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2 votes

Comparing the areas of polygons via equidecomposability in the hyperbolic plane

A proof is given in Example 8.10. of https://www.amazon.de/-/en/Johan-L-Dupont/dp/9810245084 . It is however not at all the elementary proof that you seem to be after. There is an exact sequence $$H_1 …
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8 votes
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Induced homeomorphism from a quasi-isometry between hyperbolic spaces

Properness is already needed to have a well-defined boundary at infinity, i.e., with a topology not depending on the chosen base point. This is Proposition III.3.7 in Bridson-Haefliger, which builds o …
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2 votes
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Maximally symmetric hyperbolic 3-manifolds with finite volume

Kojima has proved that every finite group occurs as the symmetry group of some compact hyperbolic 3-manifold. Hence there is nothing like a hyperbolic 3-manifold of maximal symmetry. The same result …
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7 votes
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Reconciling Sullivan's theorem with the hyperbolic structure of the Figure–8 knot complement

The statement is only true if you restrict to geometrically finite hyperbolic metrics (possibly of infinite volume) and ignore parabolic elements, which basically means that you ignore the boundary …
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4 votes
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Mostow rigidity for complex hyperbolic manifolds

The general statement of Mostow-Prasad rigidity cited from http://repository.ias.ac.in/36364/1/36364.pdf is as follows. Let $G$ (resp. $G^\prime$) be a semi-simple analytic group and $\Gamma$ (resp. …
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3 votes
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Conformal boundary and cusp of figure-8 complement

The group of parabolic isometries fixing a point at infinity is isomorphic to ${\mathbb C}$. (Because it acts simply transitively on a horosphere $H$.) The discrete group $\Gamma$ intersects this stab …
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1 vote
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Build a Fuchsian group starting from punctures on a disk

This is a very special case of the Fock-Goncharov construction. Divide your ideal n-gon into n-2 ideal triangles. Given one cross ratio associated to each edge (i.e., to the 4 ideal vertices of the …
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4 votes
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What is a half cusp in hyperbolic geometry?

This means that the boundary is geodesic with cusps in the marked points. The easiest example is a disk with 3 marked points on its boundary. In this case the hyperbolic metric is given by identifica …
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3 votes

What does it mean exactly for a pair of $S^0$'s to be unlinked on a knot $K$?

Think of $S^1$ as the ideal boundary of the hyperbolic plane, then every embedded $S^0\subset S^1$ determines a unique geodesic in the hyperbolic plane. The linking number of two embedded $S^0$s is de …
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10 votes
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Hyperbolic Volume and Chern-Simons

This is a Theorem of Yoshida, the reference is Yoshida, Tomoyoshi: ''The η-invariant of hyperbolic 3-manifolds.'' Invent. Math. 81, 473-514 (1985). http://mathlab.snu.ac.kr/~top/articles/Yoshida.pd …
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21 votes

Why are Fuchsian groups interesting?

About the relation to fractals: for Fuchsian groups of the first kind, the limit set has Hausdorff dimension 1, i.e., it is not fractal. However, for all other quasifuchsian groups of the first kind …
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6 votes

Intuition for Zagier's theorem for $\zeta_K(2)$

Too long for a comment and not sure whether this counts as a big picture, but anyway: There is a general formula for the covolume of S-arithmetic lattices in symmetric spaces, you find it in Prasad's …
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15 votes
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Failure of Mostow rigidity in dimension 2

ad (i): First consider a Dehn twist at some simple, closed curve in a closed hyperbolic surface. It is obviously a quasi-isometry (as any smooth map between closed surfaces) but not an isometry. Th …
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9 votes

Can the hyperbolic plane be immersed in three dimensional Euclidean space, if we are only lo...

Klotz Milnor proved in 1972 that there is no $C^2$ isometric embedding of $H^2$ in $R^3$ so Nash–Kuiper cannot be improved: Zbl 0236.53055. A practical realisation of an embedding is here: Crocheting …
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10 votes
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Geometrization & JSJ decomposition with boundary

The work of Jaco-Shalen and Johannson actually handles manifolds with boundary. The theorem they prove (in the language of Johannson's Book) is: An irreducible, boundary-irreducible 3-manifold with …
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