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43 votes
4 answers
4k views

A principle of mathematical induction for partially ordered sets with infima?

Recently I learned that there is a useful analogue of mathematical induction over $\mathbb{R}$ (more precisely, over intervals of the form $[a,\infty)$ or $[a,b]$). It turns out that this is an old ...
Pete L. Clark's user avatar
34 votes
3 answers
2k views

How much choice is needed to show that formally real fields can be ordered?

Background: a field is formally real if -1 is not a sum of squares of elements in that field. An ordering on a field is a linear ordering which is (in exactly the sense that you would guess if you ...
Pete L. Clark's user avatar
31 votes
3 answers
2k views

Is the fixed point property for posets preserved by products?

Recall that a partially ordered set (poset) $P$ has the fixed point property (FPP) if any order preserving function $f:P\longrightarrow P$ has a fixed point. Theorem. Suppose $P$ and $Q$ are posets ...
Mostafa Mirabi's user avatar
28 votes
1 answer
6k views

What is the cofinality of the co-infinite subsets of ${\bf N}$?

Let ${\mathcal A}$ be the family of subsets $A$ of the natural numbers ${\mathbf N}$ which are co-infinite (i.e., their complement is infinite). We partially order this family by set inclusion. A ...
Terry Tao's user avatar
  • 114k
24 votes
3 answers
2k views

Is it possible to construct an infinite subset of $\Bbb R$ that is not order isomorphic to any proper subset of itself?

Is it possible to construct an infinite subset of $\Bbb R$ that is not order isomorphic to any proper subset of itself?
Marty Colos's user avatar
24 votes
2 answers
1k views

Which are the rigid suborders of the real line?

Which are the rigid suborders of the real line? If A is any set of reals, then it can be viewed as an order structure itself under the induced order (A,<). The question is, when is this structure ...
Joel David Hamkins's user avatar
24 votes
1 answer
2k views

Why do we need "canonical" well orders?

(I asked this question on Math.SE earlier but received no response and am therefore moving it here, please note that I realise this question is probably incredibly naïve for the experienced set-...
Vivaan Daga's user avatar
23 votes
2 answers
670 views

Order type of the smallest set containing the identity function and closed under exponentiation

Let $E$ be the smallest set of functions $\mathbb{N}^+\to\mathbb{N}^+$ containing the identity function $n \mapsto n$ and closed under exponentiation $(f,g) \mapsto \left(n \mapsto f(n)^{g(n)}\right)$...
TauMu's user avatar
  • 872
20 votes
2 answers
1k views

An order type $\tau$ equal to its power $\tau^n, n>2$

(This is a re-post of my old unanswered question from Math.SE) For purposes of this question, let's concern ourselves only with linear (but not necessarily well-founded) order types. Recall that: $...
Vladimir Reshetnikov's user avatar
19 votes
1 answer
1k views

Suprema of directed sets

Let $(X, \le)$ be a partially ordered set. We call a subset $S \subseteq X$... ... a chain if each two elements in $S$ are comparable with respect to $\le$ (in other words, $S$ is linearly ordered ...
Jochen Glueck's user avatar
18 votes
2 answers
1k views

Can all $\aleph_2$-dense subsets of $\mathbb{R}$ be isomorphic?

Let $\kappa$ be an infinite cardinal. For a subset $A \subseteq \mathbb{R}$, we say that $A$ is $\kappa$-dense if $|A \cap (a, b)| = \kappa$ for every interval $(a, b)$. By Cantor, any two $\aleph_0$-...
Garrett Ervin's user avatar
17 votes
2 answers
338 views

Is it possible to reconstruct an order type from its initial segments?

Suppose $T$ is a totally ordered set without a maximal element, $\tau$ is the order type of $T$, $S$ is the set of order types of all proper initial segments (downward closed subsets) of $T$. Is it ...
Piotr Shatalin's user avatar
17 votes
1 answer
1k views

Has the exponentiation of ordinals a nice geometric model?

It is well known that the sum $\alpha+\beta$ of two ordinals $\alpha,\beta$ can be defined "geometrically" as the order type of the sum $(\{0\}\times \alpha)\cup(\{1\}\times\beta)$ endowed ...
Taras Banakh's user avatar
  • 41.8k
17 votes
1 answer
1k views

How is this fixed point theorem related to the axiom of choice?

