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Finding non-inner derivations of simple $\mathbb Q$-algebras

What's a good example of a simple algebra over a field of characteristic $0$ which has a non-inner derivation but also has the invariant basis number property (IBN)? I'm under the impression that when ...
rschwieb's user avatar
  • 1,507
2 votes
0 answers
108 views

Left-elements of a numerical semigroup generated by two elements

A numerical semigroup $S$ is a semigroup in $\mathbb{N}$ such that $\mathbb{N}\backslash S$ is finite. It is known that there exists always a set $M$ such that an element in $S$ can be expressed as a ...
elbarto's user avatar
  • 31
9 votes
1 answer
743 views

Why is choice needed in Ellis' Lemma?

Ellis Lemma on idempotent elements asserts that: Lemma (Ellis). Every compact semigroup has an idempotent. The proof below is excerpted from Todorcevic's Introduction to Ramsey Spaces, Lemma 2.1. ...
Clement Yung's user avatar
  • 1,412
1 vote
1 answer
90 views

Affine semigroup generating a lattice

This is a cross-post from MSE. Everything is assumed to be finite-dimensional. Let $S$ be a finitely generated affine semigroup (i.e. a subsemigroup of a lattice $N$ of a Euclidean space). Assume that ...
Grisha Taroyan's user avatar
2 votes
1 answer
67 views

$E$-separated semigroups

Definition. A semigroup $X$ is called $E$-separated if for any distinct idempotents $x,y\in X$ there exists a homomorphism $h:X\to Y$ to a semilattice $Y$ such that $h(x)\ne h(y)$. Observe that $X$ is ...
Taras Banakh's user avatar
  • 41.9k
6 votes
1 answer
185 views

A name for semigroups in which left and right principal ideals coincide

Is there any standard name for semigroups $S$ in which $xS=Sx$ for all $x\in S$? Examples of such semigroups are commutative semigroups and Clifford inverse semigroups.
Taras Banakh's user avatar
  • 41.9k
1 vote
0 answers
156 views

Pseudo-coherent complexes over sheaves of non-commutative rings

I am posing a question on derived categories to which I was not able to find an answer anywhere in the literature. I would appreciate any answer, hint or suggestion. Assume that $\mathcal{R}_X$ is a ...
Flavius Aetius's user avatar
3 votes
0 answers
88 views

Explicit separability idempotent for the center of a separable algebra

Let $A$ be a $k$-algebra for some commutative ring $k$. Recall that $A$ is said to be separable over $k$ if the multiplication map $A\otimes_k A^{\operatorname{op}}\to A$ has a section as a map of $A\...
Maxime Ramzi's user avatar
  • 15.8k
2 votes
1 answer
167 views

Existence of reduced norms for CSAs using fpqc descent

Let $k$ be a field and $A$ be a central simple algebra over $k$. It's known that $A$ has a splitting field (i.e. a field $K/k$ such that $A_K\cong M_n(K)$ for some $n$) which is finite and Galois. ...
Gabriel's user avatar
  • 711
4 votes
0 answers
166 views

A non-commutative, left duo ring whose only unit is the identity

Let $R$ be a ring (here, rings are always associative, unital, and non-zero). We say that $R$ is a left duo ring if $aR \subseteq Ra$ for every $a \in R$. Question. Is there a non-commutative, left ...
Salvo Tringali's user avatar
0 votes
2 answers
219 views

Are there any central simple algebras admitting a standard basis?

Are there any central simple algebras admitting a standard basis? By a standard basis I mean a normal basis that has a cyclic property generalizing that of the familiar basis $1, i, j, k$ for ...
Andy's user avatar
  • 113
5 votes
1 answer
266 views

Rings s.t. each element has a power lying in the center (and their completely prime ideals)

Let $R$ be a ring (throughout, all rings are associative and unital). We say $R$ satisfies condition (C) if, for every $a \in R$, there exists an integer $n \ge 1$ (depending on $a$) such that $a^n$ ...
Salvo Tringali's user avatar
5 votes
0 answers
241 views

Non-commutative rings where every non-unit is contained in a completely prime ideal

Below, all rings are associative and unital; and the word "ideal" always refers to a two-sided ideal. Let's stipulate that a ring $R$ has property (P) if every non-unit of $R$ is contained ...
Salvo Tringali's user avatar
5 votes
1 answer
273 views

