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The representation of functions (or objects which are in some generalize the notion of function) as constant linear combinations of sines and cosines at integer multiples of a given frequency, as Fourier transforms or as Fourier integrals.

18 votes
3 answers
7k views

Eigenvectors of the Fourier transformation

The Fourier transform $\hat u$ is defined on the Schwartz space $\mathscr S(\mathbb R^n)$ by $ \hat u(\xi)=\int e^{-2iπ x\cdot \xi} u(x) dx. $ It is an isomorphism of $\mathscr S(\mathbb R^n)$ and the …
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11 votes
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Fourier Coefficients and Hölder Continuity

There is an excellent characterization of Hölder spaces via the Fourier transform, using Besov spaces. Let $\alpha\in (0,1)$: a function $u$ defined on $\mathbb R^n$ belongs to $L^\infty\cap C^\alpha$ …
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9 votes
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Fourier transform in $L^1$?

To fix notations let us consider the Fourier transformation as acting on functions over $\mathbb R^n$. The set of functions with Fourier transform $\hat{f} \in L^1(\mathbb{R}^n)$ is the Wiener algebra …
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7 votes
2 answers
467 views

Eigenstates of Fourier transformation

Let $\gamma$ be defined on $\mathbb R^n$ by $\gamma (x)=e^{-π x^2}$. With $\mathcal F$ standing for the Fourier transformation defined on the Schwartz space by $$ (\mathcal F u)(\xi)=\int e^{-2iπ x\cd …
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6 votes

Are Besov spaces $B^{s}_{p,q}$ invariant under Fourier transform?

Let me note $\phi_k(D)$ the Fourier multiplier $\phi_k(\xi)$, i.e. $ \text{Fourier}\bigl(\phi_k(D)u\bigr)(\xi)=\phi_k(\xi)\hat u(\xi). $ $\bullet$ The answer to (1) is yes since $$ \Vert{u}\Vert_{L^1 …
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5 votes

Easy Garding Inequality

I understand that you are dealing with semi-classical symbols $$ b(x,\xi, h)=a(x,h\xi), \quad \vert\partial_x^\alpha\partial_\xi^\beta b\vert\le C_{\alpha\beta} h^{\vert \beta\vert} m(x),\quad 0<h\le …
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5 votes

Is there a compactly supported function that its Fourier transfrom vanishes at given n real ...

Consider the polynomial $ P(\xi)=\prod_{1\le j\le n}(\xi-\lambda_j). $ The inverse Fourier transform of $(\xi-\lambda_j)$ is $$ \int(\xi-\lambda_j) e^{2iπ x\xi} d\xi=(D_x-\lambda_j)(\delta_0)=\frac{\ …
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5 votes

fourier analytic proofs

Let me speak about the "Triumph of Fourier" according to the words of Laurent Schwartz in his autobiography. The Fourier transformation is a handy tool to characterize regularity of functions. Let $ …
5 votes
Accepted

About the boundedness of a multiplication operator.

When $p=2$, boundedness is a triviality and it is the only trivial case. It is not true for $p=1$ nor for $p=\infty$, although the Fourier multiplier $sign(D_x)$ sends $L^1$ into $L^1_w$ and the Marci …
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5 votes

Fourier transform of Analytic Functions

The following basic result needs to be quoted on these matters of analyticity: the Paley-Wiener-Schwartz theorem gives a characterization of distributions with compact support. Let $u$ be a tempered d …
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5 votes
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Sobolev convergence of Fourier series

Let us start with pointing out that $f\in H^\sigma$ is equivalent to $$ (\langle n\rangle^\sigma\hat f(n))_{n\in \mathbb Z}\in \ell^2(\mathbb Z), \quad \text{with $\langle n\rangle=\sqrt{1+n^2}$.} $$ …
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4 votes
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Real-analytic variant of theorem 4.2.5 of Duistermaat's "FIO", 1996

You may be able to read the Sato-Kawai-Kashiwara lecture notes if your algebraic geometry background is sufficient for this non-trivial task. On the other hand, the book by J. Sjöstrand "Singularité …
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4 votes
0 answers
925 views

Norms of the Dirichlet kernel

I guess that the following estimates are classical. Let $D_N$ be the $1D$ Dirichlet kernel, $$ D_N(t)=\frac{\sin((N+\frac12)t)}{\sin (t/2)}. $$ We have for $1<p<\infty$, \begin{align} \Vert D_N\Vert_{ …
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4 votes
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Stationary phase method for $\varphi''(x_0)= 0$

Let me assume that $a=-\infty, b=+\infty, x_0=0$ and $f$ smooth and compactly supported near 0. Then after a suitable change of variable, you get that $ I(\lambda)=\int g(t) e^{i\lambda t^3/3} dt, $ …
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4 votes
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Fourier Transform: Smoothness and Decay

Your space is some sort of Besov space, containing $B^{2+\epsilon}_{1,\infty}$. Using a Littlewood-Paley decomposition $1=\sum_\nu\varphi_\nu(\xi)$ with $\varphi_0\in C^\infty_c$, $\varphi_\nu(\xi) …
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