Skip to main content

All Questions

Filter by
Sorted by
Tagged with
1 vote
0 answers
89 views

About synonymy relationships around these two theories?

The following question is about patterns of synonymy relationships around two theories, $T^+$ and $\sf PA$. For purposes of self inclusiveness I'll re-iterate $T$ and its extensions. $\textbf{Logic:}$ ...
Zuhair Al-Johar's user avatar
-4 votes
0 answers
133 views

Which arithmetic\set theory is synonymous with this theory?

$\textbf{Logic:}$ Mono-sorted first order logic with equality. $\textbf{Extralogical Primitives: } <, \in$ Define: $x > y \iff y < x$ Define: $x \leq y \iff x < y \lor x=y$ $ \textbf{...
Zuhair Al-Johar's user avatar
-4 votes
1 answer
173 views

To which arithmetic\set theory this theory is bi-interpretable?

$\textbf{Logic:}$ Mono-sorted first order logic with equality. $\textbf{Extralogical Primitives: } <, \in$ $ \textbf{Axioms:}$ $ \textbf{Order:} \ x < y < z \to x < z $ $ \textbf{...
Zuhair Al-Johar's user avatar
1 vote
1 answer
179 views

Natural functions outside $\sf PA$?

Can theories stronger than $\sf PA$ manage to define functions from the naturals to the naturals, that $\sf PA$ cannot? If so, what are examples of those functions?
Zuhair Al-Johar's user avatar
1 vote
1 answer
146 views

Can PA define functions related to higher theories?

Working in $\sf ZFC$ we can define a function $F$ from naturals to naturals such that $F(0) = \, ^\circ\ulcorner r({\sf Z}) \urcorner$, where $r({\sf Z})$ is the Rosser sentence of Zermelo set theory $...
Zuhair Al-Johar's user avatar
1 vote
2 answers
335 views

Heuristic interpretations of the PA-unprovability of Goodstein's Theorem

I've relatively recently learned about Goodstein's Theorem and its unprovability in Peano arithmetic (the Kirby-Paris Theorem). I do not have any real knowledge of formal logic; but I think I've seen ...
Julian Newman's user avatar
1 vote
0 answers
123 views

Is possibile to define transfinite sum and product recursively? [closed]

On mathstackexchange a few days ago I published the following question where I asked about "transfinite" sum and products but actually nobody answered or gave an opinion with a comment: thus ...
Antonio Maria Di Mauro's user avatar
4 votes
1 answer
515 views

Truth Values of Statements in non-standard models

Excuse me, if the question sounds too naive. Non-standard models of PA will have statements of non-standard lengths, basically infinite. And it is also true that every statement of a theory will have ...
Amiren's user avatar
  • 1
5 votes
2 answers
432 views

Models of second-order arithmetic closed under relative constructibility

I know little to nothing about second-order arithmetic and its subsystems. However, I would like to understand when a model of (a subsystem of) second-order arithmetic ($\mathsf{Z}_2$) is downward ...
Lorenzo's user avatar
  • 2,286
-2 votes
1 answer
211 views

Would this alteration safeguard the resulting theory from inconsistency?

If we replace "Emergence" axiom in the theory $T$ presented at posting "What is the set theory synonymous with this order-set theory?" with the following axiom, call the resulting ...
Zuhair Al-Johar's user avatar
3 votes
1 answer
169 views

Would this alteration of $T$ affect its synonymy with PA?

If we replace the single axiom "Emergence" in the axiomatic system $T$ presented at posting [What is the set theory synonymous with this order-set theory], by the following schema. Would the ...
Zuhair Al-Johar's user avatar
1 vote
1 answer
313 views

What is the set theory synonymous with this order-set theory?

Let $ T$ be a theory written in Mono-sorted first order logic with equality, with extralogical primitives: $<, \in$. Define: $x \leq y \iff x < y \lor x=y$ Axioms: $\textbf{Well ordering: }\\\...
Zuhair Al-Johar's user avatar
12 votes
4 answers
1k views

Is this theory synonymous with PA?

