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In this recent question (which now has an answer), Richard Thomas asked whether any projective $k$-scheme $X$ of (local) embedding dimension $d(X)$ can be embedded in a smooth $k$-scheme of dimension $d(X)$. If $i \colon X \hookrightarrow Y$ is such an embedding, then in particular we get a surjection $i^*\Omega_Y \twoheadrightarrow \Omega_X$. My (so far unsuccessful) strategy was to obstruct such a surjection from existing.

For a coherent sheaf $\mathscr F$, write $d_x(\mathscr F) = \dim_{\kappa(x)} \mathscr F_x \otimes_{\mathcal O_{X,x}} \kappa(x)$ and $$d(\mathscr F) = \max \left\{d_x(\mathscr F)\ |\ x \in X\right\}.$$

Question. If $X$ is a quasi-projective $k$-scheme, and $\mathscr F$ a coherent sheaf, does there exist a surjection $\mathscr E \twoheadrightarrow \mathscr F$ from a locally free sheaf of rank $d(\mathscr F)$?

Already if $X = \mathbf A^n$ this seems false to me; for example there should exist finite modules $M$ with $d(M) = 2$ that cannot be generated by $2$ elements (here I am using the Quillen–Suslin theorem that a finite projective module on $\mathbf A^n$ is free). But I don't know so many ways to prove that something is not generated by $2$ elements, except for a local obstruction $d_x(\mathscr F) > 2$.

I think it should be possible to give a negative answer to Thomas's question along these lines, by exhibiting a finite flat cover $\pi \colon X \to \mathbf A^n$ such that $\pi_*\Omega_X$ does not admit a surjection from a vector bundle of rank $\deg(\pi) \cdot d(\Omega_X)$. A great answer would incorporate something like this, but I would already be very happy with some global obstruction to surjecting from a vector bundle of a given rank.

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    $\begingroup$ You may want to look at the literature around Foster-Swan theorem. $\endgroup$ Commented Jan 28, 2020 at 20:23

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Let me explain a simple example.

Let $C \subset \mathbb{P}^3$ be a twisted cubic curve. It is a locally complete intersection of codimension 2, hence its ideal $I_C$ is locally generated by two sections. Let me show that there are no surjections $E \twoheadrightarrow I_C$ from a locally free sheaf $E$ of rank 2.

Indeed, assume such a surjection exists. Its kernel is a reflexive sheaf of rank 1, hence is a line bundle, so we have an exact sequence $$ 0 \to L \to E \to I_C \to 0. $$ Restricting to $C$ we obtain an exact sequence $$ 0 \to \det N^* \to L\vert_C \to E\vert_C \to N^* \to 0, $$ where $N^*$ is the conormal bundle. But $N^*$ is locally free of rank 2, hence the surjection $E\vert_C \to N^*$ is an isomorphism, hence the middle arrow is zero, hence $$ \det N^* \cong L\vert_C. $$ But the adjunction fromula shows that $\det N^* \cong \mathcal{O}_C(-10)$, and this line bundle does not restrict from $\mathbb{P}^3$ (because 10 is not divisible by 3). This contradiction proves that no surjection from $E$ as above exists.

Of course, the same argument works for many other lci of codimension 2.

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  • $\begingroup$ Could you say a word about where $\det N^*$ comes from? (I can do a $\mathscr Tor$ computation locally, but the Koszul resolution doesn't globalise by the very statement you're trying to prove.) $\endgroup$ Commented Jan 29, 2020 at 15:12
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    $\begingroup$ In fact, it does (sometimes this is called the fundamental local isomorphism): $Tor_i(\mathcal{O}_Z,\mathcal{O}_Z) \cong \wedge^iN^*$ for any lci scheme $Z$. $\endgroup$
    – Sasha
    Commented Jan 29, 2020 at 15:53
  • $\begingroup$ I don't mean that the resolution generalizes, but its consequence (the isomorphism for $Tor_i$) does. $\endgroup$
    – Sasha
    Commented Jan 29, 2020 at 16:10
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    $\begingroup$ See "Les K-groupes d'un schéma éclaté..." by Thomason (Inventiones 1993), Lemme 3.2 (the indexing is correct). $\endgroup$
    – user147129
    Commented Jan 29, 2020 at 21:03
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    $\begingroup$ Maybe it's worth mentioning that in many "practical" situations, by the Serre construction, the existence of an isomorphism $\text{det} N^*\cong L|_C$ is exactly what is needed to give a global resolution of $I_C$. $\endgroup$ Commented Jan 31, 2020 at 6:58

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