I'm hoping the answer to this is well-known. Let $X$ be an ordered set (i.e. poset). An inflationary operator $f$ on $X$ is a function $f: X \to X$, not necessarily order-preserving, such that $f(x) \...
Tom Leinster's user avatar
  • 27.7k
16 votes
4 answers
4k views

Explicit ordering on set with larger cardinality than R

Is it possible to construct (without using Axoim of Choice) a totally ordered set S with cardinality larger than $\mathbb{R}$? Motivation: A total ordering is often called a “linear ordering”. I have ...
Sune Jakobsen's user avatar
16 votes
4 answers
1k views

Can Suslin (or Aronszajn) lines ever be orderings of abelian groups?

I am interested in realizing linear orders as orderings of abelian groups. In particular, can Suslin lines (and other classes of line) be realised in this way? Let $\mathcal{C}$ be a class of (...
Avshalom's user avatar
  • 2,111
16 votes
1 answer
2k views

totally ordered chain in the powerset with big cardinality

Let $B$ be some set. The problem is to find a set $A\subset\mathcal{P}(B)$ of subsets of $B$ which is totally ordered by inclusion and such that there exists a bijection $A\leftrightarrow \mathcal{P}(...
Toink's user avatar
  • 642
13 votes
2 answers
2k views

Ordinals that are not sets

The class of all ordinal numbers $\mathbf{Ord}$, aside being a proper class, can be thought of an ordinal number (of course it contains all ordinal numbers that are sets, not itself). Then one could ...
sdcvvc's user avatar
  • 918
13 votes
2 answers
690 views

How many subsets of $\mathbb{R}$ are order isomorphic to $\mathbb{Q}$?

How many subsets of $\mathbb{R}$ are order isomorphic to $\mathbb{Q}$? How many subsets of the long line $\omega_1\times[0,1)$ are order isomorphic to $\mathbb{Q}$? I can see that results in both ...
Hanna K.'s user avatar
  • 233
13 votes
1 answer
283 views

Can any poset of cardinality $\leq 2^{\aleph_0}$ be embedded in ${\cal P}(\omega)/(\text{fin})$?

We endow ${\cal P}(\omega)$ with an equivalence relation by saying that $A\simeq_{\text{fin}} B$ iff the symmetric difference $A\Delta B$ is finite. The resulting set of equivalence classes is denoted ...
Dominic van der Zypen's user avatar
12 votes
4 answers
1k views

Universal order type

Every countable order type, such as the countable ordinals, $\mathbb Z$, etc. can be embedded in $\mathbb Q$, so it is universal for countable order types. Is there a universal space for all linear ...
mathahada's user avatar
  • 656
12 votes
5 answers
1k views

Questions about ordering of reals and irrationals

Three problems from G.Rosenstein "Linear orderings" (from the end of Chapter 2 and beginning of Chapter 4): 1) Is there a nondecreasing function from irrationals onto reals? 2) Is there a ...
sdcvvc's user avatar
  • 918
12 votes
2 answers
677 views

What is the least ordinal than cannot be embedded in $\mathbb{R}^\mathbb{R}$?

Let $\mathbb{R}^\mathbb{R}$ be the set of functions $\mathbb{R}\to\mathbb{R}$ patially ordered by eventual domination. Obviously, every ordinal below $\omega_1$ can be embedded in $\mathbb{R}^\mathbb{...
TauMu's user avatar
  • 872
12 votes
1 answer
525 views

Is the Tukey order well-founded

Consider the Tukey order restricted to directed orders of the form $(U,\supseteq)$, where $U$ is an ultrafilter on $\omega$. It is defined as follows: For two ultrafilters $U,W$ on $\omega$, we say ...
Tom Benhamou's user avatar
12 votes
1 answer
443 views

Is each cover of the plane by lines minimizable?

A cover $\mathcal C$ of a set $X$ by subsets of $X$ is called $\bullet$ minimal if for every $C\in\mathcal C$ the family $\mathcal C\setminus\{C\}$ is not a cover of $X$; $\bullet$ minimizable if $\...
Taras Banakh's user avatar
  • 41.8k
11 votes
2 answers
682 views

On Applications of Forcing in Domain Theory

An interesting feature of domain theory is to use partial orders in order to provide a mathematical model for the computational approximation in a potentially infinite computational process (e.g. ...
Morteza Azad's user avatar
11 votes
1 answer
670 views

Do all toposes satisfy the internal Zorn's lemma?

