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3 votes
1 answer
313 views

Are local rings of monoid algebras geometrically unibranch?

Let $\mathrm{M}$ be a finitely generated submonoid of $\mathbb{Z}^{\oplus d}$ for some $d$, let $A := k[\mathrm{M}]$ be the associated monoid algebra over a field $k$, let $\mathfrak{m} \subset A$ be ...
Minseon Shin's user avatar
  • 2,017
0 votes
1 answer
153 views

C*-algebra of free monogenic inverse semigroup

Let us take the right shift operator $S$ acting on the Hilbert space $l^2(\mathbb{N})$. Consider the C*-algebra generated the operator $ \begin{pmatrix} S & 0 \\ 0 & S^* \end{pmatrix} $ ...
SiOn's user avatar
  • 493
3 votes
0 answers
79 views

Semigroups containing an ideal with a local identity

I'm looking for some classes of semigroups containing a (proper) ideal with a local identity (i.e., ideal submonoid). Can somebody give some examples or/and theorems for the followings cases: (a) ...
M.H.Hooshmand's user avatar
2 votes
1 answer
130 views

Factorisation of positive definite functions

Let $(S,\circ)$ be a semigroup with identical involution. Of course, we know that products of positive definite functions on $S$ are again positive definite. I'm interested in the other direction, ...
Tobsn's user avatar
  • 289
3 votes
0 answers
137 views

Can monoids of "continuous words" be realized as initial monoid objects?

Whenever $X$ is a set, write $X^*$ for the monoid freely generated by $X$. The elements of $X$ are, of course, words in the letters $X$. When $X$ is finite, there also seems to be a great many ...
goblin GONE's user avatar
  • 3,793
2 votes
0 answers
63 views

QF-3 monoid algebras

A finite dimensional algebra $A$ is called QF-3 in case the injective envelope of the regular module is projective. For example all Frobenius algebras are QF-3. Given a monoid algebra $kG$ of a finite ...
Mare's user avatar
  • 26.5k
2 votes
0 answers
91 views

Semigroups of nondecreasing functions

Consider some partially ordered set $(E,\leq)$. Assume either that it is countable with the discrete topology, or that it has some topology compatible with the order, preferably one that makes it into ...
Vilhelm Agdur's user avatar
4 votes
1 answer
312 views

Applications of semigroups

I am limitedly aware of some works done in connecting semigroups and computer sciences. And, indeed, there are many works in this area. May I ask you what would the ingeniously work be with this ...
Mikasa's user avatar
  • 233
10 votes
1 answer
355 views

Is Zariski closure of finitely generated matrix semigroup computable?

In general, can the Zariski closure of the semigroup of matrices $\langle M_1, \ldots, M_k \rangle$ be algorithmically computed (at least in theory)? For this purpose I'm happy to assume the ...
Joël Ouaknine's user avatar
2 votes
0 answers
98 views

If $H$ is an atomic, unit-cancellative monoid such that the set of atoms of $H$ is finite up to associates, then $H$ is BF

In a previous version of this post, $H$ was an atomic commutative monoid such that the quotient $H/H^\times$ is finitely generated, and I was asking if such conditions were enough for $H$ to be BF. ...
Salvo Tringali's user avatar
1 vote
1 answer
166 views

Reference for a proof of cancellation property of braid monoids

Let $M$ be a monoid. If $ab=ac$ implies that $b=c$, $a,b,c \in M$, then $M$ is said to have the left cancellation property. Similarly, the right cancellation property is $ba=ca$ implies that $b=c$. ...
Jianrong Li's user avatar
  • 6,201
5 votes
0 answers
64 views

Characters on monotone functions

Characters on the semigroup $(C_{+}^{b}(\mathbb{R}^{d}),+)$, i.e. on bounded positive continuous functions with the ususal pointwise addition, are known to be of the form $C_{+}^{b}(\mathbb{R}^{d})\ni ...
Tobsn's user avatar
  • 289
5 votes
0 answers
395 views

Derived tensor products and Tor of commutative monoids

Two commutative monoids $M,N$ have a tensor product $M\otimes N$ satisfying the universal property that there is a tensor-Hom adjunction for any other commutative monoid $L$: $$\text{Hom}(M\otimes N,L)...
John Berman's user avatar
4 votes
1 answer
434 views

