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Questions tagged [set-theory]

forcing, large cardinals, descriptive set theory, infinite combinatorics, cardinal characteristics, forcing axioms, ultrapowers, measures, reflection, pcf theory, models of set theory, axioms of set theory, independence, axiom of choice, continuum hypothesis, determinacy, Borel equivalence relations, Boolean-valued models, embeddings, orders, relations, transfinite recursion, set theory as a foundation of mathematics, the philosophy of set theory.

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Is it possible for countably closed forcing to collapse $\aleph_2$ to $\aleph_1$ without collapsing the continuum?

Suppose the continuum is larger than $\aleph_2$. Does there exist a countably closed notion of forcing that collapses $\aleph_2$ to $\aleph_1$, but does not collapse the continuum to $\aleph_1$? ...
Norman Lewis Perlmutter's user avatar
13 votes
1 answer
650 views

About primitively recursively recognizable ordinals

Preliminary: I believe the notion of primitive recursive functions on ordinals is standard and unproblematic (the main difference with the finite case is that one needs to introduce a $\sup$ or $\...
Gro-Tsen's user avatar
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13 votes
2 answers
1k views

The (non-)absoluteness of second-order elementary equivalence

Elementary equivalence is set-theoretically absolute between any two transitive models of set theory; this is also true for the infinitary logics - e.g., $\mathcal{L}_{\omega_1\omega}$ - at least, ...
Noah Schweber's user avatar
13 votes
3 answers
3k views

What is Gödel's pairing function on ordinals?

I find many references to Gödel's pairing function on ordinals but I have not found a definition. What is it?
Colin McLarty's user avatar
12 votes
3 answers
2k views

Why do we need a transitive model in forcing arguments?

One major approach to the theory of forcing is to assume that ZFC has a countable transitive model $M \in V$ (where $V$ is the "real" universe). In this approach, one takes a poset $\mathbb{P} \in M$, ...
dorebell's user avatar
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11 votes
0 answers
747 views

Some questions about $0^{\sharp}$ and forcing over $L$

1-Let $P\in L$ be a nontrivial set forcing or even a tame class forcing (tameness in the sense of Sy Friedman; see for example his Handbook paper), and let $G$ be $P-$generic over $L$. Then it is well-...
Mohammad Golshani's user avatar
12 votes
1 answer
744 views

Can we change the Lebesgue measure by forcing?

Suppose $M$ is a model of ZFC, and $\mu^M$ is the Lebesgue measure on $\mathbb R^M$ such that $\mu^M(\mathbb R^M)=1$. It is known that if $r$ is a Cohen real over $M$ and $N=M[r]$ then $\mu^N(\mathbb ...
Asaf Karagila's user avatar
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12 votes
1 answer
1k views

Forcing Diamond

It is well known that adding a subset of a regular cardinal $\kappa$ with partial functions of size $< \kappa$ forces $\Diamond_\kappa$. One can also see that if $S \in V$ is a stationary subset ...
Monroe Eskew's user avatar
  • 18.6k
12 votes
1 answer
648 views

For which theories does ZFC without global choice prove the existence of a proper class monster model?

Proper class sized monster models are typically formulated in a class theory like $NBG$ and they can reasonably be formalized in $ZFC$ with some kind of global choice, but for some theories you don't ...
James E Hanson's user avatar
12 votes
4 answers
1k views

Universal order type

Every countable order type, such as the countable ordinals, $\mathbb Z$, etc. can be embedded in $\mathbb Q$, so it is universal for countable order types. Is there a universal space for all linear ...
mathahada's user avatar
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12 votes
7 answers
15k views

Easy proof of the uncountability of bijections on natural numbers

Is there an easy proof of the uncountability of bijections on natural numbers? The proof that I have in mind is as follows - $\text{Gal }(\overline{\mathbb Q}/\mathbb Q)$ is a proper uncountable ...
Abhishek Parab's user avatar
12 votes
1 answer
1k views

Kolmogorov-Arnold theorem for (just-)functions

There is famous Kolmogorov-Arnold theorem for continuous functions composition - continuous function of several variables can be composed of continuous functions of two variables. Specialization of ...
kakaz's user avatar
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12 votes
2 answers
1k views

Questions about Prikry forcing and Cohen forcing

I have some questions. The first one is about the product of Prikry's forcing. Let $\kappa$ be a measurable cardinal, $U_1, U_2$ be normal measures on $\kappa$ and let $\mathbb{P}_{U_1}, \mathbb{P}...
Mohammad Golshani's user avatar
11 votes
2 answers
666 views

Non smallness of the set of anafunctors without AC?

