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On surjections, idempotence and axiom of choice

The following assertion is trivial in ZFC, or even in much weaker theories. Is it also true in ZF? (I couldn't find it in the Consequences site so far.) If $A$ is an infinite set such that $A$ can ...
Asaf Karagila's user avatar
  • 39.8k
10 votes
2 answers
455 views

Is equivalence of functions built from nested exponentiations a decidable problem?

Let $\mathcal{E}$ be the minimal set of symbolic expressions (without any predefined meaning) such that The symbol $x$ is in $\mathcal{E}$, and If expressions $P,Q\in\mathcal{E}$, then the ...
Oksana Gimmel's user avatar
10 votes
1 answer
2k views

Generating family for the Lebesgue $\sigma$-algebra

Let $X$ be a set, and $\cal F$ a family of subsets of $X$, let $\Sigma(\cal F)$ denote the smallest $\sigma$-algebra containing $\cal F$. We can also define $\Sigma(\cal F)$ internally using a ...
Asaf Karagila's user avatar
  • 39.8k
10 votes
5 answers
2k views

The use of the word "model" in Mathematical Logic vs the same word in Natural Sciences [closed]

I have always been wondering why the term "model" is used by mathematicians (especially in mathematical logic) in a conceptually different (even opposite) way than it is used by other scientists, ...
Qfwfq's user avatar
  • 23.3k
10 votes
1 answer
2k views

Finite order arithmetic and ETCS

I'm looking for a reference to the statement that Lawvere's Elementary Theory of the Category of Sets (ETCS) is equal in proof-theoretic strength to finite order arithmetic. The person who informed ...
Tom Leinster's user avatar
  • 27.7k
10 votes
1 answer
3k views

Axiom of choice and non-measurable set

We know that existence of a Lebesgue non-measurable set follows from the Axiom Of Choice. Is the converse true? That is, does the existence of a Lebesgue non-measurable set imply the Axiom Of Choice?...
Prashant Singh's user avatar
10 votes
3 answers
1k views

Categoricity in second order logic

Hi, It's shown by an easy cardinality argument that there are complete second-order theories that are not categorical (have more than one model up to isomorphism). Anyone knows of a concrete example ...
Carlos Sáez's user avatar
10 votes
1 answer
462 views

Reverse mathematics of meromorphic functions on Riemann surfaces

Various sources touch briefly on the reverse mathematics of measure theory and complex analysis. But I have found none on the uniformization theorem for Riemann surfaces or the existence of non-...
Colin McLarty's user avatar
10 votes
2 answers
504 views

A totally categorical structure with trivial geometry which is not interpretable in the trivial structure

Among the theorems of early geometric model theory there is one by Lachlan stating that every totally categorical structure with a trivial pregeometry is intrepretable in a dense linear order. That ...
Dima Sustretov's user avatar
10 votes
3 answers
545 views

A model of CH +$\lnot \diamondsuit$

All of the models of CH which I know of also satisfy $\diamondsuit$. What is the easiest way to produce a model of CH wherein $\diamondsuit$ is false?
Rumpertumskin79's user avatar
10 votes
1 answer
440 views

Reference for a generalization of Γ-spaces to monoidal model categories

Γ-spaces were introduced by Segal in 1969 as models for what can be now described as commutative ∞-monoids and ∞-groups in cartesian symmetric monoidal ∞-categories, e.g., E_∞-spaces and connective ...
Dmitri Pavlov's user avatar
10 votes
2 answers
2k views

Scott on the consistency of the lambda calculus

I have twice heard it attributed to Dana Scott that he said something to the effect that the consistency of the lambda-calculus was an accident. Does anyone have a reasonable-sounding source for this?...
Charles Stewart's user avatar
10 votes
0 answers
314 views

How much do idempotent ultrafilters generate in terms of semigroups?

It is known that the set of ultrafilters on, say, the natural numbers $\mathbb{N}$, can naturally be endowed with the structure of a compact topological left semigroup (which fails to be anything ...
Jakub Konieczny's user avatar
10 votes
3 answers
1k views

Is set-induction relatively consistent?

