes
2 answers
342 views

On a generalized homotopy transfer theorem

In the book of Loday and Vallette "Algebraic Operads" a necessary condition for the Homotopy Transfer Theorem is that the starting operad is Koszul. I am interested in a generalization of ...
groupoid's user avatar
  • 215
0 votes
1 answer
362 views

Derivations and ideals

Let $R$ be a regular local ring and $I$ and ideal of $R$. If $D$ is a derivation of $R$, let $$\lambda_D:I/I^2\to R/I$$ be the composition of the restriction of $D$ to $I$ and the quotient map $R\to R/...
Hephaistos's user avatar
4 votes
0 answers
128 views

Length of dual module

It is well known that, given a commutative ring $R$ and an $R$-module $M$, the dual module $M^\vee = \operatorname{Hom}_R(M, R)$ does not always satisfy $M^\vee \cong M \ (1)$, and not even $M^{\vee \...
JBuck's user avatar
  • 223
3 votes
0 answers
73 views

Fast checking that a system of polynomial equations is satisfiable over $\mathbb{F}_2$

I have a (fairly large) system of polynomial equations, of the form $$ c_1d_1=0,\ c_1d_2+c_2d_1=0,\ldots $$ (In case it is relevant, all the polynomials are homogeneous of degree 2, except for exactly ...
Pace Nielsen's user avatar
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2 votes
1 answer
223 views

Finitely generated $\mathbb{Z}$-algebra embeds into unramified $p$-adic ring

Let $R$ be a finitely generated ring, that is, a $\mathbb{Z}$-algebra of finite type. Assume that $\operatorname{char}(R) = 0$. It follows from Noether's normalization lemma that $R$ can be embedded ...
HASouza's user avatar
  • 423
4 votes
0 answers
396 views

Non-Noetherian (classical) algebraic geometry

My starting point for this question is that, in a very classical sense, algebraic geometry is the study of solution spaces of systems of polynomial equations over an algebraically closed field. It is ...
Daniel W.'s user avatar
  • 365
3 votes
1 answer
239 views

Vanishing of $\operatorname{Ext}_R^{1}(M,R)$ when $R$ is a Gorenstein local ring of dimension $1$ and $M$ is not finitely generated

Let $(R,\mathfrak m)$ be a Gorenstein local ring of dimension $1$. Let $M$ be an $R$-module (not finitely generated) such that $M\neq \mathfrak m M$ and there exists a non-zero-divisor $x\in \mathfrak ...
Snake Eyes's user avatar
1 vote
0 answers
42 views

If $G$ is a connected bipartite graph, then the edge ideal $I(G)$ is normally torsion free

I am studying the paper "On the Ideal Theory of Graphs" by Simis, Vasconcelos and Villarreal, Journal of Algebra 167, No. 2, 389-416 (1994), MR1283294, Zbl 0816.13003. I got stuck at theorem ...
Sowbarnika R's user avatar
3 votes
0 answers
156 views

Taylor-Wiles systems for higher dimensional deformation rings

Let $R$ be a deformation ring and $M$ be a finitely generated $R$-module. A strategy for proving the theorems $R=T$ is to associate with $(R,M)$ a Taylor-Wiles system denoted $(R_{Q},M_{Q})$. Here I'm ...
Marsault Chabat's user avatar
2 votes
1 answer
138 views

Solvability of derivation Lie algebras of local finite-dimensional commutative algebras

Let $A$ be a finite-dimensional local commutative algebra (with one) over a characteristic zero field $k$. Is it true that the Lie algebra $\operatorname{Der}_k(A)$ of $k$-derivations of $A$ is ...
მამუკა ჯიბლაძე's user avatar
0 votes
0 answers
70 views

Hensel lifting of roots of a biquadratic polynomial

Let $5$ divide $p-1$. Therefore, we have $$1+x+x^2+x^3+x^4=(x-\alpha)(x-{\alpha}^2)(x-\alpha^3)(x-\alpha^4)=f_1f_2f_3f_4$$ over $F_p,$ where $\alpha$ is an element of order $5$ in ${F_p}^\times.$ We ...
HIMANSHU's user avatar
  • 381
1 vote
1 answer
105 views

Perturbing pole of Laurent polynomial/series in a single summand

I am working with the ring of Laurent polynomials $\mathbb{F}[X,X^{-1}]$ over $\mathbb{F}$ for some algebraically closed field $\mathbb{F}$ of any characteristic. I encountered a problem emerging from ...
Jens Fischer's user avatar
2 votes
0 answers
67 views

When does an algebraically independent set "satisfy Noether normalization"?

