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What does Hilbert's 90 theorem tell us about Galois fixed points in projective space?

Consider the following statement: If $K\subseteq L$ is a Galois extension of fields with Galois group $G$ and $x \in \mathbb{P}^n(L)$ is such that $\sigma(x)=x$ for all $\sigma\in G$, then $x \in \...
Gro-Tsen's user avatar
  • 32.5k
10 votes
4 answers
2k views

Strongly Noetherian property. When is the tensor $A\otimes_{k}B$ Noetherian for Noetherian rings $A$ and $B$?

Let $k$ be a field. It is well-known that $A\otimes_{k}B$ is not necessarily Noetherian even if $k$-algebras $A$ and $B$ are Noetherian. For example $\mathbb{R}\otimes_{\mathbb{Q}}\mathbb{R}$. When ...
user2013's user avatar
  • 1,663
10 votes
1 answer
1k views

Formally smooth morphisms, the cotangent complex, and an extension of the conormal sequence

I'm reading Daniel Quillen's paper "Homology of commutative rings," in which he proves: A finitely presented morphism of rings $A \to B$ is Formally etale iff $L_{B/A}$ (this denotes the cotangent ...
Akhil Mathew's user avatar
  • 25.6k
9 votes
3 answers
1k views

Structure Theorem for finitely generated commutative cancellative monoids?

Is there a Structure Theorem for finitely generated commutative cancellative monoids? Of course they can be densely embedded into a finitely generated abelian group, whose structure is known. Also, ...
Martin Brandenburg's user avatar
9 votes
2 answers
953 views

Is there a universal property for graded localization?

Question: Let $S$ be a graded ring and $ f \in S_+$. Does the ring $ S_{(f)}$ which consists of degree $ 0$ elements of $ S_f$ represent a nice functor? Motivation: Let $ X = {\rm Spec} A$. Assume ...
Daniel Barter's user avatar
9 votes
1 answer
986 views

Tensor product of rings of Witt vectors

Let $A$, $B$, and $C$ be commutative rings such that $A\otimes_C B$ makes sense. If $W_n(A\otimes_C B), W_n(A), W_n(C),$ and $W_n(B)$ are the length $n$ Witt vectors of the rings $A,B,C,$ and $A\...
AJ Stewart's user avatar
9 votes
3 answers
2k views

Finite index free subgroups of $\mathrm{SL}(3,\mathbb{Z})$

Does $\mathrm{SL}(n,\mathbb{Z})$ have a free subgroup of finite index for some $n \geq 3$? I know that $\mathrm{SL}(3,\mathbb{Z})$ has many free subgroups and that in the case of $\mathrm{SL}(2,\...
burtonpeterj's user avatar
  • 1,769
9 votes
1 answer
2k views

Are local, Noetherian rings with principal maximal ideal PIR?

A question asked by a friend. I believe it's false, but lack a decisive counterexample. This question shows that it is true for valuation rings, but I know too little about them. In the wider ...
Andrew Homan's user avatar
9 votes
0 answers
165 views

When is the rank 2 free metabelian group of exponent $n$ center free?

Let $M_n$ be the rank 2 free metabelian group of exponent $n$. For which $n$ is $M_n$ center-free? The abelianization $M_n^{ab}\cong C_n\times C_n$, so the commutator subgroup $M_n'$ is a cyclic $(\...
stupid_question_bot's user avatar
9 votes
1 answer
295 views

Definition of packing property

Definition 1: A clutter $C$ is said to have the packing property if $C$ and all of its minors satisfy the König property. where, vertex cover of $C$ is a set of vertices that have non-empty ...
user177523's user avatar
9 votes
2 answers
559 views

Can transcedence degree be defined for arbitrary ring homomorphism?

Fix a homomorphism $f:A\rightarrow B$. Choose $\{b_1,\dots,b_n\}$, $\{b'_1,\dots,b'_m\}$ subsets of elements in $B$. Suppose that $B$ is algebraic over $f(A)[b_1,\dots,b_n]$ and $\{b_1,\dots,b_n\}$ ...
user avatar
9 votes
0 answers
644 views

Conceptual proofs for the computation of the structure sheaf

The following lemma in commutative algebra is important for the foundations of algebraic geometry: If $A$ is a commutative ring, $U \subseteq A$ is a finite subset generating the unit ideal, then ...
Martin Brandenburg's user avatar
9 votes
0 answers
204 views

Standard reference/name for "initial ideals $\Leftrightarrow$ associated graded rings"

Let $R$ be commutative ring with a $\mathbb Z$-grading $\deg$ and let $I\subset R$ be an ideal. On one hand, we may consider the initial ideal $\mathrm{in}_{\deg}(I)$. That is the space spanned by ...
Igor Makhlin's user avatar
  • 3,513
9 votes
0 answers
426 views

Is the class of commutative generalized Euclidean rings stable under quotient and localization?