Language: Mono-sorted first order logic with equality. Extralogical Primitives: $<, \in$ Define: $x \leq y \iff x < y \lor x=y$ $\textbf{Well ordering: }\\\textit{Transitive:} \ x < y \land ...
Zuhair Al-Johar's user avatar
15 votes
5 answers
2k views

In what sense does the sentence $\operatorname{con}(\mathsf{PA})$ "say" that $\mathsf{PA}$ is consistent?

It seems common amongst logicians to think of "truth" as being relative to a particular structure. Consider, for instance, the first-order theory of groups. The sentence $\forall x\forall y(...
Joe Lamond's user avatar
6 votes
0 answers
407 views

Can Set Theory be turned into Infinite Arithmetic?

The following system I'd label as "Infinite Arithmetic" is simply an endeavor to extend second order arithmetic to the infinite ordinal world, and extending with it the representation of ...
Zuhair Al-Johar's user avatar
1 vote
0 answers
129 views

Is set theory interpretable in infinite primitive recursive arithmetic?

In A Formalization of the Theory of Ordinal Numbers, Takeuti interprets $\sf ZFC$ in a first order theory extending first order arithmetic to the infinite ordinal realm, while at the same time ...
Zuhair Al-Johar's user avatar
2 votes
1 answer
329 views

Can set theory be interpreted in infinite arithmetic?

Is the following system of infinite arithmetic consistent? If so, can it interpret $\sf ZFC$? Language: first order logic Primitives: $\operatorname{Card}, <, + , \times,\text{^}$ where $\...
Zuhair Al-Johar's user avatar
-3 votes
1 answer
638 views

Analysis I, simpler proof of Tao's construction of the integers [closed]

In chapter 4 of Analysis I by Terence Tao, we have the following note about the set theoretic construction of the integers: In the language of set theory, what we are doing here is starting with the ...
HJE's user avatar
  • 23
11 votes
2 answers
379 views

Can singular long models require less than PA?

Say that a long model is an $\mathfrak{A}\models\mathsf{I\Sigma_1}$ such that $\mathfrak{A}$ has strictly greater cardinality than each of its proper initial segments (in the case $\vert\mathfrak{A}\...
Noah Schweber's user avatar
10 votes
2 answers
600 views

Is diamond consistent with 2nd order PA?

If $T$ is a theorem of ZF which says something only about reals, then one may want to prove $T$ using a theory like 2nd order PA or related theories like ZFC$^-$ or GBC$^-$ (minus accounts for the ...
Vladimir Kanovei's user avatar
2 votes
0 answers
137 views

Can we extend the projectively extended real line with a single number that stands for division of zero by zero?

If we work within $\hat{\mathbb R} = \mathbb R \cup \{\infty\}$, i.e. one point compactification of the real line. We extend $<$ relation on $\mathbb R$ to $\hat <$ defined as: $ x \ \hat{<} \...
Zuhair Al-Johar's user avatar
6 votes
1 answer
232 views

Interpretation of $ZFC^-$ in 2nd order Peano arithmetic

Let $Z_2^-$ be the 2nd order Peano arithmetic without the schema of Countable Choice. It has been known, since 1960s at least, that $ZFC^-$ (without the power set) admits an interpretation in $Z_2$ ...
Vladimir Kanovei's user avatar
3 votes
1 answer
140 views

Can we always know if an algebraic rule over the reals is preserved over the extended reals or not?

Recall a prior posting titled Is there an effective way to generalize this approach of affinely extending the number line?, and especially the accepted answer given to it. So we are working in $\sf ...
Zuhair Al-Johar's user avatar
1 vote
1 answer
213 views

Is there an effective way to generalize this approach of affinely extending the number line?

The general approach here is a follow up of the approach outlined in a prior posting on extending the projectively extended real line. In particular arithmetic operators break down to ternery ...
Zuhair Al-Johar's user avatar
-2 votes
1 answer
369 views

Is this extension of the projectively extended real line, consistent?

