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forcing, large cardinals, descriptive set theory, infinite combinatorics, cardinal characteristics, forcing axioms, ultrapowers, measures, reflection, pcf theory, models of set theory, axioms of set theory, independence, axiom of choice, continuum hypothesis, determinacy, Borel equivalence relations, Boolean-valued models, embeddings, orders, relations, transfinite recursion, set theory as a foundation of mathematics, the philosophy of set theory.

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Reference request: proof-theoretic strength of $\mathsf{KP}$ with recursively large ordinals and $\mathsf{CZF}$ with large set axioms

Large set axioms are notions corresponding to large cardinals on constructive set theories like $\mathsf{IZF}$ or $\mathsf{CZF}$. The notion of inaccessible sets, Mahlo sets, and 2-strong sets ...
Hanul Jeon's user avatar
  • 3,042
8 votes
2 answers
524 views

Analogues of worldly cardinals for (an unusual version of) second-order $\mathsf{ZFC}$

Let $\mathfrak{ZFC}(\mathsf{SOL})$ be the theory in second-order logic (with the standard semantics) gotten from $\mathsf{ZFC}$ by modifying the Separation and Replacement schemes to apply to ...
Noah Schweber's user avatar
8 votes
1 answer
1k views

Ill-founded models of set theory with well-founded ordinals

Let $(\mathcal{M},E)$ be an internally non-well-founded model of set theory i.e of $ZFC^{\neg f}=ZFC\setminus \mathrm{foundation}+\neg \mathrm{foundation}$, then $\mathcal{M}$ includes an infinite ...
Rahman. M's user avatar
  • 2,381
8 votes
1 answer
695 views

Edge chromatic number of hypergraphs

This is question Selection problem in a collection of non-empty sets with a simplification in criterion 3. Is there a set $X\neq\emptyset$ and a collection ${\cal F}\subseteq {\cal P}(X)\setminus\{\...
Dominic van der Zypen's user avatar
8 votes
1 answer
800 views

Covering compact Hausdorff spaces with closed $G_\delta$ sets

I'm thinking about results of the form: Under assumption $A$, if $X$ is a compact Hausdorff space and $C$ is a cover of $X$ by closed $G_\delta$ sets, then there is a subcover of cardinality $\leq\...
James E Hanson's user avatar
8 votes
1 answer
360 views

Models of ZFA corresponding exactly with a particular class of groups

I recently read [1], in which Blass exhibits a correspondence between: Permutation models of ZFA in which the axiom of choice (AC) fails but the Boolean prime ideal theorem (BPIT) holds; and ...
Clive Newstead's user avatar
8 votes
2 answers
635 views

Does the class category of ZF-algebras satisfy the Multiverse axioms?

I read with interest both Hamkins Multiverse Axioms and Joyal and Moerdijk's algebraic set theory. Both of these perspectives takes a set-theory universe as an object, and consider collections of set-...
user avatar
7 votes
1 answer
730 views

Do higher types in HoTT provide mathematical structures beyond ZFC?

I've been reading Andrej Bauer's blog post on "Univalent foundations subsume classical mathematics," which explains how Univalent Foundations and Homotopy Type Theory (HoTT) extend classical ...
Pan Mrož's user avatar
  • 441
7 votes
1 answer
254 views

What's the minimal weight of a maximal space?

A non-empty topological space without isolated points is called maximal if every finer topology on that space has at least an isolated point. The existence of a (Hausdorff) maximal space is a simple ...
Santi Spadaro's user avatar
7 votes
1 answer
491 views

"Robinson arithmetic" for (some) levels of $L$?

I'll write "$\mathcal{L}_\alpha$" for the fragment $\mathcal{L}_{\infty,\omega}\cap L_\alpha$. Say that a countable admissible $\alpha$ is Robinsonian if there is some sentence $\varphi\in\mathcal{L}...
Noah Schweber's user avatar
7 votes
2 answers
401 views

Definability of isomorphisms between class well-orderings

Inspired by this question, I've been trying to figure out for myself the basic properties of definable class well-orderings in transitive models $M$ of ZFC: What is $\omega_1^{CK}(\mathsf{Ord})$? ...
Elliot Glazer's user avatar
7 votes
1 answer
559 views

Proof of global Peano existence theorem in ZF?