Regarding a new algebraic structure

By "left semigroup-joined-semigroup" I mean an algebraic structures $(S,\cdot,*)$ such that both $\cdot,*$ are associative, and the following property holds (see this ) $$ x*(y\cdot z)=x*y*z\;\; ; \;...
M.H.Hooshmand's user avatar
4 votes
1 answer
154 views

Right reversibility of submonoids of nilpotent groups

Let $G$ be a finitely generated group (optionally torsion-free). Let $N$ be a submonoid of $G$ (that is, a subsemigroup with $1$). A (cancellative) monoid/semigroup $S$ is right reversible if for ...
David Handelman's user avatar
7 votes
1 answer
167 views

For which abelian groups $G$ does the monoid of zero-sum sequences over $G$ embed into a ring as a divisor-closed subsemigroup?

Let $K$ be a multiplicatively written semigroup (either commutative or not) and $H$ a subsemigroup of $K$. We say that $H$ is divisor-closed (in $K$) if $x \in H$ for all $x, y \in K$ such that $x \...
Salvo Tringali's user avatar
21 votes
1 answer
759 views

Extending $\Bbb N$ to a semiring with isomorphic additive and multiplicative structure

Seen $(\Bbb N,+,\cdot)$ as a semiring, is it possible to extend it to a semiring $(R,+,\cdot)$ so that the additive and multiplicative monoids become isomorphic? This means there is some monoid-...
M. Winter's user avatar
  • 13.6k
3 votes
0 answers
47 views

Counting the monic atoms $f$ in the semiring $\mathbf N[x]$ with $f(0)=1$, bounded coefficients, and degree $k$ (in the limit as $k \to \infty$)

Let $H$ be the multiplicative monoid of the (usual) semiring of polynomials in one variable $x$ with coefficients in $\mathbf N$. Given $\alpha, k \in \mathbf N$, denote by $\mathcal A_k(\alpha)$ the ...
Salvo Tringali's user avatar
9 votes
1 answer
193 views

Detecting/Characterising positive elements in free groups

Let $X$ be a set, and let $F(X)$ be the free group generated by $X$. I will say that an element of $F(X)$ is positive if it is in the monoid generated by all the conjugates in $F(X)$ of every member ...
user49822's user avatar
  • 2,178
3 votes
1 answer
106 views

Representation-finite symmetric monoid algebras

Is it known when a monoid algebra over a field is symmetric and representation-finite? For groups the answer is nice, so maybe there is a nice generalisation giving conditions on the field and the ...
Mare's user avatar
  • 26.5k
2 votes
1 answer
220 views

Alternative notation for Kleene star

I am writing a paper which use two different operations on sets of works $X$, both of which I want to denote by a star, $X^{\ast}$. One of these operations is the Kleene star, and for whatever reason ...
user111368's user avatar
4 votes
1 answer
173 views

On the factorization of powers of atoms in the ring of integers of a number field

Let $H$ be a multiplicatively written monoid with identity $1_H$. An atom of $H$ is a non-unit element $a \in H$ that doesn't split into the product of two non-unit elements. Given $x \in H$, we ...
Salvo Tringali's user avatar
11 votes
2 answers
574 views

Identifying a group without 2-torsion

Suppose we have a finitely presented group $G$ with solvable word problem. (For instance, the command RWSGroup in Magma terminates giving us a finite [but possibly gigantic] rewrite system.) Is there ...
Pace Nielsen's user avatar
  • 18.7k
5 votes
2 answers
252 views

Monoid of continuous self-maps of (real) surfaces

Let $S$ be a closed surface of genus $g > 0$ and $[S,S] = Hom(\pi_{1}(S),\pi_{1}(S))$ be the monoid of (homotopy classes of) continuous maps from $S$ to itself. Consider the semi-group $A$ of ...
Nick L's user avatar
  • 6,995
9 votes
4 answers
1k views

When $X \times Y \cong X \times Z$ implies $Y \cong Z$ (in the category of finite topological spaces)

The title has it all. I'm looking for a reference to the following: Q. Let $X, Y, Z$ be finite, non-empty (topological) spaces. When does $X \times Y \cong X \times Z$ imply $Y \cong Z$ (in the ...
Salvo Tringali's user avatar
5 votes
1 answer
334 views

