Skip to main content

All Questions

Filter by
Sorted by
Tagged with
4 votes
1 answer
135 views

Global splitting field for algebras

Let $A$ be a finite dimensional algebra. A field $K$ is a splitting field for an indecomposable $A$-module $M$ in case the local algebra $End_A(M)/(rad(End_A(M))$ is 1-dimensional. $K$ is called a ...
Mare's user avatar
  • 26.5k
6 votes
1 answer
203 views

Question on a subcategory being extension-closed

In the article "Homological theory of noetherian rings" by Idun Reiten from 1996, it was stated that it seems to be not known whether the subcategory $\operatorname{Tr}(\Omega^i(\mathrm{mod}\...
Mare's user avatar
  • 26.5k
6 votes
0 answers
182 views

On properties of an algebra as a bimodule

Let $A$ be a two-sided artinian ring. Recall that a module $M$ is said to have dominant dimension at least $n$ in case the terms $I_i$ in the minimal injective coresolution of $M$ are projective for $...
Mare's user avatar
  • 26.5k
2 votes
0 answers
98 views

Dimension of center of $k[G]/\mathrm{rad}k[G]$ when characteristic of $k$ divides the order of $G$

Let $G$ be a finite group and consider $k[G]$ where $k$ is a field. In the scenario where $\mathrm{char}(k)$ divides $|G|$, how can one show that the dimension of $Z(k[G]/\operatorname{rad}k[G])$ is ...
Sudarshan Narasimhan's user avatar
4 votes
0 answers
141 views

Frobenius algebras of small dimensions

In Classification of commutative Frobenius algebras , Jeremy Rickard showed that there are infinitely many commutative (local without loss of generality) Frobenius algebras of vector space dimension ...
Mare's user avatar
  • 26.5k
3 votes
1 answer
104 views

Irreducibility of product bicomodules

Let $H$ be a Hopf algebra, and $V$ and $W$ a left, and a right, $H$-comodule respectively. The tensor product $$ V \otimes W $$ has an obvious $H$-$H$-bicomodule structure. If $V$ and $W$ are ...
Jake Wetlock's user avatar
  • 1,144
2 votes
0 answers
110 views

Generalising injective modules

Free modules over a ring generalise to projective modules over a ring, which generalise to flat modules, which generalise to torsion free modules: $$ \textrm{free} \to \textrm{projective} \to \textrm{...
Todd Claymore's user avatar
3 votes
0 answers
56 views

Weakly symmetric rings and derived equivalences

A ring $R$ with Jacobson radical $J$ is called Frobenius in case $R/J \cong soc(R)$ as left and right $R$-modules and weakly symmetric in case we even have $R/J \cong soc(R)$ as $R$-bimodules. ...
Mare's user avatar
  • 26.5k
3 votes
0 answers
39 views

Positive roots of the Tits unit form and dimension vectors

Let $A$ be a finite dimensional quiver algebra such that two indecomposable modules are isomorphic iff their dimension vectors are the same. Let $T_A$ be the tits unit form of $A$ and $r_A$ the set of ...
Mare's user avatar
  • 26.5k
3 votes
1 answer
98 views

On algebras where indecomposable modules are determined by their dimension vectors

Let $A$ be a finite dimensional quiver algebra such that any two indecomposable modules with the same dimension vector are isomorphic. Question: In case $A$ has $n$ simple modules and finite global ...
Mare's user avatar
  • 26.5k
1 vote
1 answer
178 views

Representation of algebras as bounded nilpotent operators

Let $A$ be a real/complex algebra (just a real/complex vector space with a multiplication; none PI's are required). Let $\mathcal{H}$ be a real/complex Hilbert space. Let $\operatorname{B}(\mathcal{H})...
Math-Phys-Cat Group's user avatar
3 votes
0 answers
173 views

Comparing zeroth Hochschild homology and cohomology for algebras

Let $A$ be a finite dimensional algebra and $[A,A]$ its commutator and $Z(A)$ its center. Question 1: Do we have $dim(A/[A,A]) \geq dim(Z(A))$? Note that A/[A,A] is the zeroth Hochschild homology ...
Mare's user avatar
  • 26.5k
6 votes
0 answers
57 views

A characterisation of weakly symmetric algebras

A finite dimensional algebra $A$ over a field $K$ is called a Frobenius algebra in case there exists a $K$-linear map $f: A \rightarrow K$ such that $ker(f)$ contains no non-zero right ideal of $A$ (...
Mare's user avatar
  • 26.5k
2 votes
1 answer
196 views

Weight space dimension of the fundamental representation $\pi_n$ for type $C_n$

Will the fundamental representation $\pi_n$ of type $C_n$, for $n > 3$, have weight spaces of dimension greater than $1$? Is there some online resource where weight space multiplicities can be ...
Fofi Konstantopoulou's user avatar
3 votes
0 answers
138 views

Meaning of an algebra having "sufficiently many primitive idempotents"?