'Lie correspondence' for formal power series in non-commuting indeterminates

This is related to an earlier question of mine. I would like an argument or a reference (or a missing hypothesis if needed) for the following. Let $\mathbb{F}\langle\langle \alpha\rangle\rangle$ and ...
shane.orourke's user avatar
7 votes
1 answer
281 views

Question concerning the coefficients of block idempotents

Let $G$ be a finite group. Let $p$ be a prime number such that $p \mid |G|$. Let Irr$(G)$ denote the set of ordinary irreducible characters of $G$. For $\chi\in$ Irr$(G)$ define $e_{\chi} := \frac{\...
Bernhard Boehmler's user avatar
9 votes
1 answer
889 views

Combinatorics for the action of Virasoro / Kac–Schwarz operators: partition polynomials of free probability theory

In the background sections below, I establish the relations among characterizations of the action of Virasoro / Kac–Schwarz operators of 2D gravity models presented in terms of Laurent series by ...
Tom Copeland's user avatar
  • 10.5k
7 votes
0 answers
221 views

Strange formula for the dimension of a certain space of noncommutative polynomials

Consider a vector space $V_r(n)$ spanned by (noncommutative) monomials in variables $x_1,\ldots,x_r$ $$ x_{1}^{n_1}x_{2}^{n_2}\ldots x_{r}^{n_r} $$ of total degree $n.$ Inside this space consider a ...
Daniil Rudenko's user avatar
1 vote
0 answers
43 views

Interleaving in Viennot's Heaps models?

I am looking for past results on interleaving of heaps (in the sense of Viennot). For a very simplified example, suppose I have two pieces, (b1 a1 b1), and (b2 c2 b2), where the letter represents a ...
holloway's user avatar
2 votes
0 answers
73 views

Nonzero idempotents in compact semitopological semigroups with zero

Let $S$ be a compact semitopological semigroup. Then, $S$ contains minimal idempotents by Ellis' theorem. Ellis' Theorem: In a compact left-topological (resp. right-topological) semigroup, every ...
Onur Oktay's user avatar
  • 2,605
8 votes
0 answers
285 views

Matrix decompositions as monoid isomorphisms. Ever considered before?

I've noticed some correspondences between some matrix decompositions and monoid isomorphisms (always to some free commutative monoid), in addition to the one I asked about in a previous question: ...
wlad's user avatar
  • 4,943
2 votes
0 answers
145 views

Semigroup ideals of a ring or an algebra

Let $R$ be a ring or an algebra. Suppose $B\subseteq R$ satisfies the property $BR \subseteq B$ and $RB\subseteq B$. Is there a general theory of subsets with this property in a ring (resp. algebra) ...
Onur Oktay's user avatar
  • 2,605
2 votes
0 answers
119 views

The "matrix direct sum" monoid modulo unitary equivalence

Given a commutative $*$-ring $(R,*)$, let $M(R,*)$ be the monoid whose elements are matrices over $R$ of all possible shapes and entries, including those that have $0$ columns or $0$ rows. Let the ...
wlad's user avatar
  • 4,943
7 votes
0 answers
194 views

Factoring a function from a finite set to itself

Let $S$ be a finite set and $f: S \to S$ be a function. Let $k = |f(S)|$ and let $\alpha$ be the partition of $S$ into $f$-fibers, i.e. $\alpha = \{ \alpha_t \}_{t \in f(S)}$ where $\alpha_t = f^{-1}(\...
Sophie M's user avatar
  • 695
9 votes
2 answers
2k views

A ring for which the category of left and right modules are distinct

What is an example of a ring $R$ for which the abelian category of left $R$-modules is not isomorphic to the category of right $R$-modules?
Tim Montegue's user avatar
1 vote
0 answers
85 views

Exponential of a sum in a non-commutative graded algebra

Let $a,b$ be two elements of a graded algebra $A$ such that $\deg(a)=1$, $\deg(b)=0$ and $[a,b]\neq 0$. I would like to know whether there exits an explicit expression for the degree 1 component $$\...
BinAcker's user avatar
  • 789
3 votes
1 answer
299 views

RIng that is flat over a subring as a right module but not as a left module

What is an example of a ring $R$ and a subring $S \subseteq R$ such that $R$ is flat as a right module but not flat as a left module. The following question is my motivation: Faithful flatness for ...
Alain Rochefort's user avatar
4 votes
1 answer
417 views

Is a solvable group satisfying a semigroup law?