Trying to construct a model category constructively is difficult. One often mention the fact that without the axiom of choice one cannot prove that the localization of the category of small categories ...
Simon Henry's user avatar
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10 votes
0 answers
465 views

Does Sageev's result need an inaccessible?

In 1981, building on work by Ellentuck in 1974, Sageev showed ("A model of ZF + there exists an inaccessible, in which the Dedekind cardinals constitute a natural non-standard model of arithmetic," ...
Noah Schweber's user avatar
11 votes
4 answers
2k views

Earliest diagonal proof of the uncountability of the reals.

I cited the diagonal proof of the uncountability of the reals as an example of a `common false belief' in mathematics, not because there is anything wrong with the proof but because it is commonly ...
KP Hart's user avatar
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11 votes
1 answer
704 views

Is $\mathfrak j_{2:1}=\mathfrak{j}_{2:2}$ in ZFC?

A function $f:\omega\to\omega$ is called $\bullet$ 2-to-1 if $|f^{-1}(y)|\le 2$ for any $y\in\omega$; $\bullet$ almost injective if the set $\{y\in \omega:|f^{-1}(y)|>1\}$ is finite. Let us ...
Taras Banakh's user avatar
11 votes
2 answers
2k views

Can GCH fail everywhere every way?

The following question is about if it is compatible to add to $\sf ZF$ an axiom asserting the existence of a countable transitive model of $\sf ZF$ such that for every strictly increasing function $f$ ...
Zuhair Al-Johar's user avatar
11 votes
2 answers
1k views

Is sigma-additivity of Lebesgue measure deducible from ZF?

Is sigma-additivity (countable additivity) of Lebesgue measure (say on measurable subsets of the real line) deducible from the Zermelo-Fraenkel set theory (without the axiom of choice)? Note 1. ...
Mikhail Katz's user avatar
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11 votes
0 answers
556 views

Various definitions of recursion from ordinal machines

Background: I'm trying to get an intuitive understanding of α-recursion and related concepts in higher recursion theory. Once nice book is Peter Hinman's Recursion-Theoretic Hierarchies, available ...
11 votes
2 answers
2k views

Are grothendieck universes enough for the foundations of category theory?

Grothendieck universes are equivalent to ZFC+a strongly inaccessible cardinal. This is low on the large cardinal axiom list. Is it enough to place category theory on a firm foundational basis, and how ...
Mozibur Ullah's user avatar
11 votes
4 answers
3k views

the delta system lemma outside set theory

The lemma: Any uncountable set $S$ of finite sets has an uncountable subset $\Delta \subseteq S$ and an $x$ such that $\forall a,b \in \Delta$, if $a \neq b$ then $a \cap b = x$. $\Delta$ is called a ...
Ryan Thorngren's user avatar
11 votes
0 answers
374 views

A game of harmonic series(s)

Given a set $A\subseteq\mathbb{R}_{>0}$, consider the following (two-player, perfect-information, length-$\omega$) game $H_A$: Players $1$ and $2$ alternately play strictly increasing natural ...
Noah Schweber's user avatar
11 votes
3 answers
1k views

What is the shape of large cardinal tree in implication strength order?

There are two natural orders on large cardinal axioms. (a) Consistency strength order $\sigma \leq_C \theta \Longleftrightarrow ZFC\vdash Con(ZFC+\theta)\longrightarrow Con(ZFC+\sigma)$ (b) ...
user avatar
10 votes
1 answer
354 views

Elementary equivalence between $n\mapsto n+1$ and its inverse on the Stone-Čech remainder?

