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Questions tagged [ac.commutative-algebra]

Commutative rings, modules, ideals, homological algebra, computational aspects, invariant theory, connections to algebraic geometry and combinatorics.

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4 votes
1 answer
134 views

Terminology/literature for $\forall I\leq A,\; IB\cap A=I$

I am interested in extensions $A\leq B$ of commutative rings with the property that for all ideals $I\leq A$ we have $IB\cap A=I$. Is there a standard name for this property, or a standard reference ...
2 votes
0 answers
97 views

References discussing the category of ordered commutative rings

Is there a reference anywhere discussing the category of ordered commutative rings? I'm thinking of ordered commutative rings and ring homomorphisms preserving the order, but I would also be ...
7 votes
0 answers
275 views

Split epimorphism of modules - does the finite case imply the infinite case?

Let $k$ be a field, $A$ a finite dimensional $k$-algebra, $X$ a finite dimensional indecomposable (left) $A$-module and $M$ an infinite dimensional (left) $A$-module. Suppose further we have an ...
2 votes
2 answers
417 views

Transition maps in trivial direct limit

If $\{X_i, i\in I\}$ is a directed system of abelian groups such that we have $$\varinjlim_{i\in I}X_i = 0$$ is it true that for every $i$ and large enough $j\ge i$ the transition map $f_{i,j} : X_i\...
1 vote
0 answers
66 views

Prove that $f(M)=f^2(M)$ implies $f(M)$ is a direct summand of $M$ whenever $\text{End}_R(M)$ is a reduced ring

Let $M$ be a right $R$-module with the property that every homomorphism $\gamma:Sf\to M, f\in S=\text{End}_R(M)$, extends to $S\to M$. If $S$ has the property $f^2=0$ implies $f=0$ for every $f\in S$...
29 votes
2 answers
7k views

Elementary proof of Nakayama's lemma?

Nakayama's lemma is as follows: Let $A$ be a ring, and $\frak{a}$ an ideal such that $\frak{a}$ is contained in every maximal ideal. Let $M$ be a finitely generated $A$-module. Then if $\frak{a}$$M=M$...
11 votes
2 answers
287 views

Fundamental group under Gelfand duality

Gelfand duality states that the functor of continuous functions $C(-)$ from compact Hausdorff topological to commutative $C^*$-algebras is an equivalence of categories. In other words, all topological ...
18 votes
7 answers
2k views

Superfluous definitions

It is well known that the axioms of a ring R with unity 1 imply that the underlying group must be commutative. For if a and b are elements of R, and writing + for the group operation then applying ...
1 vote
0 answers
110 views

What is some algebraic intuition behind the fact that the (real part) of the logarithm of Bernoulli umbra plus $1$, is $-\gamma$?

Bernoulli umbra is defined in classical umbral calculus as in Taylor - Difference equations via the classical umbral calculus. Yu - Bernoulli Operator and Riemann's Zeta Function shows that $\...
9 votes
1 answer
661 views

What are abelian categories enriched over themselves?

As far as I understand, an arbitrary abelian category is not enriched over itself, for example, $\mathrm{ChainComplex}(\mathrm{Ab})$ is, right? On the other hand, the categories $\mathrm{Mod}(R)$ (in ...
15 votes
1 answer
664 views

R-module hom a direct summand of Z-module hom?

$\DeclareMathOperator\Hom{Hom}$Fix a commutative ring $R$. For $R$-modules $M$ and $N$, there is an inclusion of abelian groups $\Hom_R(M,N) \to \Hom_{\mathbb{Z}}(M,N).$ Are there conditions on $R$ ...
2 votes
0 answers
97 views

Binary unions are effective in abelian categories

Let $\mathsf{A}$ be an abelian category and $S,T\hookrightarrow M$ be two subobjects. We can naturally form the commutative square and it's surely cartesian. (Since intersections are given by ...
1 vote
0 answers
130 views

