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Spaces $X$ with every compactification $0$-dimensional with $\beta X\setminus X$ not locally compact

Previously, in this post I've shown the following characterization of spaces with only zero-dimensional compactifications: Theorem. Let $X$ be strongly zero-dimensional and $\beta X\setminus X$ ...
Jakobian's user avatar
  • 1,201
2 votes
1 answer
103 views

LCH spaces $X$ such that if $Y$ is a perfect image of $X$, then $Y$ is zero-dimensional

I am looking for locally compact Hausdorff spaces $X$ with the following property: If $f:X\to Y$ is a perfect map onto locally compact Hausdorff space $Y$, then $Y$ is zero-dimensional. One can see ...
Jakobian's user avatar
  • 1,201
11 votes
2 answers
314 views

Spaces with every compactification $0$-dimensional which aren't locally compact

Recently I've proven the following theorem Theorem. Let $X$ be a zero-dimensional locally compact Hausdorff space. Then the following are equivalent: Every compactification of $X$ is zero-dimensional....
Jakobian's user avatar
  • 1,201
0 votes
1 answer
79 views

Dimension of a manifold derived from a dense $G_{\delta}$ subspace

Let $X,Y$ be (compact connected) topological manifolds of dimensions $n,m$, respectively. Assume that a dense $G_{\delta}$ subspace $A$ of $X$ is homeomorphic to a dense $G_{\delta}$ subspace $B$ of $...
William of Baskerville's user avatar
1 vote
1 answer
130 views

A finite dimensional continuum with a subset $A$ such that both $A$ and $X\setminus A$ are dense and contractible

Inspired by this question we ask the following question. Note that the comment conversation and answers to the above question imply that There are two complementary subsets of the unit ...
Ali Taghavi's user avatar
3 votes
1 answer
621 views

What is the Lebesgue covering dimension of this topological space?

Take the 4 dimensional time-oriented spacetime $(M,g)$ such that it's not strongly causal. Take the induced topology defined by the Lorentzian metric called Alexandrov topology. This topology matches ...
Bastam Tajik's user avatar
3 votes
1 answer
226 views

$\sigma$-product of the Hilbert cube

Given a homogeneous space $X$ and $p\in X$, we define the sigma product to be the following subspace of $X^\omega$: $$\sigma X=\{\mathbf x \in X^\omega:x_n=p\text{ eventually}\}$$ ("eventually&...
D.S. Lipham's user avatar
  • 3,317
3 votes
0 answers
69 views

Is every weakly $1$-dimensional space embeddable in the plane?

A $1$-dimensional (separable metric) space $X$ is weakly $1$-dimensional if $$\Lambda(X)=\{x\in X:X\text{ is 1-dimensional at }x\}$$ is zero-dimensional (i.e. the space $\Lambda(X)$ has a basis of ...
D.S. Lipham's user avatar
  • 3,317
3 votes
0 answers
107 views

Does the pseudo-arc contain Erdős space?

The pseudo-arc is the unique hereditarily indecomposable chainable continuum. The Lelek fan is the unique compact, connected subset of the Cantor fan (the cone over the Cantor set) with a dense ...
D.S. Lipham's user avatar
  • 3,317
7 votes
1 answer
262 views

Can you remove a zero dimensional subspace from a cube and obtain a planar space?

The question, which came up in a conversation with my advisor Ola Kwiatkowska, is pretty much in the title: Let $Z\subseteq[0,1]^3$ be zero-dimensional. Is it possible for $[0,1]^3\setminus Z$ to be ...
Alessandro Codenotti's user avatar
5 votes
1 answer
198 views

Iterating the dimensional kernel of a metric space

Fix $n\in \mathbb N$. Let $X$ be a separable metric space of (inductive) dimension $n$. Let \begin{align} \Lambda(X)&=\{x\in X:X\text{ is $n$-dimensional at }x\}\\ \\ \Lambda^2(X)&=\Lambda(\...
D.S. Lipham's user avatar
  • 3,317
6 votes
0 answers
111 views

A generalized Hausdorff dimension in form of a Lower semi continuous function

Let $(X,d)$ be a compact metric space. Assume that $f:X\to \mathbb{R}$ is a positive continuous function. We say that the $f$-dimension of $(X,d)$ is equal to $0$ if for every $\epsilon>0$ ...
Ali Taghavi's user avatar
4 votes
0 answers
115 views

Dimension properties of some concrete hereditarily disconnected subspaces of the Hilbert cube

This question was motivated by this MO-question asking about the example of a hereditarily disconnected metrizable separable space, which is not the union of countably many totally disconnected ...
Taras Banakh's user avatar
  • 41.8k
6 votes
0 answers
144 views

Is there a hereditarily disconnected space which is not the union of countably many totally disconnected subspaces?