I came up with this question when trying to give a more detailed answer to a question by Tim Campion in a comment to Ingo Blechschmidt's answer to Examples of statements that are valid in every ...
მამუკა ჯიბლაძე's user avatar
11 votes
1 answer
803 views

Is it known whether every $\omega$-tree with an infinite antichain has an infinite chain in $\mathsf{ZF}$?

In this paper by Good and Tree, the following result is mentioned without proof as part of Proposition 6.5: Each of the following statements imply those beneath it. The countable union of finite ...
Cameron Buie's user avatar
11 votes
1 answer
418 views

A monotone countably cofinal function from $\omega^\omega$ to $\omega^{\omega_1}$

For a set $X$ we endow the set $\omega^X$ of all functions from $X$ to $\omega$ with the natural partial order $\le$ defined by $f\le g$ iff $f(x)\le g(x)$ for all $x\in X$. A function $f:\omega^\...
Taras Banakh's user avatar
  • 41.8k
11 votes
0 answers
256 views

Existence of a strong antichain

Call an antichain (set of pairwise incomparable elements) $A$ of a poset $P$ strong if for every $p,q \in P$ with $p \leq q$ there exists an $a\in A$ which is comparable with both $p$ and $q$. ...
Attila Joó's user avatar
10 votes
4 answers
383 views

Universal poset for cardinals $\kappa \geq \aleph_0$

Given a cardinal $\kappa\geq \aleph_0$, is there a poset $(P,\leq)$ with $|P| = \kappa$ such that every poset of cardinality $\kappa$ can be order-embedded into $(P,\leq)$?
Dominic van der Zypen's user avatar
10 votes
2 answers
469 views

Do operations generate well-ordered sets only?

I've read   @TauMu's question   about the set of functions   $\mathbb N\rightarrow\mathbb N$   generated from the identity map by repeatedly applying exponentiation of two already ...
Włodzimierz Holsztyński's user avatar
10 votes
3 answers
265 views

Maximal chains in a quasi-order of linear order types

Let $\mathcal{T}_\kappa$ be the set of all linear order types of cardinality $\kappa$. Let $\prec$ denote a binary relation on $\mathcal{T}_\kappa$ representing embeddability of order types (note that ...
Oksana Gimmel's user avatar
10 votes
0 answers
381 views

Can one define in ZFC a directed system of embeddings on the class of all linear orders realizing the surreal line as the direct limit?

Consider the surreal line $\langle\newcommand\No{\text{No}}\No,\leq\rangle$, in its order structure only. This is a proper class linear order, which is universal for all set-sized linear orders, as ...
Joel David Hamkins's user avatar
9 votes
2 answers
1k views

Given a cardinal k, what's the biggest dense linear order with a dense subset of size k?

It's not hard to show that for any cardinal $\kappa$, there is no dense linear order without endpoints (DLO) of size greater than $2^{\kappa}$ that has a dense subset of size $\kappa$. But one can ...
Amit Kumar Gupta's user avatar
8 votes
2 answers
698 views

Order type of $\alpha$-computable well-orderings

One of the nice features of the first admissible ordinal after $\omega$, i.e. $\omega_1^{CK}$, is that it is the collection of ordinals whose order type is that of a computable well-ordering on $\...
Nate Ackerman's user avatar
8 votes
4 answers
630 views

closure of separative quotients

Does there exist a partial order, nontrivial for forcing, that is countably closed, but whose separative quotient is not countably closed? Supposing the answer is yes, then is there a partial order, ...
Norman Lewis Perlmutter's user avatar
8 votes
2 answers
205 views

Spaces without maximal homogeneous subspaces

A homogeneous space $(X,\tau)$ is a topological space such that for all $x,y\in X$ there is a homeomorphism $\varphi:X\to X$ such that $\varphi(x)=y$. As a previous question implies, the union of an ...
Dominic van der Zypen's user avatar
8 votes
2 answers
483 views