Consider structures $(A,f)$ encoding a Boolean algebra $A$ endowed with an automorphism $f$. There is an obvious notion of isomorphism between such structures. Consider the endomorphism $\hat{\Phi}$ ...
YCor's user avatar
  • 63.9k
10 votes
2 answers
1k views

Continuum-many independent vectors over Q in R as a Q-vector space

Let's put ourselves in the framework of ZF. Is it true that if we think of the set of real numbers as a rational vector space, there are continuum-many linearly independent vectors? I feel that we ...
David Roberts's user avatar
  • 35.5k
10 votes
1 answer
937 views

Possible inconsistency of weakly Shelah cardinals (I hope not)

A Mathoverflow question by Trevor Wilson defines weakly Shelah cardinals as follows: A cardinal $\kappa$ is weakly Shelah if for all $f : \kappa \to \kappa$ there is some $\alpha < \kappa$ that is ...
Arvid Samuelsson's user avatar
10 votes
1 answer
729 views

What kind of compactness does "expanding $\mathbb{R}$ by constants" have?

EDIT: in retrospect this question should have been split up; I've accepted Joel's answer to the first part below, and asked the second part here. This question is crossposted at MSE; however, it has ...
Noah Schweber's user avatar
9 votes
3 answers
1k views

Is it consistent with ZFC (or ZF) that every definable family of sets has at least one definable member?

I consider definability to mean one of either cases: Definability without parameters (in the language of set theory), or Definability from ordinals and a real (in the same language). So my question ...
user38200's user avatar
  • 1,416
9 votes
2 answers
3k views

A question about Second-Order ZFC and the Continuum Hypothesis

Some logicians-such as G. Kreisel-have stated that the Continuum Hypothesis is decided in ZFC2 ("Second-Order ZFC") although we do not know which way it is decided. This is rather confusing, since it ...
Garabed Gulbenkian's user avatar
9 votes
1 answer
509 views

Transcendence degree of the surreals over the subfield generated by the ordinals

Consider the Grothendieck ring $K[\Omega]$ of the semiring $\Omega$ of all ordinals under the operations of natural sum and product. Its quotient field $K(\Omega)$ is naturally a subfield of the ...
Jesse Elliott's user avatar
9 votes
2 answers
3k views

Compact Hausdorff spaces without isolated points in ZF

$S$ is uncountable := $\vert\mathbb{N}\vert<\vert S\vert$ $S$ is noncountable := $\vert S\vert \not\leq \vert\mathbb{N}\vert$ $(X,T)$ is a nice space := $(X,T)$ is a compact Hausdorff space ...
user avatar
9 votes
1 answer
1k views

Uncountable disjoint closed coverings of $[0,1]$

It is well known that the unit interval $[0,1]$ cannot be decomposed as a countable union of pairwise disjoint closed (nonempty) subsets. See for instance this math.stackexchange question. The proof ...
Carlos's user avatar
  • 1,688
9 votes
3 answers
3k views

What does the axiom of replacement mean and why should I believe it?

Here Professor Blass describes the following cumulative hierarchy of sets: Begin with some non-set entities called atoms ("some" could be "none" if you want a world consisting exclusively of sets), ...
djafe's user avatar
  • 101
9 votes
1 answer
701 views

Case study: what does it take to formulate and prove Quillen's small object argument in ZFC?

I'm getting a bit lost over at Peter Scholze's interesting question about removing the dependence on universes from theorems in category theory. In particular, I'm being forced to admit that I don't ...
Tim Campion's user avatar
9 votes
2 answers
1k views

Martin's cone theorem and recursion theory

Martin's remarkable cone theorem in the theory of determinacy says the following: Suppose $A\subseteq \omega^\omega$ is Turing invariant and determined. If $\forall x\exists y(x\le_T y\& y\in ...
Andrés E. Caicedo's user avatar
8 votes
1 answer
755 views

Forcing mildly over a worldly cardinal.

A cardinal $\theta$ is worldly if $V_{\theta}$ is a model of ZFC. We could force to collapse $\theta$ to a successor cardinal, for example, and destroy the worldliness of $\theta$, but is there a ...
user avatar
8 votes
1 answer
1k views

Does the consistency strength hierarchy coincide with the "arithmetic consequence" hierarchy at ZF + Reinhardt?

