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Questions tagged [ac.commutative-algebra]

Commutative rings, modules, ideals, homological algebra, computational aspects, invariant theory, connections to algebraic geometry and combinatorics.

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4 votes
0 answers
189 views

Moduli of finite-dimensional algebras

Let $n\geq 1$ be an integer. There is an obvious family of $n$-dimensional unital algebras parametrized by $\mathbb{C}^{n(n-1)^2}$ such that any $n$-dimensional unital algebra is isomorphic to at ...
3 votes
0 answers
92 views

Cohomology with supports of dualizing sheaf

Let $Z$ be a closed subvariety of $X$ and $T_{Z/X}$ the relative tangent complex. Possibly I want to assume that $Z \hookrightarrow X$ is a regular embedding, so that $T_{Z/X}$ is just a shift of the ...
6 votes
0 answers
119 views

Norm forms, slicing, and ideal classes

Let $K$ be a number field, which we may suppose satisfies $n = [K : \mathbb{Q}] \geq 3$. Let $\mathcal{O}_K$ be the ring of integers of $K$, and let $\{\omega_1, \cdots, \omega_{n}\}$ be a basis of $\...
18 votes
3 answers
1k views

The isomorphism class of $\mathrm{Ext}^1_\mathbb{Z}(\mathbb{R}/\mathbb{Z},\mathbb{Z})$

In a recent conversation with a colleague, the following question arose: What is the isomorphism class of $\mathrm{Ext}^1_\mathbb{Z}(\mathbb{R}/\mathbb{Z},\mathbb{Z})$? That is to say, what is $...
6 votes
1 answer
454 views

Which abelian groups are $\varprojlim^1$ groups?

Question 1: Let $\mathcal A$ be an abelian group. Does there exist an inverse system $(A^n)_{n \in \mathbb N} = (\cdots \to A^n \to A^{n-1} \to \cdots \to A^0)$ such that $\varprojlim^1 A^\bullet \...
4 votes
1 answer
118 views

Computing Gröbner basis elements of some constant degree

I'm wondering if there is any way or any special set of ideals such that there is an efficient way to compute elements of degree at most $d$ in a Gröbner basis for that ideal. If you have any paper ...
42 votes
6 answers
7k views

An algebra of "integrals"

When discussing divergent integrals with people, I got curious about the following: Is there an $\mathbb{R}$-algebra $A$ together with a map (could be defined on just a subspace) $$\int_0^{\infty}: ...
6 votes
1 answer
328 views

Algebra with a certain abelian group as the multiplicative group

Let $A$ be an abelian group. Are there an algebra $\mathfrak{X}(A)$ s.t. the multiplication group is isomorphic to A ? i.e. $$ \mathfrak{X}(A)^{\times} \simeq A. $$ For example, for $A=\mathbb{Z}/4\...
3 votes
0 answers
78 views

Is $X$ closed in $Aut_{\mathbb{C}(t)}(\mathbb{C}(t)[x_1,\ldots, x_n])$?

Consider $\mathbb{C}$-algebras $$A = \mathbb{C}[t][x_1,\ldots, x_n]\subset\mathbb{C}(t)[x_1,\ldots, x_n] = B$$ Group $\operatorname{Aut}_{k(t)}(k(t)[x_1,\ldots, x_n])$ carry a power series topology (...
11 votes
1 answer
789 views

Example of a PID with a residue field of finite characteristic and a residue field of characteristic 0?

I understand that for any nonempty set $S$ of characteristics, there exists a PID $R$ such that the set of characteristics of residue fields of $R$ (i.e. quotients by of $R$ by maximal ideals -- I'm ...
2 votes
1 answer
216 views

A problem about an unramified prime in a Galois extension

I asked this question in MathStackExchange, but I didn't receive any answer. Let $K/\mathbb{Q}$ be a Galois extension of degree $n$, and denote its ring of integers by $\mathcal{O}_K$. Let $\mathfrak{...
3 votes
1 answer
186 views

If a PID has no nonzero divisible elements, then is the same true of its finitely-generated modules?