Stein Manifold and sheaf cohomology with support in a point

Let $X$ be a Stein manifold with analytic structure sheaf $\mathscr{O}_{X}$. Let $M$ be a coherent $\mathscr{O}_{X}$-module, $x \in X$, and $U$ a Stein open containing $x$. Write $\mathfrak{m}_{x}$ ...
1 vote
0 answers
173 views

Calculating multiplication in a finite dimensional algebra over $\mathbb{Q}$

Suppose $ L $ be an extension over $ \mathbb{Q} $ of degree $ n $. Let $\{e_{1},e_{2},\dots,e_{n}\} $ be a basis of this extension. Now I know the product $ e_{i}^{2} $ and $ e_{i}e_{j} $ . So we can ...
2 votes
0 answers
104 views

Does same group of units imply surjective contraction map on spectra

Let $B\subset A$ be an inclusion of Krull dimension 1 rings, and assume $A$ a Dedekind domain. I think that $\mathfrak{p}\in Spec B$ is in the image of the contraction map $\mathfrak{P} \mapsto \...
2 votes
1 answer
314 views

Algebraically characterizing morphisms of commutative rings that are a homeomorphism on the prime spectra

Let us say that a morphism $\varphi\colon A\to B$ of rings (commutative, with unit) is a homeomorphism on the (prime) spectra iff the corresponding map $\operatorname{Spec}B\to\operatorname{Spec}A$ (...
2 votes
0 answers
312 views

Degree $8$ cyclic extension over $\mathbb{Q}$

Actually I am interested in degree $ 8 $ cyclic extension over $ \mathbb{Q} $. Let $ L $ be such extension. At first I was thinking to take basis as normal basis, as we can determine the galois group ...
0 votes
1 answer
130 views

Levi-Civita field in unusual basis

Can all elements of the Levi-Civita field be represented as power series of a single element $$p=\varepsilon^{-1}-\frac{\varepsilon }{24}+\frac{3 \varepsilon ^3}{640}-\frac{1525 \varepsilon ^5}{580608}...
8 votes
3 answers
1k views

How to prove that two univariate polynomials are always algebraically dependent?

How to prove that two univariate polynomials(over any field) are always algebraically dependent? Also, how to prove the generalization of this question i.e if number of polynomials are more than ...
3 votes
0 answers
150 views

Finite commutative group schemes whose exponent coincides with its rank

In group theory, a finite commutative group $G$ contains an element whose order is the exponent of $G$. Thus, If the exponent of $G$ is the same as the order of $G$, it must be that $G$ is cyclic. ...
1 vote
1 answer
128 views

Koszul complex of equations defining a stabilizer

Very specific question. We work over $\mathbb{C}$, although really just want alg. closed of char. 0. Suppose that $G$ is an algebraic group and $V$ is a finite-dimensional $G$-module, meaning that we ...
4 votes
0 answers
258 views

Cotangent complex of a formal thickening

Let $R$ be an (animated) commutative ring, with cotangent complex $L_R$ and let $\mathcal{C}(R) = \mathcal{D}(R)_{\Sigma^{-1}L_R/}$ be the category of nice square zero extensions of $R$. A typical ...
1 vote
1 answer
205 views

Question about linear functionals over C-infinity modules

A remark in Nelson's "Tensor Analysis" implies there are no non-trivial linear functionals on the module of continuous vector fields on a manifold, when considered as a module over the ring ...
1 vote
2 answers
158 views

An example of a commutative ring with a non-zero nil ideal that is idempotent

Recall that an ideal of a commutative ring is said to be a nil ideal if each of its elements is nilpotent. I am looking for a non-zero nil ideal of a commutative ring that is idempotent.
1 vote
0 answers
39 views

When nilradical belongs to a Gabriel filter

Recall that a Gabriel filter of ideals $\mathscr{I}_\sigma$ of a commutative ring $R$ is a non–empty filter of ideals satisfying that every ideal $I$ of $R$, for which there exists an ideal $J\in\...
0 votes
1 answer
154 views

