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Real solutions to underdetermined system of polynomial equations

I have the system of multi-variable polynomial (quadratic) equations with real coefficients. The number of equations is given scales as $K$ and the number of unknowns goes as $K^2$. So for for large $...
Raisa's user avatar
  • 13
14 votes
4 answers
6k views

When is an algebra of commuting matrices (contained in one) generated by a single matrix?

Let C be an nxn matrix, then the polynomials in C (with appropriate coefficients) form an algebra of commuting matrices. I feel that I should know if the converse is true but I do not. So my first ...
Aaron Meyerowitz's user avatar
3 votes
1 answer
394 views

Residual finiteness of groups versus residual finiteness of semigroups

A group $G$ is residually finite if, for any two elements $g$ and $g^\prime$ in $G$, there is a finite group $G^\prime$ and a (group) homomorphism $f: G \rightarrow G^\prime$ such that $f(g)$ doesn't ...
dave's user avatar
  • 155
2 votes
1 answer
980 views

Spectral sequence for Ext

Why is $H^p(X, \mathcal{E}xt^q(F, I))=0$ for $p>0$ and $I$ an injective sheaf and $F$ an arbitrary sheaf? I'm trying to check the hypothesis in the grothendieck spectral sequence applied to the ...
J Delzant's user avatar
7 votes
2 answers
542 views

Does every nontrivial sheaf of rings have a maximal ideal?

Let $R$ be a sheaf of rings on a topological space $X$. Assume $R \neq 0$. Does then $R$ have a maximal ideal? So this is a spacified analogon of the theorem, that every nontrivial ring has a maximal ...
Martin Brandenburg's user avatar
5 votes
2 answers
689 views

Irreducible components of quotients of Cohen-Macaulay rings of the "correct" dimension

Suppose $R$ is a Cohen-Macaulay ring. It is well known that if $I$ is an ideal of $R$ generated by $n$ elements, and $I$ has codimension $n$, then $R/I$ is also Cohen-Macaulay. Now suppose that $I$ ...
Alexander Woo's user avatar
43 votes
5 answers
3k views

Explicit elements of $K((x))((y)) \setminus K((x,y))$

In an answer to the popular question on common false beliefs in mathematics Examples of common false beliefs in mathematics I mentioned that many people conflate the two different kinds of formal ...
Pete L. Clark's user avatar
5 votes
1 answer
378 views

Representations of products of groups (and monoids)

I have very little knowledge of representation theory, but the following has come up in my summer undergrad research project (relates to conformal field theory and geometric function theory). Suppose ...
ismythe's user avatar
  • 51
9 votes
1 answer
792 views

Reconstructing a polynomial from resultants

I am trying to compute a monic polynomial $f(x)$ with integer coefficients and known degree $d$. I am given $n$ pairwise coprime polynomials $g_1(x),\ldots,g_n(x)$, also with integer coefficients, ...
David Mandell Freeman's user avatar
3 votes
2 answers
2k views

Extension problem

As I understand, if $0\rightarrow A\rightarrow X\rightarrow B\rightarrow 0$ is a short exact sequence of abelian groups, $\mbox{Ext }_{\mathbb{Z}}^{1}(B,A)$ gives all the isomorphism classes of what ...
ashpool's user avatar
  • 2,857
2 votes
2 answers
420 views

Homological dimensions of module

$(A,\mathfrak{m})$ a Noetherian local ring, $M\neq 0$ a finitely generated $A$-module. As I understand, $\mbox{Ext }^{j}(A/\mathfrak{m}, M) = 0$ for $j<\mbox{depth }(M)$ and for $j>\mbox{inj. ...
ashpool's user avatar
  • 2,857
7 votes
2 answers
2k views

Ideals in the ring of single-variable Laurent polynomials with integer coefficients

I'm writing some software to automatically compute things like Alexander modules, Alexander ideals, Milnor signatures and Farber-Levine pairings for 1 and 2-knot complements. So among other things I'...
Ryan Budney's user avatar
  • 44.4k
14 votes
3 answers
2k views

