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14 votes
0 answers
603 views

Is the Zariski density proof of Cayley-Hamilton circular?

This old MO thread and its comments contains a discussion of the Zariski density proof of Cayley-Hamilton (I have also asked a separate question about the proof Victor gives in the comments here). ...
Qiaochu Yuan's user avatar
10 votes
0 answers
312 views

Triangle $X'\to X\to X''\to\Sigma X'$ splits if $X\simeq X'\oplus X''$?

Given a commutative ring $R$ and a distinguished triangle $X'\to X\to X''\xrightarrow e\Sigma X'$ in the derived category $D(R)$, where $X',X,X''$ are perfect complexes. If we have an equivalence $X\...
user avatar
8 votes
0 answers
292 views

Image of multiplication map in tensor powers of finite-dimensional ring

Let $R$ be a (commutative, unital) ring of dimension $n$ over a field $k$. Assume the characteristic of $k$ is greater than $n$. Then $R^{\otimes n}$ has a natural ring structure, together with an $...
Will Sawin's user avatar
  • 148k
7 votes
0 answers
226 views

Decomposing an endomorphism as a tensor product

$\DeclareMathOperator\End{End}$Let $f$ be an endomorphism of the finite-dimensional vector space $V$, over the field $K$. The question of whether $f$ is decomposable, that is, whether $V$ can be ...
Pierre's user avatar
  • 2,287
6 votes
0 answers
267 views

Is there a straightforward way to solve unmixed, homogeneous systems of polynomials?

I came across this problem in my research. It might just be an easy algebraic geometry question, but I don't know much algebraic geometry. Suppose we have a system of $k\leq n$ polynomials in $\...
Jeffrey Doker's user avatar
5 votes
0 answers
138 views

Rings over which free modules of a certain rank are reflexive (satisfy Specker's theorem)

Following this question about the case of $\mathbb{Z}_{(p)}$, I've got to ask what is known more generally about rings and dimensions for which Specker's theorem holds. Let me make the following ...
Gro-Tsen's user avatar
  • 32.5k
5 votes
0 answers
220 views

Rank of matrix over UFD polynomial ring

I have a matrix, $M$, size of approximately $20\times 25$, over a polynomial ring $\mathbb{Q}[x_1, \cdots, x_n]$ and a number $r$ such that I would like to test whether or not there exist values for ...
bark's user avatar
  • 51
4 votes
0 answers
219 views

Map $\operatorname{Sym}^{mp}(V^*) \longrightarrow K^{q}$ defined by $q$ points in $\operatorname{Sym}^p(V)$

EDIT : I have edited the question and made it more specific with respect to the kind of answer I expect. Let $V$ be a finite dimensional $K$-vector space and let $x_1, \dotsc, x_q \in V$ be $q$ points,...
Libli's user avatar
  • 7,300
4 votes
0 answers
216 views

Is an orthogonal direct sum decomposition with respect to two quadratic forms necessarily unique up to isomorphism

Consider two quadratic forms $Q$ and $P$ over a finite dimensional vector space $V$ over a quadratically closed (or perhaps Pythagorean) field $F$. If $V$ can be decomposed as $V = V_1 \oplus V_2 \...
wlad's user avatar
  • 4,943
4 votes
0 answers
211 views

Diagonalization over valuation rings

Let $\mathcal{R}$ be a valuation ring, and consider an $\mathcal{R}$-linear endomorphism $L:\mathcal{R}^{n}\rightarrow \mathcal{R}^{n}$. Is there any criterion for telling when $L$ can be diagonalized?...
FPV's user avatar
  • 541
4 votes
0 answers
312 views

Dimension of a commuting nilpotent variety

Fix $k$ an algebraically closed field, $n$ a natural number, and $\lambda=(\lambda_1,\ldots,\lambda_m)$ a partition of $n$. Let $A$ be any $n\times n$ nilpotent matrix with entries in $k$ whose ...
Jared's user avatar
  • 768
3 votes
0 answers
181 views

Levelled trees and the homotopy transfer theorem

In section 10.3.12 of Loday-Vallette's book "Algebraic operads", given a $P_\infty$-algebra $(A,d,\alpha)$ the Homotopy Transfer Theorem applied to $H_*(A,d)$ is studied. There, because the ...
groupoid's user avatar
  • 215
3 votes
0 answers
70 views

Admissibility of Ulm's invariants

Let $G$ be a reduced abelian $p$-group. We set $G_0=G$. Let $\alpha$ be an ordinal. Inductively, if $\alpha=\beta+1$ is a successor ordinal, we define $$G_{\alpha}=pG_{\beta}.$$ If $\alpha$ is a limit ...
Nini's user avatar
  • 31
3 votes
0 answers
71 views