A topological space $X$ is called $\bullet$ totally disconnected if for any distinct points $x,y\in X$ there exists a clopen set $U\subseteq X$ such that $x\in U$ and $y\notin U$; $\bullet$ ...
Taras Banakh's user avatar
  • 41.8k
6 votes
1 answer
184 views

Classification of Polish spaces up to a $\sigma$-homeomorphism

A function $f:X\to Y$ between topological spaces is called $\bullet$ $\sigma$-continuous if there exists a countable cover $\mathcal C$ of $X$ such that for every $C\in\mathcal C$ the restriction $f{\...
Taras Banakh's user avatar
  • 41.8k
10 votes
0 answers
173 views

Is there a universal totally disconnected Polish space?

A topological space $X$ is called totally disconnected if for any distinct points $x,y\in X$ there exists a clopen set $U\subseteq X$ such that $x\in U$ and $y\notin U$. In 1973 Roman Pol proved that ...
Taras Banakh's user avatar
  • 41.8k
4 votes
1 answer
133 views

Sufficient conditions for the covering dimension and large inductive dimension of compact Hausdorff spaces to coincide

I have been looking through Alan Pears' "Dimension theory of general spaces" recently. In this book Pears references a 1960 paper by Aleksandrov and Ponomarev called "Some classes of $n$...
Robert Thingum's user avatar
38 votes
1 answer
1k views

Sequences with 0's in $\mathbb R ^\omega$

Let $\mathbb R ^\omega$ be the set of all sequences of real numbers in the product topology. Let $X$ be the set of all sequences in $\mathbb R ^\omega$ which have at least one 0. Let $Y$ be the set of ...
D.S. Lipham's user avatar
  • 3,317
2 votes
0 answers
165 views

Dimension of Cartesian products

Is there a notion of dimension such that for all Borel sets $A,B\subseteq\mathbb{R}^{n}$ we have $$ \dim(A\times B)=\dim(A)+\dim(B)?$$ For topological, Minkowski, packing and Hausdorff dimension this ...
Jörg Neunhäuserer's user avatar
3 votes
1 answer
266 views

Embedding CW-complexes into infinite-dimensional topological vector spaces

Sometimes it is desirable to embed CW-complexes into real vector spaces, to use a simple linear algebra to work with them. Result on embedding into Euclidean spaces are well known, check Hatcher‘s ...
Nik Bren's user avatar
  • 519
2 votes
0 answers
83 views

Increasing a nowhere dense set in $\mathfrak E_{\mathrm{c}}$

Let $X$ be a closed nowhere dense subset of the complete Erdos space $$\mathfrak E_{\mathrm{c}}=\{x\in \ell^2:x_n\notin \mathbb Q\text{ for all }n<\omega\}.$$ Can you always find a closed nowhere ...
D.S. Lipham's user avatar
  • 3,317
3 votes
0 answers
81 views

Isotopy Classes and Embeddability of Products in $\mathbb{R}^2$

On MSE I asked if the plane contains an uncountable collection of mutually disjoint copies of the Warsaw Circle; it seems to be false, and is probably already known but I'm not sure that anybody has ...
John Samples's user avatar
6 votes
0 answers
107 views

Existence of stable spaces

An element $X$ of a class of topological spaces is called the stable space for that class if for every space $Y$ in the class we have that $X\times Y$ is homeomorphic to $X$. Note that a stable space ...
D.S. Lipham's user avatar
  • 3,317
5 votes
0 answers
182 views

Which metrizable spaces can be embedded into the countable power of $\omega$ with the cofinite topology?

Let $\omega_{cf}$ be the countable space $\omega=\{0,1,2,3,\dots\}$ endowed with the cofinite topology $$\tau_{cf}=\{\emptyset\}\cup\{U\subseteq\omega:\omega\setminus U\mbox{ is finite}\}.$$ It is ...
Taras Banakh's user avatar
  • 41.8k
5 votes
1 answer
291 views

Is the Hilbert cube the countable union of punctiform spaces?