Let $R$ be an associative ring with identity and let $E_n(R)$ be the subgroup of $GL_n(R)$ generated by matrices obtained from the identity matrix by replacing an off-diagonal entry by some $r∈R$. Let ...
Luc Guyot's user avatar
  • 7,893
9 votes
1 answer
876 views

A series that is rational?

Let $k=\mathbb F_q(T)$. Can one prove (or disprove) that the series $\sum_{n\ge0}(1-TX^{q^n})Y^{q^n}\in k[[X,Y]]$ belongs to $k(X,Y)$? At first, it looked like it was simple. But in fact, I have no ...
joaopa's user avatar
  • 3,998
9 votes
3 answers
1k views

Is $k[x_1, \ldots, x_n]$ always an integral extension of $k[f_1, \ldots, f_n]$ for a regular sequence $(f_1, \ldots, f_n)$?

The elements of a regular sequence in $k[x_1, \ldots, x_n]$ are algebraically independent over $k$ (see for example Matsumura ex. 16.6), and so for a length n regular sequence $(f_i)$ of homogeneous ...
Dave M's user avatar
  • 93
9 votes
5 answers
3k views

Alternative proof of unique factorization for ideals in a Dedekind ring

I'm writing some commutative algebra notes, but I'm facing a difficulty in organizing the order of the topics. I'd like to have the topics about factorization before speaking of integral closure. This ...
Andrea Ferretti's user avatar
9 votes
1 answer
431 views

Global obstructions for being a quotient of a rank $d$ vector bundle

In this recent question (which now has an answer), Richard Thomas asked whether any projective $k$-scheme $X$ of (local) embedding dimension $d(X)$ can be embedded in a smooth $k$-scheme of dimension $...
R. van Dobben de Bruyn's user avatar
9 votes
2 answers
2k views

What is the free monoidal category generated by a monoid?

In several places in a segment on cohomology (for example, here (PDF)) in John Baez's online lecture notes for a course in 2007 on quantum gravity, much is made of the fact that the simplex category $...
ziggurism's user avatar
  • 1,446
9 votes
3 answers
2k views

Punctured spectrums of local rings

Let $A$ be a local ring with the unique maximal ideal $\mathfrak{m}$. The punctured spectrum of $A$ is the open subset $\text{Spec}(A)\setminus \{\mathfrak{m}\}$. I have seen many papers (for ...
Fei YE's user avatar
  • 2,444
9 votes
2 answers
3k views

Projective & injective dimensions

$A$ a Noetherian local ring, $M\neq 0$ a finite $A$-module. I'm not quite sure about the relation between finiteness of projective and injective dimensions of $M$. Does the finiteness (or infiniteness)...
ashpool's user avatar
  • 2,857
9 votes
2 answers
1k views

Factorial Rings and The Axiom of Choice

It is shown in Lang's Algebra (and many other books I assume) that: if A if a principal entire ring, then A is a factorial ring. The proof uses Zorn's Lemma. Is this theorem equivalent to the axiom ...
Daniel Barter's user avatar
9 votes
2 answers
1k views

State of the art on a question on the existence of dualizing complex

Let A be a noetherian ring and D(A) be the derived category of modules on A. Recall that a dualizing complex for A is an object R in D(A) of finite injective dimension, with cohomology of finite type ...
user25309's user avatar
  • 6,920
9 votes
1 answer
698 views

Hensel's lemma, Bezout's identity, and the integers

Factorization in the ring $\mathbb{Z}[x]/(x^2+1)\mathbb{Z}[x]\cong \mathbb{Z}[i]$ is well known. For instance, $5$ and $13$ (and any prime $\equiv 1\pmod{4}$) are no longer prime. The factorization ...
Pace Nielsen's user avatar
  • 18.7k
9 votes
1 answer
607 views

Bézout ring with non-trivial Picard group?

