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Is $N_\phi = \{x \in E: \phi(\langle x,x\rangle)=0\}$ a Hilbert submodule of $E$?

Let $E$ be a (right) Hilbert module over the $C^*$-algebra $B$. Let $\phi$ be a state on the $C^*$-algebra $B$. Then consider $$N_\phi:= \{x \in E: \phi(\langle x,x\rangle)=0\}.$$ I want to show that $...
Andromeda's user avatar
  • 175
4 votes
1 answer
332 views

Normal linear functionals on bicommutants of C*-algebras

I am going through the proof of the Sherman-Takeda theorem and Fillmore's book "A User's Guide on Operator Algebras" seems to have a nice approach, but something seems off to me: We need to ...
Just dropped in's user avatar
3 votes
2 answers
606 views

Is the algebra of compact operators flat?

Suppose that $A\hookrightarrow B$ is an inclusion of $C^*$-algebras and let $K$ be the algebra of compact operators on a separable Hilbert space. Is it true that the map $A\otimes K\hookrightarrow B\...
Less's user avatar
  • 51
5 votes
1 answer
303 views

Non-unital Russo-Dye Theorem

Let $A$ be a C$^*$-algebra and let $\phi$ be a positive linear map from $A$ to $B(H)$ (bounded linear operators on Hilbert's space). If $A$ is unital, then the Russo-Dye Theorem implies that $\|\phi\...
Black's user avatar
  • 483
1 vote
1 answer
118 views

Let $V$ be a TRO such that $A(V)= \mathbb{C}$, what can we say about $V$?

Let $V$ be a TRO i.e. closed subspace of $B(H,K)$ such that $xy^*z \in V$ for all $x,y,z \in V$. Let $C(V)$ and $D(V)$ denotes the $C^{\ast}$-algebra generated by $VV^{\ast}$ and $V^*V$ respectively. ...
Math Lover's user avatar
  • 1,115
3 votes
0 answers
160 views

Construct a non-unital nuclear $C^*$-algebra without tracial states such that its multiplier algebra is also traceless

Let $H$ be an infinite dimensional separable Hilbert space. The set $K(H)$ of all compact operators is a non-unital nuclear $C^*$-algebra which has no tracial states and the multiplier algebra of $K(...
math112358's user avatar
2 votes
1 answer
448 views

The maximal tensor product is a continuous functor

I am trying to prove continuity of the maximal tensor product functor. I have a problem in the proof that I cannot see how to handle; If anyone could give me a clue on how to go on from here, I would ...
Just dropped in's user avatar
2 votes
1 answer
316 views

Decomposition of Hilbert spaces via groups and algebras representations

Let $\mathcal{H}$ be a complex finite dimensional Hilbert space and let $\mathcal{A}\subseteq \mathcal{B}(\mathcal{H})$. I am looking to understand the different decompositions of $\mathcal{H}$ ...
vand's user avatar
  • 23
5 votes
1 answer
202 views

Relating different constructions of the universal compact quantum group

Before asking my question, let me give the necessary background. Readers that are comfortable with the language of universal and reduced compact quantum groups may skip the following two sections. ...
user avatar
25 votes
2 answers
1k views

Can nuclearity be determined by tensoring with a single C*-algebra?

A C*-algebra is nuclear if the algebraic tensor product $A\odot B$ ($B$ is any other C*-algebra) admits a unique C*-norm. This definition requires testing the condition for nuclearity with `all' C*-...
Lech Roch's user avatar
  • 505
2 votes
1 answer
352 views

K-Theory of $C^{*}(X)$

I'm new to K-Theory for $C^{*}$-algebra and $C^{*}$-algebra of groups. If $X$ is the group of finite support bijections of natural numbers then what is the K-Theory of $C^{*}(X)$? I was planning to ...
Peg Leg Jonathan's user avatar
4 votes
0 answers
126 views

Can the injective envelope ever be injective for $*$-homomorphisms?

The answers to the question "Is the injective envelope functorial" resoundingly remind us that the injective envelope of a C$^*$-algebra really belongs in the category of completely positive ...
Chris Ramsey's user avatar
  • 3,984
7 votes
1 answer
479 views

Characterisation of finite dimensional C*-algebras?