By global Peano existence theorem I mean the existence of a maximal interval of solution of a first order ODE $x'=f(x,t)$ with continuous $f$. The proofs of the global Peano Theorem found in the ...
Mikhail Katz's user avatar
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7 votes
0 answers
269 views

Something like "o-minimal ordinal analysis"

Below, by "nice structure" I mean "o-minimal expansion of $(\mathbb{R};<)$ by countably many continuous functions and open relations." Suppose $\mathfrak{A}=(\mathbb{R};<,......
Noah Schweber's user avatar
7 votes
2 answers
1k views

Ordinal analysis and proofs of consistency

$\epsilon_0$ is the proof-theoretic ordinal of PA. Gentzen proved the consistency of Peano's first-order axioms for arithmetic using primitive recursive arithmetic and induction up to $\epsilon_0$. ...
John Baez's user avatar
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7 votes
2 answers
788 views

Why are stationary limits so ubiquitous when studying large cardinals?

While studying large cardinals, I have frequently noticed the following phenomenon: If X and Y are two different types of large cardinals, then every cardinal of type X is a stationary limit of ...
Anindya's user avatar
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7 votes
1 answer
436 views

Reference Request: Existence of Ordinal Rank Theory?

Notations: Recall that $\omega_1$ is the first uncountable ordinal. Let $X$ be a Polish space (completely metrizable and separable) and $F(X)$ be the collection of all real-valued functions on $X.$ ...
Idonknow's user avatar
  • 623
7 votes
2 answers
896 views

Iterated forcing and CH

I need some help with this theorem: if $P_\beta=\langle P_\alpha,\dot{Q}_\alpha:\alpha\leq\beta\rangle$, $\beta<\omega_2$, is a CSI of proper forcings, $P_\alpha\Vdash \lvert \dot{Q}_\alpha\rvert\...
Ruetta's user avatar
  • 71
7 votes
2 answers
665 views

Non-separable metric probability space

Let us say a metric probability space $(X,\rho,\mu)$ has property (*) if: the support of $\mu$ is contained in a separable subspace of $X$. Questions: 1. Is there a standard name for this property? ...
Aryeh Kontorovich's user avatar
7 votes
1 answer
948 views

Can every nonempty set carry abelian group structure? [duplicate]

Possible Duplicate: Does every non-empty set admit a group structure (in ZF)? Let $X$ be an arbitrary nonempty set. Can you define a multiplication making it into an abelian group? If $X$ is ...
Chris Heunen's user avatar
  • 3,937
7 votes
2 answers
683 views

Can second-order logic identify "amorphous satisfiability"?

Recall that a set is amorphous iff it is infinite but has no partition into two infinite subsets. I'm interested in the possible structure (in the sense of model theory) which an amorphous set can ...
Noah Schweber's user avatar
7 votes
1 answer
393 views

Models with fixed cardinality of non-Lebesgue measurable sets

In the usual $\mathsf{ZFC}$, we know that there are $2^\mathfrak{c}$ many subsets of $\mathbb{R}$ that are not (Lebesgue) measurable. On the other hand, the Solovay model also provides us a model of $\...
Clement Yung's user avatar
  • 1,442
7 votes
2 answers
722 views

Consistency of a strange (choice-wise) set of reals

Consider a set $X\subseteq \mathbb{R}$ such that $X$ is not separable wrt its subspace topology For all $r\in\mathbb{R}$ there exists a sequence $(x_n)_{n\in\omega} \subset X$ converging to $r$ In a ...
Lorenzo's user avatar
  • 2,286
7 votes
1 answer
287 views

Can $\Delta^{1}_{2}$ separate degrees of constructibility?

Suppose that $\phi(x)$ is a $\Delta^{1}_{2}$-formula (without parameters) and let $A:=\{x\subseteq\omega:\phi(x)\}$. It is clear that, e.g. if there are Cohen-generics over $L$, then $A$ cannot be the ...
M Carl's user avatar
  • 437
7 votes
1 answer
908 views

Symmetric extensions and class forcing

Suppose $V\models ZFC$ and $P\in V$ is a poset of forcing conditions. It is a basic theorem in forcing that $V[G]\models ZFC$ for any generic extension by a $V$-generic filter $G$. It is also known ...
Asaf Karagila's user avatar
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7 votes
1 answer
2k views

