Skip to main content

All Questions

Filter by
Sorted by
Tagged with
0 votes
1 answer
429 views

Separability of $\mathbb{C}[x]$ over its $\mathbb{C}$-subalgebras

For commutative rings $R \subseteq S$, recall that $S$ is separable over $R$, if $S$ is a projective $S \otimes_R S$-module, via $f: S \otimes_R S \to S$ given by: $f(s_1 \otimes_R s_2)=s_1s_2$. ...
user237522's user avatar
  • 2,837
0 votes
1 answer
299 views

K3 Surfaces : Derivations and automorphisms

The literature about K3 surfaces is extensive. Let us consider the fact that the zero locus of any smooth homogeneous degree 4 equation is a K3 surface. Let $R$ the quotient ring of a homogeneous ...
Binai's user avatar
  • 829
0 votes
1 answer
132 views

Special elements of the Cremona group

After asking this MO question, I wish to ask about the following special case: Let $f$ be a $\mathbb{C}$-algebra automorphism of $\mathbb{C}(x,y)$ and denote $u:=f(x),v:=f(y)$. Is it possible to ...
user237522's user avatar
  • 2,837
0 votes
1 answer
139 views

Projective modules and gradings

Let $A$ be a noetherian, graded ring and $M$ be a projective, graded $A$-module. Denote by $M_{\ge d}:=\oplus_{\ell \ge d} M_\ell$ the sub-module of $M$. Is $M_{\ge d}$ again a projective $A$-module?
Ron's user avatar
  • 2,126
0 votes
2 answers
758 views

Splitting field of an intermediate field

Consider the following 'wrong' question. Let $f(x) \in F[x]$ be an irreducible polynomial in a polynomial ring of a field $F$. Let $L$ be the splitting field of $f(x)$ over $F$. Assume that $L$ is a ...
seoneo's user avatar
  • 103
0 votes
1 answer
307 views

Glue DVR to itself, get a separated non-affine scheme

Here is what seems to be a fun little exercise in algebraic geometry. Take a DVR $R$ and automorphism of $Frac(R)$; glue $Spec(R)$ to itself via this automorphism. Can the glued scheme be separated ...
Lee Pak's user avatar
  • 25
0 votes
1 answer
269 views

Valuation ring satisfying either a.c.c. or d.c.c. on prime ideals

If a commutative ring with unity has finite Krull dimension, then it satisfies a.c.c. and d.c.c. on prime ideals. The converse is not true in general, as can be seen from here An infinite dimensional ...
user521337's user avatar
  • 1,209
0 votes
1 answer
339 views

Under which conditions on the homogeneous ideal $ I $, the quotient ring $ \mathbb{C} [X_0, \dots, X_n]/I $ is a regular ring?

If $ I $ is a homogeneous ideal of the ring of homogeneous polynomials $ \mathbb {C} [X_0, \dots, X_n] $ , under which conditions on the homogeneous ideal $ I $, and particularly on $ I_m $, the $m$ -...
YoYo's user avatar
  • 325
0 votes
1 answer
655 views

How to show two semigroups are isomorphic?

I have two finite semigroups namely $$S_1=\langle a,b: R\rangle,~~~S_2=\langle a,b: T\rangle$$ How can one show they are the same isomorphically? Should I show that the relations in one, implies the ...
Mikasa's user avatar
  • 233
0 votes
1 answer
165 views

How to classify a plane complex curve?

Let $p_1, p_2, t_1, t_2, a \in \mathbb{C}$ be constants. Consider the following plane complex curve in $\mathbb{C}^2$ ($c_1, c_2$ are indetermniates) \begin{align} & {p_1}^2 {p_2}^2 c_1 {t_1}^2 ...
Jianrong Li's user avatar
  • 6,201
0 votes
1 answer
309 views

exact short sequence of divisible groups splits? [closed]

Let $0 \rightarrow A \rightarrow B \rightarrow C \rightarrow 0$ be a short exact sequences of divisible abelian groups. Does then the sequence splits?
user350168's user avatar
0 votes
1 answer
153 views

C*-algebra of free monogenic inverse semigroup

Let us take the right shift operator $S$ acting on the Hilbert space $l^2(\mathbb{N})$. Consider the C*-algebra generated the operator $ \begin{pmatrix} S & 0 \\ 0 & S^* \end{pmatrix} $ ...
SiOn's user avatar
  • 493
0 votes
1 answer
343 views