Short proof a monoid is a group iff every splitting is right homogeneous

In the paper "Schreier split epimorphisms between monoids" by Bourn, Nelson, Martins-Ferreira, Montoli and Sobral, Semigroup Forum June 2014, the authors prove a characterization of groups among ...
Arrow's user avatar
  • 10.5k
1 vote
1 answer
317 views

Monoids (or semigroups) with a "finite decomposition" property

In my research I have come across the following condition on a monoid. Every element $x$ satisfies the following property: there exists a natural number $n$ such that for any $m \geq n$ and any ...
Aleš Bizjak's user avatar
1 vote
1 answer
96 views

If $H$ is commutative and unit-cancellative, then so is the monoid of non-empty ideals of $H$

Let $H$ be a (multiplicatively written) commutative monoid with identity $1_H$. Given $X, Y \subseteq H$, we take $$XY := \{xy: x \in X,\, y \in Y\}.$$ We call a set $I \subseteq H$ an ideal of $H$ ...
Salvo Tringali's user avatar
4 votes
1 answer
385 views

Which monoids can be realized as the monoid of ideals of a commutative monoid?

Let $H$ be a commutative monoid (written multiplicatively). We say that a set $I \subseteq H$ is an ideal of $H$ if $IH = I$. The set $\mathcal I(H)$ of all ideals of $H$ is made into a (commutative) ...
Salvo Tringali's user avatar
3 votes
1 answer
188 views

Finite congruence-free semigroup without zero [closed]

I am reading the book " Fundamentals of semigroup theory" by John M. Howie $\textbf{(Section 3.7)}$. I want to prove $\textbf{Theorem 3.7.2}$ If $S$ is a finite congruence free semigroup ...
Struggler's user avatar
  • 153
4 votes
1 answer
364 views

Values attained by the coheight of $(H \setminus H^\times)^k$ as a function of $H$ and $k$

Edit (Apr 24, 2017). I'm updating this post in the light of the latest developments of a related thread. Let $H$ be a multiplicatively written, commutative monoid, and set $M := H \setminus H^\times$,...
Salvo Tringali's user avatar
3 votes
2 answers
165 views

Weak ideal systems $r$ for which the $r$-coheight satisfies a kind of triangle inequality

Let $H$ be a multiplicatively written, commutative monoid with identity $1_H$, and let $\mathcal P(H)$ be the power set of $H$. If $X, Y \subseteq H$, we will set $$XY := \{xy: x \in X,\, y \in Y\}.$$ ...
Salvo Tringali's user avatar
9 votes
1 answer
154 views

Inductive and reducible functions

The question was asked by a Computer Scientist and is closely related to parallel computing. But it is clearly of algebraic nature, so I decided to post it here. Let $X$ be a set and $\bar X$ be the ...
user avatar
2 votes
0 answers
62 views

Extensions of an ideal-theoretic criterion for a monoid to be BF

Let $H$ be a multiplicatively written, commutative monoid. We denote by $H^\times$ the set of units (or invertible elements) of $H$, and by $\mathcal A(H)$ the set of atoms (or irreducible elements) ...
Salvo Tringali's user avatar
8 votes
2 answers
352 views

Non-density of invertible elements in $\ell_1(\mathbb{N}_0)$

Consider the Banach algebra $\ell_1(\mathbb{N}_0)$ (with convolution / Cauchy product of series). I am looking for an elementary proof of the fact that the group of invertible elements in this algebra ...
Tomasz Kania's user avatar
  • 11.3k
3 votes
1 answer
140 views

Monoids where every two non-unit elements have a common power

Q1. Is there any standard name for a (multiplicatively written) monoid $H$ with the property that, for all $x, y \in H \setminus H^\times$, there exist $m, n \in \mathbf N^+$ and $u, v \in H^\times$ ...
Salvo Tringali's user avatar
6 votes
2 answers
422 views

Monoids in which every prime is an atom

Let $H$ be a multiplicatively written monoid with identity $1_H$. We write $H^\times$ for the set of units (or invertible elements) of $H$. We say that an element $a \in H$ is an atom if $a \notin H^\...
Salvo Tringali's user avatar
2 votes
1 answer
122 views

If $H$ is essentially equimorphic to $K$, then is $H$ atomic only if so is $K$?

