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Questions tagged [ra.rings-and-algebras]

Non-commutative rings and algebras, non-associative algebras, universal algebra and lattice theory, linear algebra, semigroups. For questions specific to commutative algebra (that is, rings that are assumed both associative and commutative), rather use the tag ac.commutative-algebra.

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When does End(M) consist entirely of zero, zero divisors, and units?

Let $R$ be a commutative ring (with $1$) such that every non-zero divisor in $R$ is a unit (see Rings in which every non-unit is a zero divisor for various stabs at what these are called). Let $M$ be ...
Bill Cook's user avatar
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Rigid monoidal and closed monoidal categories

I am trying to understand the relationship between rigid monoidal categories and closed monoidal categories. First every rigid monoidal category is closed, with an adjoint to the functor $X \otimes -$ ...
Jake Wetlock's user avatar
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Unitary unit conjecture for group rings

The famous "unit conjecture" for group rings states that all units of a group ring $K[G]$ are trivial for a field $K$ and a torison-free group $G$. We are far away from solving the conjecture (See e.g....
Joerg Sixt's user avatar
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Endofunctors on the category of groups which are Galois- related to a linear map on $\mathbb{Q}[x]$

I thank J.C. and Arturo Magidin for interesting suggestions in the comments to this question In this post the field of rational numbers is denoted by $\mathbb{Q}$. The space of polynomials with ...
Ali Taghavi's user avatar
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1 answer
751 views

What's the relationship between a $E_2$-Hochschild Cohomology module and a D-module?

Let's say for simplicity $A$ is a smooth algebra over a field $k$ ($A$ and $k$ are discrete commutative rings but from now on we are fully derived), and we will consider the $E_2$ algebra $HH^{\bullet}...
Andy Jiang's user avatar
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2 answers
622 views

Maximal centralizer in full matrix ring

I will be so thankful if someone can help me with the following question. Is it possible to obtain all maximal centralizers in the full matrix ring, $M_n(F)$, for an arbitrary finite field $F$? Here, ...
Hamid's user avatar
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1 answer
344 views

Surjection onto endomorphisms of multiplicative group of a field

Let $k$ be an algebraically closed field of characteristic $p > 0$. Denote by $k^\times$ the multiplicative group of $k$. There is a ring homomorphism given by restriction to $k^\times$ $$ \mathbb{...
Nicholas's user avatar
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4 answers
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Are quotients of polynomial rings almost UFDs?

If $K$ is a field then the polynomial ring $K[x_1,\ldots, x_n]$ is a UFD. On the other hand, quotients of such a polynomial ring usually don't enjoy unique factorization: consider, for instance, $\...
Armin Straub's user avatar
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1 answer
367 views

Reference request: locally erasable delta-functor is universal

It is well-documented that an erasable delta-functor $(F^n,\delta)$ is universal. However, in 'small' abelian categories (in the technical sense or otherwise), there aren't always enough objects to ...
R. van Dobben de Bruyn's user avatar
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Zappa-Szép products of the monoid of integers with itself

Question What are all the functions $\alpha , \beta : \mathbb{N} \to \mathbb{N}$ satisfying the following functional equations? $\bullet ~~~~ \alpha(0)=0, \quad \beta(0)=0\\ \bullet ~~~ \...
HeinrichD's user avatar
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Left-Module Structure on the Tensor Product ofTwo Left Modules

Given a noncommutative ring $R$, and two (left) $R$-modules $M$ and $N$, how does one define a left action on the the vector space tensor product $M \otimes N$? Multiplying on just the first factor of ...
Ago Szekeres's user avatar
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3 answers
758 views

Unital *-homomorphisms between matrices

It is mentioned on Wikipedia that every unital *-homomorphism $\Phi:M_i\to M_j$ is necessarily of the form $\Phi(a)=U^*(a\otimes I_r)U$ for some unitary $U$ and some $r$. (Here $M_i$ are the $i\times ...
Dominique Unruh's user avatar
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0 answers
241 views

Non-commutative rings where every non-unit is contained in a completely prime ideal

Below, all rings are associative and unital; and the word "ideal" always refers to a two-sided ideal. Let's stipulate that a ring $R$ has property (P) if every non-unit of $R$ is contained ...
Salvo Tringali's user avatar
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2 answers
974 views