Posets obtained from a semigroup by the definition $x \leq y \iff x \cdot y = x$

A po-groupoid is a groupoid $\langle A,\cdot\rangle $ such that the relation defined by $$ x \leq y \text{ if and only if } x \cdot y = x $$ is a partial order on $A$, the order related to $\langle ...
Pedro Sánchez Terraf's user avatar
8 votes
1 answer
415 views

Decomposing posets into countably many chains

A conjecture of Galvin's is that the following is possible (which I take to mean that the consistency of the following can be proven relative to the consistency of something like ZFC, or ZFC plus some ...
Amit Kumar Gupta's user avatar
8 votes
1 answer
314 views

A strictly decreasing function between uncountable subsets of the reals

By a standard technique of inductive killing everything relevant (in this case decreasing homeomorphisms between uncountable $G_\delta$-subsets of the real line) it is possible to prove the following ...
Taras Banakh's user avatar
  • 41.8k
8 votes
0 answers
227 views

Is there a 'local' version of Near Coherence of Filters?

The axiom Near Coherence of Filters (NCF) is known to be independent of ZFC. Axiom (NCF I): For any two free ultrafilters $\mathcal D$ and $\mathcal E$ on $\mathbb N$, there exist finite-to-one ...
Daron's user avatar
  • 1,955
8 votes
0 answers
171 views

Can $Ded(\kappa)$ be a supremum?

Definition If there is a dense linear order w/o endpoints of size $\lambda$ with a dense subset of size $\kappa$ then write $D(\kappa,\lambda)$. $Ded(\kappa)=\sup_\lambda \{D(\kappa,\lambda)\}$. It ...
Ioannis Souldatos's user avatar
7 votes
3 answers
355 views

Extracting countable chains from linear orders

There is a well-known fact in infinite combinatorics asserting that for each infinite linear order $P$ there is a countable subset $R\subseteq P$ of order type either $\omega$ or $\omega^{*}$ (by $\...
Tomasz Kania's user avatar
  • 11.3k
7 votes
2 answers
344 views

Surjective order-preserving map $f:{\cal P}(X)\to \text{Part}(X)$

Let $X$ be a set, and let $\text{Part}(X)$ denote the collection of all partitions of $X$. For $A, B\in \text{Part}(X)$ we set $A\leq B$ if $A$ refines $B$, that is for all $a\in A$ there is $b\in B$ ...
Dominic van der Zypen's user avatar
7 votes
2 answers
496 views

Counterexample for Chvatal's conjecture in an infinite set

Let $X \neq \emptyset$ be a set. We say that ${\cal F} \subseteq {\cal P}(X)$ is a down-set if ${\cal F}$ is closed under taking subsets. Whenever $a \in X$, we let ${\cal F}_a = \{ S \in F : a \in S\}...
Dominic van der Zypen's user avatar
7 votes
1 answer
579 views

Progress on determining which partial orders embed into the rationals

The following result is relatively well-known: (for example in Math StackExchange answer #37161) For every countable linear order $(R,\prec)$, there is an $X\subseteq\mathbb Q$ such that $(R,\prec)$ ...
C7X's user avatar
  • 2,031
7 votes
2 answers
874 views

Which linearly ordered sets have the property that their completion is equipotent with their powerset?

As is well-known, ZFC proves the equipotency of $\mathbb{R}$ and $\mathcal{P}(\mathbb{Q}).$ Is there a nice characterization of those linearly ordered sets $L$ which, like $\mathbb{Q}$, have the ...
goblin GONE's user avatar
  • 3,793
7 votes
1 answer
278 views

Incomparable dense linear orderings extending $\langle \mathbb{R},< \rangle$

Where $a<b$, say that the four “types” of non-empty bounded intervals are: $(a,b)$, $[a,b]$, $(a,b]$, and $[a,b)$. Let $\langle X,< \rangle$ and $\langle Y,< \rangle$ be dense linear ...
Haidar's user avatar
  • 449
7 votes
1 answer
952 views

Strictly order preserving maps into the integers

If $P$ and $P'$ are partial orders, a strictly order preserving map from $P$ to $P'$ is an $f:P\to P'$ satisfying that $x\lt y$ implies $f(x)\lt f(y)$ for all $x,y\in P$. An interval in $P$ is a set ...
Andrés E. Caicedo's user avatar