Relative Bertini Theorem

Let $A \colon= {\Bbb C}[S_1,\ldots,S_n]$ with $1 \leq n < \infty$ $B \colon= A[X_1,\ldots,X_d]$ with $2 \leq d < \infty$. $O \colon= (0,\ldots,0)$ be the origin of ${\mathrm{Spec}}\,B$. ...
Pierre's user avatar
  • 563
0 votes
1 answer
73 views

A question on infinite local rings which are not division ring

Is it true that if $(R,m)$ is a (not necessary commutative) local ring then $R$ and $m$ have the same cardinal ? (Exclude TWO trivial cases: when $R$ is finite and when $R$ is a division ring) On ...
Mark 's user avatar
  • 271
0 votes
1 answer
300 views

Behaviour of length function under faithfully flat extension

Let $(R,m)$ and $(S,n)$ be local Noetherian rings such that $S$ is a faithfully flat extension of $R$. Let $J\subsetneq I $ ideals of $R$. Can we relate $l_R(I/J)$ and $l_S(IS/JS)$? PS: Here $l(-)$ ...
Cusp's user avatar
  • 1,713
0 votes
1 answer
266 views

Example of a principal ideal which is properly contained in its relative integral closure

Let $I$ be an ideal in a Noetherian quasi-unmixed local ring $(R,\mathfrak m)$ of dimension $d.$ Let $q(I)=\overline{I}\cap I^{sat}$ where $I^{sat}=\cup_{n\geq 0}I:\mathfrak m^n.$ Then $q(I)$ is ...
Cusp's user avatar
  • 1,713
0 votes
1 answer
372 views

The growth of the Hilbert function of a graded ring

Let $A=\bigoplus A_i$ be a finitely generated commutative unital graded algebra over a field $k$. Let $d(i)=\dim A_i$. In general $d(i)$ is not a polynomial in $i$ (even not eventually polynomial). ...
Rami's user avatar
  • 2,649
0 votes
1 answer
131 views

Radical of modules [closed]

Let $R$ be a local ring with the unique maximal ideal ${\frak m}_R$ and $M$ be a $R$-module. Define $I(M) \colon= \cap ~({\mathrm{all~ proper~ maximal ~submodules~ of}}~M)$, where proper means ...
Pierre MATSUMI's user avatar
0 votes
1 answer
2k views

injective modules and divisible modules

The following result is basic ( P.J.Hilton, U.Stammabach, a course in homological algebra ). Let $A$ be a principal ideal domain. Then a $A$ module is injective iff it is divisible. Now if the ...
user95223's user avatar
0 votes
1 answer
185 views

Linkage is equivalence relation

Let $(R,m)$ be a Cohen-Macaulay local ring, I and J are ideals of height $r.$ Then we say $I$ is directly linked to $J$, i.e. $I \sim J$ if there exists an ideal K generated by a regular sequence $x_1,...
Cusp's user avatar
  • 1,713
0 votes
1 answer
232 views

Inverse Galois Problem ; Galois group of some branched cover of $P^{1}$ defined over $\mathbb{Q}$

I was trying to read a paper on Inverse Galois problem . I understands what the inverse Galois problem is. It asks if every finite group is the Galois group of some extension of the rationals. The ...
Tensor_Product's user avatar
0 votes
3 answers
439 views

Example of indecomposable self injective ring

Is there any example of an indecomposable self-injective commutative ring with 4 or more maximal ideals?$$$$$$$$
arenna's user avatar
  • 9
0 votes
1 answer
381 views

Maximal group image

How does one prove: if $S$ is a finitely generated Clifford semigroup its maximal group image is actually $S_{e_{n}}$?
Daisy's user avatar
  • 1
0 votes
1 answer
168 views

integral closure of m-primary ideals

I need help with this excercise Let $k[X_1,\ldots,X_d]$ be the polynomial ring in $X_1,\ldots,X_d$ over a field $k$, and let $F_1,\ldots,F_m$ be forms of degree $n$. Assume that $(X_1,\ldots,X_d)=\...
Monica's user avatar
  • 19
0 votes
1 answer
301 views

local cohomology and radical of ideal

Let $R$ be commutative ring with identity, $M$ an $R$-module, and $I$ an ideal of $R$ . One defines $I$-torsion functor $Γ_I$ as: $\Gamma_I(M)=\bigcup_{n\in N} (0:_MI^n).$ When $R$ is Noetherian, it'...
user 1's user avatar
  • 1,355
0 votes
1 answer
124 views

polynomial expression for counting number of integral points of a set

Let $v_i=a_ie_i\in\mathbb R^d$ and $w_i=b_ie_i\in\mathbb R^d$ for $i=1,\dots,d$ where $e_i$'s are unit vetcors and $a_i,b_i$ are positive integers. Let $$S=conv\{0,rv_i+sw_i:i=1,\dots,d\}.$$ Can we ...
Cusp's user avatar
  • 1,713
0 votes
1 answer
165 views