Recall that a (separable) metric space is called punctiform, if all its compact subspaces are zero-dimensional. While "natural" spaces would seem to be punctiform if they already themselves ...
Arno's user avatar
  • 4,717
9 votes
2 answers
505 views

A natural $\mathbb Q\times \mathbb P$ subset of $\mathbb R$?

I would like a simple description of a dense subset of $\mathbb R$ which is homeomorphic to $\mathbb Q\times \mathbb P$. Preferably the description will be of an algebraic nature, and perhaps the set ...
D.S. Lipham's user avatar
  • 3,317
1 vote
1 answer
132 views

Perfect images of complete Erdős space

Let $\mathbb P$ denote the space of irrational numbers. In an answer to this question, Taras Banakh showed that the perfect images of $\mathbb P$ are precisely the Polish spaces with no compact ...
D.S. Lipham's user avatar
  • 3,317
1 vote
1 answer
234 views

Quotients of the irrationals

Everyone knows that there is a closed equivalence relation $\sim$ on the Cantor set $C$ such that each non-trivial equivalence class has exactly $2$ points and $[0,1]\simeq C/\sim$. Thus a closed ...
D.S. Lipham's user avatar
  • 3,317
4 votes
0 answers
441 views

The "core" of complete Erdős space

This question is about the Erdős spaces: $\mathfrak E=\{x\in \ell^2:x_n\in \mathbb Q\text{ for all $n<\omega$}\}$; and $\mathfrak E_c=\{x\in \ell^2:x_n\in \mathbb P\text{ for all $n<\omega$}\}...
D.S. Lipham's user avatar
  • 3,317
10 votes
2 answers
871 views

Is the complement of a zero-dimensional subset of the plane path-connected?

Let $X$ be a zero-dimensional subset of the plane $\mathbb R ^2$. Is $\mathbb R ^2\setminus X$ necessarily path-connected? I feel the answer must be yes but I need a reference. If it helps, assume $...
D.S. Lipham's user avatar
  • 3,317
6 votes
1 answer
231 views

A classification of $G_{\delta\sigma}$ zero-dimensional spaces?

Among separable metrizable spaces: Cantor set is the unique compact zero-dimensional space without isolated points. $\mathbb Q$ is the unique countable space without isolated points $\mathbb R \...
D.S. Lipham's user avatar
  • 3,317
4 votes
2 answers
1k views

A set whose Hausdorff dimension gradually changes?

Can there be a set whose Hausdorff dimension gradually changes? For instance, a set of real numbers contained in an interval, whose Hausdorff dimension is 0 at the beginning and 1 closer to the end, ...
Anixx's user avatar
  • 10.1k
11 votes
1 answer
992 views

Why are homeomorphism groups important?

For a compact metric space $X$ let $\mathcal H(X)$ denote the set of homeomorphisms in the compact-open topology (also generated by sup metric). It is known that $\mathcal H(X)$ is a Polish ...
D.S. Lipham's user avatar
  • 3,317
3 votes
0 answers
146 views

Separating a countable closed set from a point

Let 𝑋 be a separable metrizable space. An intersection of clopen subsets of $X$ is called a C-set. Question. If each singleton of $X$ is a C-set, $A\subseteq X$ is closed and countable, $x\in X\...
D.S. Lipham's user avatar
  • 3,317
6 votes
1 answer
489 views

Is there an almost strongly zero-dimensional space which is not strongly zero-dimensional

A Tychonoff space $X$ is called strongly zero-dimensional if each functionally closed subset $F$ of $X$ is a $C$-set, which means that $F$ is the intersection of a sequences of clopen sets in $X$. A ...
Lviv Scottish Book's user avatar
5 votes
1 answer
213 views

One-dimensional compacta as projective limits

Let $X$ be a (not necessarily metrizable) Hausdorff compact space of covering dimension = 1. Is it possible to express $X$ as a filtering projective limit of finite graphs? Here finite graphs ...
user147412's user avatar
3 votes
1 answer
2k views

Dimension of a topological space equals the supremum of the dimension of open subsets in an open cover

For a topological space $X$ which is covered by a family of open subsets $\{U_i\}$, show that $\dim(X)=\sup (\dim(U_i))$. I understand that $\dim(X)\geq \sup(\dim(U_i))$, so it only suffices to show ...
Bencheng Li's user avatar
6 votes
3 answers
1k views

Topological dimension of the image of continuous surjective functions

Consider two topological spaces $(X,\tau)$ and $(Y,\omega)$ and a continuous surjective function $f\colon X\to Y$. Let $\mathrm{dim}(X)$ and $\mathrm{dim}(Y)$ denote the Lebesgue covering dimension ...
JLM's user avatar
  • 71
32 votes
1 answer
1k views

If $\text{dim}(X \times X) = 2\text{dim}(X)$, does $\text{dim}(X^n) = n\text{dim}(X)$?