Intuition for Model Theoretic Proof of the Nullstellensatz

I recently read the model-theoretic proof of the Nullstellensatz using quantifier elimination (see www.msri.org/publications/books/Book39/files/marker.pdf). I'm convinced that the Nullstellensatz is ...
David Corwin's user avatar
  • 15.4k
4 votes
2 answers
2k views

Existence of a minimal generating set of a module

Does a module (over a commutative ring) always possess a minimal generating set? When the module is not finitely generated, the typical Zorn's lemma type argument doesn't seem to work. More precisely, ...
ashpool's user avatar
  • 2,857
36 votes
4 answers
12k views

Flatness and local freeness

The following statement is well-known: Let $A$ be a commutative Noetherian ring and $M$ a finitely generated $A$-module. Then $M$ is flat if and only if $M_{\mathfrak{p}}$ is a free $A_{\mathfrak{p}}$-...
ashpool's user avatar
  • 2,857
4 votes
2 answers
2k views

Non-finite version of Nakayama's lemma?

Let $A$ be a local ring with nilpotent maximal ideal $\mathfrak{m}$ (i.e., some power of $\mathfrak{m}$ vanishes), and $M$ an $A$-module (not necessarily finitely generated). Let $\bar{S}\subset M/\...
ashpool's user avatar
  • 2,857
12 votes
2 answers
3k views

Is tensor product of local algebras local?

In general, the tensor product of two local rings is not local. For example, $\mathbb{C} \otimes_{\mathbb{R}} \mathbb{C}\ $ is not a local ring. Let $\mathbb{F}_{p}$ denote the finite field with $p$ ...
N. Kumar's user avatar
  • 592
13 votes
3 answers
3k views

Zero divisor conjecture and idempotent conjecture

Let $G$ be a torsion-free group and $C$ the ring of complex numbers. The zero divisor (idempotent, resp.) conjecture is that there is no nontrivial zerodivisor (idempotent, resp.) in $CG$. The wiki ...
yeshengkui's user avatar
  • 1,373
16 votes
4 answers
3k views

Cardinal of maximal linearly independent subsets of a free module

Is it true that the cardinality of every maximal linearly independent subset of a finitely generated free module $A^{n}$ is equal to $n$ (not just at most $n$, but in fact $n$)? Here $A$ is a nonzero ...
ashpool's user avatar
  • 2,857
2 votes
0 answers
797 views

How can I prove R[x] is integrally closed iff R is integrally closed ? (R: integral domain) [closed]

$R$ is a integral domain. How can I prove $R[x]$ is integrally closed iff $R$ is integrally closed?
Qijun Yan's user avatar
6 votes
3 answers
3k views

Tor and projective dimension

Is it possible that $\mbox{Tor }^{r+1}(M,N)=0 \ \ \forall N$ yet $\mbox{proj. dim }M>r$? What I do know is that if $(A,\mathfrak{m})$ is Noetherian local and $M$ is finitely generated over $A$ ...
ashpool's user avatar
  • 2,857
1 vote
4 answers
2k views

Reduced rings, idempotents and their prime spectrum

Let $B$ be a commutative unitary reduced ring and let $A$ be a subring of it. Let $e$ be an idempotent of $B$. Then we have a natural surjective ring homomorphism $A\rightarrow Ae$ defined by $a\...
Jose Capco's user avatar
  • 2,275
4 votes
0 answers
179 views

Global dimensions of orders over non-Gorenstein centers

This question concerns the following Lemma 4.2 in this paper by Van den Bergh: Lemma: Let $R$ be local, normal Gorenstein ring of dimension $d$. Suppose $M$ is a reflexive $R$ module such that $A=\...
Hailong Dao's user avatar
  • 30.5k
15 votes
1 answer
1k views

Countable Hom/Ext implies finitely generated

Today I learned this interesting fact from Jerry Kaminker: If $A$ is an abelian group such that $\mathrm{Hom}(A,\mathbb{Z})$ and $\mathrm{Ext}(A,\mathbb{Z})$ are both countably generated, then in fact ...
Greg Kuperberg's user avatar
3 votes
2 answers
571 views

What is the relation between the number syntactic congruence classes, and the number of Nerode relation classes?