$\inf\{i\in \mathbb N \cup \{0\}\cup\infty\mid Ext^i_R(R/I,R)\neq 0\}=0 ?$

Let $R := k[x_1, \cdots, x_n, \cdots]/(x_1^1, \cdots , x^n_n, \cdots),$ where $k$ is a field. Set $I:=(x_1, \cdots, x_n, \cdots)$. the questions are: Is $\inf\{i\in \mathbb N \cup \{0\}\cup \{\...
user 1's user avatar
  • 1,355
0 votes
1 answer
229 views

Canonical module of rees algebra

[Example 4.27, Integral Closure, Rees Algebras, Multiplicities, Algorithms] by Vasconcelos, says that if $I=(f_1,\ldots,f_g)$ is an ideal generated by a regular sequence with $g\ge 2$ then the ...
Aurora's user avatar
  • 591
0 votes
1 answer
824 views

Extension of homomorphism to place in quotient field, or of local ring to valuation ring in quotient field

Let be given a domain $R$ (that can be supposed to be integrally closed if this can help), and $\varphi$ an homomorphism of $R$ into a field $F$. $\varphi$ extends uniquely to a homomorphism $\varphi'...
MikeTeX's user avatar
  • 687
0 votes
1 answer
615 views

Uniform Artin-Rees

The Artin-Rees lemma states that if $R$ is a Noetherian ring, $I \subseteq R$ is an ideal and $N \subseteq M$ are finitely generated $R$-modules, then there exists an integer $k$ such that for every $...
user447241's user avatar
0 votes
1 answer
149 views

$I$ is principal if and only if $ID_M$ is principal for all $M \in Max(D)$

In a semmi-quasi local domain $D$ ( i.e. $D$ has finitely many maximal ideals), an ideal $I$ is principal if and only if $ID_M$ is principal for all $M \in Max(D)$. [See Comm. Rings by Kaplansky, ...
deleted's user avatar
  • 41
0 votes
2 answers
824 views

Computing the minimal free resolution of a coherent sheaf on projective space

Most books on commutative algebra explain Grobner bases in the non graded case and minimal free resolutions in the local case. I like projective geometry and want to compute the minimal free ...
Daniel Barter's user avatar
0 votes
2 answers
416 views

Computing toric ideals via saturation and Groebner bases of toric ideals

About a month ago I asked this question on math.stackexchange and unfortunately there was no response. Perhaps someone here knows the answer. Let $A \in \mathbb{Z}^{m \times n}$ be a matrix of full ...
Toric Donut's user avatar
0 votes
1 answer
172 views

$I/N$ is finitely presented module

Let $R$ be a commutative ring and $N = Nil(R)$ the set of its nilpotent elements. Suppose that $N$ is a divided prime ideal, i.e. for any ideal $I$ of $R$ either $I \subseteq N$ or $N \subseteq I$. ...
Bacem's user avatar
  • 1
0 votes
3 answers
2k views

Multiplicative functions $\phi : M_n(F) \longrightarrow F$ with $\phi(I) = 1$

Let $F$ be an infinite field and let $f \in F[x_{11},x_{12},...,x_{nn}]$ be an arbitrary polynomial in $n^2$ variables. Consider the function $\phi : M_n(F)\longrightarrow F$ defined by $\phi((a_{...
M92's user avatar
  • 447
0 votes
1 answer
235 views

Projective bundles

Fix $n$ and let $0\leftarrow \mathcal{F}\leftarrow \bigoplus \mathcal{O}_{\mathbb{P}^n}(a_i)\leftarrow \bigoplus \mathcal{O}_{\mathbb{P}^n}(b_i)\leftarrow \cdots$ be an exact sequence. Then we can ...
Bajouca's user avatar
  • 39
0 votes
1 answer
606 views

Number of Minimal left ideals in the full matrix ring over a finite commutative local ring

Inspired with another QUESTION I would like to know the number of minimal left ideals of $M_n(R)$ in terms of $n$ and $R$ where $R$ is a finite local commutative ring with identity ?
user avatar
0 votes
1 answer
227 views

krull dimension [closed]

im looking for a non-noetherian ring with infinite krull dimension.would you help?
sasha's user avatar
  • 15
0 votes
1 answer
1k views

