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Banach spaces, function spaces, real functions, integral transforms, theory of distributions, measure theory.

18 votes
3 answers
4k views

Formal adjoint of the covariant derivative

Let $E \to M$ be a vector bundle over some Riemannian metric $(M, g)$ and endow it with some fibre metric. Assume that covariant derivative $\nabla$ is compatible with the metric. It is essentially …
Tobias Diez's user avatar
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17 votes
1 answer
1k views

Invariant definition of the space of symbols on a vector bundle (pseudo-differential operators)

Normally, in the context of pseudo-differential operators, a symbol on a vector bundle $E$ is defined as a smooth function on $E$ which in each trivializing chart fulfills the usual symbol estimates …
Tobias Diez's user avatar
  • 5,824
16 votes
1 answer
900 views

Pedagogically intuitive reformulation of Zorn's Lemma for functional analysis

While teaching an applied functional analysis class, I’ve noticed that students often struggle to develop an intuitive understanding of Zorn’s lemma. It’s relatively straightforward to explain why tra …
Tobias Diez's user avatar
  • 5,824
14 votes
2 answers
521 views

Reference Request: Elliptic differential operators in the Fréchet setting

Normally the theory of (elliptic) differential operators between vector bundles (or $\mathbb{R}^n$) is presented in the language of Sobolev spaces. I'm searching for a book (or something similar) whic …
Tobias Diez's user avatar
  • 5,824
13 votes
3 answers
2k views

Space of sections of a fibre bundle with non-compact base space

Let $\pi: E \rightarrow M$ be a fiber bundle over the manifold M and denote by $\Gamma(E)$ the space of smooth sections of $E$. For compact $M$ it is well known (Hamilton 1982, Part II Corollary 1.3.9 …
Tobias Diez's user avatar
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11 votes

Hodge decomposition of smooth n-forms: is it an isomorphism of topological vector spaces?

Yes, the Hodge decomposition is a topological decomposition with respect to the $C^\infty$-topology. One can argue, for example, that the Laplace-Beltrami $\Delta$ operator is elliptic and hence can b …
Tobias Diez's user avatar
  • 5,824
8 votes
1 answer
501 views

Examples of topologies compatible with a given dual pair

Let $\langle X, Y \rangle$ be a pair of vector spaces put in duality by a non-degenerate bilinear form $\langle \cdot, \cdot \rangle: X \times Y \to \mathbb{R}$. A topology $\tau$ on $X$ is called com …
Tobias Diez's user avatar
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8 votes
Accepted

Smooth structure on the space of sections of a fiber bundle and gauge group

Your intuition is right. To endow the space of sections of a fiber bundle $F$ with a manifold structure at $\phi \in \Gamma^\infty(F)$ you consider a tubular neighborhood (respecting the fiber structu …
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7 votes
Accepted

Equivariant implicit function theorem

The equivariant version of the implicit function theorem is the following. Let $f: \mathbb{R}^p \times \mathbb{R}^n \to \mathbb{R}^m$ be a smooth function (possibly only defined on open neighborhoods …
Tobias Diez's user avatar
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7 votes
2 answers
624 views

Inverse of partial differential operator as a smooth tame map

Tameness for maps is one of the main ingredients for the Nash-Moser inverse function theorem. A linear map $f: X \to Y$ between Fŕechet spaces with fixed seminorms is called tame if we have an estima …
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7 votes

Functional approach vs jet approach to Lagrangian field theory

This is meant as a long comment to the very good answer by Pedro Ribeiro. There is a nice analog of the variational bicomplex in the functional framework. Namely, the space of differential forms on $M …
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6 votes

Smooth curves in a Frechet space

Yes, the spaces are isomorphic as Fréchet spaces. This is often called the exponential law and holds for every compact manifolds $M$ and $N$, $$C^\infty(M \times N) = C^\infty(M, C^\infty(N))$$ and as …
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5 votes
0 answers
140 views

Extension of elliptic complex to an exact sequence

This questions concerns elliptic complexes and is closely related to Green's operator of elliptic differential operator. Let $T_f:\Gamma(E)\rightarrow\Gamma(F)$ be an elliptic partial differential op …
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5 votes

Intuition for failure of Implicit Function theorem on Frechet Manifolds

As Henry T. Horton already pointed out, there exists a Fréchet version of the inverse function theorem. Therefore, the easiest way to get an intuition about what can go wrong with the classical Banach …
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4 votes

Topology on the dual of a Frechet space

This map is not smooth for every vector space topology on the dual space, see Remark I.3.9. in Neeb, K.-H. "Towards a Lie theory of locally convex groups" 2006 for an explicit counterexample. Thus t …
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