One way to state the axiom of foundation is that the $\in$ relation on any transitive set is well-founded in the following sense: A relation $(X,\prec)$ is well-founded if for any subset $S\subseteq ...
Mike Shulman's user avatar
  • 66.8k
10 votes
2 answers
2k views

The egg and the chicken

After posting this question (in particular after Carl's and Peter's answers) I have realized that the answer seems to depend on a basic problem in foundations. Most mathematicians accept as given the ...
Andrea Ferretti's user avatar
10 votes
5 answers
1k views

On the notion of partial semigroup

A partial binary operation on a set $X$ is just a (partial) function $\varphi: X \times X \rightharpoonup X$ (I'm using \rightharpoonup for partial maps), and a partial magma is a pair $\mathbb M = (M,...
Salvo Tringali's user avatar
10 votes
0 answers
514 views

Existence of a regular subposet which collapses everything except the top cardinal

Suppose $\delta$ is an inaccessible cardinal, and $\mathbb{P}$ is the Levy Collapse $\text{Col}(\kappa, \delta)$ which adds a surjection from $\kappa \to \delta$ (for some regular $\kappa < \delta$)...
Sean Cox's user avatar
  • 2,231
9 votes
1 answer
649 views

Can $\mathbb{R}$ be partitioned into dedekind-finite sets?

Assuming $ZF$ itself is consistent, it is consistent that there are sets $D$ which are infinite but cannot be placed in bijection with any of their proper subsets; such sets are called "strictly ...
Noah Schweber's user avatar
9 votes
1 answer
698 views

Source for NBG+Equipollence conservative over ZFC?

The "conservative" class theory, NBG, proves no new theorems about sets (with respect to ZFC). The choice function used here is set choice, and it's not too hard to prove (if M is a ctm for ZFC, then ...
Richard Rast's user avatar
  • 1,979
9 votes
2 answers
1k views

What sort of structure can amorphous sets support?

Assuming the Axiom of Choice, every cardinal is either finite (i.e., an element of $\omega$) or Dedekind-infinite (i.e., in bijection with a proper subset of itself). This dichotomy is not true in ZF, ...
Noah Schweber's user avatar
9 votes
1 answer
496 views

Can two versions of $\omega_1^{CK}(\mathsf{Ord})$ ever coincide?

The goal of this question is to fill in the gap in this old answer of mine. For a transitive set $M$, thought of as an $\{\in\}$-structure, we define the following ordinals (this is not the notation ...
Noah Schweber's user avatar
9 votes
1 answer
336 views

How much can complexities of bases of a "simple" space vary?

Given a countable subbase of a topology, we can consider its complexity in terms of the difficulty of determining whether one family of basic open sets covers another basic open set. My question is ...
Noah Schweber's user avatar
9 votes
1 answer
634 views

Starting Hilbert's Program on the other end

The idea of Hilbert's program was to start with a simple finitary logic and proof the consistency of more complex systems in this system. Of course, this turned out to be problematic. Even when ...
Lucas K.'s user avatar
  • 1,659
9 votes
3 answers
1k views

First-order axiomatization of free groups

Is there a way to axiomatize [non-abelian] free groups in first-order logic using the language of groups (which contains the binary operation symbol $\cdot$, and the constant symbol $e$)? Is there ...
Asaf Karagila's user avatar
  • 39.8k
9 votes
1 answer
232 views

Elementary equivalence of monoidal categories =?

Recall that, in model theory, two models $M_1$ and $M_2$ of the same signature are elementary equivalent if $ M_1 \models \phi \Leftrightarrow M_2 \models \phi $ for every first order formula $\phi$ ...
André Henriques's user avatar
9 votes
1 answer
782 views

Can the first ordinal in which $V\neq HOD$ be $\aleph_\omega$?

Assume that $V\neq HOD$ and let $\kappa = \min \{\alpha\in On \mid \mathcal{P}(\alpha) \not\subseteq HOD\}$. Clearly, $\kappa$ is a cardinal. Question: Is it consistent that $\kappa = \aleph_\...
Yair Hayut's user avatar
  • 5,112
9 votes
2 answers
2k views

What is the free monoidal category generated by a monoid?