EDIT: The question was originally about general Noetherian rings instead of PID's. Thanks to YCor for pointing out how wrong this was in the comments below (1 2 3). Question 1: Let $R$ be a PID. ...
4 votes
1 answer
698 views

Picard group of hypersurfaces in $\mathbb{P}^r\times\mathbb{P}^s$

Let $k$ be an algebraically closed field, say $k=\mathbb{C}$. Let $r,s$ be sufficiently large integers. Is it true that, for any irreducible hypersurface $X$ of bi-degree $(d,1)$ in $\mathbb{P}^r\...
0 votes
1 answer
164 views

Naive question on tensor product

Let $A, B$ be $\mathbb{C}$-algebras, which are also integral domains. Suppose there is an injective ring homomorphism $f:A \to B$. Assume further than $f$ is a finite morphism in the sense that $f$ ...
1 vote
1 answer
231 views

Is every regular local ring a filtered colimit of essentially finitely generated regular local rings?

Is every regular local ring $R$ a filtered colimit of regular local rings which are essentially of finite type over $\mathbb{Z}$ (i.e. localizations of finitely generated rings)? For comparison, ...
3 votes
1 answer
366 views

flatness and reduction

Let $\mathcal J$ be an ideal sheaf on a (Noetherian) $Y$-scheme $X$, and let $\mathcal I$ be the unique primary ideal in a primary decomposition $\mathcal J$ corresponding to a minimal associated ...
3 votes
0 answers
59 views

Kernel of the map $\mathbb{C}[G]^U \to \mathbb{C}[U^+]$

$\DeclareMathOperator{\SL}{\operatorname{SL}}$Let $G=\SL_k$ be the special linear group, $U$ the unipotent subgroup consisting of all lower unipotent triangular matrices, $U^+$ the unipotent subgroup ...
7 votes
1 answer
1k views

Expressing primes $p\equiv 1 \pmod 3$ in the form $p = x^2 + xy + y^2$

Fermat famously showed that the only primes $p$ of the form $x^2 + y^2$ are the primes such that $p \equiv 1 \mod{4}$. Furthermore, we now know “effective” versions of Fermat's theorem, i.e. given a ...
2 votes
0 answers
80 views

Reference request: additive basis of $\mathbb{C}[N]$

Let $N$ be the maximal unipotent subgroup of $SL_k$. I think that the following is an additive basis of $\mathbb{C}[N]$: $$\{ e_T: T \text{ is a semi-standard Young tableau with at most $k-1$ rows and ...
8 votes
0 answers
179 views

Rlim versus tensor product

Let $R$ be a coherent ring, and let $(M_n)_{n\geq 1}$ and $(N_n)_{n\geq 1}$ be two inverse systems of finitely generated flat $R$-modules. If $R^1 \lim M_n=R^1 \lim N_n = 0$, is it true also that $R^1 ...
0 votes
0 answers
105 views

An ideal invariant under an automorphism

The following question appears here; hopefully, it is appropriate for MO. Let $k$ be a field of characteristic zero, and let $\beta: k[x,y] \to k[x,y]$ be the following involution $\beta: (x,y) \...
10 votes
1 answer
1k views

SOS polynomials with rational coefficients

Suppose we are given a univariate polynomial with rational coefficients, $p \in \Bbb Q [x]$, and are told that $p$ can be expressed as the sum of $k$ squares of polynomials with rational coefficients. ...
11 votes
1 answer
803 views

Maximum number of common zeros of n polynomials in n-1 variables

Given $n$ quadratic polynomials in $n-1$ variables over the complex field, what is the maximum number of common zeros? Can we have $2^{n-1}-1$ common zeros? I assume that a linear combination of the ...
1 vote
0 answers
174 views

What are the irreps in this canonical action of $\operatorname{PGL}_2(F_q)$?

Consider the permutation action of $\operatorname{PGL}_2(\mathbb F_q)$ on $\mathbb P^1(\mathbb F_q)$ by fractional linear transformations. We can consider the associated (complex) representation of ...
2 votes
0 answers
130 views

Sources for describing the characteristic polynomial of a nonintegral hyperplane arrangement in terms of point counting?