This posting has been Edited. The edited material shall be noted. The projectively extended real line $\hat {\mathbb R}= \mathbb R \cup \{\infty\}$ is one system which allows division by zero! Yet it ...
Zuhair Al-Johar's user avatar
1 vote
0 answers
117 views

Can this type theory interpret second order arithmetic?

Language: multi-sorted first order logic with equality and membership, where for each natural $t$ there is a set $x^t$ of sort $t$. Equality "$=$" only occurs between variables of the same ...
Zuhair Al-Johar's user avatar
32 votes
2 answers
3k views

Can we interpret arithmetic in set theory, with exactly PA as the ZFC provable consequences?

There are many interpretations of arithmetic in set theory. The Zermelo interpretation, for example, begins with the empty set and applies the singleton operator as successor: $$0=\{\ \}$$ $$1=\{0\}$$ ...
Joel David Hamkins's user avatar
0 votes
0 answers
152 views

What is the strength of allowing multiple predecessor numbers?

If we have a theory of numbers, pairs of numbers, and sets of those, and axiomatize that the relation $<$ on numbers is both extensional and well founded, then this theory would prove all PA axioms ...
Zuhair Al-Johar's user avatar
2 votes
1 answer
147 views

Representation of the equality relation between hereditarily finite sets in weak set theories

Consider General Set Theory ($ \mathsf { GST } $) axiomatized by the following. Axiom of Extensionality: The sets $ x $ and $ y $ are the same set if they have the same members: $$ \forall x \forall ...
Mohsen Shahriari's user avatar
5 votes
0 answers
317 views

$\Sigma_n$-complete sets in the Levy hierarchy

Recall that a set $A \subseteq \mathbb N$ is (many-one, Turing) $\Sigma_n$-complete if it's $\Sigma_n$ and any other $\Sigma_n$ set (many-one, Turing) reduces to it. This definition actually makes ...
Corey Bacal Switzer's user avatar
11 votes
1 answer
400 views

What is the Turing degree of the monadic theory of the real line?

The monadic theory of the real line is the set of all sentences in the monadic second-order language of order which are true in $\mathbb{R}$. In this 1982 paper, Gurevich and Shelah show that true ...
Keshav Srinivasan's user avatar
16 votes
2 answers
1k views

How special is first-order $\mathsf{PA}$?

This is a modified version of a question which was asked and bountied at MSE without success. Below, "$\mathsf{PA}$" refers to first-order Peano arithmetic. There are various "...
Noah Schweber's user avatar
3 votes
0 answers
191 views

Set theories that are complete modulo finite-order arithmetic

In a previous question, I asked whether there can be effectively axiomatizable set theories (at least as strong as, say, ZF) that are complete modulo first-order arithmetic, to which the answer is no; ...
BPP's user avatar
  • 675
1 vote
1 answer
396 views

Complete and consistent first-order theories that contain interesting phenomena

Gödel has shown that a consistent recursively axiomatizable first-order theory that can interpret Robinson arithmetic is incomplete. I think there is some sentimental value in working with a theory ...
user avatar
5 votes
3 answers
1k views

Are there first-order statements that second order PA proves that first order PA does not?

Are there first-order statements that second order PA proves that first order PA does not? Is this known one way or the other? Could you share an example? (edit: to clarify, by 'second order PA' I don'...
pathway's user avatar
  • 117
9 votes
0 answers
325 views

Is there a definable model of PA whose domain is a proper class and whose complete theory is not definable?

Assume ZFC. Is there a formula of $\mathcal{L}_\in$ (without parameters) defining a model $\mathcal{M}$ of PA whose domain is a proper class but the complete theory of that model is not definable by ...
Guy Crouchback's user avatar
16 votes
2 answers
2k views

Could Kronecker accept a proof of Goodstein's theorem?

A famous result of Goodstein asserts that the Goodstein sequence of integers terminates. For a precise statement and a short proof, see https://en.wikipedia.org/wiki/Goodstein%27s_theorem. A well ...
Piotr Hajlasz's user avatar
3 votes
0 answers
301 views

What does second order set theory give us that is new?