In several places in a segment on cohomology (for example, here (PDF)) in John Baez's online lecture notes for a course in 2007 on quantum gravity, much is made of the fact that the simplex category $...
ziggurism's user avatar
  • 1,446
9 votes
1 answer
552 views

"Towers" on singular cardinals with countable cofinality

Let $\lambda$ be a singular cardinal of countable cofinality. Is there necessarily a sequence $\{A_\alpha\mid\alpha<\lambda^+\}$ of countable subsets of $\lambda$, such that $\alpha<\beta$ if ...
Asaf Karagila's user avatar
  • 39.8k
9 votes
0 answers
256 views

A bi-modal logic related to determinacy

The short version of my question is as follows. There is a natural (I hope!) way to associate a bimodal theory to a game (two-player, perfect-information, length-$\omega$, on $\omega$); are there "...
Noah Schweber's user avatar
9 votes
9 answers
2k views

Existence of unknowable algorithms ?

Here by «algorithm» I mean a (halting) Turing machine with finite alphabet and memory. Is it possible to obtain by purely existential (i.e. non-constructive) means the existence of an algorithm ...
Loïc Teyssier's user avatar
9 votes
1 answer
470 views

Is there any o-minimal expansion of the real field with functions of growth higher than exponential?

Let $\bar{\mathbb{R}}$ be the structure of the real field, that is $(\mathbb{R},0,1,+,-,*,<)$ . We say that a function $f$ is of growth higher than exponential if for all $N\in \mathbb{N}$ there $f(...
Santiago's user avatar
  • 345
9 votes
1 answer
377 views

Is restricting Replacement and Separation enough to make $Q+I\Sigma_n$ bi-interpretable with Set Theory?

We have the result that $\mathsf{ZFCfin}$, the usual $\mathsf{ZFC}$ axioms with the axiom of infinity replaced by its negation, is bi-interpretable with $\mathsf{PA}$, first order Peano Arithmetic. We ...
Not_Here's user avatar
  • 482
9 votes
1 answer
489 views

Intuition behind Pincus' "injectively bounded statements"

In David Pincus, Zermelo-Fraenkel Consistency Results by Fraenkel-Mostowski Methods, The Journal of Symbolic Logic, Vol. 37, No. 4 (Dec., 1972), pp. 721-743 Pincus introduces the notion of ...
David Roberts's user avatar
  • 35.5k
9 votes
1 answer
765 views

Why relative consistency results by forcing arguments are provable in finitistic metatheory

It is claimed in many textbooks that relative consistency results, such as $\text{Con}(\text{ZFC})\rightarrow\text{Con}(\text{ZFC}+2^{\aleph_0}\geq\aleph_2)$, are provable in the finitistic metatheory....
Ruizhi Yang's user avatar
9 votes
1 answer
603 views

Substitutional modality

An informal definition of a logical truth is a sentence that's true in virtue of its form alone: $\phi$ is logically true iff all substitutions of $\phi$ that leave its logical vocabulary alone are ...
Andrew Bacon's user avatar
9 votes
1 answer
834 views

Axiom of class collection

One version of the Axiom of Collection says that any surjection $A\to B$ from a class $A$ to a set $B$ is factored through by some surjection $C\to B$ where $C$ is a set. Note that assuming $B$ is a ...
Mike Shulman's user avatar
  • 66.8k
9 votes
1 answer
749 views

Has Goedel's Second Incompleteness Theorem been proven using Lawvere's Fixed Point Theorem?

This question is a request for assistance in surveying the existing literature on applications of Lawvere's Fixed Point Theorem (LFPT). Yanofsky [0] has demonstrated several applications of LFPT to ...
jpt4's user avatar
  • 93
9 votes
0 answers
161 views

Number of tautologies of a given size?