[I asked this on stackexchange here a few weeks ago to no response] A ring is called Bézout when its finitely generated ideals are principal. Q: Is there a nice example of a Bézout ring $R$ with ...
Badam Baplan's user avatar
9 votes
1 answer
443 views

Rings with all non-prime ideals finitely generated

Motivated by this question, I would like to ask: If all non-prime ideals in a ring are finitely generated, then is the ring Noetherian? Can we at least say anything in the local case? Note that ...
user avatar
9 votes
3 answers
1k views

Is reflexivity an open condition?

Is the condition that a module is reflexive an open condition? That is, if $X$ is a smooth projective complex variety, $T$ a quasi-projective variety, and $F$ a finitely presented module on $X \...
jlk's user avatar
  • 3,284
9 votes
2 answers
3k views

Localization and intersection

It is very well known that if $\mathfrak p_1, \ldots,\mathfrak p_n$ are prime ideal of an integral domain $A$, then we have the equality$$S^{-1}A=\bigcap_{i=1}^n A_{\mathfrak{p}_i},$$ where $S:=A\...
Vincenzo Zaccaro's user avatar
9 votes
1 answer
1k views

First-order UFD (factorial ring) condition / pre-Schreier rings

All rings in this post are commutative and with $1$. Everyone knows the definition of a factorial ring, a. k. a. unique factorization domain (UFD). I have been wondering about some variations ...
darij grinberg's user avatar
9 votes
2 answers
790 views

Algebraic power series of finite order

Apologies if the question is too elementary/something well-known. I believe it is a well-known fact that the rational formal power series $F(z)=\frac{P(z)}{Q(z)}$ which have finite order under ...
Sam Hopkins's user avatar
  • 24.2k
8 votes
1 answer
497 views

q-Integer-valued polynomials

For $n \in \mathbb{Z}_{\geq 0}$, let $[n]_q := (1-q^n)/(1-q) = (1+q+...+q^{n-1})$ as is customary, with $[0]_q=0$. Let $R$ be the subring of $\mathbb{Q}(q)[x]$ consisting of all $f$ such that $f([n]...
Sam Hopkins's user avatar
  • 24.2k
8 votes
1 answer
238 views

Functions over monoids which factor in two different ways

This is a follow-up question to this MO question, which was asked by Richard Stanley in a comment to my answer there. Let $S$ be a commutative monoid and $f(x_1, \dots, x_n)$ be a function from $S^n$ ...
Tony Huynh's user avatar
  • 32.1k
8 votes
1 answer
2k views

A "geometric" insight into a proof of Krull intersection theorem?

I an not 100% sure that this question has an answer, but still I would like to ask it. There is a short an simple proof of Krull intersection theorem (for example page 12 in http://www.jmilne.org/math/...
aglearner's user avatar
  • 14.3k
8 votes
1 answer
656 views

Given a zero-dimensional ideal $(f_1,...,f_n)$, is the ideal $(f_1-\alpha_1,...,f_n-\alpha_n)$ also zero-dimensional?

Suppose you have a zero-dimensional ideal $I=(f_1,...,f_n)$ in a polynomial ring $R=k[x_1,...,x_n]$ over a field $k$, so that $\dim_k(R/I)<\infty$. Take indeterminates $\alpha_1,...,\alpha_n$ and ...
Stephen McKean's user avatar
8 votes
2 answers
687 views

Looking for a simple one-dimensional noetherian domain whose regular locus is not open

In the wikipedia webpage for "excellent ring", one finds the following. If R is the subring of the polynomial ring k[x1,x2,...] in infinitely many generators generated by the squares and cubes of ...
Matthieu Romagny's user avatar
8 votes
2 answers
2k views

Fermat's Last Theorem in finite fields

Consider the finite field $\mathbb{F}_q$. Schur (1916) proved that, given $n$, when the field is sufficient large, this equation, $$x^n+y^n= z^n$$ always has a nontrivial solution. What conditions ...
Cubic Bear's user avatar
8 votes
2 answers
786 views

Quotients in Sums of Rings

Suppose we are given a commutative ring $R$ with a unit. Suppose that $R$ is the direct product of two rings $R\cong R_1\times R_2$. It's straightforward to show that any ideal $I\subset R$ maps to an ...
Felix Springer's user avatar
8 votes
0 answers
4k views