Automorphisms of matrix algebras and Picard group

This is a repost of https://math.stackexchange.com/questions/4692364/automorphisms-of-matrix-algebras-and-picard-group (asked on MSE). Notation. In what follows, $R$ is a commutative ring with $1$, $n\...
GreginGre's user avatar
  • 1,766
3 votes
0 answers
249 views

Grothendieck schemes and the Sheffer differential op calculus (Rota, Roman, et al. finite operator calculus)

In "Left differential operators on non-commutative algebras" on p. 4, Michiel Hazewinkel displays "precisely the right definition of differential operator" as $$D\; X^n = F(\tfrac{...
Tom Copeland's user avatar
  • 10.5k
3 votes
0 answers
120 views

Checking the generic rank of a matrix

Suppose that $A,B\in M_{p,q}(\mathbb{Z})$ are two rectangular integer matrices of the same size. Suppose that one has a conjecture stating that the rank of the matrix $A+tB$ for Zariski generic values ...
Vladimir Dotsenko's user avatar
3 votes
0 answers
155 views

Bass theorem on non-affine scheme

A famous theorem of Bass tells that over a noetherian ring $A$, with $\operatorname{Spec}(A)$ connected, every projective module of infinite type is free. Now, consider a connected noetherian scheme $...
prochet's user avatar
  • 3,472
3 votes
0 answers
56 views

Regular sequence of binary forms in a subspace

Let $A_d=\mathbb{C}[x_1,\dots,x_n]_d$ denote the vector space of homogeneous polynomials of degree d. And assume $U\subset A_d$ is a subspace of codimension $d-1$ such that there is no point in $\...
blacky's user avatar
  • 51
3 votes
0 answers
97 views

Minimal localization need it to "diagonalize" a matrix

Let $A$ be an $n\times n$-matrix over $\mathbb Z[t^\pm]$. In general doesn't exist $P,Q\in GL(n,\mathbb Z[t^\pm])$ such that $PAQ$ is a diagonal matrix (this happens cause $\mathbb Z[t^\pm]$ is not a ...
bruno mazorra's user avatar
3 votes
0 answers
288 views

When is a polynomial ring free over a graded subalgebra?

Keep the setting of my previous question and let $I := k[x_1, \dots, x_n] \cdot A_{>0}$ be an ideal of the algebra $k[x_1, \dots, x_n]$ generated by the set $A_{>0}$. It is clear that $I$ is a ...
user avatar
3 votes
0 answers
211 views

the annihilator of cokernel in a particular case

Let $A\in Mat(m,n;R)$ for $m\le n$ and $R$ a local ring. Consider the $mn\times(m^2+n^2)$ matrix $A\otimes 1_{nn}\oplus 1_{mm}\otimes A^T$, here $1_{mm}$, $1_{nn}$ are identity matrices. I'd like to ...
Dmitry Kerner's user avatar
3 votes
0 answers
112 views

Nullspace of a matrix modulo an ideal

Suppose $R$ is a multivariate polynomial ring and $I$ is an ideal in $R$. Let $M$ be a $n\times n$ square matrix with entries in $R$, and suppose that det($M$) lies in $I$. Thus, $M$ has a non-...
Thomas Ivey's user avatar
3 votes
0 answers
474 views

Jacobson-Bourbaki correspondence

The Jacobson-Bourbaki correspondence induces the traditional, finite Galois correspondence by suitable restriction; I've been pondering two things: 1. Are there any (other) interesting applications of ...
Stephan F. Kroneck's user avatar
3 votes
0 answers
473 views

Infinite Galois correspondence "according to Artin"

Ever since Artin's lectures on Galois Theory one knows how to set up and derive the usual Galois correspondence in the finite(-dimensional) case using just a bit of elementary Linear Algebra, and ...
Stephan F. Kroneck's user avatar
2 votes
0 answers
59 views

Tensor product of two transcendental flat algebras is not a field?

I'm considering the correctness of the following assertion, which is related to linear disjointness (I'm trying to generalize it to subalgebras), What does "linearly disjoint" mean for ...
Jz Pan's user avatar
  • 173
2 votes
0 answers
112 views

Invariant factors and commuting matrices over a discrete valuation ring

$\DeclareMathOperator\Im{Im}\DeclareMathOperator\Ker{Ker}$Let $A$ be a discrete valuation ring with uniformizer $p$. Let $X, Y\in M_n(A)$ be square matrices such that $XY=YX$, and let $X^T$, $Y^T$ be ...
Sylvain Brochard's user avatar
2 votes
0 answers
164 views

Can the equation $1+z^p+z^q+z^r=z^n$ have multiple complex roots $z$?

