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6 votes
0 answers
532 views

Can one calculate Ext's between microlocalized perverse sheaves/D-modules using topology?

So, I know one really good technique for calculating Ext's between perverse sheaves/D-modules using topology: the convolution algebra formalism, worked out in great detail in the book of Chriss and ...
Ben Webster's user avatar
  • 44.7k
5 votes
2 answers
2k views

Homotopy Pushouts via Model Structure in Top

As far as I know, one way to take a homotopy colimit in a model category is to replace (up to acyclic fibration) all arrows in the diagram with cofibrations, and take the strict colimit of the ...
Joey Hirsh's user avatar
  • 1,033
15 votes
3 answers
3k views

H-space structure on infinite projective spaces

Any Eilenberg-MacLane space $K(A,n)$ for abelian $A$ can be given the structure of an $H$-space by lifting the addition on $A$ to a continuous map $K(A\times A,n)=K(A,n)\times K(A,n)\to K(A,n)$. Does ...
Hanno Becker's user avatar
20 votes
2 answers
1k views

Are non-empty finite sets a Grothendieck test category?

A "test category" is a certain kind of small category $A$ which turns out to have the following property: the category $\widehat{A}$ of presheaves of sets on $A$ admits a model category structure, ...
Charles Rezk's user avatar
  • 27.2k
11 votes
1 answer
1k views

Why does the internal singular simplicial space realize to the same thing as the discrete singular simplicial set?

There are two version of the singular simplicial space of a topological space $X$, one discrete and one internal. At least if X is nice, both of them have homotopy equivalent geometric realizations (...
Chris Schommer-Pries's user avatar
14 votes
1 answer
961 views

Founding of homological without quite involving derived categories

I am looking at the foundations of homological algebra, e.g. the introduction of Ext and Tor, and am unsatisfied. The references I look at start with "this is called a projective module, this is ...
Allen Knutson's user avatar
23 votes
3 answers
6k views

Does homology detect chain homotopy equivalence?

Is the following true: If two chain complexes of free abelian groups have isomorphic homology modules then they are chain homotopy equivalent.
Stephen Bigelow's user avatar
39 votes
4 answers
7k views

Two kinds of orientability/orientation for a differentiable manifold

Let $M$ be a differentiable manifold of dimension $n$. First I give two definitions of Orientability. The first definition should coincide with what is given in most differential topology text books, ...
Anweshi's user avatar
  • 7,442
4 votes
1 answer
972 views

relationship between borromean rings and hanging-a-picture-from-three-nails puzzle?

I recently heard the following puzzle: There are three nails in the wall, and you want to hang a picture by wrapping a wire attached to the picture around the nails so that if any one nail is removed ...
Aaron Mazel-Gee's user avatar
21 votes
3 answers
1k views

What's the analogue of the Hilbert class field in the following analogy?

There's a wonderful analogy I've been trying to understand which asserts that field extensions are analogous to covering spaces, Galois groups are analogous to deck transformation groups, and ...
Qiaochu Yuan's user avatar
7 votes
5 answers
980 views

Killing the torsion in homotopy

Origin This question was asked by John Baez in This Week's Finds in Mathematical Physics (Week 286). Therefore, please don't upvote this question (unless you really want to), but do upvote the ...
Ilya Nikokoshev's user avatar
8 votes
4 answers
586 views

Examples of the varying strengths of topological invariants

In my first algebraic topology class, I remember being told that the simplest reason for homology was to distinguish spaces. For example, if is X=circle and a Y= wedge of a circle and a 2-sphere then ...
5 votes
1 answer
383 views

Killing Chern classes

Let $G$ be a compact connected Lie group and let $E\to B$ be a principal $G$-bundle. Suppose $a$ is a rational cohomology class of $E$ such that its pullback $b$ under an orbit inclusion map $G\to E$ ...
algori's user avatar
  • 23.5k
15 votes
1 answer
1k views

Stable ∞-categories as spectral categories

Let C be a stable ∞-category in the sense of Lurie's DAG I. (In particular I do not assume that C has all colimits.) Then C does have all finite colimits, the suspension functor on C is an ...
Reid Barton's user avatar
  • 25.2k
7 votes
2 answers
2k views

categorical homotopy colimits

let $hTop_*$ denote the homotopy category of pointed spaces. I believe that it has no pushouts, in general. the reason is that you can't expect the involved homotopies to be compatible. can anyone ...
Martin Brandenburg's user avatar
8 votes
2 answers
431 views

Formulas for vector fields on Grassmannians?

The Wikipedia article on (real) Grassmannians gives a simple argument that the Euler characteristic satisfies a recurrence relation $$\chi G_{n,r} = \chi G_{n-1,r-1} + (-1)^r \chi G_{n-1,r}$$. This ...
Ryan Budney's user avatar
  • 44.4k
15 votes
2 answers
973 views

Infinity de Rham quasi-isomorphism

This question is similar to Do chains and cochains know the same thing about the manifold? in the sence that both deal with a natural "comparison" quasi-isomorphism that does not preserve the ring ...
algori's user avatar
  • 23.5k
45 votes
10 answers
4k views

effective teaching

Eric Mazur has a wonderful video describing how physics is taught at many universities and his description applies word for word to the way I learned mathematics and the way it is still being taught, ...
3 votes
1 answer
858 views

Any reason why K_23(Z) has order 65520?