This is a phrase Ringel uses a few times in his writing, and I'm not sure exactly what he means by it. The context is that we have a quiver $Q$ with path algebra $\mathbf{k}Q$. If $Q$ is not a finite ...
Mike Pierce's user avatar
  • 1,161
2 votes
1 answer
250 views

Example of a projective bimodule with isomorphic left and right duals

What is an example of a non-free finitely generated $R$-bimodule $M$ satisfying i) $M$ is projective as both a left and right $R$-module ii) the right dual $\mathrm{Hom}_R(M,R)$ and the left dual ...
Fofi Konstantopoulou's user avatar
3 votes
1 answer
244 views

Left module which cannot be made into a bimodule?

Let $A$ be a noncommutative unital algebra, defined over $\mathbb{C}$ say. What is an example of a left $A$-module $M$ that does not admit a right $A$-module structure giving $M$ the structure of a ...
Fofi Konstantopoulou's user avatar
3 votes
2 answers
1k views

Dual of a projective module

Let $R$ be a noncommutative ring with unit, let $P$ be a projective left $R$-module, and denote $^{\vee}\!P := \,_R\mathrm{Hom}(P,R)$. One often sees it written that projectivity implies an ...
Fofi Konstantopoulou's user avatar
5 votes
1 answer
224 views

Convolution algebra associated to a finite dimensional algebra

Given a finite dimensional $k$-algebra $A$ (we can assume it is given by a connected quiver with relations). One can form its trivial extension $T(A)$ (see for example https://math.stackexchange.com/...
Mare's user avatar
  • 26.5k
5 votes
1 answer
704 views

Representations of tensor products of algebras

For two associative unital algebras $A$ and $B$, defined over $\mathbb{K} = \mathbb{R}, \mathbb{C}$, is it possible to have an irreducible representation of $A \otimes_{\mathbb{K}}B$ which is not of ...
Max Schattman's user avatar
6 votes
1 answer
339 views

Monoidal categories from the projective modules of a ring

Let $R$ be a not necessarily commutative ring, and denote by $_R\mathrm{lp}_R$ the category of $R$-bimodules, which are finitely generated projective as left modules, with morphism $R$-bimodule maps, ...
Max Schattman's user avatar
2 votes
1 answer
98 views

A weaker version of strongly graded algebras

Let $A = \oplus_{i \in \mathbb{Z}} A_i$ be a graded algebra. We say that it is strongly graded if $A_i.A_j = A_{i+j}$, for all $i,j \in \mathbb{Z}$. Can there be existing a graded algebra such that $$...
Fofi Konstantopoulou's user avatar
5 votes
2 answers
680 views

Characters on Hopf algebras

For any algebra $A$, a character for $A$ is a non-zero algebra map $c:A \to \mathbb{C}$. For $H$ be a Hopf algebra, a character is given by $\epsilon:H \to \mathbb{C}$ the counit of $H$. I am looking ...
Fofi Konstantopoulou's user avatar
4 votes
1 answer
375 views

Invertible bimodules and projectivity

Let $A$ be a noncommutative algebra over a field, say $\mathbb{C}$ or $\mathbb{R}$, and let $L$ be a bimodule over $A$. If $L$ is invertible, that is, if the dual right $A$-module $L^*$ satisfies $$ L^...
Rodrigo Alfonso de la Paz's user avatar
3 votes
1 answer
313 views

indecomposable modules of gentle algebras

Let $A = \mathcal{k}Q/I$ be a gentle algebra (where $\mathcal{k}$ is algebraically closed). In the paper Auslander-Reiten Sequences with Few Middle Terms and Application to String Algebras, Butler and ...
Hui Yu's user avatar
  • 31
8 votes
2 answers
498 views

