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4 votes
1 answer
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Approximation of multipliers by multipliers of a smaller set

Let $X$ be a compact metric space, and let $B$ be a convex balanced bounded set in $C(X)$ such that for every $x\in X$ there is $f\in B$ with $f(x)\ne 0$. Let $M=\{u\in C(X),~ uf\in B,~\forall f\in B\...
erz's user avatar
  • 5,529
5 votes
1 answer
158 views

What is a name for co-Sobczyk Banach spaces?

Definition. Let us define a Banach space $X$ to be co-Sobczyk if every linear bounded operator $T:Z\to c_0$ defined on a separable subspace $Z$ of $X$ extends to a bounded operator $\bar T:X\to c_0$. ...
Taras Banakh's user avatar
2 votes
0 answers
129 views

Logical axioms used in the construction of counterexamples to ISP

In many cases, some problems are either solved in an affirmative way, or in a negative way. However, in some cases it turns out that some logical axioms lead to a proof of a certain statement, while ...
Manuel Norman's user avatar
0 votes
1 answer
81 views

If $\tau_1\subset \tau_2$ and $X^*$ is separable for $\tau_1$ then $X^*$ is separable for $\tau_2$?

Let $X$ be a Banach space the associated dual space is denoted by $X^*$. Take $\tau_1$ and $\tau_2$ two topologies in $X^*$ compatible with the duality $(X^*,X)$, such that $\tau_1\subset \tau_2$. ...
Karim KHAN's user avatar
5 votes
4 answers
4k views

Non-separable Banach space

The vector space $C_b(\mathbb R)$ of bounded continuous functions on $\mathbb R$ is non-separable: it is possible to produce a direct proof of this fact, mimicking the standard proof for the non-...
Bazin's user avatar
  • 16.2k
4 votes
1 answer
137 views

Are unit balls in Banach spaces retracts of bidual balls?

Let $X$ be a separable Banach space embedded canonically in $X^{**}$. Is there a retraction from the unit ball $B_{X^{**}}$ of $X^{**}$ onto the unit ball $B_X$ of $X$? When we insist on uniformly ...
A. U.'s user avatar
  • 97
11 votes
3 answers
445 views

Does the generator of a 1-parameter group of Banach space isometries know which elements are entire?

Let $X$ be a complex Banach space. Let $(\sigma_t)_{t \in \mathbb{R}}$ be a 1-parameter group of linear isometries of $X$ which is strongly continuous i.e. $t \mapsto \sigma_t(x)$ is continuous for ...
Michael's user avatar
  • 662
2 votes
3 answers
256 views

Compact restrictions of the inclusion of $J:L_\infty(0,1)\to L_1(0,1)$

Given Banach spaces $X$, $Y$ and a bounded operator $T:X\to Y$ with non-closed range, a perturbation argument shows that there exists an infinite-dimensional closed subspace $M$ of $X$ such that the ...
M.González's user avatar
  • 4,461
4 votes
2 answers
244 views

Compact images of nowhere dense closed convex sets in a Hilbert space

Let $B=-B$ be a nowhere dense bounded closed convex set in the Hilbert space $\ell_2$ such that the linear hull of $B$ is dense in $\ell_2$. Question. Is there a non-compact linear bounded operator ...
Taras Banakh's user avatar
1 vote
0 answers
64 views

Embedding a normed space as a hyperplane

Let $X$ be a real normed space and suppose that $X$ is a closed hyperplane of a bigger space $\tilde X$. Given any unit vector $u$ in $\tilde X\setminus X$, consider the function $p:X\to\mathbb R$ ...
Black's user avatar
  • 483
0 votes
1 answer
81 views

Ultrabornological representation for the space of uniformly continuous functions?

Let $\{\omega_i\}_{i\in I}$ be a non-empty set of increasing (not necessarily strictly) continuous functions preserving $0$. Then, for each $i \in I$ define the space $$ C_{\omega_i}(\mathbb{R}^n,\...
ABIM's user avatar
  • 5,405
11 votes
1 answer
953 views

Separable bidual but nonseparable third dual

Does there exist a Banach space $X$ such that $X^{**}$ is separable but $X^{***}$ is non-separable? More generally, for every natural $n$ can someone construct an example of Banach space $X$ such ...
Tanmoy Paul's user avatar
-1 votes
1 answer
320 views

Existence of weak limit for bouded sequence $\{y_n\}$ such that for every weak limit point $\{y_n\}$ must equal $y$