Cofibrant Replacement of chain complexes

Hi, I encountered an issue today that I can't resolve to myself: Consider the projective model structure on chain complexes over a ring R (Ch(R)), bounded below if you like. Projectives in Ch(R) ...
Tom Sutton's user avatar
0 votes
1 answer
315 views

Generalized Picard group (reflexive fractional ideals, principal ideals)

Given $\mathcal{O}=k[[u,v]]$ with maximal ideal $\mathfrak{m}$ and an $\mathcal{O}$-algebra $A$, free as an $\mathcal{O}$-module of rank $n^2$. $A$ is genertaed by two elements $x,y$ with $x^n=u$, $y^...
TonyS's user avatar
  • 1,391
0 votes
1 answer
379 views

Is a tensor product of two dvrs semilocal?

Under what conditions is the tensor product of two dvrs semilocal? The same question about being reduced. Tensor product is taken over another dvr or over a field to make things simpler. For ...
unknown's user avatar
0 votes
1 answer
285 views

A Nomenclature Issue : Imprimitive Semigroup?

The following question was asked by me on the forum sci.math.research, “An imprimitive group is a transitive permutation group with a non-trivial equivalence relation compatible with the action of ...
Nobody's user avatar
  • 113
0 votes
1 answer
370 views

Proving that two local PIDs, one inside the other, with the same field of fractions are equal.

Let $R\subset S$ be two local PIDs that have the same fields of fractions. How to prove that they are equal?
user4949's user avatar
0 votes
3 answers
2k views

Equality of elements in localization via universal property

I've been studying universal objects of universal algebra in a quite general setting and try to exhibit the structure of their elements just using the universal property. A very nice example for this ...
Martin Brandenburg's user avatar
0 votes
1 answer
473 views

A subfield $R \subseteq \mathbb{C}(x,y)$ with 'many' generators $w$, $R(w)=\mathbb{C}(x,y)$

Let $R \subseteq \mathbb{C}(x,y)$ and assume that $R=\mathbb{C}(u,v)$, where $u,v \in \mathbb{C}[x,y]$ are algebraically independent over $\mathbb{C}$. Here $\mathbb{N}$ includes $0$. Assume that $R$ ...
user237522's user avatar
  • 2,837
0 votes
1 answer
118 views

$S/I$-freeness of $I/I^2$ vs $I/I^{(2)}$, where $I$ is a radical ideal of regular local ring $S$

Let $I$ be a radical ideal of a regular local ring $S$. Put $R:=S/I$. Let $I^{(n)}$ be the $n$-th symbolic power of $I$. It is well-known that $I^n \subseteq I^{(n)}$. Is it true that $I/I^2$ is $R$-...
uno's user avatar
  • 412
0 votes
1 answer
186 views

Does going-down theorem hold for local homomorphism of finite flat dimension?

Let $f:(A,m)\rightarrow (B,n)$ be a local homomorphism of Noetherian local rings of finite flat dimension. Does the going-down theorem hold for $f$? If yes, then by Theorem 15.1 in Matsumura’s ...
Boris's user avatar
  • 639
0 votes
1 answer
137 views

$k(F_i)_{i=1}^{n}=k(G_j)_{j=1}^{m}$ iff there exist $a_i,b_j \in k$ such that $\langle F_i-a_i \rangle_{i=1}^{n} = \langle G_j-b_j \rangle_{j=1}^{m}$

Let $k$ be an algebraically closed field of characteristic zero, for example $k=\mathbb{C}$ and let $F_1,\ldots,F_n,G_1,\ldots,G_m \in \mathbb{C}[x,y]$, $n,m \in \mathbb{N}-\{0\}$. Claim: $\mathbb{C}(...
user237522's user avatar
  • 2,837
0 votes
1 answer
287 views

When is the power-bounded subring top. of finite type?

Very naive question here. Let $K$ be a complete nonarchimedean field, $A$ a reduced affinoid $K$-algebra. When is the power-bounded subring $A^\circ$ topologically of finite type, in the sense that we ...
Satan's Minion's user avatar
0 votes
1 answer
88 views

Proving finite presentation [closed]

Let $R$ be an integral domain, $S$ be a finitely presented $R$ algebra. Then for a flat $R$ module $M$ which is also a finitely generated $S$ module I need to show that $M \otimes_{R}T$ is a fintely ...
user443060's user avatar

1
112 113
114
115 116
122