For a monoid $M$ and a subset $S$ of $M$, define the syntactic congruence $\equiv_S$ of $S$ as the least congruence on $M$ that saturates $S$, i.e. : $$u \equiv_S v \Leftrightarrow (\forall x, y)[xuy \...
Michaël's user avatar
  • 786
5 votes
2 answers
2k views

Is there a non-projective flat module over a local ring?

Is there a non-projective flat module over a local ring? Here I assume the ring is commutative with unit.
ashpool's user avatar
  • 2,857
14 votes
0 answers
899 views

Frobenius upper shriek/flat of a dualizing complex

Let $X$ be a separated connected scheme of characteristic $p > 0$. I am going to assume that $F : X \to X$ (the absolute Frobenius) is a finite map. This condition is called being $F$-finite. ...
48 votes
4 answers
4k views

Are there more Nullstellensätze?

Over which fields $k$ is there a reasonable analogue of Hilbert's Nullstellensatz? Here is a more precise formulation: let $k$ be an arbitrary field, $n$ a positive integer, and $R = k[t_1,..,t_n]$. ...
Pete L. Clark's user avatar
9 votes
3 answers
1k views

Vector spaces with natural bases

Sergeib's question asks about vector spaces without a natural basis. Actually, I would claim (apparently in accord with many comments and answers to Sergeib's question ) that this is the default ...
4 votes
2 answers
883 views

Group & modules of arbitrary cardinality [closed]

How do I see that there is a group of an arbitrary cardinality? Is this also true for abelian groups? Also, given a commutative ring $R\neq 0$ how do I see that there is an $R$-module of arbitrary ...
ashpool's user avatar
  • 2,857
13 votes
0 answers
496 views

Are the supports of $Ext^i(M,N)$ eventually periodic?

Let $R$ be a Noetherian, commutative ring and $M,N$ be finitely generated $R$-modules. Question: Do the sets of minimal primes of $\text{Ext}^i_R(M,N)$ (for a fixed pair of $M,N$) become periodic ...
Hailong Dao's user avatar
  • 30.5k
2 votes
1 answer
918 views

Is a formally smooth morphism a filtered inductive limit of smooth algebras?

Given a unital commutative ring $A$ (not necessarily noetherian) and a formally smooth morphism of rings $f:A \to B$, where $B$ is not necessarily noetherian, is (or when is) $B$ a filtered inductive ...
Lutz Geissler's user avatar
4 votes
1 answer
405 views

Vocabulary on monoid periodicity

I'm learning about periodic languages, and I'm confused over the vocabulary used to describe the periodicity of (syntactic) monoids. If I understand correctly, a monoid M is periodic if : $$(\forall ...
Michaël's user avatar
  • 786
2 votes
1 answer
1k views

For which rings does there exist an invertible Vandermonde matrix?

Suppose $R$ is a commutative ring, and $S \subset R^{n\times n}$ is an $R$-module. We are given $H_0,\dots,H_n \in R^{n\times n}$, and we know that for all $r \in R$, $$H_0 + r H_1 + \dots r^n H_n \in ...
Laurent Lessard's user avatar
1 vote
0 answers
534 views

Integral element in the quotient of a polynomial ring

Hello, I'm writting a "report" (to learn) on algebraic geometry, and was looking to write a proof for the following statement : Theorem : Let $K$ be an algebraically closed field and $C_1, C_2 \...
warsomekey's user avatar
11 votes
1 answer
1k views

The associated prime ideals of $Ext^i_R(M,N)$

If R is a commutative noetherian ring, M and N are modules with M finite. It is well known in commutative algebra that $AssHom_R(M,N)=Supp(M)\cap Ass(N)$. But I want to know whether there is a ...
TmobiusX's user avatar
  • 1,207
28 votes
6 answers
5k views

Expressing $-\operatorname{adj}(A)$ as a polynomial in $A$?