Shape of axioms in algebraic structures

When defining algebraic structures (like monoids, groups, etc...), are there some constraints on the shape of the axioms, for the structure to have good properties that we implicitly use in many ...
Denis's user avatar
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1 answer
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$\text{Mod}(A)$ is an $E_n$ category $\Leftrightarrow$ $A$ is an ??? algebra

Say we're working in a symmetric monoidal $\infty$-category $\mathcal{S}$, and $A$ is an associative algebra in it. For instance, $$\mathcal{S}\ =\ \text{dg vector spaces},\ \ \ A\ =\ \text{a dg ...
Pulcinella's user avatar
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Can the trivial module be stably free for a monoid ring?

Let $M$ be a non-trivial monoid and $\mathbb ZM$ its monoid ring. All modules are left modules in what follows. Suppose that $M$ contains a zero element (or absorbing element) $z$. That is $mz=z=zm$ ...
Benjamin Steinberg's user avatar
5 votes
2 answers
332 views

Questions on weakly symmetric algebras

A finite dimensional algebra $A$ over a field $K$ is called weakly symmetric in case $soc(P)=top(P)$ for every indecomposable projective module $P$ and it is called symmetric in case $D(A) \cong A$ as ...
Mare's user avatar
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2 answers
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Have semigroups with actions on themselves that have a dual to the compatibility axiom ever been studied?

For a semigroup $G$ with a left action on itself, the axiom for compatibility becomes: $$ \forall f,g,h\in G:hg(f)=h(g(f)) $$ Now suppose there is additional axiom, or constraint if you prefer, ...
James Smith's user avatar
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0 answers
245 views

Orders of Clifford algebra

Let $C_n$ be the Clifford algebra over $\mathbb{Q}$ associated to negative definite quadratic form $-I_n$ (i.e. $-x_1^2-\dots-x_n^2$). Let $\mathcal{O}$ be a $\mathbb{Z}$-order of $C_n$. Q1) Is it ...
Subhajit Jana's user avatar
5 votes
1 answer
353 views

Existence of non-trivial reflexive modules

Recall that a module $M$ over a ring $R$ is reflexive in case the natural evaluation map $f_M:M \rightarrow M^{**}$ (where $M^{*}=Hom_R(M,R)$) is an isomorphism, where $f_M(m)=g$ with $g(h)=h(m)$, ...
Mare's user avatar
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Are PD-, $\lambda$-, $\psi$-, and $\delta$-rings monoids in a monoidal category?

$\newcommand{\pt}{\mathrm{pt}}\newcommand{\N}{\mathbb{N}}\newcommand{\Z}{\mathbb{Z}}$A number of algebraic structures can be defined as monoids in some appropriate monoidal category: A monoid ...
Emily's user avatar
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1 answer
428 views

Cancellable elements of a power semigroup

For a semigroup $S,$ its power semigroup $P(S)$ is the semigroup of all non-empty subsets of $S$ with the operation given by $AB=\{ab\,|\,a\in A,b\in B\}.$ I would like to know about the cancellable ...
Michał Masny's user avatar
4 votes
1 answer
348 views

Do Frobenius subalgebras form a lattice?

A finite-dimensional, unital, associative algebra $A$ over a field $k$ is termed a Frobenius algebra if it is endowed with a nondegenerate bilinear form $\sigma : A \times A \to k$ satisfying the ...
Sebastien Palcoux's user avatar
4 votes
1 answer
569 views

Name for a Hopf algebra whose only grouplike element is the identity?

For a $k$-Hopf algebra $H$ and element $h \in H$ is called grouplike is $\Delta(h) = h \otimes h$ and $\epsilon(h)=1_k$ ($\epsilon$ is the counit). The identity $1_H$ is clearly grouplike, but in ...
Spyros Olympopolous's user avatar
4 votes
1 answer
202 views

Subalgebras of singular matrices (less naive version)

Is it true that, for any subalgebra $\cal S$ of the algebra of linear operators in a finite-dimensional vector space $V$ over a field, $$ \bigcap_{A\in\cal S}\ker A=\{0\}\hbox{ and } \bigcup_{A\in\cal ...
Anton Klyachko's user avatar
4 votes
1 answer
451 views