$\DeclareMathOperator\Spec{Spec}$Let $A$ be a finite dimensional $*$-algebra over $\mathbb C$. (Namely, an associate algebra equipped with an involution $*:A\to A$ satisfying $(ab)^*=b^*a^*$ and $(\...
André Henriques's user avatar
-1 votes
1 answer
246 views

Density of normal elements in a C*- algebra [closed]

Let $A$ be a unital C*-algebra. I wanted to know if there is a necessary and sufficient condition for normal elements to be dense in $A$?
user531706's user avatar
4 votes
1 answer
152 views

$\tau (p) = \tau (q)$ for all normalized traces does not imply $p \sim q$

Could you give an example of a unital simple $C^*$-algebra that $\tau (p) = \tau (q)$ for all normalized traces does not imply $p \sim q$?
Peg Leg Jonathan's user avatar
2 votes
0 answers
141 views

Is it true that $\varinjlim A_n^{**}=(\varinjlim A_n)^{**}$?

Let $(A_n, \phi_n)$ be an inductive system of $C^*$ algebras. It's well known double dual of $C^*$-algebra is again a $C^*$ algebra. Is it true that $\varinjlim A_n^{**}=(\varinjlim A_n)^{**}$ Can ...
Math Lover's user avatar
  • 1,115
3 votes
0 answers
179 views

Stinespring's theorem: can we choose the dilation to be an isometry?

Let $A$ be a $C^*$-algebra and $\varphi: A \to B(H)$ be a completely positive contractive map. Stinespring's theorem says that there exists a $*$-representation $\pi: A \to B(H')$ and a bounded ...
Andromeda's user avatar
  • 175
0 votes
1 answer
158 views

Abelian twisted reduced group C*-algebra

Let $G$ be an abelian discrete group. Then is $C_r^*(G, \sigma)$ abelian?
Peg Leg Jonathan's user avatar
9 votes
1 answer
237 views

A non nuclear $C^*$ algebra $A$ for which the algebraic tensor product $A\otimes A$ admits a unique $C^*$ norm

Is there a non nuclear $C^*$ algebra $A$ for which the minimum and maximum $C^*$ norms on $A\otimes A$ coincide? A somewhat similar question is discussed here.
Ali Taghavi's user avatar
0 votes
1 answer
163 views

Regarding socle of a C* algebra

I wanted to know if the socle of a complex C*-algebra is essential? Can anyone suggest a text where the socle is studied in detail. I tried reading it from the book by Bernard Aupetit, A Primer in ...
user531706's user avatar
3 votes
1 answer
451 views

On equation $e^{xy-yx}=e^xe^ye^{-x}e^{-y}$ in $C^*$ algebras

Inspired by this MSE question we ask the following question: Is there a noncommutative $C^*$-algebra $A$ for which the following identity holds for all $x,y \in A$? $$e^{(xy-yx)}= e^xe^y e^{-x}e^{-...
Ali Taghavi's user avatar
0 votes
0 answers
119 views

Subalgebras of $B(H)$ consisting of all operators leaving a given finite dimensional space invariant

Let $H$ be an infinite dimensional separable Hilbert space. Let $V$ be a finite dimensional subspace of $H$. Put $$A=\{T\in B(H)\mid T(V)\subseteq V\}.$$ So $A$ is a Banach algebra. Can we equip $A$ ...
Ali Taghavi's user avatar
5 votes
0 answers
136 views

C^*-algebra theory with all the Koszul signs

I was wondering if someone knows of a reference in which $\mathbb{Z}_2$-graded $C^*$-algebra theory is developed using the sign convention $(ab)^* = (-1)^{|a||b|}b^* a^*$. I would be most enthusiastic ...
Luuk Stehouwer's user avatar
1 vote
0 answers
57 views

Is the universal representation an order isomorphism?

Let $A$ be a Banach *-algebra. By a *-representations of $A$, we mean a *-homomorphism $\pi:A\to B(H_\pi)$, where $B(H_\pi)$ is the space of all bounded linear maps on a Hilbert space $H_\pi$. Let $\...
ABB's user avatar
  • 4,058
4 votes
1 answer
510 views

Strict topology and $*$-strong toppology on $B(H)$ coincide

In the paper Woronowicz - $C^*$-algebras generated by unbounded elements, I read that the $*$-strong operator topology on $B(H)$ and the strict topology on $B(H)$ coincide. I believe this means the ...
user avatar
6 votes
1 answer
623 views

Is the conditional expectation faithful?