Least ordinal not in a countable transitive model of ZFC

Frequently it is useful do deal with countable transitive models M of ZFC, for example in forcing constructions. The notion of being an ordinal is absolute for any transitive model, so certainly if ...
Kiochi's user avatar
  • 884
7 votes
2 answers
490 views

$\mathfrak{c}$-universal linear order

I've been told once or twice that the following holds: There is a model of $ZFC+MA+\neg CH$ in which there is a $\mathfrak{c}$-universal linear order embedded in $(\omega^\omega, \le^\ast)$ ...
Not Mike's user avatar
  • 1,615
7 votes
2 answers
2k views

Non Lebesgue measurable subsets with "large" outer measure

It is well known that for any set A in R^d there exists a measurable set E such that E contains A and m*(A)=m*(E). Is it possible to go the other direction? In other words, is it true that for any ...
Haim's user avatar
  • 850
7 votes
2 answers
383 views

Infinite projective plane with small edges

Let $\kappa$ be an infinite cardinal. We say $E\subseteq {\cal P}(\kappa)$ is an infinite projective plane on $\kappa$ if $e_1\neq e_2\in E$ implies $|e_1\cap e_2| = 1$, and whenever $n\neq m\in \...
Dominic van der Zypen's user avatar
7 votes
1 answer
319 views

On a property possibly separating countable and not countable cardinals

The following question is inspired by Function with vector space , which has been closed for unknown reason and which may have a wellknown answer. Is the following true? Let $X$ be an uncountable set....
Dieter Kadelka's user avatar
7 votes
1 answer
621 views

Failure of Shoenfield's Absoluteness

Shoenfield's absoluteness states that if $M \subseteq N$ are models of $ZF$ and $M \supseteq \omega_1^N$, then every $\Sigma^1_2$ formula with parameters in $M$ is absolute between $M$ and $N$. In ...
Ohad Drucker's user avatar
7 votes
2 answers
735 views

For a partition of $\mathbb{R}$ into countably infinite sets, must there be an almost-disjoint family of $2^{\frak c}$ many selectors?

My question arises from a construction I gave in my recent answer to a question of Alexander Pruss concerning large families of independent non-measurable sets of reals. In that argument, using the ...
Joel David Hamkins's user avatar
7 votes
1 answer
924 views

Infinite graphs isomorphic to their line graph

The only finite connected graphs $G$ that are isomorphic to their line graph $L(G)$ are the cycle graphs $C_n$ (see this link for example). There are connected countable graphs that are isomorphic to ...
Dominic van der Zypen's user avatar
7 votes
1 answer
524 views

Destroying the Mahloness of a cardinal with $\kappa$.c.c. forcing

Question: Is it possible to have a Mahlo cardinal $\kappa$ such that there is a $\kappa$.c.c. forcing that makes it non-Mahlo? If this is possible then this forcing must change the cofinality of all ...
Yair Hayut's user avatar
  • 5,112
7 votes
1 answer
952 views

Strictly order preserving maps into the integers

If $P$ and $P'$ are partial orders, a strictly order preserving map from $P$ to $P'$ is an $f:P\to P'$ satisfying that $x\lt y$ implies $f(x)\lt f(y)$ for all $x,y\in P$. An interval in $P$ is a set ...
Andrés E. Caicedo's user avatar
7 votes
9 answers
7k views

Ultrainfinitism, or a step beyond the transfinite

Cantor has, in the immortal words of D. Hilbert, given all of us a paradise (or perhaps, I would rather say, a great vacation spot), the TRANSFINITE. $\aleph_0, \aleph_1,\aleph_2\dots$ the lists ...
Mirco A. Mannucci's user avatar
7 votes
1 answer
500 views

Elementary Embeddings and Relative Constructibility

Suppose $$j:M\prec N$$ is a non-trivial elementary embedding. Under what conditions on the sets (classes?) $M$ and $N$ (or even the critical point of $j$) does $j$ extend to an elementary embedding $$...
Everett Piper's user avatar
7 votes
5 answers
2k views

What axioms are stronger than the Axiom of choice?

What other axioms in set theory are stronger than AC ? I mean what are those axioms that will imply AC ?
user avatar
7 votes
1 answer
429 views

How many closed measure zero sets are needed to cover the real line, really?