I'm rereading my notes and they mention that $K_{23}(\mathbb Z) = \mathbb Z/(65520)$ This looks like a good point to stop and ask whether there is any explanation for this $K$-group of integers (23 ...
Ilya Nikokoshev's user avatar
20 votes
5 answers
2k views

Equivalence of ordered and unordered cech cohomology.

Given a topological space X and a finite cover X = $\cup X_i$, one can define Cech cohomology of a sheaf of abelian groups F with respect to the cover $\{X_i\}$ in two different ways: (Ordered): ...
David Zureick-Brown's user avatar
90 votes
5 answers
7k views

Algorithm or theory of diagram chasing

One of the standard parts of homological algebra is "diagram chasing", or equivalent arguments with universal properties in abelian categories. Is there a rigorous theory of diagram chasing, and ...
Greg Kuperberg's user avatar
7 votes
4 answers
686 views

Realizing complexes with bases as cellular complexes

This is a question a friend of mine asked me some time ago. I suspect the answer is "no" but can't prove it. Every free complex of abelian groups is isomorphic to the reduced cellular complex of some ...
algori's user avatar
  • 23.5k
17 votes
4 answers
2k views

Characteristic classes in generalized cohomology theories?

Hello, 'ordinary' Stiefel-Whitney classes are elements of the singular cohomology ring and are constructed using the Thom isomorphism and Steenrod squares. So I think they should exist for any (...
Jonas Morrissey's user avatar
3 votes
1 answer
299 views

disagreement between two definitions of the singular boundary map

Hi everyone, I have a little problem with the definition of singular boundary map in singular homology theory. It appears to be some disagreement between two authors. The first one is Hatcher in his '...
Dan's user avatar
  • 105
11 votes
4 answers
1k views

Equivariant singular cohomology

One can define the $G$-equivariant cohomology of a space $X$ as being the ordinary singular cohomology of $X \times_G EG$ --- I think this is due to Borel? (See e.g. section 2 of these notes) ...
Kevin H. Lin's user avatar
12 votes
3 answers
2k views

How does one find vanishing algebraic cycles?

I have a question, related to what I asked before. Let's consider a smooth hyperplane section $X$ of a smooth projective variety $Y$ over $\mathbb C$. According to Weak Lefschetz theorem, cohomology ...
Evgeny Shinder's user avatar
19 votes
4 answers
3k views

What are the fibrant objects in the injective model structure?

If C is a small category, we can consider the category of simplicial presheaves on C. This is a model category in two natural ways which are compatible with the usual model structure on simplicial ...
Chris Schommer-Pries's user avatar
18 votes
1 answer
943 views

Do chains and cochains know the same thing about the manifold?

This question was inspired by Poincaré quasi-isomorphism Let $M$ be a closed oriented $n$-manifold. The cap product with the fundamental class of $M$ induces an isomorphism $H^i(M,\mathbf{Z})\to ...
algori's user avatar
  • 23.5k
8 votes
2 answers
1k views

Poincaré quasi-isomorphism

Suppose we have a simplicial combinatorial manifold (just a triangulated manifold) and its Poincaré dual cell complex. Corresponding homology simplicial and homology cell complexes are quasi-...
Nikolai Mnev's user avatar
  • 1,482
39 votes
3 answers
6k views

Why do finite homotopy groups imply finite homology groups?

Why does a space with finite homotopy groups [for every n] have finite homology groups? How can I proof this [not only for connected spaces with trivial fundamental group]? The converse is false. $\...
roger123's user avatar
  • 2,782
23 votes
13 answers
7k views

Pedagogical question about linear algebra

Last semester I taught a linear algebra class that is intended to introduce young students (at a sophmore-junior level) to "abstract mathematics". It seems that a major conceptual hurdle for many of ...
23 votes
4 answers
4k views

Curriculum reform success stories at an "average" research university

Greetings all, There's a never-ending story that many of us have sunk our teeth into. How do we go about teaching subjects like calculus and analysis "well?" Most universities that I'm familiar ...
7 votes
2 answers
541 views

(Co-) Homology associated to Waldhausen K-Theory

Waldhausen K-Theory takes as input a Waldhausen category C and produces a spectrum K(C). I would like to know what is known about generalized (co-) homology theories that can be realized by this ...
user2146's user avatar
  • 1,273
11 votes
4 answers
958 views