Non-associative commutative "group"

When dealing with some hash functions that I was trying to speed up, I toyed with a binary operation with the goal to "approximate" the addition on $\{0,1\}^*$ when seen as binary ...
Dominic van der Zypen's user avatar
4 votes
2 answers
483 views

Rank of sum of Galois conjugates of a matrix

Given an invertible square matrix $M$ with entries from some number field $K$ which is Galois over $\mathbb{Q}$, sum the Galois conjugates of $M$ to form a new matrix $M' = \Sigma_{\sigma \in \mathrm{...
ndkrempel's user avatar
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4 votes
0 answers
162 views

Prime/irreducible elements in certain (integral) ring extensions

The answer to this question says the following: Let $R$ be a finitely generated $k$-algebra, where $k$ is a field. If $p \in R$ is a prime element, then $p$ is a prime element in $\tilde{R}$, the ...
user237522's user avatar
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4 votes
0 answers
157 views

On skew monoid rings and skew ordered series rings

To my knowledge (see, e.g., H.H. Brungs and G. Törner's Skew Power Series Rings and Derivations [J. Algebra 87 (1984), 368-379]), skew polynomial rings were first introduced by Ø. Ore in 1933: Given ...
Salvo Tringali's user avatar
4 votes
1 answer
674 views

What is the relationship between the Dirac algebra and the Clifford algebra?

While I'm still trying to understand the issues raised on my previous question, I decided to first address the Clifford algebra used on formulating the famous Dirac equation. In this context, what is ...
JustWannaKnow's user avatar
4 votes
0 answers
216 views

Characterizing atomicity in a commutative domain

In Proposition 1.1 of [Math. Proc. Cambridge Phil. Soc. 64 (1968), No. 2, 251-264], P.M. Cohn famously claimed (without proof) that a commutative domain is atomic if and only if it satisfies the ...
Salvo Tringali's user avatar
4 votes
1 answer
366 views

Splitting the Witt vectors of $\overline{\mathbb{F}_p}$

Let $\overline{\mathbb{F}_p}$ be the algebraic closure of $\mathbb{F}_p$. Let $W({-})$ denote the functor of taking $p$-typical Witt vectors. Then the extension $\mathbb{F}_p\rightarrow \overline{\...
kiran's user avatar
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4 votes
1 answer
1k views

Commutative associative rational binary operations

What are all the nondegenerate rational binary operations that are commutative and associative? (Examples: $(x,y) \mapsto x+y$, $xy+x+y$, $xy/(x+y)$.) Feel free to re-tag if you can think of ...
James Propp's user avatar
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4 votes
2 answers
322 views

A hands-on description of a "completion" of the free commutative monoid on countably many generators

This is basically an I'm-weak-at-algebraic-geometry question. I asked it as a warm-up question here, but Ilya N asked me to break that post up into several questions. Consider the free commutative ...
Theo Johnson-Freyd's user avatar
4 votes
0 answers
362 views

Comparing different Euclidean algorithms on a Euclidean domain

I have posted this question at stackexchange (502413), without responses until now. In the papers by T. Motzkin: The Euclidean Algorithm, Bull. AMS 55, 1949, pp. 1142--1146 and P. Samuel: About ...
Torsten Schoeneberg's user avatar
4 votes
0 answers
152 views

Nilpotent operator of the Weyl algebra

For a research project I'm currently working on, I came across the following problem: Let $A=$ $^{k <x,y> }\Big/_{(yx-xy-1)}$ be the Weyl Algebra over a field $k$ of characteristic $p$, where $...
u1571372's user avatar
  • 499
4 votes
1 answer
604 views

chain of prime ideals in polynomial ring $S=\Bbb{R}[x_1,x_2,...,x_n,...]$

Consider the polynomial ring of countable variables with coefficients in the real numbers, i.e, $S=\Bbb{R}[x_1,x_2,x_3,...,x_n,...]$. Is the following question true? Question: Is there any maximal ...
Alex's user avatar
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4 votes
1 answer
919 views

How does Constructive Quantum Field Theory work?