Nullstellensatz and nilpotence of a module

Let $\nu : G \rightarrow H$ be a surjective group homomomorphism with kernel $N$, $H$ abelian, and $G$ finitely generated. The rational abelianization of $N$, $H_1(N)$ is a $\mathbb{C}[H]$-module, ...
3 votes
1 answer
452 views

Commutative algebra for the Conway games

I was reading the book On Number And Games and I have some question. In this book Conway constructed the set of "games" with a addition and a multiplication. I understand that the surreal numbers are ...
0 votes
0 answers
218 views

Cohen-Macaulay modules and connections to Mirror Symmetry

Let $ R $ be a local Noetherian Gorenstein domain. Suppose a module $ M $ fits into an exact sequence $$ 0 \rightarrow K \rightarrow R^n \rightarrow M \rightarrow 0 $$ Then we write $ K = tM $. A ...
1 vote
0 answers
61 views

When some idempotent ideals belong to the Gabriel filter of ideals for a hereditary torsion theory

Let $\mathscr{I}_\sigma$ be the Gabriel filter of ideals for a hereditary torsion theory $\sigma$ over a commutative ring $R$. I am looking for equivalent conditions on either $\sigma$ or $R$ under ...
2 votes
1 answer
253 views

Strict henselianization and branches of explicit curve at singularity

Let $A$ be a local ring, which we can assume is reduced. Let $k$ be the residue field of $A$. In the Stacks project (https://stacks.math.columbia.edu/tag/06DT), I have learned some notion of the ...
6 votes
1 answer
245 views

Reference request for results that involve the transcendence degree

Currently I'm reading "On the Decidability of the Real Exponential Field" by Macintyre and Wilkie and the Proof of Theorem 1.1 (page 462-464) uses two algebraic results that involve the ...
0 votes
2 answers
299 views

A question about localization of commutative rings

Given a commutative ring $ R $ and a multiplicatively closed subset $ S $ of $ R $, there are two ways to consturct $ S^{-1}R $: define an equivalence relation $ \sim $ on $ R\times S $ and then take ...
2 votes
0 answers
235 views

Formally étale maps of animated $k$-algebras

In Lurie's DAG, he defines what it means for a natural transformation $T:\mathcal{F}\to\mathcal{F}'$ of functors $\mathcal{F},\mathcal{F}':\mathcal{SCR}\to\mathcal{S}$ to be formally étale. Namely, it ...
3 votes
0 answers
292 views

modules over principal ideal rings

Let $R$ be a commutative principal ideal ring (not necessarily Artinian) and let $M$ be a finitely generated $R$-module. Is $M$ a direct sum of cyclic $R$-modules? (i.e. a generalization of the theory ...
10 votes
3 answers
3k views

Sum of radical ideals

Let $A$ be a commutative ring and endow the closed subsets of $\operatorname{Spec}(A)$ with the Grothendieck topology of finite covers. One may ask if the presheaf $V \mapsto A/I(V)$ is a sheaf. This ...
2 votes
0 answers
115 views

When $k(f(x), g(x)) = k(x)$? In other words, when is a given polynomial parametrization of an affine planar (rational) curve proper?

If $f, g \in k[x]$, where $k$ is a field, then $k(f, g) = k(h)$ for some rational function $h \in k(x)$ (this is a special case of Lüroth's theorem). Question 1: Under what conditions does the above ...
0 votes
1 answer
128 views

About cluster variables obtained by (sequentially) mutating at exchangeable variables from an initial cluster

Let $\Sigma=(X,ex,B)$ be a seed, $\mathcal{A}(\Sigma)$ a corresponding geometric cluster algebra and $\mathcal{X}_{\Sigma}$ the set of all cluster variables of $\mathcal{A}(\Sigma)$. We call a ...
4 votes
0 answers
356 views

Jet Nestruev's proof that the exterior derivative $d$ on a real line is not a Kähler differential $d_{C^\infty(\mathbb{R})/\mathbb{R}}$

