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If $H$ is commutative and unit-cancellative, then so is the monoid of non-empty ideals of $H$

Let $H$ be a (multiplicatively written) commutative monoid with identity $1_H$. Given $X, Y \subseteq H$, we take $$XY := \{xy: x \in X,\, y \in Y\}.$$ We call a set $I \subseteq H$ an ideal of $H$ ...
Salvo Tringali's user avatar
1 vote
0 answers
294 views

Is it true that the functor of completion of a module over a local ring is injective on isomorphism classes?

Let $A$ be a commutative Noetherian local ring and $\hat A$ be its completion. Then we have the functor of completion from the category of finitely generated $A$-modules to the category of finitely ...
Sergei Ivanov's user avatar
1 vote
1 answer
263 views

Relationship between units of a ring and primitive characters of the ring under addition

Let $(R,+,\cdot)$ be a finite ring. Obviously, $(R,+)$ is an abelian group; however the unit (multiplicative) group need not be abelian. My question is the following problem: Given the dual group $\...
Kofi Amponsah's user avatar
1 vote
0 answers
73 views

Relationship between units and primitive characters 2

This is a follow up to this question. Let $(R,+,\cdot)$ be a finite ring. Definition Given the dual group $\widehat{R}$ of $(R,+)$, a character $\chi\in\widehat{R}$ is said to be primitive with ...
Kofi Amponsah's user avatar
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0 answers
178 views

A locally convex $C^*$ algebra without zero divisor

Let we have a locally convex $C^*$ algebra $A$. That is $A$ is a TVS equipped with an algebra and an involution structure such that all operations are continuous. Moreover the topology on $A$ ...
Ali Taghavi's user avatar
1 vote
1 answer
306 views

Simple $C^*$ algebras whose all commutator elements have scalar square

Is there a simple $C^*$ algebra $A$, not isomorphic to $M_2(\mathbb{C})$, such that for every commutator element $x=ab-ba$, $x^2$ is an scalar element?
Ali Taghavi's user avatar
1 vote
1 answer
154 views

A property similar to arithmetical property

By an arithmetical ring is understood a commutative ring $R$ with identity for which the ideals form a distributive lattice, i.e., for which $(I+J)\cap K=(I\cap K)+(J\cap K)$ for all ideals $I, J$ ...
Warner's user avatar
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1 answer
328 views

Number of minimal left ideals

Is there any way to compute the number of minimal left ideals of $M_n(K)$, the full $n\times n$ matrix ring with entries in the field $K$ ?
user avatar
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1 answer
403 views

When does a power semigroup have a zero, and what can the zero be?

Let $S$ be a semigroup. The power semigroup of $S$ is the set $P(S)=2^S\setminus\lbrace\varnothing\rbrace $ with the operation $$AB=\lbrace ab\ |\ a\in A,\ b\in B\rbrace.$$ This operation is ...
Michał Masny's user avatar
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1 answer
155 views

Does the set of positive definite kernels on some set X form a ring?

Given some non-empty set $X$, does the set of positive definite kernels on $K_X$ form a ring with pointwise addition and multiplication. I am convinced it does not as surely if $k \in K_X$ then we ...
Jack O'Connor's user avatar
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74 views

Commutative rings with many nilpotent elements and efficient computation

Let $K$ be commutative ring. Assume that for natural $n$ there are $n$ nilpotent elements $y_i \in K$ satisfying $y_i^2=0, y_i y_j=y_j y_i \ne 0$ and $\prod_1^ny_i \neq 0$. Is it possible to compute ...
joro's user avatar
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2 answers
345 views

Dual of a module

Let $M$ be a $ \mathbb{Z}_{p}[[T]] $-module and $X=Hom(M,\mathbb{Q}_{p}/\mathbb{Z}_{p})$ be the dual of $M$. Let $X[p^n]$ denotes the $p^n$-torsion points of $X$. Is $X/X[p^n]$ the dual of $M[p^n]$ $?$...
Andrew's user avatar
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0 answers
643 views

A new generalization of the dimension?