Let $X$ be separable Banach space and $\{x_n\}$ be a bounded sequence, relatively weakly compact sequence in $X$. we set $y_n=\frac{1}{n}\sum_{i=1}^{n}{x_i}$, then (together with the Krein and ...
Karim KHAN's user avatar
2 votes
1 answer
70 views

Equicontinuity-like property of a convex compact set

Let $X$ be a Tychonoff topological space and let $x\in X$. Let $B\subset C(X)$ be convex and compact in the topology of pointwise convergence, and such that $f(x)=1$, for every $f\in B$. Is there an ...
erz's user avatar
  • 5,529
7 votes
0 answers
124 views

The bidual of the space of divergence-free vector fields

Consider the Banach space $L_1(\mathbb R^n, \mathbb R^n)$ of integrable vector fields $(n>1$) together with its subspace $N$ formed by those vectors fields whose divergence (computed in the ...
Tomasz Kania's user avatar
  • 11.3k
3 votes
3 answers
358 views

Preannihilators of subspaces of separable duals

If $Y\subset X^*$ is a closed subspace (where $X$ is a separable Banach space), the preannihilator of $Y$ in $X$ is $Y_{\perp}:=\{x\in X : y^*(x)=0, \forall y^*\in Y \}$. If $Y$ is a proper subspace ...
Markus's user avatar
  • 1,361
6 votes
2 answers
735 views

Tensor product space with projective norm is incomplete

Ryan says in his book "Introduction to Tensor Products of Banach Spaces"(pg. 17) that for Banach spaces $X$ and $Y$, $X\otimes Y$ equipped with projective norm is not complete unless $X$ and $Y$ are ...
CSH's user avatar
  • 163
8 votes
1 answer
268 views

Two questions about basic sequences

Suppose $(x_n)$ and $(y_n)$ are two basic sequences in a separable Banach space $X$ such that $\overline{span}\{(x_n), (y_n)\}=X$. Can we always pass to subsequences $(x_{n_k})$ and $(y_{n_k})$ such ...
Adi Tcaciuc's user avatar
17 votes
1 answer
912 views

$(1+\epsilon)$-injective Banach spaces, complex scalars

It is well known that a real Banach space which is $(1+\epsilon)$-injective for every $\epsilon >0$ is already 1-injective (Lindenstrauss Memoirs AMS, 1964, download here). Using common ...
Fred Dashiell's user avatar
1 vote
0 answers
139 views

Any reflexive space has the property of Banach-Saks?

We say that a Banach space $(X,\|.\|)$ has the Banach-Saks property if every bounded sequence $(x_m)_m$ in $X$ admits a subsequence $(x_{m_n})_n$ which converges in the sense of Cesàro, that is, there ...
Made's user avatar
  • 115
4 votes
1 answer
191 views

Intrinsic volumes of non-polyconvex, non-compact sets

I am reposting this question I asked and bountied on Math SE, which has been upvoted but not answered or commented on. The intrinsic volumes (AKA Minkowski Functionals or, with different ...
Joe Previdi's user avatar
6 votes
3 answers
3k views

Why isn't the theorem of approximation applicable in Banach spaces?

Let X be a Hilbert space, A a convex, closed subset of X. Then there exists for every x in X exactly one best approximation in A, that is there exists a y in A such that || x-y || = d(x,A) = inf { || ...
Linda Raabe's user avatar
30 votes
3 answers
3k views

Surjectivity of operators on $\ell^\infty$

Can anyone give me an example of an bounded and linear operator $T:\ell^\infty\to \ell^\infty$ (the space of bounded sequences with the usual sup-norm), such that T has dense range, but is not ...
Amir's user avatar
  • 301
3 votes
1 answer
273 views

Predual to Lipschitz maps with $p$ derivatives

Let $p\in \mathbb{N}$, and define $\mathrm{Lip}_p$ be the collection of functions from $\mathbb{R}^d$ to itself, with $p-1$ first derivatives bounded and whose $p^{\mathrm{th}}$ derivative is ...
ABIM's user avatar
  • 5,405
10 votes
0 answers
230 views

Norm-attaining operators with values in a 2-dimensional Hilbert space

Is the set $N\!A(X,\ell_2^2)$ of norm-attaining operators from a Banach space $X$ onto the $2$-dimensional Hilbert space $\ell^2_2$ dense in the Banach space $L(X,\ell_2^2)$ of all linear continuous ...
Lviv Scottish Book's user avatar
13 votes
4 answers
2k views

Is the category of Banach spaces with contractions an algebraic theory?