I have a family of hyperplane arrangements, and I'd like to describe their characteristic polynomials. When the hyperplanes are defined over the integers, the easiest way for me to do this is to use ...
8 votes
1 answer
256 views

$\operatorname{SL}_2(k)$ invariant polynomials in $k[x_1,x_2,y_1,y_2]$

Let $k$ be a field and let $\operatorname{SL}_2(k)$ act on $k[x_1,x_2]$ and $k[y_1,y_2]$ in the usual ways. These actions induce an action on the tensor product $k[x_1,x_2,y_1,y_2]$ that preserves ...
1 vote
1 answer
218 views

An example of a special $1$-dimensional non-Noetherian valuation domain

I am looking for a $1$-dimensional non-Noetherian valuation domain $R$ such that there exists a sequence $\{a_i\}_{i=1}^\infty$ of elements of $R$ such that $\langle a_1\rangle \subsetneqq\langle a_2\...
2 votes
0 answers
115 views

Existence theorem for symmetric nondegenerate forms over a ring

There exists a rich theory for inner product spaces (i.e. vector spaces with a symmetric nondegenerate bilinear form) over fields, and it can be discussed in the context of local rings and free ...
3 votes
1 answer
195 views

Solutions to nonhomogeneous quadratic equation mod $N$

Is there any way to find non-trivial solutions to the equation $x^2 + y^2 - x \equiv 0 \mod{N}$? There are clearly several trivial solutions, for example $(x, y) = (0, 0), (1, 0), (2^{-1}, 2^{-1}), (2^...
8 votes
0 answers
314 views

Cohomology of the complement of the resonance hyperplane arrangement

Here was a question about resonance arrangement. It is defined as follows. Let $x_i$ be the standard coordinates on $\mathbb{C}^n$. For each nonempty $I\subseteq\{1,\dots,n\}$, define the hyperplane $...
2 votes
0 answers
70 views

Properties preserved in addition of ideals

If I and J are prime (radical) ideals then what are the conditions under which we can define a prime (radical) ideal from I+J?
0 votes
1 answer
208 views

Separable non-flat simple ring extension

Let $R \subseteq S$ be two commutative $\mathbb{C}$-algebras such that: (1) $R$ and $S$ are integral domains. (2) $Q(R)=Q(S)$, namely, their fields of fractions are equal. (3) $S=R[w]$, for some $w \...
0 votes
0 answers
182 views

non constant regular function derivative is zero

Let $R$ be a Noetherian regular $k$-algebra (where $k$ any field of char = 0) of dimension greater than 0. Is it true that $H^{0}_{dR}(R \lvert k) = k$?. More generally we could ask, Is it true that $...
5 votes
0 answers
587 views

When is the cotangent complex perfect?

Let $X\rightarrow S$ be a proper flat morphism of schemes. When is the cotangent complex $L_{X/S}$ perfect ? It is well known, that for local complete intersections the cotangent complex is perfect, ...
3 votes
0 answers
69 views

On Ext-duals of injective modules for commutative rings

Let $R$ be a commutative noetherian ring and $I=E(R/p)$ the injective hull of the module $R/p$ for a prime ideal $p$. Question: Is there a (more) explicit description of the $R$-modules $Ext_R^i(I,R)$...
0 votes
1 answer
94 views

$k[h(x),y] \subseteq k[h(x),y] + \langle h(x),y \rangle \subseteq k[x,y]$

Let $k$ be a field of characteristic zero. Let $h=h(T) \in k[T]$ with $\deg(h)=d \geq 2$ and $h(0)=0$ (namely, $h$ has zero constant term). Consider the following chain of $k$-algebras: $$k \subseteq ...
5 votes
4 answers
6k views

Are quotients of polynomial rings almost UFDs?

If $K$ is a field then the polynomial ring $K[x_1,\ldots, x_n]$ is a UFD. On the other hand, quotients of such a polynomial ring usually don't enjoy unique factorization: consider, for instance, $\...
2 votes
1 answer
259 views

Scheme-theoretic image and delta-invariants

Let $(X,o)$ be an affine, isolated, normal, Gorenstein singularity. Let $f$ and $g$ be two morphisms from $\mbox{Spec}(\mathbb{C}[[t]])$ to $X$ (also known as formal arcs) such that the closed point ...
2 votes
0 answers
130 views