Let $S$ be the free semigroup on the set $\{x_1,\ldots ,x_n\}$, where $n$ is a positive integer. Suppose that $\mu=\mu (x_1,\ldots ,x_n)$ and $\nu = \nu (x_1,\ldots ,x_n)$ are two elements in $S$. We ...
mahdi meisami's user avatar
4 votes
0 answers
363 views

A projective module over a domain that is not faithfully flat?

Let $R$ be a (noncommutative) unital ring which is a domain and let $\mathcal{N}$ be a non-zero projective (right) module. Projectivity of course implies that $\mathcal{N}$ is flat, but does the fact ...
Tim Montegue's user avatar
8 votes
1 answer
645 views

Isomorphic morphisms. A 27-morphism category

Two morphisms of category $\ \mathbf C\ $ are isomorphic to one another $\ \Leftarrow:\Rightarrow\ $ they are the opposite edges that are drawn horizontally (aimed East) of a commutative square that ...
Wlod AA's user avatar
  • 4,786
2 votes
2 answers
181 views

Module complements to rings embedded in a projective module

Let $R$ be noncommutative unital ring and $M$ a projective (right) $M$-module. Assume that $R$ embedds into $M$ as a right -module. A) If $R$ is a semisimple ring, then of course $R$ admits an $R$-...
Dick Johnson's user avatar
0 votes
1 answer
139 views

Computationally intractable orbit of a monoid action on a finite set

Suppose for each integer $n\geq 1$ we have a submonoid $M_n\subset \mathrm{Self}(\{1, \dots, n\})$ of self-maps of $\{1, \dots, n\}$. A characterization of $M_n$ is an algorithm that takes an integer $...
westlon's user avatar
2 votes
0 answers
203 views

Can the relation between count of commuting pairs and conjugacy classes for finite groups be generalized to semigroups?

It is well-known that number of pairs of commuting elements in finite group G is equal to number of conjugacy classes multiplied by cardinality of G. More generally here (MO275769) Qiaochu Yuan ...
Alexander Chervov's user avatar
2 votes
1 answer
166 views

Submonoid of free monoid with certain properties

Let $N$ be a submonoid of a free monoid $M$ such that $m_1nm_2\in N \Rightarrow m_1,m_2\in N$ for any $m_1,m_2\in M$ and $n\in N\setminus\{1\}$. $\quad\quad\quad\quad$ (C) Do such submonoids ...
Ralle's user avatar
  • 491
9 votes
0 answers
347 views

What is the precise connection between logarithmic algebraic geometry and the field with one element?

Monoid schemes (a.k.a. $\frak M$-schemes) have been introduced by Deitmar as a possible approach to geometry over the field with one element. These build upon monoids as the basic building blocks for ...
Emily's user avatar
  • 11.8k
1 vote
0 answers
88 views

Sequences generated from commuted quaternions and general commuted linear transformations

Given a pair of non-commuting linear transformations, $A$ and $B$, define the "next pair" in a sequence as $A*B$ and $B*A$. I am interested in finite cycles (i.e., the sequence eventually ...
bobuhito's user avatar
  • 1,547
2 votes
1 answer
287 views

Every module of finite uniform dimension is a direct sum of (finitely many) indecomposable

Crossposted on StackExchange on July 28 (no answer so far). Let $R$ be a (commutative or non-commutative, associative, unital) ring. It is well known that any artinian or noetherian $R$-module $M$ can ...
Salvo Tringali's user avatar
1 vote
0 answers
56 views

Effect on finite transformation semigroup under a particular modification of the generators

The following question arises in connection with problems in automata theory related to the road problem. Let $f_1, f_2: [N] \to [N]$ be maps such that the transformation semigroup $S = \langle f_1, ...
Sophie M's user avatar
  • 695
26 votes
3 answers
724 views

Subtraction-free identities that hold for rings but not for semirings?