Let $k$ be a field, $A$ a finitely generated $k$-algebra. By Noether normalization, we know that there exists a finite morphism of $k$-algebras $\varphi : k[x_1, \ldots, x_d] \hookrightarrow A$, with $...
Adelhart's user avatar
  • 237
5 votes
1 answer
357 views

Does the category of integral domains admit a symmetric monoidal structure?

Let $\mathbf{Int}$ be the category of integral domains with injective homomorphisms. Does it admit a symmetric monoidal structure? If so, can we choose $\mathbb{Z}$ as the unit object? If it helps to ...
Martin Brandenburg's user avatar
21 votes
1 answer
638 views

Grothendieck group of the Fibonacci monoid

Let's denote the Fibonacci numbers by $F_0=0,F_1=1,F_{n+2}=F_{n+1}+F_n \; \forall n \ge 0$. According to Zeckendorf's theorem, every positive integer can be represented uniquely as the sum of some (at ...
Zerox's user avatar
  • 1,543
1 vote
0 answers
168 views

Does the symmetric algebra functor preserve inclusions?

Theorem: For any compact abelian group $G$, the homogeneous component $% H^{2}\left( B_{G};% %TCIMACRO{\U{2124} }% %BeginExpansion \mathbb{Z} %EndExpansion \right) $ of degree $2$ is naturally ...
Mehmet Onat's user avatar
  • 1,367
3 votes
0 answers
161 views

Amalgamation of commutative subrings

Let $A$ and $B$ be commutative subrings of a non-commutative ring $X$. Is there always a commutative ring $Y$ containing $A$ and $B$ preserving their intersection? This is equivalent to ask if in the ...
user520947's user avatar
0 votes
0 answers
329 views

Smooth morphisms under base change, Qing Liu's proposition 4.3.38

I have a concern about the first assertion in the proof of proposition 4.3.38 of Qing liu's "Algebraic Geometry and Arithmetic Curves". Referring to smooth morphisms, he says "The ...
BernyPiffaro's user avatar
3 votes
1 answer
228 views

Van der Waerden's classical paper on Hilbert polynomials and Bezout's theorem

Is it possible to obtain an electronic copy of Van der Waerden's "On Hilbert series of composition of ideals and generalisation of the Theorem of Bezout", Proceedings of the Koninklijke ...
pinaki's user avatar
  • 5,339
4 votes
1 answer
334 views

GCD in $\mathbb{F}_3[T]$ with powers of linear polynomials

This is a continuation of my previous question on $\gcd$s of polynomials of type $f^n - f$. Let us call $n > 1$ simple at a prime $p$ when $p-1 \mid n-1$ but $p^k - 1 \not\mid n-1$ for all $k > ...
Martin Brandenburg's user avatar
4 votes
1 answer
278 views

If $\mathbb{C}(u(x,y),v(x,y),f(x))=\mathbb{C}(x,y)$, for every $f(x) \in \mathbb{C}[x]-\mathbb{C}$, then already $\mathbb{C}(u,v)=\mathbb{C}(x,y)$?

The following question is a direct continuation of this elaborate question; it is mentioned there at the end: Let $u,v \in \mathbb{C}(x,y)$ or $u,v \in \mathbb{C}[x,y]$, if it is easier to answer in ...
user237522's user avatar
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1 vote
0 answers
97 views

Algorithms to decompose a graded module over $R[x]$, where $R$ is a PID

There is a certain class of objects, which can be thought of either as modules over a ring $R[x]$ or as functors. A few equivalent definitions are given below. The question is what computer algorithms ...
GHPR's user avatar
  • 11
3 votes
1 answer
162 views

Question on the extension theorem from Humphreys' book on linear algebraic groups

On page 2 of Humphreys' book "Linear algebraic groups" he presents the "extension theorem". I will copy it below: Extension theorem. Let $R/S$ be an integral extension, $K$ an ...
Mr Dumas's user avatar
3 votes
1 answer
372 views

Subalgebras of quadratic algebras that are not quadratic

Suppose $A=k\oplus A_1 \oplus A_2\oplus \cdots$ is a quadratic algebra over a field $k$. Let $B$ be the subalgebra generated by a subspace $V\subseteq A_1$. What are the examples of such subalgebras $...
Lorenzo Del Vecchiopontopolos's user avatar
5 votes
1 answer
327 views

Generalizations of Chevalley–Shephard–Todd's Theorem?