Let $G$ be a locally compact group and let $H$ be an open subgroup in $G$. Then the full group $C^*$-algebra of $H$, $C^*(H)$, is a subalgebra of $C^*(G)$ and there is a conditional expectation $$E\...
Sabrina Gemsa's user avatar
2 votes
1 answer
452 views

Uniqueness of the direct sum of $C^*$ algebras as quotient of free products

Suppose that you have $A, B$ two unital $C^*$ algebras and let $A \ast B$ the reduced free product (I think that it is the reduced amalgamated product over the common $*$-subalgebra $\mathbb{C} 1$) ...
JBrude's user avatar
  • 115
5 votes
1 answer
385 views

hereditary C*-subalgebra of a non-elementary simple C*-algebra

A is said to be elementary if A is isomorphic to some $K(H)$ or $M_n$. A C*-subalgebra $B$ is said to be hereditary if for every $0≤a≤b∈B$ we have $a∈B$. I wanted to know that is this statement true? ...
Peg Leg Jonathan's user avatar
2 votes
0 answers
243 views

Reference request: definiitions of exact C* algebra and group C* algebra

I am writing my Ph.D. thesis and I would like to cite the specific papers where the concept of exact $C^*$ algebra and group $C^*$ algebra was defined. In the book of Brown and Ozawa "$C^*$-...
JBrude's user avatar
  • 115
5 votes
1 answer
520 views

Embedding of Cuntz algebras $O_2\subseteq O_3$?

The Cuntz algebra $O_n$ is the (universal) C*-algebra generated by n-isometries $s_1,...,s_n$ such that $$\sum_{i=1}^n s_is_i^\ast =\mathbf{1}, \ \hbox{and}\ s_i^\ast s_j=\delta_{ij} \mathbf{1}\ (\...
Paulo's user avatar
  • 155
2 votes
2 answers
214 views

Commutative C*-rings

Let us consider the unital commutative $C^*$-algebra $C[0,1]$. We say $A\subseteq C[0,1]$ forms a C*-subring if it satisfies the following conditions: 1- $A$ is an involutive unital subring (closed ...
ABB's user avatar
  • 4,058
2 votes
2 answers
217 views

Kernel of intertwiner is invariant (compact quantum groups)

Before asking my question, let me introduce the relevant terminology. Throughout, let $(A, \Delta)$ be a compact quantum group. Definition: A representation $v$ on the Hilbert space $H$ is an element $...
user avatar
2 votes
0 answers
203 views

Quasidiagonal C*-algebras

Let $A$ be a nuclear $C^*$-algebra satisfying UCT condition. Then under what assumptions $A$ is quasidiagonal?
Peg Leg Jonathan's user avatar
12 votes
0 answers
814 views

Why do some tricks in homological algebra work over the category of C*-algebras?

The category of $C^*$-algebras is not abelian (a "proof" that it is pre-abelian can be found here, but it does not seem correct; I can't find any authoritative sources). However, it's ...
xuq01's user avatar
  • 1,084
3 votes
1 answer
112 views

Is restriction to the center an open map?

Given a type one $C^*$-algebra $A$, its center $Z$ acts by scalars on each irreducible representation space. Mapping a representation to its central character yields a continuous map from the ...
user avatar
7 votes
0 answers
113 views

Does the following tracial inequality (involving certain function applications) hold for positive semi-definite matrices?

Given $n \in \mathbb{N}$ we define the function $f_{i,n}: [0,1] \rightarrow \mathbb{R}$ for $i \in \{1,..., n\}$ by $f_{i,n} = 0$ on the interval $[0,(i-1)/n]$, $f_{i,n} = 1$ on $[i/n,1]$, and $f_{i,n}...
Lise Wouters's user avatar
2 votes
2 answers
291 views

If either $A$ is exact or $B$ is nuclear then every closed ideal of $A\otimes_{min}B$ is of the form $A \otimes _{min}J$ for some ideal $J$ of $B$

From one of the talks I attended long back, I vaguely seem to remember the following fact: Let $A$ and $B$ be $C^{\ast}$-algebras. If either $A$ is exact or $B$ is nuclear then every closed ideal of $...
Math Lover's user avatar
  • 1,115
2 votes
2 answers
302 views

Is $x \mapsto x \otimes 1$ $\sigma$-weakly continuous?

