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Complex analysis, holomorphic functions, automorphic group actions and forms, pseudoconvexity, complex geometry, analytic spaces, analytic sheaves.
37
votes
Does module Hom commute with tensor product in the second variable?
You can think about tensor products as a kind of colimit; you're asking the hom functor $\text{Hom}_A(L, -)$ to commute with this colimit in the second variable, but usually the hom functor only commu …
33
votes
Demystifying complex numbers
If the students have had a first course in differential equations, tell them to solve the system
$$x'(t) = -y(t)$$
$$y'(t) = x(t).$$
This is the equation of motion for a particle whose velocity vect …
30
votes
1
answer
2k
views
Which of the proofs of the fundamental theorem of algebra can actually produce bounds on whe...
One of the old classic MO questions is a big-list of proofs of the fundamental theorem of algebra. Here is a second big-list question about this big list:
Which of the FTA proofs can, even in prin …
23
votes
0
answers
651
views
Which proofs of the fundamental theorem of algebra are "essentially the same" vs. "essential...
The classic MO thread Ways to prove the fundamental theorem of algebra contains $60$ proofs of FTA, and I'm sure there are many more in the literature. It would be nice to have some way to organize th …
21
votes
Is this a rational function?
$\sum a_n z^n$ is a rational function iff $a_n$ is a sum of polynomials times exponentials. This is a straightforward corollary of partial fraction decomposition. So, suppose $\frac{1}{2^n - 1}$ can b …
20
votes
Accepted
Algebraic independence of shifts of the Riemann zeta function
$\zeta(s - z)$ has an Euler product $\prod_p \frac{1}{1 - p^{z-s}}$, and so a monomial $\prod_i \zeta(s - z_i)$ (with the $z_i$ not necessarily distinct) has an Euler product
$$\prod_i \zeta(s - z_i) …
17
votes
3
answers
2k
views
What is a reasonable finitary analogue of the statement that harmonic functions are smooth?
In my answer to this question on MU, I suggested that the OP think about the difference between real-differentiable and complex-differentiable functions by using a sort of finitary analogue. One way …
15
votes
Why do functions in complex analysis behave so well? (as opposed to functions in real analysis)
To expand on Dinakar's comment about boundary value problems, the physical intuition one should have here is that the real and complex parts of a complex differentiable functions are harmonic function …
13
votes
1
answer
859
views
What does the incidence algebra of the lattices in C tell us about modular forms?
I have two different and probably unrelated questions that can both be superficially described by the title, so I hope you'll forgive me if I ask them together. They both fall under the category of t …
12
votes
1
answer
2k
views
Wick rotation and the Riemann zeta function
The goal of this question is to conceptualize in some way the fact that the Riemann zeta function $\zeta(s)$, and other zeta functions like it, have analytic continuations.
Background
I have by now …
9
votes
What is $\sum (x+\mathbb{Z})^{-2}$?
As long as we're talking about the Weierstrass function, consider the parallels between the following:
1) Given a lattice $\Gamma$ in $\mathbb{R}$, the quotient $\mathbb{R}/\Gamma$ is topologically …
8
votes
1
answer
588
views
Defining holomorphic functions in terms of Banach algebras, and similarly for C*-algebras
Let $C$ be the category of commutative Banach algebras and let $U : C \to \text{Set}$ be the usual forgetful functor. The holomorphic functional calculus guarantees that every holomorphic function $f …
7
votes
1
answer
446
views
Reference for equivalent definitions of the genus
Let $X$ be a (edit: nonsingular) projective complex algebraic curve. The genus of $X$ can be defined as the dimension of the space of holomorphic $1$-forms on $X$, which in turn can be defined either …
7
votes
Spectra of elements of a Banach algebra and the role played by the Hahn-Banach Theorem.
I do not believe that the Hahn-Banach theorem is necessary. At some point I had planned on writing up a blog post verifying this but I lost the motivation...
The idea is that you can prove Liouville …
4
votes
Relationships between the roots of an entire function and the roots of its derivative
Let $f(x) = (1 - r_1 x)...(1 - r_n x)$ be a polynomial. Then $f(x) = 1 - e_1 x^1 + e_2 x^2 \mp ... $ where the $e_i$ are the elementary symmetric functions in the $r_i$. We define also $p_k = \sum_i …