Major Edit I will reformulate my question signicantly, given Anton Geraschenko's comment. The old version of the question is bellow. For simplicity, my base field is $\mathbb{C}$. If $G<\...
jg1896's user avatar
  • 3,318
8 votes
1 answer
356 views

Homological conjectures for finite dimensional commutative algebras

$\DeclareMathOperator\Ext{Ext}\DeclareMathOperator\Hom{Hom}$>Question: What are some (open) homological conjectures that are also relevent for finite dimensional commutative algebras over a field $...
Mare's user avatar
  • 26.5k
4 votes
1 answer
168 views

Does local homomorphism of finite flat dimension preserve Krull dimension?

Let $f:A\rightarrow B$ be a local homomorphism of Noetherian local rings, such that the $A$-module $B$ has finite flat dimension. Is it true that the Krull dimensions of $A$ and $B$ agree? If yes, ...
Boris's user avatar
  • 639
1 vote
0 answers
85 views

Regarding the common zeros of the system of equations

Consider the following two systems of n homogeneous polynomials in n variables of degree $d$ with complex coefficients: System 1 ($S_1$): $f_1(x_1,\dots,x_n) = 0$, $f_2(x_1,\dots,x_n) = 0$, $\vdots$ $...
GA316's user avatar
  • 1,269
3 votes
1 answer
1k views

irreducibility of the polynomial $ x^4 +1 $

Let $K$ be a field. We consider the polynomial $f(x) = x^4 + 1$. It is known that $f(x)$ is irreducible over $\mathbb{Q}$ but reducible over any finite field. Thus $ f(x)$ is reducible over any field $...
Sky's user avatar
  • 923
28 votes
2 answers
863 views

$A^2$ is isomorphic to $A^{(\omega)}$, but not $A$

Is there an abelian group $A$ with $A\not\cong A\oplus A\cong A\oplus A\oplus A\oplus\cdots$ (a direct sum of countably many copies of $A$)? Edited to add: As no answers are forthcoming, does anyone ...
Pace Nielsen's user avatar
  • 18.7k
0 votes
1 answer
118 views

$S/I$-freeness of $I/I^2$ vs $I/I^{(2)}$, where $I$ is a radical ideal of regular local ring $S$

Let $I$ be a radical ideal of a regular local ring $S$. Put $R:=S/I$. Let $I^{(n)}$ be the $n$-th symbolic power of $I$. It is well-known that $I^n \subseteq I^{(n)}$. Is it true that $I/I^2$ is $R$-...
uno's user avatar
  • 412
2 votes
0 answers
165 views

A direct proof that every projectivity between parallel lines is affine

Definition 1. An affine plane is a pair $(X,\mathcal L)$ consisting of a set $X$ and a family $\mathcal L$ of subsets of $X$ called lines which satisfy the following axioms: Any distinct points $x,y\...
Taras Banakh's user avatar
1 vote
0 answers
166 views

Reference request showing that a very general Abelian variety $ A $ of genus $ g>1 $ has cyclic class group with ample generator

In Example of a $ \mathbb{Q} $-factorial, CM normal, projective, Mori dream space $ Z $ such that $ \operatorname{Cox}(Z) $ is integral and not CM I asked for an example of a Cohen Macaulay, normal, ...
Schemer1's user avatar
  • 912
2 votes
1 answer
365 views

Correspondence between fundamental group and geometric properties of $X$

At the time of studing some algebraic topology I was wondering about the following. Let $X$ be a topological space and $\pi_1(X)$ be its fundamental group. If we assume some algebraic property of $\...
KAK's user avatar
  • 613
78 votes
9 answers
26k views

Irreducibility of polynomials in two variables

Let $k$ be a field. I am interested in sufficient criteria for $f \in k[x,y]$ to be irreducible. An example is Theorem A of this paper (Brindza and Pintér, On the irreducibility of some polynomials in ...
Hailong Dao's user avatar
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