I will first state my question, and then give all the relevant definitions. Q. Let $H$ and $K$ be monoids, and assume $H$ is essentially equimorphic to $K$. Is it true that $H$ is atomic only if so ...
Salvo Tringali's user avatar
9 votes
2 answers
1k views

Ternary associative multiplication

In this answer Brian M. Scott describes the following generalization of a binary associative multiplication to a ternary one: it is a function $$[\cdot,\cdot,\cdot] : G\times G \times G \to G$$ such ...
Anton Fetisov's user avatar
8 votes
1 answer
314 views

What algebras are quotients of $\ell_1(\mathbf{N})$?

Every separable Banach space is a linear quotient of $\ell_1$, however not every separable Banach algebra is a Banach-algebra quotient of $\ell_1(G)$ for some group $G$ (these are the so called ...
user512365's user avatar
1 vote
0 answers
58 views

A class of finitely generated semigroups

Let $G$ be a finitely generated group with a probability measure $\nu$. Suppose we have a finite first moment function $f:G\to \mathbb{R}$, i.e, such that $\Sigma_{g\in G}f(g)\nu(g)< \infty$. Then, ...
user148455's user avatar
3 votes
0 answers
110 views

Distributive lattices -> left regular bands -> Atomistic lower semimodular lattices

Consider the following construction : let $(L,\vee,\wedge)$ be a finite distributive lattice, and let $(\mathrm{Int}(L),\star)$ be the monoid defined on the set of non empty intervals of $L$ $$\mathrm{...
Olivier Bégassat's user avatar
3 votes
2 answers
101 views

A non-reduced, commutative BF-monoid s.t. $au = u$ for all $a \in \mathcal A(H)$ and $u \in H^\times$

Let $H$ be a monoid, and denote by $H^\times$ and $\mathcal A(H)$, respectively, the set of units (or invertible elements) and the set of atoms (or irreducible elements) of $H$ (an element $a \in H$ ...
Salvo Tringali's user avatar
5 votes
2 answers
137 views

The smallest number of vertices for a graph with the same endomorphism monoid

Let $G$ be a directed graph without loop and suppose that $M$ is its endomorphism monoid. First how we can create a simple graph $\Gamma$ (using $G$), with the same endomorphism monoid? and then how ...
khers's user avatar
  • 237
2 votes
1 answer
368 views

Finding index/period of a semigroup element

The index and period of a finite monogenic semigroup $\langle x\rangle$ are the smallest numbers $i$ and $p$, respectively, satisfying $x^{i+p}=x^p$. The question is: Is there an algorithm to find ...
M. Farrokhi D. G.'s user avatar
5 votes
0 answers
99 views

Zappa-Szép products of the monoid of integers with itself

Question What are all the functions $\alpha , \beta : \mathbb{N} \to \mathbb{N}$ satisfying the following functional equations? $\bullet ~~~~ \alpha(0)=0, \quad \beta(0)=0\\ \bullet ~~~ \...
HeinrichD's user avatar
  • 5,482
5 votes
1 answer
243 views

Terminology for a monoid $H$ s.t. $xy \in H^\times$ only if $x, y \in H^\times$

The title has it all. Is there any consolidated terminology for referring to a (multiplicative) monoid $H$ such that $xy \in H^\times$ (if and) only if $x, y \in H^\times$? Here is a short list of ...
Salvo Tringali's user avatar
3 votes
1 answer
122 views

A BF-monoid $H$ s.t. $H^\times$ is not divisor-closed

Let $H$ be a (multiplicative) monoid, and denote by $H^\times$ the set of units of $H$ and by $\mathcal A(H)$ the set of atoms of $H$ (let me recall that an element $a \in H$ is an atom if (i) $a \...
Salvo Tringali's user avatar
2 votes
0 answers
51 views

Existence of a canonical embedding from a quotient of $\mathscr{F}^\ast(\mathcal A(H))$ to another

Let $H$ be a multiplicative, commutative monoid, and denote by $H^\times$ the group of units of $H$, by $\mathcal A(H)$ the set of atoms (or irreducible elements) of $H$, by $\mathscr{F}^\ast(\mathcal ...
Salvo Tringali's user avatar
2 votes
1 answer
169 views

A completely simple semigroup with cancelation is a group (simple proof)

Is there a simple proof of the following fact: Fact. Let $S$ be a completely simple semigroup with cancellations, i.e. each of the equalities $xa=xb$, $ax=bx$ implies $a=b$. Prove that $S$ is a group....
Artem's user avatar
  • 153

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