Consider the category of Banach spaces with contractions as morphisms (weak, so $\|T\| \le 1$). Is this an algebraic theory? I suspect that this is true. The "operations" will be weighted sums, ...
Andrew Stacey's user avatar
7 votes
1 answer
1k views

weak*-closed subspaces

Recall that a closed subspace $Y$ of a Banach space $X$ is weakly complemented if the set $$Y^{\bot}:= \{ f\in X^*| f(y) = 0 \forall y\in Y\}$$ is a complemented subspace of $ X^*$. For example, $c_0$ ...
Denis Poulin's user avatar
4 votes
1 answer
388 views

Condition for Banach space that the distance function can always reach its minimum at a unique point

Let $(X,\|\cdot\|)$ be a Banach space and $B\subset X$ be a bounded subset. Now define a function $f_B:X\to [0,\infty)$ by $f_B(x)=\sup_{b\in B}\|b-x\|$. My question is in which kind of Banach space,...
ah--'s user avatar
  • 155
0 votes
2 answers
1k views

Does point-wise weak convergence give weak convergence in $L^2(I;X)$?

Let $X$ be a separable reflexive Banach space, $F$ be a locally Lipschitz nonlinear operator on $X$ that is weakly continuous on $X$, and $u_n$ are $u_n$ weakly converges to $u$ on $L^2(0,T;X)$. Now, ...
Saj_Eda's user avatar
  • 395
0 votes
1 answer
178 views

Convergence in LB-spaces

Edit: Let $X$ be a strict LB-space described by $\lim X_n$ and suppose that $\{x_n\}_{n \in \mathbb{N}}$ converges in $X$. I'm looking for a reference showing that $x_n$ must converge in some $X_N$.
ABIM's user avatar
  • 5,405
10 votes
1 answer
366 views

Are all compact subsets of Banach spaces small in a measure-theoretic sense?

Definition. A subset $K$ of a topological group $X$ is called measure-continuous if there exists a $\sigma$-additive Borel probability measure $\mu$ on $X$ such that for every compact subset $C\subset ...
Taras Banakh's user avatar
8 votes
1 answer
325 views

Why $S$ cannot be homeomorphic to the $1$-sphere of $\ell^2$?

Consider the $\ell^2$ complex Hilbert space. Let $m\in \mathbb{N}^*$ be a fixed number, and set $$ S=\left\{ x=(x_n)_n\subset \ell^2\ :\ \sum_{n=1}^m \frac{|x_n|^2}{n^2}=1\right\}.$$ I want to ...
Schüler's user avatar
  • 724
15 votes
3 answers
2k views

Disintegrations are measurable measures - when are they continuous?

This is a sequel to another question I have asked. The notion of disintegration is a refinement of conditional probability to spaces which have more structure than abstract probability spaces; ...
Tom LaGatta's user avatar
  • 8,512
4 votes
0 answers
75 views

What are the complemented subspaces of $(\bigoplus\ell_q^n)_p$?

Bourgain/Casazza/Lindenstrauss/Tzafriri proved in their unconditional basis UTAP book (1985) that $\ell_1$ is the only nontrivial complemented subspace of $(\bigoplus\ell_2^n)_1$, and hence by duality ...
Ben W's user avatar
  • 1,591
1 vote
1 answer
394 views

Are $\| \Delta u \|_{L^p(\Bbb R^d)} + \| u \|_{L^p(\Bbb R^d)}$ and $\| u \|_{W^{2,p}(\Bbb R^d)}$ equivalent norms?

Is it true that $$\| \Delta u \|_{L^p(\Bbb R^d)} + \| u \|_{L^p(\Bbb R^d)}\quad\text{and}\quad\| u \|_{W^{2,p}(\Bbb R^d)}$$ are equivalent norms? This results is pretty easy and straightforward for $...
Guy Fsone's user avatar
  • 1,101
2 votes
0 answers
83 views

Integral convergence with two sequences of functions

I came across this theorem just stated but has not proved and marked by 'it is easy to see'. Theorem If $u_m$ and $v_m$ converges to $u$ and $v$ in $L^2([0,T];H^1(\Omega))$ weakly and $L^2([0,T];L^2(\...
Lev Bahn's user avatar
  • 239
1 vote
0 answers
73 views

The $w^{*}$-convergent sequences and the Mackey topology on $X^{*}$

Let $X$ be a Banach space. Recall that the Mackey topology $\mu(X^{*},X)$ on $X^{*}$ is the topology of uniform convergence on weakly compact subsets of $X$. Let $(x^{*}_{n})_{n}$ be a sequence in $X^{...
Dongyang Chen's user avatar
8 votes
1 answer
523 views

Are the following subsets of a Hilbert space always homeomorphic?