Here is a concrete, if seemingly unmotivated, aspect of the question I am interested in: Question 1. Let $a$ and $b$ be two elements of a (noncommutative) semiring $R$ such that $1+a^3$ and $1+b^3$ ...
darij grinberg's user avatar
0 votes
1 answer
49 views

More vocabulary for periodic elements in monoids

Let $M$ be a monoid, and let $x\in M$. One says that $x$ is periodic if $$x^{i+j}=x^j$$ for some integers $i\geq 1$ and $j\geq 0$. An easy division algorithm argument shows that if $m$ is the ...
Pace Nielsen's user avatar
  • 18.7k
8 votes
1 answer
238 views

Functions over monoids which factor in two different ways

This is a follow-up question to this MO question, which was asked by Richard Stanley in a comment to my answer there. Let $S$ be a commutative monoid and $f(x_1, \dots, x_n)$ be a function from $S^n$ ...
Tony Huynh's user avatar
  • 32.1k
3 votes
0 answers
62 views

Image of the reduction of a maximal order in a central simple algebra over $\mathbb Q$

Suppose $A$ is a $n^2$-dimensional central simple algebra over $\mathbb Q$, and $O_A$ is an maximal order of $A$. Choose a finite place $p$ such that $A \otimes \mathbb Q_p \cong M_n(\mathbb Q_p)$. ...
Zhiyu's user avatar
  • 6,622
1 vote
0 answers
66 views

First isomorphism theorem for inverse semigroups together with v-prehomomorphisms?

In this old paper D. B. McAlister has introduced another class of morphisms for inverse semigroups, called v-prehomomorphisms. For such a morphism $\theta : S \to T,$ instead of preserving the ...
Bumblebee's user avatar
  • 1,093
2 votes
0 answers
98 views

Do $r(a) \leq^\oplus R$ and $r(a) = r(a^2)$ imply $r(a) = eR$ and $aR \subseteq (1-e)R$ for some idempotent $e$?

Let $R$ be a (commutative or non-commutative, associative) ring with unity, and let $a$ be an element of $R$ such that $r(a) = r(a^2)$, where $r(\cdot)$ denotes a right annihilator. It follows that $r(...
Salvo Tringali's user avatar
1 vote
0 answers
170 views

What is this algebraic object (special case of a semigroup)?

Let $(M,*)$ be a finite semigroup. Further we demand the following: Zero element: $\exists0\in M \forall m\in M:0*m=0=m*0$. Left cancelation: $\forall m,n,n'\in M:0\neq m*n =m*n' \Rightarrow n=n'$. ...
kevkev1695's user avatar
1 vote
0 answers
39 views

Rings where every indecomposable principal right ideal is extensive

Let $R$ be a (commutative or non-commutative, associative) unital ring. Following Nicholson & Yousif [1, p. 21], we say that a right ideal $\mathfrak i$ of $R$ is extensive if every $R$-linear ...
Salvo Tringali's user avatar
2 votes
2 answers
105 views

Every non-zero submodule of $R_R$ has an indecomposable direct summand: True when $R$ is von Neumann regular?

Let's say that a (right) module $M$ is well complemented if every non-zero submodule of $M$ has an indecomposable direct summand (by the way, is there a better or more standard name for this property?)...
Salvo Tringali's user avatar
1 vote
0 answers
124 views

On the rings $R$ with the property that $eR \cong fR$ for all primitive idempotents $e, f \in R$

Let $R$ be a (commutative or non-commutative) ring with identity. As usual, an idempotent $e \in R$ is primitive if $eR$ (the principal right ideal generated by $e$) is indecomposable as a right ...
Salvo Tringali's user avatar
3 votes
1 answer
311 views

Functors that preserve monoids

In the comments section of this question there was a question that I don't know if it has been asked on the site. It is well-known and easily proved that lax monoidal functors preserve monoids. So the ...
Javi's user avatar
  • 499
6 votes
0 answers
584 views

What are the topics in noncommutative algebraic geometry?

Preface: I know very little about noncommutative algebra and noncommutative geometry, so please feel free to make improvement suggestions for my question. Also, to my knowledge there are several ...
2 votes
1 answer
192 views

Origins of a theorem on an atomic factorizations in domains and cancellative monoids satisfying the ACCPL and the ACCPR

Let $H$ be a (commutative or non-commutative) monoid. We say that $H$ satisfies the ACCPL (ascending chain condition on principal left ideals) if there exists no infinite sequence of principal left ...
Salvo Tringali's user avatar

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