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Banach spaces, function spaces, real functions, integral transforms, theory of distributions, measure theory.
2
votes
Accepted
Extracting each field operator as Wightman fields from a set of time-ordered products satisf...
The same paper shows that the converse is true: starting from time-ordered Green functions satisfying axioms T1-T7 as in subsection I.1 one can get the Schwinger functions (Theorem 1, pp. 99, add Coro …
4
votes
Is every closed subspace of the Schwartz space densely embedded into its dual space?
This is more of a long(ish) comment than an actual answer... The question(s) asked above are not the same as the one posed in the title. In the former you are referring only to closed subspaces of $\m …
2
votes
Clarification on the Interpretation of Fourier Coefficients in the Context of Fourier Projec...
As pointed by LSpice's comment to the OP, the answer to 1. is yes, for $\{e_k\ |\ k\in\mathbb{Z}^d\}$ is an orthonormal (topological) basis of $L^2(\mathbb{T}^d)$. As for 2., equation (3.33) is one of …
2
votes
"Completeness" for weak convergence of unbounded closed operators on a separable Hilbert spa...
Not always. What you are talking about is also called "convergence in the sense of sesquilinear forms", because you are taking a pointwise limit in $D\times D$ of a sequence of sesquilinear forms $\al …
7
votes
Accepted
For a tempered distribution $F$ on $\mathbb{R}^2$, what exactly does it mean by $\lvert F(x,...
I'll try to explain what Igor meant in his comments in a different way, maybe it helps.
Of course, any tempered distribution is a distribution in the broader sense - more precisely, any compactly sup …
5
votes
Accepted
Singular support: equivalent definition
The basic idea is the one put forward by Pierre PC's comment above. More precisely, let $u,\varphi,x$ be as in the last paragraph of the OP. There is no loss of generality in assuming that $\varphi(x) …
8
votes
Separate continuity implies (joint) continuity
This is easy and comes from the fact that $V$, being a Fréchet space, is barrelled, that is, the locally convex topology of $V$ coincides with its strong topology $\beta(V,V')$ (where $V'$ = topologic …
4
votes
What properties should $C(M,\mathbb{R})$ have when $M$ is a $n$-dimensional manifold?
This is not really an answer but rather a long-ish comment.
First of all, if $M$ is not compact, $\mathfrak{A}=C(M,\mathbb{R})$ is not really a C${}^*\!$-algebra but actually only a locally C${}^*\!$- …
12
votes
Why does Riesz's Representation Theorem apply in quantum mechanics?
$\DeclareMathOperator\Ann{Ann}\DeclareMathOperator\Tr{Tr}$My answer is somewhat complementary to Nik Weaver's, and admitedly more focused on Question 2 since I have nothing more to add to the latter r …
4
votes
Quantum fields and infinite tensor products
The "infinite tensor product" picture may be useful as a sort of concrete image of the state space of a quantum field theory, but in practice is rarely used because of the technical difficulties it br …
20
votes
Accepted
Functional approach vs jet approach to Lagrangian field theory
I do not know if it is good form for MO to cite one's own papers when answering a question, but I will take the chance. This matter is addressed in quite a bit of detail in my joint paper with Romeo B …
5
votes
2
answers
241
views
Extension of Valdivia-Vogt isomorphism from $\mathscr{D}(K)$ to $\mathscr{E}'(K)$
Let $M$ be a $d$-dimensional (say, Hausdorff, paracompact, connected and oriented) smooth manifold, and $K\subset M$ compact with $\mathring{K}\neq\varnothing$. M. Valdivia has shown (based on previou …
8
votes
2
answers
357
views
Can smoothness of curves into a convenient locally convex vector space be tested with just a...
Let $E$ be a (Hausdorff) locally convex vector space (from now on just "lcs" for short). We say that $E$ is convenient (also called locally complete, Mackey-complete or $c^\infty$-complete) if, given …
5
votes
Accepted
Regularity of Fourier transforms of $L^p$ functions for $2<p\le\infty$
You do not need Hahn-Banach to extend a continuous linear map defined in a dense subspace of a Hausdorff topological vector space into another, complete Hausdorff topological vector space. The extensi …
4
votes
Accepted
Is every continuous microlocal operator a pseudo-differential operator?
This is more like a longish series of comments somewhat complementing Ilya Zakharevich's answers rather than an answer by itself. First of all, notice that since $\mathscr{S}(\mathbb{R}^n)$ embeds con …