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Mathematical methods in classical mechanics, classical and quantum field theory, quantum mechanics, statistical mechanics, condensed matter, nuclear and atomic physics.
22
votes
Hamiltonian, Lagrangian and Newton formalism of mechanics
Each of the different formalism of classical mechanics has its advantages and disadvantages. However, in the end all three frameworks tend to be equivalent, and thus the following list is very subject …
17
votes
2
answers
3k
views
Symplectic formulation of statistical physics
Does there exists a symplectic formulation of statistical physics?
I know that thermodynamics can be written in a symplectic language and of course classical mechanics is intrinsically formulated sym …
13
votes
1
answer
3k
views
unbounded self-adjoint operator as Killing vector fields
Hey,
the following is well-known (e. g. Ashtekar/Schilling, Brody/Hughston): A bounded self-adjoint operator $A$ on a Hilbert space $H$ induces a globally defined vector field $X$ on the projective …
13
votes
1
answer
4k
views
Curvature as infinitesimal holonomy
Let $P \to M$ be a principal $G$-bundle, assume as much regularity as you want (compact $G$ or compact base manifold, ect). Via parallel transport, a connection $A$ on $P$ gives rise to the holonomy m …
13
votes
3
answers
2k
views
Space of sections of a fibre bundle with non-compact base space
Let $\pi: E \rightarrow M$ be a fiber bundle over the manifold M and denote by $\Gamma(E)$ the space of smooth sections of $E$.
For compact $M$ it is well known (Hamilton 1982, Part II Corollary 1.3.9 …
9
votes
are there natural examples of classical mechanics that happens on a symplectic manifold that...
The classical phase space of the spin degrees of freedom is represented by the two-sphere with a symplectic form given by $s$ times the standard volume form. This is clearly no cotangent bundle to som …
6
votes
The Precise Meaning of the Moduli Space of Flat Connections?
Let $P \to M$ be a principal $G$-bundle. The moduli space of flat connections on $P$ is, by definition, the space $\mathcal{M} = \mathcal{C}_0 / \mathcal{G}$, where $\mathcal{C}_0$ denotes the subspac …
6
votes
3
answers
4k
views
Flow of a Hamiltonian vector field
Smooth vector fields are in a one-to-one relationship with flows $\Phi: D \subseteq M\times \mathbb{R} \rightarrow M$,
$$X_m = {\frac{d}{d t}}_{t=0} \Phi(m, t),$$
and by the symplectic form also with …
5
votes
Accepted
Yang-Mills Functional and Energy
The easiest way to see that the norm of the curvature corresponds to the energy is to consider the special case of an abelian U(1)-Yang-Mills theory (i.e. electrodynamics). If you write out the norm s …
5
votes
1
answer
380
views
Stabilizer groups of Yang-Mills connections
Let $G$ be a compact Lie group with complexification $G^c$, and consider a principal $G^c$-bundle $P^c \to M$ together with a reduction $P \subseteq P^c$ to $G$. Assume that $M$ is a Riemann surface.
…
5
votes
4
answers
989
views
Where to start with research regarding maslov index/class
Hi,
I am a physicist and currently doing my bachelor thesis about geometric quantization.
In the book by Bates and Weinstein I encountered the Maslov index, which seems to be very important :-).
But …
5
votes
Lifting a diffeomorphism into a spinor bundle automorphism
As spinors transform with a minus sign under a full rotation, there is no (non-trivial) lift of the action of the group of diffeomorphisms to the spinor bundle (i.e. the spinor bundle is not a natural …
4
votes
1
answer
481
views
Extending the variational bicomplex to Hamiltion or Hamiltion-Jacobi formalism
The variational bicomplex seams to provide a modern formulation of the variational problem in terms of modern differential geometry. In particular the bigraded complex of differential forms $\Omega^{p …
4
votes
0
answers
501
views
Local version of a slice (for a Lie group action)
Let $\Upsilon: G \times M \to M$ be a smooth action of a Lie group $G$ on a manifold $M$.
Isenberg and Marsden (1982) define a slice at $m \in M$ as a submanifold $S \subseteq M$ containing $m$ such …
4
votes
Accepted
Transferring connection information to associated bundles and back
Ad 1.: Since every vector can be decomposed in its horizontal and vertical part. Thus it is enough to consider the case a) where all vectors are horizontal (this is trivial) and b) where at least one …