Left-right non-bimodule examples

Let $A$ be a unital algebra, defined over the complex numbers. Any bimodule $M$ over $A$ must, by definition, be a left, and right, module satisfing $$ a.(m.b) = (a.m).b, ~~~~~~~ \textrm{ for all } a,...
Rodrigo Alfonso de la Paz's user avatar
4 votes
1 answer
175 views

Group representation with algebra structure

I haven't seen this question in standard textbooks, so I decide to give it a try here. It might relate to deeper structures of certain TQFTs, but I'm not sure. Let $G$ be a finite group. Its finite-...
Student's user avatar
  • 5,230
2 votes
0 answers
72 views

injective map between tensor products of two irreducible modules of simple Lie algebra sl_{n+1}

Let $1 \leq i_1 < i_2 < i_3 \leq n$. I know that there is an injective map from $V(\omega_{i_1}+\omega_{{i_2} -1})\otimes V(\omega_{{i_3}+1})$ to $V(\omega_{i_1}+\omega_{i_2})\otimes V(\omega_{...
Rekha Biswal's user avatar
6 votes
2 answers
358 views

Duals of the spinor representations of $\frak{so}_{2n}$

For the $D_n$-series simple Lie algebra $\frak{so}_{2n}$ a curious phenomenon occurs for the fundamental representations corresponding to the spinor nodes of the Dynkin diagram, which is to say the ...
Rodrigo Alfonso de la Paz's user avatar
2 votes
1 answer
211 views

Choice of a ground ring for cluster algebras

In order to define cluster algebra one needs to define its ground ring. In most cases, we take a group $P$ (often called a coefficient group) which is taken to be an abelian multiplicative group . ...
amator2357's user avatar
4 votes
2 answers
360 views

Double centralizer in special linear algebra

It is well known that for a matrix $A$ in $\mathfrak{sl}_n(\mathbb{C})$, we have the following equivalence: $$\dim Z(A) \text{ is minimal} \leftrightarrow A \text{ is cyclic}$$ where $Z(A)$ is the ...
AThomas's user avatar
  • 617
6 votes
0 answers
259 views

Diameter of finite rational matrix groups

Suppose $G$ is a finite subgroup of $\mathrm{GL}(n,\mathbb{Q})$. For a set $\mathcal{M} \subseteq G$ that generates $G$, define the $\mathcal{M}$-diameter $\mathit{diam}(G, \mathcal{M})$ of $G$ to be ...
Stefan Kiefer's user avatar
6 votes
2 answers
501 views

Complete reducibility and field extension

Let $\pi$ be a representation of a Lie algebra $L$ in a finite-dimensional linear space $V$ over the field $F$. Let $K$ be a field extension of $F$. Let $\pi_K=\pi\otimes K$ be the corresponding ...
liorz's user avatar
  • 71
4 votes
1 answer
520 views

List of Casimir elements of low dimensional Lie algebras

I am interested in explicit formulae for the Casimir elements (or "Casimir operators") of low-dimensional, real, non-Abelian Lie algebras (d=2,3, and possibly 4). I am wondering if there is any ...
Aureliano Tinajero's user avatar
5 votes
0 answers
140 views

Open problems about Morita and derived invariants

Are there properties of rings of which one does not know whether they are Morita or derived invariances? For a recent such example for Morita invariance, see https://www.sciencedirect.com/science/...
Mare's user avatar
  • 26.5k
13 votes
3 answers
2k views

Classification of commutative Frobenius algebras

Are there attempts to classify commutative finite dimensional Frobenius algebras? They appear often in mathematics, such as in algebraic geometry and the famous category equivalence between ...
Mare's user avatar
  • 26.5k
5 votes
1 answer
175 views

Ideals of commutative Frobenius algebras

Given a finite dimensional commutative (connected=local) Frobenius algebra $A$ over a field $K$. Question 1: Does $A$ have only finitely many ideals? (the answer should be no in the non-commutative ...
Mare's user avatar
  • 26.5k
2 votes
1 answer
143 views

A weak Schur's lemma for non-semisimple finite dimensional algebras

Let $B \subseteq C$ be an inclusion of finite dimensional (associative) algebras over a field $k$. Assume that $C$ is a free $B$-module. Let $\bigoplus_i U_i$ be a decomposition of $B$ into ...
Sebastien Palcoux's user avatar
5 votes
1 answer
256 views