I have been learning some (topological) dimension theory and have gotten through most of the basic material, at this point, and am about to start looking at papers. In particular, I want to get ...
John Samples's user avatar
1 vote
1 answer
260 views

Understanding equivalent condition for covering dimension

Let dim $X$ denote the Lebesgue covering dimension for a topological space $X$. Now a result in common books concerning dimension theory states the following: If $X$ is a normal topological space, ...
user531706's user avatar
2 votes
1 answer
133 views

Topologically Ordered Families of Disjoint Cantor Sets in $I$?

Suppose that we have an uncountable collection $C_\alpha$ of disjoint Cantor Sets contained in the closed unit interval $I$. Suppose we have ordered the indices $\alpha \in [0,1]$ as well. Then is ...
John Samples's user avatar
3 votes
2 answers
152 views

What is the dimension of a subspace of the product of $n$ linearly ordered compacta

This question is motivated by this problem of Dominic van der Zypen. Problem. Let $X=\prod_{i=1}^nX_i$ be the Tychonoff product of linearly ordered compact Hausdorff spaces $X_1,\dots,X_n$. Is it ...
Taras Banakh's user avatar
  • 41.8k
17 votes
1 answer
525 views

Lowest Dimension for Counterexample in Topological Manifold Factorization

Bing gave a classical example of spaces $X, Y, Z$ such that $X \times Y = Z$, where $X$ and $Z$ are manifolds but $Y$ isn't. The space $Z$ in his example has dimension four. Is it known if this is ...
John Samples's user avatar
6 votes
1 answer
422 views

Transitive homeomorphisms of Erdős spaces

A surjective homeomorphism $h:X\to X$ is minimal if $$\overline{\{h^n(x):n\in \mathbb N\}}=X$$ for every $x\in X$. In other words, the orbit of each point is dense. Does either of the Erdös spaces $\...
D.S. Lipham's user avatar
  • 3,317
5 votes
1 answer
209 views

Direct limit of Cantor sets

Let $C$ be the Cantor set, and $\omega$ the discrete space of integers $\{0,1,2,...\}$. My conjecture: (1) For each $n<\omega$ let $f_n:C\to C$ be a continuous function (possibly not onto). Let ...
Forever Mozart's user avatar
7 votes
2 answers
546 views

Doubling dimension vs other metric dimensions

For separable metric spaces, three fundamental notions of dimension are equivalent: $$ \text{dim }X = \text{Ind }X = \text{ind }X ,$$ Where does the doubling dimension fit into the picture?
Aryeh Kontorovich's user avatar
3 votes
1 answer
148 views

Fiber dimension formula for compact Hausdorff spaces?

In Algebraic Geometry one has a very useful formula for the dimension of fibers. Specifically I am thinking about a statement of the following form: Let $C$ be a curve over $\mathbb{C}$, and let $S$...
Niki's user avatar
  • 335
2 votes
1 answer
406 views

Extremally disconnectedness and 0-dimensional space

Let $X$ be a non-empty topological space. Then we have the following concepts for the topological space $X $: 1) We say $X $ has property $*$, if for every closed subset $A$ of $X$ and every open ...
Alesix's user avatar
  • 21
2 votes
1 answer
370 views

One-dimensional topological spaces

We know that all connected (not a singleton) subsets of $\mathbb{R}$ (with the usual topology) has no empty interior. This fact does not remains true for a general connected topological space with the ...
Didi's user avatar
  • 95
3 votes
1 answer
160 views

Topological spaces with Lebesgue covering dimension 1

We know that all connected subsets of $\mathbb{R}$( with the usual topology) has no empty interior. I would like to know if this fact remains true for a general connected topological space with the ...
Didi's user avatar
  • 95