The math overflow post asks whether the equation $1+z^p+z^q=z^n$ can have multiple complex roots where $p<q<n$ (On the irreducibility of certain trinomials and quadrinomials). Q. Let us ...
ABB's user avatar
  • 4,058
2 votes
0 answers
97 views

How to decompose a matrix over a ring $F[X_1,\ldots,X_k]$ as a product of two matrices

Let $F$ be a field. Assume any reasonable conditions if needed, such as $F=\mathbb R$, $F=\mathbb C$, $F$ is a finite field, or $F$ has a specific characteristic, etc. Let $C$ be an $n\times1$ matrix ...
zxcv's user avatar
  • 131
2 votes
0 answers
115 views

Linear algebra. commutative algebra, a matrix having the maximal rank

I found a matrix that looks to have the maximal rank for my research. I would really appreciate if some of you could give me any comments or suggestions. Thanks in advance. Sincerely, Yong-Su Shin Let ...
YONG-SU SHIN's user avatar
2 votes
0 answers
238 views

Computing the codimension of the variety defined by a system of quadratic forms

Suppose I have an $m \times n$ matrix $L$, where $m \leq n$ and each entry is $L_{i,j}(x_1, ..., x_s)$ which is a linear form over $\mathbb{C}$. Let $\mathbf{y} = (y_1, \ldots, y_n)$. Let us consider ...
Johnny T.'s user avatar
  • 3,625
2 votes
0 answers
60 views

Linearity of a canonical morphism related to scalar extension and coextension

Let $h\colon R\rightarrow S$ be a morphism of commutative ring. Let $M$ and $N$ be $R$-modules. We consider the canonical morphism of $R$-modules $$p\colon{\rm Hom}_R(S\otimes_RM,N)\rightarrow{\rm Hom}...
Fred Rohrer's user avatar
  • 6,700
2 votes
0 answers
197 views

Full-rank factorization property of integer-valued matrices

$\newcommand{\al}{\alpha} \newcommand{\de}{\delta} \newcommand{\De}{\Delta} \newcommand{\ep}{\varepsilon} \newcommand{\ga}{\gamma} \newcommand{\Ga}{\Gamma} \newcommand{\la}{\lambda} \newcommand{\Si}{\...
Iosif Pinelis's user avatar
2 votes
0 answers
87 views

How to prove this matrix is idempotent and that it obeys a telescoping identity

Let $P_k$ be the size $k$ leading principal submatrix of the real-valued $N \times N$, invertible matrix $M$, and let $Q_k$ be the size $N$ matrix having $P_k^{-1}$ in the top left corner, and zeroes ...
Gl0ven0r's user avatar
1 vote
0 answers
37 views

Bounding the length of an R-module of matrices

Loosely related to this: Bounding the length in a module of evaluated skew polynomials Let $C$ be an $\mathbb{F}_q$-vector subspace of $m \times n$ matrices over $\mathbb{F}_q$. Assume WLOG that $m \...
JBuck's user avatar
  • 223
1 vote
0 answers
60 views

Bounding the length in a module of evaluated skew polynomials

Let $R$ be a finite principal ideal ring, $S$ a Galois extension of $R$ of degree $m$ (so in particular $S$ is a free $R$-module of rank $m$, and we have an $R$-module isomorphism $S^n \cong \...
JBuck's user avatar
  • 223
1 vote
0 answers
130 views

A basis of the weight space in the semi-invariant ring corresponding to the weight $\langle(2,3,2),\cdot\rangle$

I'm trying to understand Example 10.11.1 on page 225 of the book "An introduction to quiver representations" by Harm Derksen and Jerzy Weyman (see the attached screenshot below) I want to ...
It'sMe's user avatar
  • 839
1 vote
0 answers
24 views

One-step vectorial recurrence into multi-step scalar recurrence on commutative rings with boundary conditions

Introduction over unbounded domain Consider the forward time shift $\mathsf{z}$ acting on a discrete function of time (sequence) $f=(f^n)_{n\in\mathbb{N}}$ as $(\mathsf{z} f)^{n} = f^{n+1}$. Also ...
94thomas's user avatar
1 vote
0 answers
45 views