Definition of a Dirac operator

So it seems that a Dirac operator acting on spinors on $\psi=\psi(\mathfrak{su}(2),\mathbb{C}^2)$ can be written in this case simply as: $D=\sum_{i,j} E_{ij}\otimes e_{ji}$, where $E_{ij}$ are ...
CristinaSardon's user avatar
7 votes
1 answer
370 views

Gorenstein symmetric conjecture for arbitrary rings

The Gorenstein symmetric conjecture states that for Artin algebras $A$ one has the the regular module has finite injective dimension as a right module if and only if it has finite injective dimension ...
Mare's user avatar
  • 26.5k
3 votes
1 answer
102 views

Algorithms for the explicit matrix isomorphism problem over $\mathbb{C}$

Suppose that $A$ is a $d^2$ dimensional algebra over $\mathbb{C}$ and we know the multiplication tensor $c_{ij}^k$ and the unit $u^k$ in some basis. If $A$ is semi-simple and has a single simple ...
Daniel Barter's user avatar
4 votes
0 answers
153 views

Recovering the bimodule from the trivial extension

Given a ring $S$ with a non-zero $S$-bimodule $M$, the trivial extension of $(S,M)$ is defined as the ring $R:=T_M(S)$ with $R= S \oplus M$ with multiplication $(s,m)(s',m')=(s s', sm' +m s')$. We ...
Mare's user avatar
  • 26.5k
3 votes
0 answers
134 views

Proving that the exterior algebra is symmetric via the polynomial ring

Recall that a finite dimensional algebra $A$ over a field $K$ is called Frobenius in case $A \cong D(A)$ as right modules, and it is called symmetric in case $A \cong D(A)$ as bimodules (where $D=...
Mare's user avatar
  • 26.5k
12 votes
1 answer
922 views

Does this algebra have finite global dimension ? (Human vs computer)

Usually computers can calculate the global dimension of a finite dimensional quiver algebra much faster than humans. But in this case a high end computer (calculating for 3 weeks) was not able to ...
Mare's user avatar
  • 26.5k
4 votes
1 answer
215 views

Explicit examples of finite dimensional, involutive Hopf algebras with traceless antipode?

$\require{AMScd}$ In the paper [1], it is shown that there exist finite dimensional, semisimple Hopf algebras $H$ where the antipode $S:H \to H$ is traceless. Unfortunately, the method of proof in [...
Julian Chaidez's user avatar
5 votes
1 answer
1k views

$Hom_G(C_c^{\infty}(G),\pi)\cong Hom_{\mathbb{C}}(\pi^{\vee},\mathbb{C}) ?$

$G$ is an p-adic group, and $\pi$ is an irreducible representation of $G$, then do we naturally have $Hom_G(C_c^{\infty}(G),\pi)\cong Hom_{\mathbb{C}}(\pi^{\vee},\mathbb{C})$? I think it is true, but ...
Cooler Panda's user avatar
1 vote
0 answers
71 views

tensor product of two compact induced representations

Suppose $A \subset A^{\prime}$ and $B \subset B^{\prime}$ are all p-adic groups, and $V_{\pi}$ is a representation of $A$; $V_{\rho}$ is a representation of $B$. Define $ind_{A}^{A^{\prime}}V_{\pi}...
Cooler Panda's user avatar
7 votes
2 answers
450 views

Ideals invariant under ring automorphisms

I am looking for ideals $I\subset \mathbb{F}_2[x,y]$ with the following properties: $I$ is generated by two homogeneous elements; $I$ is invariant under the $SL_2(\mathbb{F}_2)$-action on $\mathbb{F}...
HenrikRüping's user avatar
4 votes
2 answers
453 views

Global dimension of the tensor algebra

Let $R$ be a semisimple ring with a non-zero $R$-bimodule V. Let $T_R(V):= \bigoplus\limits_{k=0}^{\infty}{V^{\otimes_k}}$ be the tensor algebra of $V$. Question 1: Is there a simple proof that $...
Mare's user avatar
  • 26.5k
4 votes
1 answer
463 views

Global dimension of a graded algebra

Let $A= \bigoplus\limits_{n=0}^{\infty}{A_n}$ be an $\mathbb{N}$-graded algebra with semisimple $A_0$. Question: Do we have that the global dimension of $A$ is equal to $\sup \{i \geq 0 | Ext_A^i(...
Mare's user avatar
  • 26.5k

1 2 3
4
5
9