During my research, I came a cross on these notions : Definition 1: A structure $S$, is a pair $(X, \mathcal T)$ with $X$ a set and $\mathcal T$ a set of subsets of $X$, stable by arbitrary ...
Dattier's user avatar
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0 answers
88 views

Automorphism group of a Lie group $G$ vs that of a double covering group $\tilde{G}$: same or not? [duplicate]

Previously there are some counterexamples given in Automorphism group of a Lie group $G$ vs that of a covering group $\tilde G$: same or not? such that the automorphism group of a Lie group 𝐺 is not ...
wonderich's user avatar
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0 answers
71 views

Generalization of Levi-Civita type construction towards divergent integrals and corresponding questions

A known generalization of Levi-Civita field is a field of Hahn power series of $\varepsilon$ of the form $\mathbb{R}[[\varepsilon^{\mathbb{Q}}]]$. Assuming $\varepsilon=1/\omega$, we can naturally ...
Anixx's user avatar
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0 votes
1 answer
304 views

A Lie group whose Lie algebra is equal to (the Lie algebra? of )all functions with fibrewise polynomial growth

Let $M$ be a Riemannian manifold. We denote by $\mathfrak{g}$ the space of all smooth function $f:TM\to \mathbb{R}$ with fibre wise polynomial growth. Is it a Lie algebra wrt the Poisson bracket ...
Ali Taghavi's user avatar
0 votes
1 answer
152 views

Is it possible to generalize a result of Wang?

Assume $A$ and $B$ are commutative algebras with $1$. There is a nice result of Wang, Corollary 8, which says the following: "Let $B = A[z] = A[Z]/(h(Z))$. Then $B$ is a separable algebra over $A$ if ...
user237522's user avatar
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0 votes
1 answer
791 views

Maximal subgroups of indefinite special orthogonal group SO(p,q)

Can someone answer the following question: Is there any classification of maximal proper Zariski-closed real subgroups of $SO(p,q)$ which are not parabolic, and satisfy the following conditions: ...
Vanya's user avatar
  • 601
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0 answers
208 views

A noncommutative analogy of the tube lemma

Assume that $A$ and $B$ are two unital commutative Banach algebras. Assume that $\phi \in \mathcal{M} (A)$ is an element of the maximal Ideal space. Define $\alpha: A\hat{\otimes} B \to \mathbb{C}\...
Ali Taghavi's user avatar
0 votes
1 answer
83 views

Is the union of 1-dimensional pro-tori in a finite dimensional pro-torus dense?

Is the union of 1-dimensional compact connected abelian subgroups in a finite dimensional compact connected abelian group dense?
Mehmet Onat's user avatar
  • 1,367
0 votes
1 answer
434 views

Reference request: Any connected Lie group has a countable base for its topology

I am looking for a reference for the assertion in the title. This assertion is proved in a comment of user nfdc23 to this question. Has any proof of this assertion been published?
Mikhail Borovoi's user avatar
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0 answers
172 views

The largest abelian subgroups of a Lie group

Let $G$ be a semisimple Lie group. Denote $d(G)$ as the maximal integer $p$ such that $\mathbb{Z}^p$ is isomorphic to a discrete subgroup of $G$ and $c(G)$ is the maximal integer $q$ such that $\...
Yushi MuGiwara's user avatar
0 votes
1 answer
187 views

How to prove a bracket is super anti-commutative?

On page 12 of the paper, there is a formula about super Poisson bracket on a Lie super group $G$: \begin{align} \{\phi, \psi\} = \sum_{\mu, \nu} (-1)^{|\phi||\nu|} r^{\mu \nu} ( R_{\mu} \phi R_{\nu} \...
Jianrong Li's user avatar
  • 6,201
0 votes
0 answers
303 views

For which monic irreducible $f \in \mathbb{C}[x,y][T]$, $\mathbb{C}[x,y][T]/(f)$ is a UFD?

Let $f=f(T) \in \mathbb{C}[x,y][T]$ be a monic irreducible polynomial: $f=T^n+a_{n-1}T^{n-1}+\cdots+a_1T+a_0$, $a_j \in \mathbb{C}[x,y]$, $0 \leq j \leq n-1$. Denote $B=\mathbb{C}[x,y,T]/(f)=\mathbb{C}...
user237522's user avatar
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