Kunneth spectral sequence

In Rotman's Homological Algebra, 1st edition, there is written: Is every detail of 11.31-11.35 correct? Isn't the spectral sequence in 11.35 1st quadrant and not 3rd quadrant? Do 11.34-35 also hold ...
Leo's user avatar
  • 1,589
8 votes
2 answers
3k views

Equivalent definitions of arithmetically Cohen-Macaulay varieties

Let $X\subset \mathbb{P}^n$ be a projective algebraic variety with coordinate ring $R$. $X$ is said to be arithmetically Cohen-Macaulay if $R$ is a Cohen-Macauly ring. A equivalent definition is that ...
Fei YE's user avatar
  • 2,444
8 votes
1 answer
345 views

Partial Orders realized by Prime Ideals on commutative rings

Is there a general criterion for which partial orders can be realized by the prime ideals of commutative rings (like we have for topological spaces - https://en.wikipedia.org/wiki/Spectral_space)? ...
Alon Navon's user avatar
8 votes
3 answers
1k views

Derivations of C(X)? or Why Must Supermanifolds be Smooth?

What are the derivations of the algebra of continuous functions on a topological manifold? A supermanifold is a locally ringed space (X,O) whose underlying space is a smooth manifold X, and whose ...
Chris Schommer-Pries's user avatar
8 votes
5 answers
1k views

Examples of left reversible semigroups

I am looking for concrete examples of cancellative, left reversible semigroups. Left reversible semigroups are also called "Ore semigroups". See this wikipedia page for the definition of a left ...
Orr Shalit's user avatar
8 votes
1 answer
979 views

Koszul-Tate Resolution for Subvarieties of $\mathbb P^n$

All varieties appearing below are assumed smooth projective over $\mathbb C$ and all vector bundles, sections etc are assumed to be algebraic/holomorphic. We use the word resolution to mean quasi-...
Mohan Swaminathan's user avatar
8 votes
2 answers
822 views

Free ordered field?

There is no such thing as a free field, because there are no morphisms between fields of different characteristics. However, ordered fields seem to be much better behaved: There is an initial object ($...
Zemyla's user avatar
  • 309
8 votes
0 answers
285 views

Matrix decompositions as monoid isomorphisms. Ever considered before?

I've noticed some correspondences between some matrix decompositions and monoid isomorphisms (always to some free commutative monoid), in addition to the one I asked about in a previous question: ...
wlad's user avatar
  • 4,943
8 votes
1 answer
1k views

Direct sum of injective modules over non-Noetherian rings

By the Bass-Papp theorem, if every direct sum of injective $R$-modules is injective then $R$ is Noetherian. I would like to know if there exists an injective module over $R$ non-Noetherian, that ...
Aaron Bennet's user avatar
7 votes
0 answers
194 views

Factoring a function from a finite set to itself

Let $S$ be a finite set and $f: S \to S$ be a function. Let $k = |f(S)|$ and let $\alpha$ be the partition of $S$ into $f$-fibers, i.e. $\alpha = \{ \alpha_t \}_{t \in f(S)}$ where $\alpha_t = f^{-1}(\...
Sophie M's user avatar
  • 695
7 votes
2 answers
269 views

Double dual of free $\mathbb{Z}_{(p)}$-modules

For an abelian group $A$, put $DA=\text{Hom}(A,\mathbb{Z})$ and $D_{(p)}A=\text{Hom}(A,\mathbb{Z}_{(p)})$. It is a theorem of Specker that when $A$ is free abelian of countable rank, the natural map $...
Neil Strickland's user avatar
7 votes
2 answers
327 views

How to understand the "boundary" of subscheme, as defined in "An elementary characterisation of Krull dimension"

In An elementary characterisation of Krull dimension and A short proof for the Krull dimension of a polynomial ring, Coquand, Lombardi, and Roy give an elementary characterization of Krull dimension, ...
Somatic Custard's user avatar
7 votes
3 answers
2k views

$R$ a DVR with fraction field $K.$ What are the $R$-submodules of $K^n?$

It is known that if $R$ is a DVR with fraction field $K,$ then the $R$-submodules of $K$ are $0,K,x^nR,$ with $n$ any integer and $x$ a generator of the maximal ideal of $R.$ I was wondering if there ...
Chris Leary's user avatar

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