In these slides (see especially slide 26), Steel emphasizes the phenomenon that for all known "natural" extensions of ZFC, the ordering by consistency strength agrees with the ordering by containment ...
Tim Campion's user avatar
8 votes
1 answer
420 views

Undetermined games of "overdetermined" type

This is motivated by a previous question of mine, but I think it is ultimately more interesting (and hopefully easier to answer in the positive). In that question, a class of games (on $\omega$, of ...
Noah Schweber's user avatar
8 votes
2 answers
577 views

Possible cardinality and weight of an ordered field

Is it true (in ZFC) that for any regular infinite cardinal $\kappa$ there exists an ordered field of weight $\kappa$ and cardinality $2^\kappa$ (or at least $>\kappa$)? The field of real numbers ...
Taras Banakh's user avatar
8 votes
1 answer
525 views

Intersection of two generic extensions

It is well known that the intersection of two models of ZFC does not have to be a model of ZFC (or even ZF). Now what if we restrict ourselves to models $M[G]$, $M[H]$ which are generic over $M$ for ...
Jonathan Schilhan's user avatar
8 votes
1 answer
580 views

Indeterminacy of long games

Hello, all, Several months ago I sat in on a seminar on AD+, which was incredibly wonderful even though I could barely follow it at all. AD+ is a technical variant of AD, the axiom of determinacy, ...
Noah Schweber's user avatar
8 votes
4 answers
1k views

Formalizations of The Matchstick Diagram Representation of Ordinals

The matchstick diagram is a really interesting and intuitive method of representing countable ordinals. However, because of how difficult it is to graphically represent ordinals with it, I started ...
Keith Millar's user avatar
  • 1,252
8 votes
1 answer
769 views

Can $V\neq\text{HOD}$ if every $\Sigma_2$-definable set has an ordinal-definable element?

This question arises from an issue arising in user38200's recent question concerning models of set theory in which every definable set has a definable element. In my answer to that question, with ...
Joel David Hamkins's user avatar
8 votes
1 answer
736 views

Stationarity and Fodor's lemma for a (nice) poset?

The notion of a stationary set is peculiar in that it applies to subsets of certain very particular posets -- ordinals or powersets. At least to a non-set-theorist, the situation seems to beg for the ...
Tim Campion's user avatar
7 votes
2 answers
268 views

Meeting a set of lines in $\mathbb{R}^n$

Fix an integer $n\ge 2$ and suppose that ${\cal L}$ is a set of lines in $\mathbb{R}^n$. Is there a set $M\subseteq \mathbb{R}^n$ with the following properties? $M$ intersects all the elements of ${\...
Dominic van der Zypen's user avatar
7 votes
1 answer
781 views

How do we know if Vaught's Conjecture is Absolute?

Please note that this might be some confusion on my part about the work surrounding Vaught's conjecture. First of all, Vaught Conjecture states that if a first-order complete theory $T$ in a ...
Kyle Gannon's user avatar
7 votes
1 answer
1k views

Set-theoretic tautologies

Let us consider unquantified formulas of a set theory (for example, NBG), more precisely, the formulas, constructed from variables and the constants $\emptyset, V$ (the empty set and the class of all ...
Victor Makarov's user avatar
7 votes
1 answer
488 views

Ref. request: Additive probability measure on $\mathcal P({\bf N})$ supplies subset of $\mathbf R$ without Baire property

ZFC proves, among the other things, the existence of a (finitely) additive probability measure $\theta: \mathcal P(\mathbf N) \to \mathbf R$ on the power set of $\mathbf N$ such that $\theta(X) = 0$ ...
Salvo Tringali's user avatar
7 votes
1 answer
555 views

Limitations of determinacy hypotheses in ZFC

When considering (set-theoretic) games, we have three parameters we can adjust: Definability of the payoff set The set of legal moves The length of the game When working in $\textsf{ZFC}$, what are ...
Dan Saattrup Nielsen's user avatar

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