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Lie algebras are algebraic structures which were introduced to study the concept of infinitesimal transformations. The term "Lie algebra" (after Sophus Lie) was introduced by Hermann Weyl in the 1930s. In older texts, the name "infinitesimal group" is used. Related mathematical concepts include Lie groups and differentiable manifolds.

11 votes
1 answer
439 views

Lie subalgebras of $\chi^{\infty}(M)$ of codimension $n = \dim M$

For a connected $n$-manifold $M$, the Lie algebra of all smooth vector fields is denoted by $\chi^{\infty}(M)$. For a point $p\in M$ we define $L_{p}=\{X\in \chi^{\infty}(M)\mid X(p)=0\}$. Of course …
Ali Taghavi's user avatar
8 votes
2 answers
373 views

The minimum codimension of Lie subalgebra of $\chi^{\infty}(M)$

Assume that $M$ is an arbitrary manifold. Is there a Lie subalgebra of $\chi^{\infty}(M)$, the space of smooth vector fields on $M$, whose codimension is equal to one? If not, what is a counter …
Ali Taghavi's user avatar
7 votes
1 answer
848 views

The Hessian of invariant functions on a Lie group

Assume that $G$ is a Lie group with Lie algebra $\mathfrak{g}$. We fix an invariant Riemannian metric on $G$ and fix its corresponding $LC$ connection. Consider the natural right action of …
Ali Taghavi's user avatar
6 votes
1 answer
570 views

A vector space associated with a vector field on a symplectic manifold

$\DeclareMathOperator\Div{Div}$Edit: The correct formulation of the vector space $S(X)$ which is defined in this question is the following:$$S(X)=\{Y\in \chi^{\infty}(M)\mid X.\omega(X,Y)=(1 …
Ali Taghavi's user avatar
6 votes
1 answer
322 views

An extension of symplectomorphism group

$\DeclareMathOperator\GL{GL}\DeclareMathOperator\Sp{Sp}$Let $\omega=\sum dx_i\wedge dy_i$ be the standard symplectic structure of $\mathbb{R}^{2n}=\mathbb{R}^{n}\times \mathbb{R}^n$. We consider the …
Ali Taghavi's user avatar
5 votes
1 answer
110 views

Fredholm elements of a Lie algebra

An element $a$ of a Lie algebra $L$ is called a Fredholm element if the adjoint operator $\mathrm{ad}_a:L \to L$ is a Fredholm linear map. That is: its kernel is a finite-dimensional space and its ran …
Ali Taghavi's user avatar
5 votes
0 answers
371 views

A (possible) Lie algebra extension of the Lie algebra of a foliation

Motivation: The aim of this post is to extend the Lie algebra of a foliation to a bigger Lie algebra. We assume that a manifold $M$ is foliated by compat leaves. The Lie algebra of the foliation is th …
Ali Taghavi's user avatar
4 votes
1 answer
224 views

A Manifold for which $\chi^{\infty}(M)$ is rich

Is there a manifold $M$ for which $\chi^{\infty} (M)$, the lie algebra of smooth vector fields on $M$ contains all finite dimensional Lie algebras(Up to isomorphism)? A weaker question: Is there a …
Ali Taghavi's user avatar
4 votes
1 answer
284 views

A different Lie algebra structure on $\chi^{\infty}(\mathbb{R}^{2})$

In this question $\chi^{\infty}(\mathbb{R}^{2})$ or $\chi^{\infty}(S^{2})$ is the space of all smooth vector fields on the plane or sphere. A limit cycle for a vector field $X$ is an isolated closed …
Ali Taghavi's user avatar
4 votes
0 answers
330 views

The geometry of the holomorph of a Lie group

Every Lie group $G$ is naturally contained in its holomorph Hol($G$) = $G \rtimes $ Aut($G$) Is Hol$(G)$ always a Lie group? If the answer is yes our main questions: 1.For a left invariant metr …
Ali Taghavi's user avatar
3 votes
1 answer
265 views

Lie algebra of invariant polynomials or invariant smooth functions

Is there a symplectic structure on $M_{2n}(\mathbb{R})$, not necessarily with constant coefficients, such that the space of smooth invariant functions, those smooth functions $f:M_{2n}(\mathbb …
Ali Taghavi's user avatar
3 votes
1 answer
667 views

A particular embedding of a Lie group in Euclidean space

I apologize in advance if my question is elementary. Before I present my question I mention my motivation: Motivation: A Lie group is a manifold. At the same time it is a Riemannian manifold equippe …
Ali Taghavi's user avatar
3 votes
1 answer
363 views

When is the exterior derivation $d$ a Lie algebra morphism?

In this question we search for some conditions under which the exterior derivation $d:\Omega^i(M)\to \Omega^{i+1}(M)$ on a differentiable manifold $M$ is a Lie algebra morphism in a certain sense. We …
Ali Taghavi's user avatar
3 votes
1 answer
392 views

A particular Lie algebra $L_{n}$ and (various) lie groups whose Lie algebra is isomorphic to...

Edit: According to the comment by @LSpice we realise the existing link to the main motivation of the question is not available. Then we search for the paper we found the following version: https://www …
Ali Taghavi's user avatar
2 votes
1 answer
212 views

The centralizer of Lienard equation

Consider the lienard vector field $\cases{ x'=y -F(x) \\ y'=-x } $ in $\mathbb{R}^{2}$, where $F$ is a polynomial fuction with $F(0)=0$. Assume that $Y$ is a smooth vector field globally defined o …
Ali Taghavi's user avatar

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