Question about Zariski cancelation problem

If $\mathbb{Q}[t_1,\ldots, t_n] = A[x_1,\ldots, x_{n-1}]$ has it been proven that $A\cong\mathbb{Q}[t]$?
5 votes
1 answer
182 views

A question on $SK_1$ of rings

Let $B$ be a commutative ring with unity and $B/nil(B):=B_{red}$, where $nil(B)$ is the nilradical of $B$. Is $SK_1(B)=SK_1(B_{red}) ?$ In particular, is it true when $B$ is an affine algebra over an ...
0 votes
0 answers
103 views

A certain property of integral domains $A \subseteq B$ with $Q(A) \cap B= A$

I have asked the following question in MSE: Let $k$ be a field of characteristic zero. Let $A \subseteq B$ be $k$-algebras which are also (commutative) integral domains with fields of fractions $Q(A) \...
1 vote
0 answers
94 views

What would be the quotient groups $U_{\mathrm{gen}}/U_{\mathrm{gen}}^{(n)}$ and $U_{\mathrm{gen}}^{(n)}/U_{\mathrm{gen}}^{(n+1)}$?

Let $K \supseteq \mathbb{Q}_p$ be a $p$-adic field with ring of integer $O$ and maximal ideal $m$. Let $O^*$ be the group of units in $O$. Consider the group of units $U^{(0)}=U=O^*$ and $U^{(n)}=1+m^...
7 votes
0 answers
344 views

Irreducibility of a palindromic polynomial

I have strong reasons to believe that the palindromic polynomial $p_n(x)$ defined by $$p_n(x) = x^{2n}+2x^{2n-1}+3x^{2n-2}+ \cdots+ nx^{n+1}+(n+3)x^{n}+nx^{n-1}+\cdots+2x+1$$ is irreducible in $\...
1 vote
0 answers
360 views

A composition of a simple extension and a separable extension is simple

Let $K/L/M$ be a tower of finite field extensions with $K/L$ separable and $L/M$ simple (in the sense of being generated by a single element). How does one show that $K/M$ is also simple? I know that ...
3 votes
0 answers
214 views

formal smoothness and cotangent complex

If $k$ is a field and $A$ is a formally smooth $k$-algebra, then we know that $\Omega^{1}_{A/k}$ is projective. What about its cotangent complex $L_{A/k}$? When is it quasi-isomorphic to $\Omega^{1}_{...
1 vote
1 answer
219 views

Self-map of short exact sequences

Consider the commutative diagram of finite abelian groups $\require{AMScd}$ \begin{CD} 0@>>> A @>i>> B@>\pi>> C@>>> 0\\ \ @VV 0 V@VVfV@VV 0 V\\ 0@>>>A @&...
2 votes
0 answers
69 views

Nonvanishing criterion for a polynomial of polynomials

Let $P \in \mathbb{F}_q[x_1, \dots, x_n][y]$ be some fixed polynomial. Substituting polynomials for the variables in $P$ gives a map $\mathbb{F}_q[x]^{n+1} \to \mathbb{F}_q[x]$ defined by $$(Q_1(x), \...
1 vote
1 answer
388 views

Necessary and sufficient condition for $can : A^X\otimes_A A^Y\rightarrow A^{X\times Y}$ to be an embedding

The two sets are, of course, supposed infinite. This question is related to that one Commutation of tensor products with inverse limits in a specific case where it received a (partial) answer ($A$ ...
0 votes
1 answer
270 views

Which theorems in commutative algebra describe the closed property of curves (i.e. algebraic varieties) in algebraic geometry?

In $R^2$, we have those solutions of $x^2+y^2-1=0$ describe a closed unit disk and $y^2 = x^3 − x + 1$ describes an unclosed elliptic curve. When we consider corresponding algebras e.g. ${R^2}/ \...
2 votes
0 answers
102 views

In char zero $ \operatorname{Cox}(\operatorname{Bl}_{[1:1:1]}(\mathbb{P}(a:b:c))) $ is finitely generated, but not in char p. How?

Let $ X(a_{1}:a_{2}:a_{3}) $ be the blow-up of $ \mathbb{P}(a_{1}:a_{2}:a_{3}) $ at $ [1:1:1] $, the identity of the torus. In Steven Dale Cutkosky's paper Symbolic Algebras of Monomial Primes ...

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