This is a refinement of an earlier question. This question assumes familiarity with combinatorial cardinal characteristics of the continuum. For the reader's convenience, I reproduce below the ...
Boaz Tsaban's user avatar
  • 3,104
7 votes
1 answer
278 views

Incomparable dense linear orderings extending $\langle \mathbb{R},< \rangle$

Where $a<b$, say that the four “types” of non-empty bounded intervals are: $(a,b)$, $[a,b]$, $(a,b]$, and $[a,b)$. Let $\langle X,< \rangle$ and $\langle Y,< \rangle$ be dense linear ...
Haidar's user avatar
  • 449
7 votes
1 answer
540 views

Are larger large cardinals less expressible?

First note to the following well known theorems:‎‎ Theorem (1): ‎The ‎notion ‎of ‎"‎$‎‎x$ ‎is a strongly inaccessible cardinal‎" ‎is ‎first ‎order ‎expressible ‎and ‎‎$‎‎\Pi_{1}$‎. Theorem (2):‎‎ ‎...
user avatar
7 votes
2 answers
455 views

Ultrafilters preserved by $\mathbb{P}$ but not by products?

Let $U\in V$ be an ultrafilter on $\omega$. We say $U$ is preserved under forcing with $\mathbb{P}$ if $\Vdash \forall x\subset \omega \ \exists Z\in U \ Z\subset x \vee Z\subset x^c$. In other words,...
Jing Zhang's user avatar
  • 3,038
7 votes
1 answer
1k views

Cardinality of $\omega\uparrow^\omega\omega$

I was wondering what the cardinality of $\omega\uparrow^\omega\omega$ is, with $\uparrow$ being Knuth's up-arrow notation. I ask this purely out of curiosity; after finding out about set theory I feel ...
B H's user avatar
  • 397
7 votes
1 answer
324 views

Inaccessible becomes successor of singular

Is it possible, starting from any large cardinal assumption, to find a countably closed forcing $\mathbb{P}$ such that for some inaccessible $\kappa$, $\Vdash_\mathbb{P} "\kappa = \lambda^+$ and $\...
Monroe Eskew's user avatar
  • 18.6k
7 votes
1 answer
291 views

Reducing largeness notions, uniformly

This question is a particular take on the following theme. Suppose $A$ and $B$ are two notions of "large subset of $\omega^\omega$;" when is there a uniform method for turning an element of $...
Noah Schweber's user avatar
7 votes
1 answer
236 views

Does a continuous map from $\kappa^\omega$ to $[0,1]^\omega$ have a non-scattered fiber?

Question. Let $\kappa>\mathfrak c$ be a cardinal endowed with the discrete topology and $f:\kappa^\omega\to[0,1]^\omega$ be a continuous map. Is there a point $y\in[0,1]^\omega$ whose preimage $f^{-...
Taras Banakh's user avatar
  • 41.9k
7 votes
1 answer
306 views

On the cardinal arithmetic of accessible categories

If $\lambda, \mu$ are regular cardinals, say that $\lambda \trianglelefteq \mu$ if $\lambda \leq \mu$ and $$\forall X, \, |X| < \mu \implies \mathrm{cf} (P_\lambda(X)) < \mu$$ Here $P_\lambda(X)...
Tim Campion's user avatar
7 votes
2 answers
861 views

Which large cardinals are upward reflecting?

Let the first order formulas $p(x)$ and $wi(x)$ assert "$x$ is a large cardinal of type $p$" and "$x$ is weakly inaccessible" respectively. The large cardinal type $p$ is upward reflecting if $ZFC\...
user avatar
7 votes
0 answers
381 views

Why has Sacks' "Measure-theoretic uniformity" not been more influential?

In the 1969 paper "Measure-theoretic uniformity in recursion theory and set theory," Trans. Amer. Math. Soc. 142 1969 381–420, Sacks gave a measure-theoretic approach to several results previously ...
John Stillwell's user avatar
7 votes
1 answer
262 views

Different ways of making $HOD$ far from $V$

There are different criteria for building a model $V$ of $ZFC$ which is far from its $HOD$, for example: $(A)$ Cardinality criteria: For this in a joint work with James Cummings and Sy Friedman, we ...
Mohammad Golshani's user avatar
7 votes
1 answer
476 views

Under $\neg CH$, have countable unions of rationally independent numbers inner measure zero?

In their 1943 paper On non-denumerable graphs, Erdos and Kakutani suggest as likely the following proposition. (EK*) Suppose CH fails and $\lbrace M_n : n \in \omega \rbrace$ is a countable family of ...
Avshalom's user avatar
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