Please correct me if I'm wrong, but it seems to me that two and three dimensional axiomatic quantum field theory were constructed as follow: the wightman axioms were formulated in euclidean space via ...
Jimbo's user avatar
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4 votes
0 answers
158 views

Is the group ring of an amenable group, viewed as multiplicative monoid, amenable?

Motivated by this question, it seems natural to ask the following: Question 1: Is there a [finitely generated discrete] torsion-free virtually Abelian (but not Abelian) group $G$ so that the ...
ARG's user avatar
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4 votes
1 answer
1k views

Is the universal enveloping algebra of a finite-dimensional Lie algebra (left) noetherian?

The universal enveloping algebra of a Lie algebra $\mathfrak{g}$ is a flat deformation of $S(\mathfrak{g})$, so these algebras should be similar in many ways. Does at least this general similarity ...
Oleg's user avatar
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4 votes
1 answer
447 views

About a categorical definition of graded (coloured) algebra

The definition of graded algebra had a growing interest in algebra and mathematical physics (see $[GTC]$), I see that this topic has an elegant and simple categorical generalization, but I have not ...
Buschi Sergio's user avatar
4 votes
1 answer
655 views

Are all algebras Igusa-Todorov?

A finite dimensional algebra A is called (n-)Igusa-Todorov in case there exists a module V such that for any module M there is an exact sequence: $0 \rightarrow V_2 \rightarrow V_1 \rightarrow \Omega^{...
Mare's user avatar
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4 votes
0 answers
333 views

Other kinds of equivalence relations on the set of idempotents of a Banach or $C^*$-algebra or a ring (Can we get a new kind of K-theory?)

The standard equivalent relations on idempotents of a $C^*$ algebra or a Banach algebra are Murray von Neumann, similarity and homotopy equivalent. In this post we consider two other kinds of ...
Ali Taghavi's user avatar
4 votes
1 answer
153 views

Linear maps preserved by algebra automorphisms

Let $A$ be a finite dimensional , associative, unital $F$-algebra, where $F$ is a field. Let $s_A:A\to F$ be an $F$-linear map. Now consider an arbitrary field extension $K/F$, and define $s_{A\...
GreginGre's user avatar
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4 votes
1 answer
385 views

Which monoids can be realized as the monoid of ideals of a commutative monoid?

Let $H$ be a commutative monoid (written multiplicatively). We say that a set $I \subseteq H$ is an ideal of $H$ if $IH = I$. The set $\mathcal I(H)$ of all ideals of $H$ is made into a (commutative) ...
Salvo Tringali's user avatar
4 votes
0 answers
248 views

When are all modules direct factors of a direct product of a fixed one?

Background: For a ring $R$, we denote by ${\rm\mathop Mod}(R)$ the category of all (say right) $R$-modules. If $R$ is pure semisimple, then it is known that ${\rm\mathop Mod}(R)={\rm\mathop Add}(M)$, ...
George C. Modoi's user avatar
4 votes
0 answers
210 views

A presentation for a subalgebra

Let $K$ be a field, and let $I=(g_1,\ldots, g_r)$ be an ideal in $A:=K[X_1,\ldots ,X_n]$. Let $\{f_1,\ldots f_m\}$ be a subset of $A$, and let $B$ be the $K$-subalgebra of $A$ generated by $f_1,\...
Ehud Meir's user avatar
  • 5,039
4 votes
1 answer
145 views

Why does the type-A subdivision algebra look like the Rota-Baxter algebra axiom?

Let $\mathbf{k}$ be a commutative ring, and $\beta$ an element of $\mathbf{k}$. Fix a positive integer $n$, and set $\left[n\right] = \left\{1,2,\ldots,n\right\}$. The $n$-th type-A subdivision ...
darij grinberg's user avatar
3 votes
1 answer
158 views

Local Frobenius algebras and their opposite algebras

Assume all algebras are finite dimensional quiver algebras over a field (no restriction of generaltiy if the field is algebraically closed). Let A be a local Frobenius algebra. Is A isomorphic to its ...
Mare's user avatar
  • 26.5k
3 votes
1 answer
328 views

What does it mean for the surreal numbers/partizan games to be "universally embedding"?

In "On numbers and games", Conway writes that the surreal Numbers form a universally embedding totally ordered Field. Later Jacob Lurie proved that (the equivalence classes of) the partizan ...
FreakyByte's user avatar

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