Geometry of the multilagrangian Grassmannian

Let's introduce the following variety $MG(3,6)$, which is a "multisymplectic" analog of a Lagrangian Grassmannian $LG(3,6)$. Consider a 3-form $\omega = dx1 \wedge dx2 \wedge dx^3 - dx4 \wedge dx5 \...
Evgeny Shinder's user avatar
3 votes
2 answers
465 views

Branched coverings over orbifolds with reflector lines

It is well known that if $F\to B$ is a $n$-finite branched covering over an orbifold with cone-points then the orbifold Euler's characteristics are related via $\chi(F)=n(\chi(B)-\sum_i^r\frac{a_i-1}{...
janmarqz's user avatar
  • 345
32 votes
8 answers
2k views

Noncommutative rational homotopy type

Ok, this question is much less ambitious than it might sound, but still: Two commutative differential graded algebras (cdga's) are quasi-isomorphic if they can be connected by a chain of cdga quasi-...
algori's user avatar
  • 23.5k
5 votes
2 answers
357 views

Truncated exact sequence of homotopy groups

This is a question about a name of a very useful lemma, that permits one in particular to show that smooth birational complex projective varieties have isomorphic fundamental groups. If this lemma ...
Dmitri Panov's user avatar
  • 28.9k
40 votes
4 answers
3k views

Chain homotopy: Why du+ud and not du+vd?

When one wants to prove that a morphism $f_*$ between two chain complexes $\left(C_*\right)$ and $\left(D_*\right)$ is zero in homology, one of the standard approaches is to look for a chain homotopy, ...
darij grinberg's user avatar
149 votes
7 answers
23k views

Homotopy groups of Lie groups

Several times I've heard the claim that any Lie group $G$ has trivial second fundamental group $\pi_2(G)$, but I have never actually come across a proof of this fact. Is there a nice argument, ...
Matt Noonan's user avatar
  • 4,014
19 votes
6 answers
3k views

Diffeomorphism of 3-manifolds

Surgery theory aims to measure the difference between simple homotopy types and diffeomorphism types. In 3 dimensions, geometrization achieves something much more nuanced than that. Still, I wonder ...
Tim Perutz's user avatar
  • 13.2k
39 votes
4 answers
4k views

What manifolds are bounded by RP^odd?

Real projective spaces $\mathbb{R}P^n$ have $\mathbb{Z}/2$ cohomology rings $\mathbb{Z}/2[x]/(x^{n+1})$ and total Stiefel-Whitney class $(1+x)^{n+1}$ which is $1$ when $n$ is odd, so it follows that ...
Pierre Weil's user avatar
176 votes
7 answers
19k views

Proofs of Bott periodicity

K-theory sits in an intersection of a whole bunch of different fields, which has resulted in a huge variety of proof techniques for its basic results. For instance, here's a scattering of proofs of ...
Eric Peterson's user avatar
21 votes
1 answer
767 views

The density hex

Gale famously showed that the determinacy of n-player, n-dimensional Hex is equivalent to the Brouwer fixed point theorem in n dimensions. We can (and Gale does) view this as saying that if you d-...
Harrison Brown's user avatar
2 votes
1 answer
510 views

Are the C(S^n, S^n)'s homeomorphic ?

Let m, n > 1. Is it true that C(S^m, S^m), and C(S^n, S^n) are homeomorphic ? [both endowed with the sup metric (or equivalently the compact-open topology)] Generally, C(S^n, S^n), with n >= 1, is a ...
Ady's user avatar
  • 4,060
14 votes
2 answers
790 views

Finding cocycles that square to zero

Suppose $x$ is a chosen class in the singular cohomology (integer coefficients) of a space $X$. I'm thinking primarily of classes of odd degree on a simply connected space. What are necessary ...
Tim Perutz's user avatar
  • 13.2k
15 votes
1 answer
2k views

Graded commutativity of cup in Hochschild cohomology

I am trying to get used to Hochschild cohomology of algebras by proving its properties. I am currently trying to show that the cup product is graded-commutative (because I heard this somewhere); ...
darij grinberg's user avatar
11 votes
5 answers
7k views

(infinity,1)-categories directly from model categories

Edit & Note: I'm declaring a convention here because I don't feel like trying to fix this in a bunch of spots: If I said model category and it doesn't make sense, I meant a model-category "model" ...
19 votes
6 answers
3k views

Simplicial homotopy book suggestion for HTT computations

I'm struggling through Lurie's Higher Topos Theory, since it appears that someone reading through the book is expected to be somewhat comfortable with simplicial homotopy theory. The main trouble I'...
71 votes
10 answers
25k views

Nice proof of the Jordan curve theorem?

As a student, I was taught that the Jordan curve theorem is a great example of an intuitively clear statement which has no simple proof. What is the simplest known proof today? Is there an intuitive ...
user2498's user avatar
  • 1,843
5 votes
2 answers
666 views

HNN extensions which are free products

which HNN-extensions are free products? this question is related with another still unsolved about Nielsen-Thruston-reducibility and connected-sum-irreducibility of 3d-torus- bundles...
janmarqz's user avatar
  • 345