Suppose $A\in R^{n\times n}$, where $R$ is a commutative ring. Let $p_i \in R$ be the coefficients of the characteristic polynomial of $A$: $\operatorname{det}(A-xI) = p_0 + p_1x + \dots + p_n x^n$. I ...
Laurent Lessard's user avatar
20 votes
1 answer
3k views

On a theorem of Jacobson

In a comment to an answer to a MO question, in which Bill Dubuque mentioned Jacobson's theorem stating that a ring in which $X^n=X$ is an identity is commutative (theorem which has shown up on MO ...
Mariano Suárez-Álvarez's user avatar
4 votes
1 answer
914 views

Elements of trace zero in a field extension

Let $K=F_q$ and $F=F_{q^3}$, define the set A={$x \in F$ : $Tr_{F/K} (x)=0$}. Is it true that for every $x \in A$ there are $y,z \in A$ such that $x=yz$?
Izhar Oppenheim's user avatar
5 votes
4 answers
388 views

Familiar equations in more general settings

What equations, or results about equations, generalize in interesting ways from number theory or geometry to more abstract settings? The motivating example for this question was as follows: ...
Robin Saunders's user avatar
16 votes
4 answers
2k views

Neusis constructions

Is there some simple description of which complex numbers are "constructible" with straightedge and compass and neusis? See http://en.wikipedia.org/wiki/Constructible_number and http://en.wikipedia....
user avatar
2 votes
0 answers
165 views

Ideals weak equivalence and "finite" equivalence

Let $R$ be an order in a number field. Two $R$-ideals $I$ and $J$ are weak equivalent if there exist (necessarily invertible) ideals $X$ and $Y$ such that $I X=J$ and $J Y=I$. This is equivalent to ...
Pedro Martins Rodrigues's user avatar
54 votes
8 answers
58k views

Modern algebraic geometry vs. classical algebraic geometry

Can anyone offer advice on roughly how much commutative algebra, homological algebra etc. one needs to know to do research in (or to learn) modern algebraic geometry. Would you need to be familiar ...
16 votes
5 answers
5k views

An advanced exposition of Galois theory

My knowledge of Galois theory is woefully inadequate. Thus, I'd be interested in an exposition that assumes little knowledge of Galois theory, but is advanced in other respects. For instance, it would ...
0 votes
1 answer
630 views

Useless question on rank

What is the rank of $A^{n}$ if A is the zero ring? It's clearly not $n$ as many careless authors claim, since it's not even invariant. I don't think it's 0 either because it does have a linearly ...
ashpool's user avatar
  • 2,857
114 votes
2 answers
12k views

How would you solve this tantalizing Halmos problem?

$1-ab$ invertible $\implies$ $1-ba$ invertible has a slick power series "proof" as below, where Halmos asks for an explanation of why this tantalizing derivation succeeds. Do you know one? Geometric ...
Bill Dubuque's user avatar
  • 4,736
1 vote
1 answer
219 views

Name for a module with only one associated prime

In EGA IV2, Def. 3.2.4, Grothendieck defines a quasicoherent sheaf over a locally Noetherian scheme to be "irredondant" if it has a unique associated point. Presumeably, a module over a Noetherian ...
Charles Staats's user avatar
16 votes
1 answer
2k views

Does ZF prove that all PIDs are UFDs?

Main Question: Does ZF (no axiom of choice) prove that every Principal Ideal Domain is a Unique Factorization Domain? The proofs I've seen all use dependent choice. Minor Questions: Does ZF + ...
user avatar
7 votes
2 answers
1k views

Is the category of affine schemes (over a fixed field) Cartesian closed?

This is probably a trivial question, but I don't see the answer, and I haven't found it on Wikipedia, nLab, nor MathOverflow. Let $\text{ComAlg}$ denote the category whose objects are commutative ...
Theo Johnson-Freyd's user avatar
2 votes
0 answers
348 views

How much can we say about the number of nilpotents in a finite local commutative ring?

A commutative ring is local if it has a single maximal ideal. If the ring is finite, this implies that all elements are either units or nilpotents. Further, all finite local rings have prime power ...
Oliver's user avatar
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