Let $F$ be a infinite-dimensional complex Hilbert space, with inner product $\langle\cdot\;| \;\cdot\rangle$, the norm $\|\cdot\|$, the 1-sphere $S(0,1)=\{x\in F;\;\|x\|=1\}$ and let $\mathcal{B}(F)$ ...
Schüler's user avatar
  • 724
1 vote
1 answer
303 views

Density of norm-attaining operators

By Bishop-Phelps theorem we know that for a real Banach space, the set of all norm attaining bounded linear functionals is norm-dense in $X^*$, the topological dual of $X$. We also know that in ...
Anupam's user avatar
  • 585
-1 votes
1 answer
108 views

Are local diffeomorphisms Fredholm maps with index zero? [closed]

Does this statement correct? if it does how we can prove it. In Banach spaces a map is local diffeomorphism if and only if it is a Fredholm map of index zero with no critical points?
Richard Kim's user avatar
13 votes
1 answer
724 views

Trace-class operator satisfies $\sum |\lambda_n|<\infty$?

Here's an "exercise" which I thought should be easy, but which I find myself unable to do. Let $V$ be a Banach space. Recall that an operator $f:V\to V$ is trace-class if it is in the image of the ...
André Henriques's user avatar
0 votes
1 answer
208 views

Can a hyperplane be contained in a subspace?

Suppose $Y$ is a subspace of a normed linear space $X$ and let $y\in S_Y, y^*\in S_{Y^*}$ such that $y^*(y)=1$, where $S_Y$ denotes the closed unit sphere in $Y$. My question is the following: Is it ...
Anupam's user avatar
  • 585
3 votes
3 answers
2k views

Determining if a set is a Basis for l^2

For each $ n\ge 1$ Define the vectors $e_n = (e_{nk})$ where $ k\ge 1$ and $ e_{nk} = \frac{1}{k^n}$ Is this set a basis for $l^2$? Thanks,
Ali's user avatar
  • 4,153
0 votes
1 answer
102 views

Law of a step function and its generalization to two dimensions on an appropriate spaces

Let's consider two discontinuous functions defined on $D$ and $D \times [0,T]$, respectively: A step function: $u_1(x)=\begin{cases} u_{L}, x<c_1, \\[2ex] u_{R}, x>c_1, \end{cases}$ A "...
Mark's user avatar
  • 657
2 votes
1 answer
378 views

Does the norm on a sequence space have to be monotone?

Let $\rho:[0,+\infty)^{\mathbb{N}}\to[0,+\infty] $ satisfy the following properties: $\rho(\lambda u)=\lambda\rho( u)$, for every $u\in [0,+\infty)^{\mathbb{N}}$ and $\lambda\ge 0$; $\rho(u+v)\le \...
erz's user avatar
  • 5,529
0 votes
1 answer
131 views

A question on the metric approximation property

Let $X,Y$ be Banach spaces. Suppose that $X^{***}$ has the metric approximation property. Let $T:X^{**}\rightarrow Y$ be a finite-rank operator and let $\epsilon>0$. Is there a finite-rank operator ...
Dongyang Chen's user avatar
8 votes
0 answers
330 views

Complementability of finite dimensional subspaces

Suppose $X$ is a separable infinite dimensional Banach space, $E$ a finite dimensional subspace which is $c$-complemented in $X$. Is the following true? For any $\varepsilon>0$, one can find $x\...
Markus's user avatar
  • 1,361
6 votes
2 answers
3k views

Closed convex bounded sets are weakly compact for which spaces?

It is known that for all reflexive Banach spaces, closed convex bounded sets are weakly compact (compact for the weak topology). What is the general class of topological vector spaces for which this ...
Jon-S's user avatar
  • 549
0 votes
0 answers
170 views

Limit of balls in $L^p$

Setup: Let $\mu$ be a measure on a measurable space $(X,\Sigma)$, such that for every $p ,q\in [1,\infty)$, $L^p_{\mu}(\Sigma)\subseteq L^q_{\mu}(\Sigma)$ if $p\geq q$. Furthermore, the inclusions ...
ABIM's user avatar
  • 5,405
6 votes
1 answer
450 views

Is each compact metric space a subset of a compact absolute 1-Lipschitz retract?

A metric space $X$ is called an absolute $L$-Lipschitz retract if for any metric space $Y$ containing $X$ there exists a Lipschitz retraction $r:Y\to X$ with Lipschitz constant $Lip(r)\le L$. ...
Taras Banakh's user avatar

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