The relation between the exterior derivative $d:C^\infty(\mathbb{R})\to\Omega^1\mathbb(\mathbb{R})$ and the Kähler differential $d_{C^\infty(\mathbb{R})/\mathbb{R}}:C^\infty(\mathbb{R})\to\Omega_{C^\...
1 vote
2 answers
311 views

A variation on Abhyankar–Moh–Suzuki theorem

The well-known theorem of Abhyankar–Moh–Suzuki says the following: Let $f=f(t), g=g(t) \in k[t]$, $k$ is a field of characteristic zero. If $k[f,g]=k[t]$, then $\deg(f) \mid \deg(g)$ or $\deg(g) \mid \...
5 votes
0 answers
276 views

Analysis proof of dual number spectral theorem

Let the dual numbers be $\mathbb R[\varepsilon]/(\varepsilon^2)$. Write a general dual number as $a + b \varepsilon$ (where $\varepsilon^2 = 0$). Given a symmetric matrix $M$ over the dual numbers (i....
1 vote
1 answer
203 views

Special cases of the embedding problem

Embedding problem. Let $I$ be the ideal of polynomial algebra $A=K^{[n]}$, such that $A/I$ is also a polynomial algebra with smaller number $k$ of variables. Is it true that $I$ is generated by $n-k$ ...
10 votes
1 answer
327 views

Proving that polynomials belonging to a certain family are reducible

In an article, I've found the following result. Unfortunately, it was derived from a general, somewhat complicated theory, that would be cumbersome for this result alone. Assume that $\mathbb F_p$ is ...
0 votes
0 answers
112 views

Existence of a subspace of having no isotropic 2-plane

Let $V$ be a vector space of dimension $n$ over the field $\mathbb {Q} $. A subspace $W$ is isotropic for a skew-bilinear form $\alpha$ on $V$ if $\alpha(x,y) = 0$ for all $x,y \in W$. More ...
6 votes
1 answer
442 views

If power of an ideal is locally free then it is locally free

Let $X$ be a noetherian scheme and $\mathcal{I} \subset \mathcal{O}_X$ a coherent sheaf of ideals. Suppose that $\mathcal{I}^d$ is locally-free for some power $d$. Then the blowing up $\mathrm{Bl}_{\...
3 votes
0 answers
234 views

Non-flat base change

Let $(R,\mathfrak{m},k,E)$ be a Noetherian local ring with $E$ an injective hull of $k$, let $M$ be a finitely generated $R$-module and $M^{\vee}=\mathrm{Hom}_{R}(M,E)$. Is there a non-flat $R$-...
2 votes
0 answers
132 views

Pushforward of a Cohen-Macaulay module

Let $f \colon R \to S$ be a homomorphism between (local Noetherian) rings which turns $S$ into a finitely generated $R-$module and let $M$ be a finitely generated over $S$. Is $M$ is Cohen-Macaulay ...
9 votes
2 answers
417 views

Over which (graded) rings are all modules decomposable into indecomposables?

A module is decomposable if it is the direct sum of two modules. The process of splitting summands off of a decomposable module does not need to terminate, so infinitely generated modules do not ...
2 votes
0 answers
112 views

Abelian approximation of fields

Given a field extension $K/k$ of finite degree and a norm $d$ on $\overline{k}$, what is the smallest real number $\alpha_{d}^K$ such that for every element $z$ of $K$ there is an element $z^a$ of $k^...
2 votes
0 answers
160 views

Descent of codimension of a closed subscheme

Let $X$ be an affine integral normal scheme, $Z\subset X$ a constructible closed subscheme of codimension $\geq 2$. We can write $X$ as a limit of schemes $(X_{\lambda})_{\lambda\in \Lambda}$ of ...
4 votes
0 answers
85 views

Do generators of the radical of an ideal generated by polynomials with rational coefficients have rational coefficients?

Let $I\in\mathbb{C}[x_1,\dots,x_n]$ be a an ideal generated by polynomials with rational coefficients. Is $\sqrt{I}$ also generated by polynomials with rational coefficients?

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