There is a natural analogy between the theories PA and ZFC. See the linked question by Gro-Tsen here. Peano arithmetic (PA) is a first order approximation to the natural numbers. As is well known, ...
Pace Nielsen's user avatar
  • 18.7k
29 votes
10 answers
4k views

Defining the standard model of PA so that a space alien could understand

First, some context. In one of the comments to an answer to the recent question Why not adopt the constructibility axiom V=L? I was directed to some papers of Nik Weaver at this link, on ...
Pace Nielsen's user avatar
  • 18.7k
18 votes
1 answer
3k views

Existence of a model of ZFC in which the natural numbers are really the natural numbers

I know that, from compactness theorem, one can prove that there are models of first order arithmetic in which there is some "number" which is not a successor of zero, in the sense that it is strictly ...
display llvll's user avatar
10 votes
1 answer
541 views

Looking for “Set theory for a small universe” by Ketonen

In the paper Partition theorems for systems of finite subsets of integers, Pudlák and Rödl show a Ramsey-type result. The main feature of this result is that the sizes of sets in such systems are not ...
Pedro Sánchez Terraf's user avatar
19 votes
1 answer
747 views

What non-standard model of arithmetic does Hofstadter reference in GEB?

Following some of the coolest bits of Hofstadter's Gödel, Escher, Bach, extensions of the standard model of arithmetic are described. A ways in, the paragraph "Supernatural Addition and Multiplication"...
Dave Pritchard's user avatar
6 votes
1 answer
727 views

What is the consistency strength of this theory?

Language: first-order logic Primitives: $=, S, \in $ (the first denotes identity, the second denotes “is a successor of”, and the third denotes membership relation). Axioms: those of identity ...
Zuhair Al-Johar's user avatar
1 vote
0 answers
346 views

approaching the border between absolute convergence and divergence of series

Let us consider absolute convergent series $\ell^{1^+}$ ordered under eventual dominance (mod finite) $<^*$. T. Bartoszynski proved that unbounded number ${\frak b}(\ell^{1^+}, <^*)$ equals ...
Peter Vojtas's user avatar
3 votes
0 answers
144 views

A conservativity result of intuitionistic set theory over arithmetic

In their 1985 paper "Arithmetic Transfinite Induction and Recursive Well-Orderings", Friedman and Ščedrov prove that the theory $\mathbf{ZFI}$ is conservative over $\mathbf{HA}^*$ (see here, Theorem ...
namsap's user avatar
  • 355
8 votes
0 answers
344 views

What arithmetic is interpretable in Mayberry's Euclidean set theory?

John Mayberry published what he calls a Euclidean set theory in his book The Foundations of Mathematics in the Theory of Sets. It is ZF with the axiom of infinity replaced by an axiom saying "the ...
Colin McLarty's user avatar
8 votes
1 answer
535 views

Is ZFC+(negation of a large cardinal axiom) arithmetically sound?

My knowledge in set theory is very limited, so I apologize if this question is naive or trivial: Let $A$ to be a large cardinal axiom. $T=ZFC+\neg A$ is a consistent theory. My question is: Question ...
Payam Seraji's user avatar
1 vote
2 answers
777 views

Can you remove all the extra arithmetic from ZFC (or other theories)?

Let $\mathbb{N}$ be the standard model of the natural numbers. For any statement in the language of arithmetic, we can translate into a statement in the language of set theory by asking if it is true ...
Christopher King's user avatar
12 votes
2 answers
1k views

Trouble with models of PA and ZFC

I have a big trouble in my mind, here is my false reasoning: The Goodstein's theorem is undecidable in (first order) Peano Arithmetic. There exist a non standard model N of PA where the Goodstein's ...
PostAsAGuest's user avatar
2 votes
1 answer
142 views

Does $WKL_0$ plus CON(PA+X) give a binary tree model of PA+X?

In the context of reverse mathematics $WKL_0$ is considered equivalent to Gödel's completeness theorem over $RCA_0$. Does this mean that e.g. $WKL_0$ plus the consistency statement CON(PA+X) gives a ...
Frode Alfson Bjørdal's user avatar