Let $M\subseteq B(H)$ be a von Neumann algebra. Is it true that the mapping $$\psi: M \to B(H \otimes H): m \mapsto m \otimes \text{id}_H$$ is $\sigma$-weakly continuous? Here the $\sigma$-weak ...
user avatar
2 votes
0 answers
119 views

Does this groupoid have a quasi-diagonal reduced $C^*$-algebra?

Let $H$ be a discrete group, and let $X$ be the one-point compactification of $\mathbb{N}$. Consider the étale groupoid $G = H \times \{\infty\} \sqcup \mathbb{N}$, whose unit space is $X$, and with ...
Diego Martinez's user avatar
13 votes
0 answers
3k views

Connes Embedding Conjecture is false [closed]

This preprint from yesterday claims to prove that Connes Embedding Conjecture fails. Since the paper is from outside Operator Algebras (Computer Science/Quantum Computing) and they actually work on ...
Martin Argerami's user avatar
3 votes
0 answers
69 views

Trying to understand morphisms in category of ternary $C^*$-rings

Recall that a ternary $C^*$-ring is a complex Banach space $X$, equipped with a associative ternary product $[.,.,.]:X^3 \to X$ which is linear in outer variables and conjugate linear in middle ...
Math Lover's user avatar
  • 1,115
0 votes
0 answers
88 views

$*$–homomorphisms of the center of $C^*$-algebras

Let $A$ and $B$ be $C^*$-algebras with centers $Z_A$ and $Z_B$. Suppose $\rho:A\rightarrow B$ is a surjective $*$- homomorphism. It is easy to check $\rho(Z_A)\subset Z(B)$. I wonder how to assure ...
math112358's user avatar
0 votes
1 answer
495 views

Separability of an algebra is equivalent to separability of its spectrum

Let $A$ be a commutative C*-algebra. I would like to show that $A$ is separable (i.e. has a countable dense subset) if and only if the spectrum of $A$ (denoted by $\Omega(A)$) is separable. Notes ...
ned grekerzberg's user avatar
5 votes
1 answer
245 views

Colimits of short exact sequences of C*-algebras

Assume I have an inductive system of short exact sequences of $C^{\ast}$-algebras (i.e., short exact sequences $0 \to A_n \to B_n \to C_n \to 0$ together with transformations from the $n$-th to the $(...
AlexE's user avatar
  • 2,998
4 votes
1 answer
341 views

On differential equation $Z'=Z^2-Z$ on a $C^*$ algebra

Let $A$ be a Banach or a $C^*$ algebra. We consider the differential equation $$(*)\;\;\;\;Z'=Z^2-Z$$ on $A$. Obviously the singularities of this systems are just the idempotents of the ...
Ali Taghavi's user avatar
2 votes
1 answer
254 views

Is the reduced group $C^*$-algebra quasidiagonal

Let $G$ be an amenable group. I wonder whether it is true that the reduced group $C^*$-algebra $C_r^*(G)$ is quasidiagonal.
mathbeginner's user avatar
6 votes
1 answer
347 views

Morita-invertible C*-algebras

I am familiar with the Morita theory of rings, and the hermitian Morita theory of rings with involution, and I am trying to understand some parallels and differences with the Morita theory of C*-...
Captain Lama's user avatar
4 votes
1 answer
201 views

Is the unit ball of $A \odot B$ strictly dense in that of $M(A \otimes B)$?

Let $A$ and $B$ be $C^*$-algebras and let $A \otimes B$ their minimal tensor product and $M(A \otimes B)$ the associated multiplier algebra. On $M(A \otimes B)$, we consider the strict topology which ...
user avatar
19 votes
1 answer
773 views

Are algebraically isomorphic $C^*$-algebras $*$-isomorphic?

If A and B are C^*-algebras that are algebraically isomorphic to each other, does this imply that they are *-isomorphic to each other?
Doc Matrix's user avatar
3 votes
2 answers
260 views

Jordan isomorphisms of type I von Neumann algebras

Let $\mathcal M$ and $\mathcal N$ be two von Neumann algebras. A linear map $J:\mathcal M\to\mathcal N$ is said to be a Jordan isomorphism if $J$ is bijective, $*$-preserving and $J(xy+yx)=J(x)J(y)+J(...
A beginner mathmatician's user avatar

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