Lifting module homomorphisms imposing conditions on characteristic polynomials

Suppose that we are in the setting described in the first two paragraphs of this MSE post. My question wants to deal with an instance of the study of the amount of freedom that the choice of the ...
Hvjurthuk's user avatar
  • 573
1 vote
0 answers
186 views

Proving the non-existence of canonical isomorphisms

From time to time, during my undergraduate lectures on linear algebra appears the following question from the most smart students in the class. I asked to my algebra colleagues but I have not received ...
Johnny Cage's user avatar
  • 1,561
1 vote
0 answers
41 views

A bi-variate polynomial interpolation question

Let $R$ be a commutative unital ring, and $R^{m\times k}$ denote the set of $m\times k$ matrices with entries from $R$. A matrix $U\in R^{m\times m}$ is elementary if $U$ is obtained from the identity ...
TimeaV's user avatar
  • 11
1 vote
0 answers
45 views

A "spectral theorem" to SVD reduction for every commutative *-ring

Given any commutative $*$-ring $R$ of uneven characteristic, is it true that for every square matrix $M$ and unitary matrix $W$, if $W^* \begin{bmatrix} 0 & M \\ M^* & 0 \end{bmatrix} W$ is ...
wlad's user avatar
  • 4,943
1 vote
0 answers
145 views

Has anyone studied this possible generalisation of the Singular Value Decomposition to all commutative $*$-rings?

I don't know any abstract algebraists personally, which is why I'm asking this question here. Let $(R,*)$ be a commutative $*$-ring where $*:R \to R$ is an involution. Each conjecture below is stated ...
wlad's user avatar
  • 4,943
1 vote
0 answers
108 views

When do the kernels of module homomorphisms between rings whose kernels contain a given fixed ideal contain every prime ideal over it?

$\DeclareMathOperator{\Hom}{Hom}$All our rings are commutative with unity and, if necessary, we can suppose that they are actually polynomial rings over a field in finitely many variables where the ...
Hvjurthuk's user avatar
  • 573
1 vote
0 answers
33 views

Making a generating set of a section of a graded polynomial $R$-module coming from a quotient into a basis of a quotient by higher degree polynomial

Denote the graded rings $R:=\mathbb{R}[x_{1},\dots x_{n}]$ and $S:=R[x_{0}]$ adding the homogenizing variable $x_{0}.$ Consider $h\in S$ a homogenous polynomial of degree $d$ with leading coefficient $...
Hvjurthuk's user avatar
  • 573
1 vote
0 answers
126 views

Algebraic structures on graphs

There are many algebraic structures linked to graphs. For example one can find zero divisor graphs $[1]$, $[2]$ and many other graphs. Does there exist any survey paper which characterizes all the ...
Charlotte's user avatar
  • 444
1 vote
0 answers
246 views

Frobenius twist of a field

Let $k$ be a field of characteristic $p>0$ (not necessarily perfect). Consider the Frobenius endomorphism $F : k \to k$, $x \mapsto x^p$. I am curious about what happens when we take $k$ as a $k$-...
VerrückterPinguin's user avatar
1 vote
0 answers
1k views

Are the integers a vector space or algebra over "some" field or over "some" ring?

Every vector $v$ in a finite-dimensional vector space space $V$ of dimension $n$ over a field $F$ has a unique representation in terms of a basis ${\frak B} \subseteq V$, where a basis for $V$ is a ...
étale-cohomology's user avatar
1 vote
0 answers
95 views

Is it true that the generator of maximal ideal in $M_n(P[x])$ can be choosen to be monic?

Let $P$ be a finite field and $R=M_n(P[x])$ be a matrix polynomial ring. I want to prove that for every polynomial (not necessary with invertible leading term) $A(x)\in R$ such that $R\cdot A(x)$ is ...
Mikhail Goltvanitsa's user avatar
1 vote
0 answers
59 views

How to associate the following two kinds of real polynomials?

Suppose the following real polynomial of $n$ variables $$f(X_1,X_2,\cdots,X_n)=\sum_{I=(i_1,i_2,\cdots,i_n)}a_IX_1^{i_1}X_2^{i_2}\cdots X_n^{i_n}$$ is easy or familiar to us, but I need to deal with ...
user173856's user avatar
  • 1,997
1 vote
0 answers
1k views

Algebraic Independence of Polynomials in n Variables with Real Coefficients

I am considering the problem of determining the algebraic independence of $n$ polynomials in $m$ variables with real coefficients, where $m \geq n$. The variables will be denoted by $a_{1}, a_{2}, ... ...
mnh1364's user avatar
  • 11