Fix some complete set of $L$ logical connectives such as $\{ \wedge, \neg \}, \{\Rightarrow, \neg \}, \{\ \vee, \wedge, \neg \}, \{ \uparrow\}, \{\wedge, \vee, \neg, \Rightarrow \}$ - I'll assume all ...
Sprotte's user avatar
  • 1,075
9 votes
1 answer
341 views

Logics detecting their own equivalence notions, take two: $\mathcal{L}_{\omega_2,\omega}$

This question is a follow-up to another question of mine, with different language - see the link below. Say that an infinite regular cardinal $\kappa$ is Fraissean iff the logic $\mathcal{L}_{\kappa,\...
Noah Schweber's user avatar
9 votes
1 answer
559 views

Just a little absoluteness might be cheaper?

Absoluteness is a wonderful thing, but expensive consistency-strength wise. My question is, when can we get large amounts of absoluteness in specific situations for much cheaper? Specifically, fix a ...
Noah Schweber's user avatar
9 votes
1 answer
514 views

Is Heyting arithmetic sufficient to prove its own (formalized) existence property?

Let $\mathsf{HA}$ denote first-order Heyting arithmetic (viꝫ., Peano axioms with unrestricted recursion scheme, in first-order intuitionistic logic). It is known (e.g., Troelstra & van Dalen, ...
Gro-Tsen's user avatar
  • 32.5k
9 votes
2 answers
426 views

Can local $0^\#$ exists in L?

Assume $0^\#$ exists and there is an inaccessible cardinal. Are there two transitive sets $M,N$ s.t. $M\in N,M\vDash ZF+V=L[0^\#],N\vDash ZF+V=L$?
Reflecting_Ordinal's user avatar
9 votes
2 answers
844 views

Connection between the two-variable case of Hilbert's Tenth Problem and Roth's Theorem.

Connection between Hilbert's Tenth Problem and Roth's Theorem. The following two decision problems seem to be open: Given a polynomial equation in two variables with integer coefficients, determine ...
Sidney Raffer's user avatar
9 votes
4 answers
3k views

Incompleteness and nonstandard models of arithmetic

The following are a collection of doubts, some of which shall have concrete answers while others may have not. Any kind of help will be welcome. Reading Peter Smith's "Gödel Without (Too Many) Tears",...
Marc Alcobé García's user avatar
9 votes
1 answer
862 views

Harrington's unpublished note "The constructible reals can be anything"

Around 1974, Leo Harringto wrote an unpublished note entitled "The constructible reals can be anything", in which he proved that it is consistent that being $\Delta^1_n$ is the same as being ...
Mohammad Golshani's user avatar
9 votes
3 answers
2k views

What is the reverse mathematics of first-order logic and propositional logic?

Suppose one tries to formalize first-order logic. How much "strength" is required to do this? Strength can mean in various senses: The fragment of ZFC needed to codify first-order logic. Which ...
user avatar
9 votes
3 answers
1k views

Structure Theorem for finitely generated commutative cancellative monoids?

Is there a Structure Theorem for finitely generated commutative cancellative monoids? Of course they can be densely embedded into a finitely generated abelian group, whose structure is known. Also, ...
Martin Brandenburg's user avatar
9 votes
0 answers
243 views

Is this cardinal characteristic trivial? (Number of strategies needed to guarantee at least one win)

(Previously asked at MSE.) Let the determinacy number, $\mathfrak{g}$ (for "game"), be the smallest cardinal such that for every (two-player, perfect-information, length-$\omega$) game on $\...
Noah Schweber's user avatar
9 votes
1 answer
1k views

Definable set in ZF that cannot be proved to be Borel

Is there a predicate $P(x)$ such that $\mathrm{ZF} \vdash \exists! x. P(x)$, and $\mathrm{ZF} \vdash \forall x. P(x) \to (x \subseteq \mathbb R)$, but $\mathrm{ZF} \nvdash \forall x. P(x) \to \mathsf{...
Trebor's user avatar
  • 1,262
9 votes
0 answers
440 views

A new maximality principle and its consequences

Let us consider the following maximality principle: $(MP_*):$ For all uncountable regular cardinals $\kappa, 2^{<\kappa}=\kappa^{+}$ and all trees of height and size $\kappa$ are specialized. It ...
Mohammad Golshani's user avatar

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